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GATE Biotechnology Mock Test - 2 - GATE Biotechnology MCQ


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30 Questions MCQ Test - GATE Biotechnology Mock Test - 2

GATE Biotechnology Mock Test - 2 for GATE Biotechnology 2025 is part of GATE Biotechnology preparation. The GATE Biotechnology Mock Test - 2 questions and answers have been prepared according to the GATE Biotechnology exam syllabus.The GATE Biotechnology Mock Test - 2 MCQs are made for GATE Biotechnology 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Biotechnology Mock Test - 2 below.
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GATE Biotechnology Mock Test - 2 - Question 1
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In the year 2022, June Huh was awarded the Fields Medal, which is considered the highest honor in the field of Mathematics.
During his early years, he also engaged in poetry. He did not win any medals at the International Mathematics Olympiads and left college without completing his degree.
Based solely on the details provided above, which of the following statements can be logically concluded with certainty?

GATE Biotechnology Mock Test - 2 - Question 2
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"You are delaying the completion of the assignment. Kindly send  _______ contributions at your earliest convenience."

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GATE Biotechnology Mock Test - 2 - Question 3
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A boat navigates between three points along a river: A, B, and C, with B being an intermediate point that is equidistant from both A and C. The entire duration for the boat to go from A to B and back to A is 6 hours. If the trip from A to C takes 4 hours, what is the duration needed for the boat to travel from C back to A?

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 3

The boat navigates between points A, B, and C, with B being equidistant from A and C. The boat takes 6 hours to travel from A to B and back, and 4 hours to travel from A to C. We need to find the duration for the boat to travel from C back to A.

Let the speed of the boat in still water be v_b and the speed of the river current be v_r. The time for the journey from A to B and back is:

\

The time from A to C is:

To find the time from C to A, we use the equation:

Thus, the duration needed for the boat to travel from C back to A is 8 hours.

GATE Biotechnology Mock Test - 2 - Question 4
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Ranjan moves 5 km north from a specific location. He then takes a right turn and travels 3 km. Afterward, he makes another right turn and goes another 5 km. Finally, he turns left and continues for 4 km. What is the distance and direction from his initial position to his current location?
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 4


The diagrammatic representation of the same is given above:
Required distance = SD = SC + CD = 3 km + 4 km = 7 km
Thus, option 2 is correct.

GATE Biotechnology Mock Test - 2 - Question 5
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To construct a wall, sand is mixed with cement in a ratio of 3:1. The costs of sand and cement are in the ratio of 1:2.
If the total expenditure for sand and cement to erect the wall is 1000 rupees, what is the cost (in rupees) of the cement used?
GATE Biotechnology Mock Test - 2 - Question 6
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What is the coefficient of x4 in the expansion of the expression (x − 1)3 (x − 2)3?
GATE Biotechnology Mock Test - 2 - Question 7
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What is the value of the expression represented in the image above?
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 7


On solving it, we get,

GATE Biotechnology Mock Test - 2 - Question 8
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Which HIV protein binds to the CD4 receptor present on T-cells during the early stage of infection?
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 8

The entry of HIV into a host cell begins when the viral envelope protein gp120 binds to the CD4 receptor, a protein on the surface of certain T-cells. The binding of gp120 to CD4 changes the shape of gp120, allowing it to attach to another receptor on the cell membrane, usually CCR5. gp41 is another surface protein that mediates fusion of HIV with the target cell. The protein p17 forms the outer nucleocapsid layer in HIV.

GATE Biotechnology Mock Test - 2 - Question 9
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Evaluate the correctness of the following Assertion [a] and Reason [r].
Assertion [a]: In multicellular organisms, cells derived from various lineages show unique gene expression profiles.
Reason [r]: Alternative splicing is the only mechanism that contributes to the generation of protein diversity.
GATE Biotechnology Mock Test - 2 - Question 10
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Dendritic cells play a role in the cross-presentation of antigens. Which of the following protein(s) are necessary for this cross-presentation?

