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GATE Chemical Engineering Mock Test - 1 - GATE Chemical Engineering MCQ


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30 Questions MCQ Test GATE Chemical Engineering 2025 Mock Test Series - GATE Chemical Engineering Mock Test - 1

GATE Chemical Engineering Mock Test - 1 for GATE Chemical Engineering 2024 is part of GATE Chemical Engineering 2025 Mock Test Series preparation. The GATE Chemical Engineering Mock Test - 1 questions and answers have been prepared according to the GATE Chemical Engineering exam syllabus.The GATE Chemical Engineering Mock Test - 1 MCQs are made for GATE Chemical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Chemical Engineering Mock Test - 1 below.
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GATE Chemical Engineering Mock Test - 1 - Question 1

Identify the sentence with correct punctuation:

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 1

The sentence uses correct punctuation, including the Oxford comma before "and" in a list.

GATE Chemical Engineering Mock Test - 1 - Question 2

In a classroom of NIT Jaipur, the ratio of boys to girls is 3/4​.
If there are 84 students in total, how many boys and how many girls are there?

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 2

The total number of students is 84, so:
3x + 4x = 84
Calculate the number of boys and girls:
Number of boys = 3x = 3 × 12 = 36  
Number of girls = 4x = 4 × 12 = 48  

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GATE Chemical Engineering Mock Test - 1 - Question 3

Choose the synonym that fits best in the blank:
"After the long hike, we felt completely ________ and needed to rest."

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 3

"Exhausted" means extremely tired, which fits the context of needing rest after a long hike.

GATE Chemical Engineering Mock Test - 1 - Question 4

Inhaling the smoke from a burning _________ could _________ you quickly. 

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 4
  • A homophone refers to a word that is pronounced the same as another word but that has a different spelling and meaning.
  • For example  - 
    • The words 'Peace' ( a stress-free state of security and calmness)  and 'piece' (one of the parts that something is made of)
    • The words 'cent' (small unit of money ) and  'scent' (a pleasant or distinctive smell produced by something)
  • Based on the above given points,  the word 'tyre' fits in the first blank contextually. A tyre is a thick piece of rubber which is fitted onto the wheels of vehicles (रबड़ का एक मोटा टुकड़ा जो वाहनों के पहियों पर लगाया जाता है). ​
    • Ex: Tom was driving along the motorway when his tyre burst.
  • Similarly, the word which is most suitable for the second blank is 'tire' which means 'to become weary' (थक जाना) as the sentence states how the smoke from a burning tire can weaken  a person.

Therefore, the correct answer is Option C.

GATE Chemical Engineering Mock Test - 1 - Question 5

A sphere of radius r cm is packed in a box of cubical shape.
What should be the minimum volume (in cm3) of the box that can enclose the sphere?

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 5


Diameter of sphere = Side of cube
a = 2r
Volume of cube = (2r)3
= 8r3

GATE Chemical Engineering Mock Test - 1 - Question 6

A game consists of spinning an arrow around a stationary disk as shown below. When the arrow comes to rest, there are eight equally likely outcomes. It could come to rest in any one of the sectors numbered 1, 2, 3, 4, 5, 6, 7 or 8 as shown. Two such disks are used in a game where their arrows are independently spun.
What is the probability that the sum of the numbers on the resulting sectors upon spinning the two disks is equal to 8 after the arrows come to rest?

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 6

Probability of getting only one number = 1/8
As they are independent spins probability of getting one number for each disc is
P = 1/8 x 1/8
Possible outcomes to the sum of 8 = (1, 7), (2, 6), (3, 5), (4, 4), (5, 3), (6, 2), (7, 1)
Required probability = 7/64

GATE Chemical Engineering Mock Test - 1 - Question 7

Consider the following inequalities.
(i) 3p - q < 4
(ii) 3q - p < 12
Which one of the following expressions below satisfies the above two inequalities?

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 7

Adding both equation
2p + 2q < 16
p + q < 8

GATE Chemical Engineering Mock Test - 1 - Question 8

In a family of six members A, B, C, D, E, and F, B is the mother of C, C is the sister of D, E is the father of B, and F is the brother of B. How is D related to E?

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 8

Since D’s gender is not specified, we cannot determine if D is the grandson or granddaughter of E.

