AIIMS CRE Electrical JE/AE Mock Test- 5 - NEET MCQ

Clipboard stores the cut or copied texts in MS Word.

The Cut command removes the selected text or element from the document and stores it on the Clipboard, allowing you to paste it into the document or into another application. The Copy command also copies the selected text or element to the Clipboard, but it does not remove it from the original location.

A can fill 1 unit of water in the tank in 1/20 hours

B can fill 1 unit of water in the tank in 1/24 hours

C can fill 1 unit of water in tank in 1/30 hours

(A+B+C) can fill 1 unit of water in tank in 1/20+1/24+1/30=6+5+4/120 =15/120=1/8 days

Therefore,

(A+B+C) can fill a full tank in 8 days.

Smelting is the process of applying heat to ore to melt out a base metal. It is a form of extractive metallurgy. It is used to extract many metals from their ores, including silver, iron, copper, and other base metals.

- wire strain gage can effectively measure strain in only one direction. To determine the three independent components of plane strain, three linearly independent strain measures are needed. i.e., three strain gages positioned in a rosette-like layout.

Hence, the correct option is (C)

From the above Diagram

Current Flowing towards the Point: I₂, I₆, I₄

Current Flowing Away from the Point: I₁, I₃, I₅

So, I₂ + I₆ + I₄ = I₁ + I₃+ I₅

Putting the value of the current

2A + 7A + I4 = 4A + 3A + 8A

I₄ = 15A − 9A = 6A

I₄ = 6A

Hence, the correct option is (D).

Hence, the correct option is (B).

1.Clamps & Jacks.

2.Earth Clamps & Cable.

3.Hazard Protection.

4.MIG Argon +5.

5.Plugs & Adaptors.

6.Welding Tables.

7.Hand screen.

8.Electrode holder

9.Gloves & Gauntlets.

10.Plugs / Sockets.

Hence, the correct option is (C)

Hence, the correct option is C.

Relays are switches that open and close circuits electromechanically or electronically.

Reactance relay is used for Short transmission line

Impedance Relay is used for Medium transmission line

Admittance Relay is used for Long

transmission line

Hence, the correct option is (C)

Hence, the correct option is (D)

Hence, the correct option is (B).

Hence, the correct option is (B)

Hence, the correct option is (A)

Then by using the following Ohm’s Law equations:

Let, area of cross-section of conductor = a annual interest and depreciation on capital cost of the conductor = C1

annual running charges = C2

Now, annual interest and depreciation cost is directly proportional to the area of conductor.

i.e., C1 = K1a

And, annual running charges are inversely proportional to the area of conductor.

C2 = K2/a

Where, K1 and K2 are constants.

Now, Total annual cost = C = C1 + C2

C = K1a + K2/a

For C to be minimum, the differentiation of C w.r.t a must be zero. i.e. dC/da = 0.

Therefore,

"The Kelvin's law states that the most economical size of a conductor is that for which annual interest and depreciation on the capital cost of the conductor is equal to the annual cost of energy loss."

From the above derivation, the economical cross-sectional area of a conductor can be calculated as,

a = √(K2/K1)

• The load curves of different interconnected stations are generally different.

• The result is that the maximum demand on the system is much reduced as compared to the sum of individual maximum demands of different stations.

• In other words, the diversity factor of the system is improved, so increasing the effective capacity of the system.