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Test: Pipelining Hazards - Computer Science Engineering (CSE) MCQ


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10 Questions MCQ Test Computer Architecture & Organisation (CAO) - Test: Pipelining Hazards

Test: Pipelining Hazards for Computer Science Engineering (CSE) 2024 is part of Computer Architecture & Organisation (CAO) preparation. The Test: Pipelining Hazards questions and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus.The Test: Pipelining Hazards MCQs are made for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Pipelining Hazards below.
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Test: Pipelining Hazards - Question 1

Consider a pipelined processor operating at 2 GHZ with 5 stages, Instruction fetch (IF), Instruction decode (ID), Execute (EX), Memory access (MEM), and write back (WB). Each stage of the pipeline, except the EX stage, takes one cycle. The EX takes one cycle for ADD and SUB, three cycles for MUL, two cycles for DIV Instruction.

Consider the following instructions:

Find, the number of true data dependences in the above code and the execution time using operand forwarding technique respectively is______.

Detailed Solution for Test: Pipelining Hazards - Question 1


∴ 2 true dependencies are there.
∴ f = 2GHz


Total cycles require = 11
∴ Execution time = 11 × 0.5 = 5.5 ns.

Test: Pipelining Hazards - Question 2

Which of the following hazards occurs when the pipeline makes the wrong decision on a branch prediction and therefore brings instructions into the pipeline that must subsequently be discarded? 

Detailed Solution for Test: Pipelining Hazards - Question 2

Concept:
Branch hazards occur when the pipeline makes wrong decisions on branch prediction and therefore brings instructions into the pipeline that must subsequently be discarded.

  • The term branch hazard also refers to a control hazard or instruction hazard.
  • Branch hazard form of dependence happens when control instructions such as BRANCH, CALL, JMP, and others are transferred. When the processor wants to introduce a new instruction into the pipeline, it will not know the target address of these instructions on many instruction architectures.

Hence the correct answer is Branch hazard.

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Test: Pipelining Hazards - Question 3

Which of the following is NOT an instruction pipeline hazard ?

Detailed Solution for Test: Pipelining Hazards - Question 3

Concept:
Hazards are the conditions that can prevent some instructions in the instruction stream from executing during its designated clock cycle.
Pipeline hazard is a condition that causes a stall in pipeline operations and degrades the performance of the pipeline. 
There are three types of pipeline hazard:

  1. Control hazard: Control hazards occur due to wrong branch predictions and other instruction that causes changes in the program counter.
  2. Data hazard: Data hazards occur when data dependency exists among instructions that are in different stages of execution in the pipeline.
  3. Structural hazard: Structural hazard arises due to resource conflicts.

Hence, the Address hazard is NOT an instruction pipeline hazard.

Test: Pipelining Hazards - Question 4

The locality of reference concept will fail in which of the following cases?
Where there are

Detailed Solution for Test: Pipelining Hazards - Question 4

The locality of the reference concept will fail where there are many unconditional jumps.
Concept
The locality of Reference: 

  • It is the phenomenon in which a computer program tends to access the same set of memory locations for a particular time period. There are two basic types of reference locality – temporal and spatial locality.
  • Temporal locality: If at one point a particular memory location is referenced, then it is likely that the same location will be referenced again in the near future.
  • Spatial locality: If a particular storage location is referenced at a particular time, then it is likely that nearby memory locations will be referenced in the near future.
  • In unconditional Jump, the computer program won't be able to access the same set of memory locations for a particular time period.
Test: Pipelining Hazards - Question 5

If instruction X tries to modify some data before it is written by instruction (X-1), it can result in a ________ hazard.

Detailed Solution for Test: Pipelining Hazards - Question 5

Initially A = 20

Instruction: X – 1, writes the value 70
Instruction: X, overwrites it with 90
In system, after T1 and T2 execution value of A = 90
Ideally value should be 20 + 50 + 70 = 140
These hazards arise due to write after write

*Answer can only contain numeric values
Test: Pipelining Hazards - Question 6

A processor X1 operating at 2 GHz has a standard 5-stage RISC instruction pipeline having a base CPI (cycles per instruction) of one without any pipeline hazards. For a given program P that has 30% branch instructions, control hazards incur 2 cycles stall for every branch. A new version of the processor X2 operating at same clock frequency has an additional branch predictor unit (BPU) that completely eliminates stalls for correctly predicted branches. There is neither any savings nor any additional stalls for wrong predictions. There are no structural hazards and data hazards for X1 and X2. If the BPU has a prediction accuracy of 80%, the speed up (rounded off to two decimal places) obtained by X2 over X1 in executing P is ______.


Detailed Solution for Test: Pipelining Hazards - Question 6

Concept:
The given data,
Cycle time (tp) = 2 GHz = 0.5 nanoseconds.
K = 5,
X1:
Without branch prediction.

CPI = 1 + Number of stalls instruction
CPI = 1 + (0.3) × 2
CPI = 1.6
Average serial instruction execution time = CPI * Cycle time
Average serial instruction execution time = 1.6* 0.5nsec 
Average serial instruction execution time = 0.8 ns.
X2:
If BPU predicted the correct branch then it eliminate stalls but if BPU predicted the wrong branch then BPU does not add any additional stalls but the remaining stalls will be present.

CPI = 1+(0.3 ×0.2 ×2)
CPI =1.12
Average parallel instruction execution time = CPI × Cycle time
Average parallel instruction execution time = 1.12 × 0.5 ns
Average parallel instruction execution time = 0.56 ns.

Speedup:
A speedup is a number that measures the relative performance of two systems processing the same problem.
Speedup = Serial Execution Time / Parallel Execution Time.
Speed up= 0.8 / 0.56
Speed up=1.428
Hence the correct answer is 1.428.

Test: Pipelining Hazards - Question 7

Which among the following is correct for the causes of pipeline conflict in pipelined processor?
(i) Resource
(ii) Data dependency
(iii) Branch difficulties
(iv) control dependency

Detailed Solution for Test: Pipelining Hazards - Question 7

Concept:
Resource conflicts caused by access to memory by two segments at the same time. Most of these conflicts can be resolved by using separate instructions and data memories.
Data dependency conflicts arise when an instruction depends on the result of a previous instruction, but this result is not yet available.

Test: Pipelining Hazards - Question 8

One instruction tries to write an operand before it is written by previous instruction. This may lead to a dependency called

Detailed Solution for Test: Pipelining Hazards - Question 8

Option 1: True dependency
True dependency is when Read-after-Write or RAW occurs
Option 2: Anti-dependency
Anti-dependency is when Write-after-Read or WAR occurs
Option 3: Output Dependency
Output dependency is when Write-after-Write or WAW occurs
Option 4: Control hazard
Control Hazard is when pipeline makes wrong decisions on branch prediction

Test: Pipelining Hazards - Question 9

In the context of an instruction set, orthogonality indicates that other elements of an instruction are ______ of/by the opcode.

Detailed Solution for Test: Pipelining Hazards - Question 9
  • Instruction set is said to be orthogonal if any instruction can use data of any type through any addressing mode.
  • Orthogonality in other sense is,   instruction type and the addressing mode vary independently
  • Orthogonality doesn’t limit any instruction to use specific register
Test: Pipelining Hazards - Question 10

The method used for resolving data dependency conflict by the compiler itself is

Detailed Solution for Test: Pipelining Hazards - Question 10
  • In the case of the delayed load technique, the compiler detects the data conflict and recorder the instruction as necessary to delay the loading of the conflicting data by inserting no operation instructions (NOP).
  • Therefore the method used for resolving data dependency conflict by the compiler itself is delayed load.
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