GATE Chemical Engineering Mock Test - 1 - Question 9

Given matrix  the ordered pair (x, y) for which det(A) = 0 is

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 9


For,    |A| = 0
Row 2 element is 2 times of Row 1
=> y = 2x
So, option (b) satisfies this equation.

GATE Chemical Engineering Mock Test - 1 - Question 10

Let f(x) = e-|x|, where x is real. The value of df/dx at x = -1 is

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 10


GATE Chemical Engineering Mock Test - 1 - Question 11

For a single component system at vapor-liquid equilibrium, the extensive variables A, V, S and N denote the Helmholtz free energy, volume, entropy, and number of moles, respectively, in a given phase. If superscripts (v) and (/) denote the vapor and liquid phase, respectively, the relation that is NOT CORRECT is

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 11

At equilibrium of vapor and liquid phases

GL = GV

TL = TV

PL = PV

We know, A = U - TS

A + TS = U

So internal energy is not equal at equilibrium condition.

Option (d) is incorrect.

dA = -SdT - PdV

GATE Chemical Engineering Mock Test - 1 - Question 12

A thermal energy reservoir (TER) has

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 12

The thermal energy reservoir has infinite heat capacity thus even when a huge amount of heat is either taken out or transferred to the reservoir its temperature is considered constant.

GATE Chemical Engineering Mock Test - 1 - Question 13

The energy/heat required to completely vapourize 10 g of water beginning at 0º C. (The heat capacity of water is 4.2 J/g.K and the ΔH vapourization of water is 2260 kJ/kg).

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 13

Q = mCp​ ΔT + mλV
Q = 0.01(4.2 × 100 + 2260 × 103)
ΔT = 373K − 273K
(373K − Boiling point of water; 273 K – Initial Temperature)
= 26800 J = 

GATE Chemical Engineering Mock Test - 1 - Question 14

Consider turbulent flow in a pipe under isothermal conditions. Let r denote the radial coordinate and z denote the axial flow direction. On moving away from the wall towards the center of the pipe, the rz-component of the Reynolds stress 

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 15

Consider interphase mass transfer of a species S between two immiscible liquids A and B. The interfacial mass transfer coefficient of S in liquid A is twice of that in liquid B. The equilibrium distribution of S between the liquids is given by yAS = 0.5 yBS, where yAS and yBS are the mole-fractions of S in A and B, respectively. The bulk phase mole fraction of S in A and B is 0.10 and 0.02, respectively. If the steady-state flux of S is estimated to be 10 kmol h-1 m-2, the mass transfer coefficient of S in A is ______ kmol h-1 m-2 (rounded off to one decimal place).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 15

Given: ka = 2 kb

Equilibrium relation is

So, NA = kB (0.11 - 0.02)

kA = 2 × 111.11 = 222.22 kmol/m2.hr

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 16

A wet solid containing 20% (w/w) moisture (based on mass of bone-dry solid) is dried in a tray-dryer. The critical moisture content of the solid is 10% (w/w). The drying rate (kg m-2 s-1) is constant for the first 4 hours, and then decreases linearly to half the initial value in the next 1 hour. At the end of 5 hours of drying, the percentage moisture content of the solid is ________ % (w/w) (rounded off to one decimal place).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 16

Initial moisture content (xi) = 0.2
Critical moisture content (xc) = 0.1
Time taking in constant rate period,

Given: tc = 4 hr


So,

In case IInd: Falling rate period is linear and rate of drying in falling period is half of rate of drying in constant rate period.

[Given: f = 1 hr]

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 17

A process described by the transfer function

is forced by a unit step input at time t = 0. The output value immediately after the step input (at t = 0+) i s _________(rounded off to the nearest integer).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 17


From initial value theorem:

GATE Chemical Engineering Mock Test - 1 - Question 18

N moles of an ideal gas undergo a two-step process as shown in the figure. Let P, V, and T denote the pressure, volume, and temperature of the gas, respectively. The gas, initially at state-1 (P1, V1, T1), undergoes an isochoric (constant volume) process to reach state-A, and then undergoes an isobaric (constant pressure) expansion to reach state-2 (P2, V2, T2). For an ideal gas, CP - CV = NR, where CP and CV are the heat capacities at constant pressure and constant volume, respectively, and assumed to be temperature independent. The heat gained by the gas in the two-step process is given by

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 18


Assume at point '2' temperature is T.