P. Basic leucine zipper ATF-like transcription factor 3 (BATF3)

Q. Membrane associated ring-CH-type finger 1 (MARCH-1)

R. Solute carrier family 10 member 1 (SLC10A1)

S. Class II-associated invariant chain peptide (CLIP)
GATE Biotechnology Mock Test - 2 - Question 11
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In eukaryotes, the process of transcription is carried out by 
GATE Biotechnology Mock Test - 2 - Question 12
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In the context of ELISA, which of the following enzymes are linked to antibodies for the purpose of analyte detection?

P. Alkaline phosphatase

Q. Trypsinase

R. Horseradish peroxidase

S. Amylase
GATE Biotechnology Mock Test - 2 - Question 13
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What does the term Lyonisation refer to?
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 13

In humans, females have two copies of the X-chromosome whereas males have only one. X-inactivation (also called lyonization) is a process by which one of the copies of the X chromosome present in female mammals is inactivated. The inactive X chromosome is silenced by it being packaged in such a way that it has a transcriptionally inactive structure called heterochromatin.
 

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GATE Biotechnology Mock Test - 2 - Question 14
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A diagnostic test is performed to detect a particular disease. It is known that 15% of the results classified as positive and 20% of those classified as negative are inaccurate. If the probability of an individual obtaining a positive result is 0.02, what is the probability that a person tested will receive an incorrect result? (Provide your answer up to three decimal points)

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 14

Probability of incorrect report,

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GATE Biotechnology Mock Test - 2 - Question 15
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Let x and y be two random variables such that E[x2] equals E[y2], and both have a mean of zero. Define two new random variables, w1 and w2, as follows:
w1 = x × y and w2 = x − y.
What is the correlation coefficient between w1 and w2?

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 15


⇒ E[(x + y)(x – y)] – E[x + y] E[x – y] = E[x2 – y2] = 0
pw1w2 = 0
x + y and x – y are orthogonal to each other.

GATE Biotechnology Mock Test - 2 - Question 16
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Match the organelles in Group I with their functions in Group II.
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 16

P. Lysosome → 1. Digestion of foreign substances
Lysosomes contain digestive enzymes that break down foreign materials and cellular waste.

Q. Smooth ER → 3. Lipid synthesis
The smooth endoplasmic reticulum (Smooth ER) is involved in lipid and steroid hormone synthesis.

R. Golgi apparatus → 2. Protein targeting
The Golgi apparatus modifies, sorts, and packages proteins for transport to different destinations.

S. Nucleolus → 5. rRNA synthesis
The nucleolus is the site of ribosomal RNA (rRNA) synthesis and ribosome assembly.

The correct match is: P-1, Q-3, R-2, S-5

GATE Biotechnology Mock Test - 2 - Question 17
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Determine the turnover number for an enzyme that catalyzes a reaction at a velocity of 2.0 × 105 mol s-1μ-1. (In this case, [S] = Km; [E] = 10-3 mol μl-1)
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 17

When [S] = Km,
V = Vm/2
Or Vm = V × 2
= 2.0 × 105 × 2
= 4.0 × 105 mol s-1 μl-1 
Turnover number kcat = Vm/[E]
= 4.0 × 105/10-3
= 4.0 × 108s-1  

GATE Biotechnology Mock Test - 2 - Question 18
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Which of the following statements about cell division are correct?

P. During the anaphase phase of mitosis and meiosis I, sister chromatids detach from each other.
Q. In the anaphase of mitosis and meiosis II, sister chromatids move apart from one another.
R. Homologous chromosomes and sister chromatids are positioned at the metaphase plate during the metaphase phase of mitosis and meiosis I, respectively.
S. Unpaired chromosomes and homologous chromosomes are arranged at the metaphase plate during the metaphase stage of mitosis and meiosis I, respectively.
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 18

The events in meiosis II are similar to those that take place in mitosis, i.e. the sister chromatids separate from each other during the anaphase stage. In meiosis I, homologous chromosomes separate from each other during anaphase. There is no homologous pairing in mitosis and hence, unpaired chromosomes align at the metaphase plate.

