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GATE Biotechnology Mock Test - 5 - GATE Biotechnology MCQ


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30 Questions MCQ Test - GATE Biotechnology Mock Test - 5

GATE Biotechnology Mock Test - 5 for GATE Biotechnology 2025 is part of GATE Biotechnology preparation. The GATE Biotechnology Mock Test - 5 questions and answers have been prepared according to the GATE Biotechnology exam syllabus.The GATE Biotechnology Mock Test - 5 MCQs are made for GATE Biotechnology 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Biotechnology Mock Test - 5 below.
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GATE Biotechnology Mock Test - 5 - Question 1

We possess two rectangular sheets of paper, M and N, each measuring 6 cm x 1 cm. Sheet M is rolled to create an open cylinder by joining the shorter edges of the sheet. Sheet N is divided into equal square pieces and assembled to construct the largest possible closed cube. Assuming the cylinder's ends are sealed, what is the ratio of the volume of the cylinder to that of the cube? __________

GATE Biotechnology Mock Test - 5 - Question 2

Consuming a nutritious diet is essential for healthy aging. At what point should one begin to eat healthily? It appears that there is no time too early to start. For instance, infants who adopt healthy eating habits within their first year are more likely to enjoy better overall health as they grow older.
Which of the following is the CORRECT logical conclusion derived from the details presented in the above passage?

GATE Biotechnology Mock Test - 5 - Question 3

P invested ₹ 5000 per month for 6 months of a year and Q invested ₹ x per month for 8 months of the year in a partnership business. The profit is shared in proportion to the total investment made in that year.
If at the end of that investment year, Q receives 4/9 of the total profit, what is the  value of x (in ₹)?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 3

  • Calculate P's total investment: ₹5000 per month for 6 months = 5000 x 6 = ₹30,000.

  • Q receives 4/9 of the profit, so P receives 5/9. This implies Q's investment is 4/9 of the total investment.

  • Let Q's total investment be 8x (since x is invested per month for 8 months).

  • Set up the ratio: 8x / (30000 + 8x) = 4/9.

  • Cross-multiply to solve: 72x = 4(30000 + 8x).

  • Simplify and solve: 72x = 120000 + 32x, so 40x = 120000.

  • Divide both sides by 40: x = 3000.

  • The correct answer is B: ₹3000.


  •  
GATE Biotechnology Mock Test - 5 - Question 4

If there exists a relationship among the following numbers, which of the subsequent numbers corresponds to the question mark?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 4

First line: (5 × 1 + (5 – 1)) = 5 + 4 = 9
Second line: (9 × 2 + (9 – 2)) = 18 + 7 = 25
Third line: (25 × 3 + (25 – 3)) = 75 + 22 = 97

GATE Biotechnology Mock Test - 5 - Question 5

The spinner initially points towards the west. Azad rotates it clockwise  revolutions and subsequently rotates it anti-clockwise  revolutions. After completing both movements, which direction will the spinner be pointing?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 5

After clockwise  revolutions pointer will show N. After anti-clockwise  revolutions pointer will show E.

GATE Biotechnology Mock Test - 5 - Question 6

In the process of adsorption chromatography, the mechanism by which uncharged solute molecules adhere to a silica-based stationary phase is through ________.

GATE Biotechnology Mock Test - 5 - Question 7

The transfer function of a certain process is represented as G(s) = where Kp denotes the gain and τp signifies the time constant. This is classified as a ________ process.

GATE Biotechnology Mock Test - 5 - Question 8

Examine the following statements concerning the primary roles of the plasma membrane:
P. The plasma membrane distinguishes the fluid environments within and outside of the cell.
Q. It regulates the passage of molecules and ions into and out of the cell.
R. It facilitates recognition and communication among various cells and tissues.
S. It is involved in the synthesis of proteins utilized in the formation of the cell wall.
Select the correct combination of statements.

GATE Biotechnology Mock Test - 5 - Question 9

A matrix B is said to be skew-symmetric if it meets certain criteria.

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 9

A square matrix B is defined as skew-symmetric if and only if BT = –B, by definition.

GATE Biotechnology Mock Test - 5 - Question 10

Let [A] be a square matrix that is neither symmetric nor skew-symmetric, and let [A]T denote its transpose. The matrices' sum and difference are defined as [S] = [A] [A]T and [D] = [A] – [A]T, respectively. Which of the following statements is correct?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 10

Since, St = (A + At)t = At + (At)t = At + A = S
i.e. St = S
S is symmetric
Since Dt = (A – At)t = At – (At)t = At – A = –(A – At) = –D
i.e. Dt = D
So, D is skew-symmetric.

GATE Biotechnology Mock Test - 5 - Question 11

All of the following statements regarding scanning tunneling microscopy are accurate, except for one.

GATE Biotechnology Mock Test - 5 - Question 12

Evaluate the statements below concerning traditional breeding and RDT.
P. Traditional breeding is limited to introducing desired traits found within the same species, whereas RDT can facilitate the introduction of desired traits from both the same and different species.
Q. Traditional breeding is a quicker process, while RDT requires more time.
R. RDT involves the transfer of only specific gene(s), while traditional breeding results in the transfer of numerous unselected genes.

Which of the statements above illustrates the advantages of RDT compared to traditional crop breeding methods?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 12

Traditional breeding has many limitations like it can be used to select only those traits that are naturally present in plants of that species, it also leads to selection of multiple other genes which scientists do not wants to transfer. Apart from that, it is very time taking process as it depends on field trials and data collection for selection of plants with desired traits. All these limitations are not there in RDT.

GATE Biotechnology Mock Test - 5 - Question 13

A concentration of dissolved oxygen that exceeds the critical value (Dcrit) results in

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 13

When oxygen is rate limiting factor, specific growth rate of microorganism varies with dissolved oxygen concentration, but above a critical oxygen concentration, the growth rate becomes independent of DO concentration.