In process 1 to 2 volume is constant so

du = dQ - dw

du1 = dQ1

du1 = CV (T - T1)

In process 2-3 pressure is constant so

du2 = dQ2 - dw

Here,

dw = P2 (V2 - V1)

du2 = CV (T2 - T)

So, heat gained by process

dQ1 + dQ2 = du1 + du2 + dw

= P2 (V2 - V1) + CV (T2 - T) + CV (T2 - T1)

= P2 (V2 - V1) + CV (T2 - T) + CV (T2 - T1)

Correct option is (a).

GATE Chemical Engineering Mock Test - 1 - Question 19

A horizontal cylindrical water jet of diameter D1 = 2 cm strikes a vertical solid plate with a hole of diameter D2 = 1 cm, as shown in the figure. A part of the jet passes through the hole and the rest is deflected along the plate. The density of water is 1000 kg m-3. If the speed of the jet is 20 m s-1, the magnitude of the horizontal force, in N, required to hold the plate stationary is

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 19


Applying momentum balance, we get

GATE Chemical Engineering Mock Test - 1 - Question 20

Which of the following is correct :

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 20

Corrosive fluid is preferred to send in shell side of heat exchanger.
This is correct. Corrosive fluids are often placed on the shell side because it is easier and cheaper to replace or repair the shell and its components than the tubes. Moreover, it allows for better material selection and easier maintenance.

GATE Chemical Engineering Mock Test - 1 - Question 21

Which of the following statements is correct regarding the heat transfer mechanisms of convection and radiation?

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 21

In convection, heat is transferred by the bulk movement of fluid molecules, such as air or water, which carry energy from one place to another. In radiation, heat is transferred via electromagnetic waves (such as infrared radiation) and does not require any material medium (it can occur in a vacuum, such as in space).

GATE Chemical Engineering Mock Test - 1 - Question 22

In a chemical reaction following Michaelis-Menten kinetics, the reaction rate at high substrate concentrations approaches:

Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 22

In Michaelis-Menten kinetics, at high substrate concentrations, the enzyme active sites become saturated, and the reaction rate reaches a maximum, constant rate (Vmax​).

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 23

An equimolar binary mixture is to be separated in a simple tray-distillation column. The feed rate is 50 kmol min-1. The mole fractions of the more volatile component in the top and bottom products are 0.90 and 0.01, respectively. The feed as well as the reflux stream are saturated liquids. On application of the McCabe-Thiele method, the operating line for the stripping section is obtained as
y = 1.5 x - 0.005
where y and x are the mole fractions of the more volatile component in the vapor and liquid phases, respectively. The reflux ratio i s ______ (rounded off to two decimal places).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 23

Equimolar binary mixture, x 05
Feed flowrate = 50 kmol/min
xD = 0.9, xw= 0.01
Stripping line equation:
1.5x - 0.005
and Saturated feed (q) = 1

FxF = DxD + WxW
50 x 0.5 = D x 0.9 + w x 0.01
25 = D x 0.9 + (50 - D) x 0.01
25 - 0.5 = D(0.9 - 0.01)
D = 27.52, w = 22.47


For saturated feed

For enriching section
V= L + D
44.94 - 27.52 = L = 17.42 kmol/min
So,

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 24

Information for a proposed greenfield project is provided in the table. The discounted cash flow for the fourth year is Rs_______crores (rounded off to one decimal place).

k: years post start-up d: Depreciation amount BV: Book value


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 24

Given:
FCI (excluding land) = 250 crores
Salvage value = 0
Yearly revenue from product sales = 120 crores
Yearly Manufacturing cost = 30 crores
(excluding depreciation)
Interest rate = 10% compounded annually
Annual taxation rate = 30%
Profit = 120 - 30 = 90 crores
Depreciation for 
From double declining balance method,


Taxable profit = 90 - 26.03 = 63.96 crore
Tax paid = 63.96 x 0.3 Profit after tax = 44.77 crore
Cash flow = PAT + Depreciation = 44.77 + 26.03
= 70.80 crore
Discounted cash flow = Present value at time, t = 0