GATE Biotechnology Mock Test - 2 - Question 19
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Identify the Newton-Raphson method for iteratively finding the square root of 2.
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 19

We have, x = √2 or x2 - 2 = 0
or f(x) = x2 - 2
From Newton-Raphson iteration,

GATE Biotechnology Mock Test - 2 - Question 20
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What is the enzyme's turnover number when under saturating conditions, given that Vm is 4 × 108 molμl-1s-1 and the total enzyme concentration ([E]) is 2 × 102 mol/μl?
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 20

The turnover number, Kcat = Vm/[E].
Putting in the values, we get
Kcat = 4 × 108/2 × 102
Kcat = 2 × 106 s-1

GATE Biotechnology Mock Test - 2 - Question 21
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Which of the following statements is NOT correct regarding the structure of the lipid bilayer in the membrane of animal cells?

P. The main forces that organize the bilayer are covalent and ionic interactions.

Q. Lipids within the bilayer are capable of rotating freely about their axes.

R. The distribution of phospholipids in the plasma membrane is symmetrical.

S. The fluidity of the membrane reduces with an increase in temperature.
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 21

The primary forces for organising the bilayer are hydrophobic interactions. The phospholipids are asymmetrically distributed in the plasma membrane and the membrane fluidity increases with increase in temperature.

GATE Biotechnology Mock Test - 2 - Question 22
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Match the multi-protein complexes presented in Group I with their respective prosthetic groups found in Group II.
Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 22


NADH-CoQ reductase is Complex 1 in the electron transport chain.It contains 25 different proteins including several nonheme iron proteins.
Succinate dehydrogenase (SDH) or succinate-coenzyme Q reductase (SQR) or respiratory Complex II is an enzyme complex, found in many bacterial cells and in the inner mitochondrial membrane of eukaryotes.
CoQH2-cytochrome c reductase or respiratory Complex III is present in the mitochondria of all animals and all aerobic eukaryotes and the inner membranes of most eubacteria.
The enzyme cytochrome c oxidase or Complex IV is a large transmembrane protein complex found in bacteria, archaea, and in eukaryotes in their mitochondria. It is the last enzyme in the respiratory electron transport chain of cells located in the membrane.

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GATE Biotechnology Mock Test - 2 - Question 23
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If 

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GATE Biotechnology Mock Test - 2 - Question 24
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A container contains 8 white balls and 6 red balls. What is the probability of drawing two balls of the same color?
(Provide your answer rounded to two decimal places)

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 24


= 0.472
= 0.47

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GATE Biotechnology Mock Test - 2 - Question 25
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(Provide your answer rounded to the nearest integer)

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 25

Let 
At → 0, f(x) is of the form of (0/0).
So, applying L-Hospital's rule

1/1 = 1

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GATE Biotechnology Mock Test - 2 - Question 26
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In an autoclave, the temperature controller is configured to maintain a temperature range from 60 °C to 130 °C. With the proportional band setting of the controller being 25%, what is the proportional gain value?

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GATE Biotechnology Mock Test - 2 - Question 27
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Determine the expected frequency of the genotype Aa.

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 27

The frequency of allele A = p = [2 x No. of AA + No. of Aa]/2 x No. of individuals
p = 2 x 430 + (540/2) x 1000
p = 0.7
Similarly, frequency of allele a = q = 2 x 30 + (540/2) x 1000
q = 0.3
Expected frequency of Aa = 2pq = 2 x 0. 7 x 0.3 x 1000 = 420

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 2 - Question 28
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Determine the absolute value of the inbreeding coefficient for the specified population. (Present your answer rounded to two decimal places)

Detailed Solution for GATE Biotechnology Mock Test - 2 - Question 28

Heritability, F = (2pq – H)/2pq
Where, H is the observed frequency of heterozygotes.
F = (420 – 540)/420
F = - 0.28

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 2 - Question 29
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A master mix of dNTPs is prepared by combining 40 µL from each 20 mM stock solution of dNTPs (dATP, dCTP, dGTP, and dTTP). Following this preparation, 4 µL of the dNTP master mix is added to a PCR reaction, and the overall volume is brought to 50 µL. What is the concentration (in mM) of the total dNTPs present in the PCR mixture?

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GATE Biotechnology Mock Test - 2 - Question 30
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The reaction depicted below demonstrates the production of biomass from hexadecane:
C16 H34 12.5O2 2.13NH3 → 10.6CH1.66 O0.27 N0.27 5.37CO2 11.4H2O

In this equation, CH1.66O0.27 N0.27 represents the biomass. What is the respiratory quotient's value (rounded to two decimal places)? ___________

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