GATE Biotechnology Mock Test - 5 - Question 14

The rate equation for the reaction involving substances A and B is expressed as rate = k[A]n[B]m. If the concentration of A is doubled and the concentration of B is reduced to half, what will be the ratio of the new reaction rate to the original reaction rate?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 14

GATE Biotechnology Mock Test - 5 - Question 15

Which of the following statements regarding microscopes is accurate?

GATE Biotechnology Mock Test - 5 - Question 16

In a gene cloning procedure, which enzyme would be effective for transforming sticky ends into blunt ends?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 16

Mung bean nuclease can cleave single stranded DNA, and commonly used to trim single stranded region in a double stranded DNA.

GATE Biotechnology Mock Test - 5 - Question 17

A total of ten cells were introduced into a culture medium for animal cells. After a period of ten days, six of these cells underwent three rounds of cell division, while the remaining four cells did not divide at all. At this current stage, what is the aggregate number of kinetochores present in all the cells combined?

GATE Biotechnology Mock Test - 5 - Question 18

Identify the accurate pairing of the secretory forms of antibody classes along with their characteristics:

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 18

In membrane bound form almost all the antibodies classes are usually found in monomeric form. But in secretory form IgM is usually found in pentameric form, IgA in dimeric form and other three in monomeric form.

GATE Biotechnology Mock Test - 5 - Question 19

Which of the following assertions are accurate regarding the fluid-mosaic model of cellular membranes?

P. They have a thickness ranging from 5-8 nm and exhibit a trilaminar appearance when examined in cross-section using an electron microscope.

Q. They measure less than 1 nm in thickness and are composed of a protein layer situated between two layers of phospholipids.

R. They exist in the lipid bilayer, with proteins embedded at irregular intervals, maintained by hydrophilic interactions between lipids and the hydrophilic regions of the proteins.

S. The protein domains that are exposed on one side of the lipid bilayer differ from those that are exposed on the opposite side.

GATE Biotechnology Mock Test - 5 - Question 20

The Damköhler numbers (Da) are denoted by which expression?

GATE Biotechnology Mock Test - 5 - Question 21

If five stem cells undergo five rounds of asymmetric cell divisions, how many stem cells will be present at the conclusion of all five divisions?

GATE Biotechnology Mock Test - 5 - Question 22

The DNA sequence shown below is to be amplified by PCR:
5'GCTAAGATCTGAATTTTCC....TTGGGCAATAATGTAGCGC3'
3' CGATTCTAGACTTAAAAGG.....AACCCGTTATTACATCGCG5'
Which one of the following pair of primers can be used for this amplification?

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 22

Polymerase Chain Reaction (PCR) is a technique used to amplify specific DNA sequences.

  • To perform PCR, you need two primers that complement the DNA strands.
  • Primers must bind to the ends of the target sequence on opposite strands.

In the given DNA sequence, the correct primers are:

  • 5' GCTAAGATCTGAATTTTC - This primer matches the start of the top strand.
  • 5' GCGCTACATTATTGCCCA - This primer matches the end of the bottom strand.

This combination corresponds to Option B.

GATE Biotechnology Mock Test - 5 - Question 23

Which of the following assertions regarding the immune response are TRUE?

[P] T cells are stimulated by antigen-presenting cells

[Q] Class II MHC proteins do not present foreign peptides to helper T cells

[R] Dendritic cells are known as professional antigen-presenting cells

GATE Biotechnology Mock Test - 5 - Question 24

W, X, and Y serve as intermediates in a biochemical pathway illustrated below:

Mutants that are auxotrophic for Z are classified into four distinct complementation groups: Z1, Z2, Z3, and Z4. The growth patterns of these mutants on media enriched with W, X, Y, or Z are indicated below (Yes: indicates growth observed; No: indicates growth not observed):

What is the sequence of the four complementation groups regarding the specific step they inhibit?

GATE Biotechnology Mock Test - 5 - Question 25

What is the application of cryo-electron microscopy?

GATE Biotechnology Mock Test - 5 - Question 26

The immune response known as delayed type hypersensitivity is categorized as one that is mediated by

Detailed Solution for GATE Biotechnology Mock Test - 5 - Question 26

Delayed hypersensitivity is mediated by T-Cells.

GATE Biotechnology Mock Test - 5 - Question 27

Which lipid is found in the highest quantity in the plasma membrane?

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 5 - Question 28

The arrangement of a 1 Mb long DNA strand is random, with all four bases present in equal amounts. On average, how many nucleotides are there between two consecutive EcoRl recognition sites, GAATTC?


*Answer can only contain numeric values
GATE Biotechnology Mock Test - 5 - Question 29

Aspergillus niger is cultivated in a 10,000 L stirred batch bioreactor under aerated conditions for citric acid production. Under steady state oxygen transfer conditions, the specific oxygen uptake rate of the organism and the volumetric mass transfer coefficient are and 60 min-1, respectively.
If the oxygen solubility is 8×10-3 kg m-3 under the given operating conditions, based solely on oxygen dynamics, what is the maximum possible cell concentration in ________kg m-3 (Provide your answer as an integer).


*Answer can only contain numeric values
GATE Biotechnology Mock Test - 5 - Question 30

At 25 °C, the change in free energy for the hydrolysis of ATP is -32.2 kJ mol-1. Similarly, the free energy change for the hydrolysis of ±-glycerophosphate into glycerol at 25 °C is -8.2 kJ mol-1. Given this information, what is the free energy change associated with the synthesis of ±-glycerophosphate from glycerol and ATP, expressed in kJ mol-1 (Provide your answer as an integer)?


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