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 25

In a jaw crusher, material of size 50 mm is crushed to a product of 5 mm and energy required comes at ‘E1’ kW.hr/tons while when a feed of size 25 mm is crushed to a product of size 2.5 mm, Energy required is ‘E2’ in kW.hr/tons. If Kick’s law is used what is the ratio of  E1/E2. (Upto one decimal place).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 25

To solve this problem using Kick's Law, we need to understand that Kick's law states that the energy required for size reduction is proportional to the logarithm of the ratio of the initial size to the final size:
E = K. In(Di/Df)
Where:
E = Energy required for size reduction (in kW.hr/tons),
K = Kick's constant (in kW.hr/tons),
Di​ = Initial particle size (in mm),
Df​ = Final particle size (in mm).
Given that the energy required for the two different feed and product sizes follows Kick’s law, we can set up a relationship between the energy values for the two conditions.
Let:
E1​ = Energy required for the first crushing (from 50 mm to 5 mm),
E2​ = Energy required for the second crushing (from 25 mm to 2.5 mm).
First condition: Di1 = 50 mm, Df1 = 5 mm
Second condition: Di2 = 25 mm, Df2 = 2.5 mm
Using Kick's law for each condition:
E1 = K. In (50/5) E2 = K. In (25/2.5)
Now, calculate the logarithmic ratios:
50/5 = 10,ln(10) ≈ 2.3026
25/2.5 = 10,ln(10) ≈ 2.3026
So, the energy required for each condition is:
E1 = K⋅2.3026 and E2 = K⋅ 2.3026
To find the ratio of E1 to E2​: E1/E= K . 2.3026 / K. 2.3026 = 1
Thus, the ratio of the energies required is 1.

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 26

For a cube with side ‘a’ the sphericity comes out to be 'ϕ1' if the side of cube is changed to ‘2a’ and sphericity becomes 'ϕ2'. what will be the ratio of 


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 26


*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 27

What is the total annual cost for option 2.
(in rupees to the nearest integer) ………………


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 27

Annual cost of capital recovery option 2 = 
Total annual cost = 5131.12 + 500 = Rs. 5631.12

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 28

Solute B has to be extracted from a solution containing solute B and solvent A with 30% of B by weight using solvent C. 1.5 kg of solution is feed with 1 kg of solvent C. Distribution coefficient is given as:

Solvent A and B are immiscible.
Calculate the amount of solute B in extract phase (in kg, upto two decimal place)


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 28

In feed, Solute 'B' = 1.5 × 0.3 kg
Solvent 'A' = 1.5 × 0.7 = 1.05 kg
Kg of solvent 'A' in raffinate = R′
Kg of solvent 'C' in extract = E′
r' (3/7 - x) = E'(Y' - 0)
05(0.428 – x) = (1.70 x) y = 0.278
Amount of solute B = 0.282 kg

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 29

The equation dy/dx  = xy2 + 2y + x - 4.5 with the initial condition y{x = 0) = 1 is to be solved dx using a predictor-corrector approach. Use a predictor based on the implicit Euler’s method and a corrector based on the trapezoidal rule of integration, each with a full-step size of 0.5. Considering only positive values of y, the value of y at x = 0.5 is __________ (rounded off to three decimal places).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 29

dy/dx = xy2 + 2y + x - 4.5

Given:

y(0) = 1

h = 0.5

→ x1 = x0 + h = 0 + 0.5 = 0.5

by Implicit Euler formula

y1 = y0 + h f(x1, y1)

dy = (x y2 + 2y + x - 4.5) dx



By trapezoidal rule,

*Answer can only contain numeric values
GATE Chemical Engineering Mock Test - 1 - Question 30

A venturi meter (venturi coefficient, Cv = 0.98) is connected to a pipe of inner diameter 50 mm. Water (density 1000 kg m-3) is flowing through the pipe. The pressure-drop measured across the venturi meter is 50 kPa. If the venturi throat diameter is 20 mm, the estimated flow rate of water is ______ x 10-3 m3 s-1 (rounded off to two decimal places).


Detailed Solution for GATE Chemical Engineering Mock Test - 1 - Question 30

Data given: Cd = 0.98

Pipe diameter, D0 = 50 mm, d0 = 20 mm (throat diameter)

ΔP = 50 kPa

ρw = 1000 kg/m3

For venturimeter, the flow rate is given by

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