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AIIMS CRE Electrical JE/AE Mock Test- 10 - NEET MCQ


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30 Questions MCQ Test AIIMS CRE Group B & C Mock Test Series - AIIMS CRE Electrical JE/AE Mock Test- 10

AIIMS CRE Electrical JE/AE Mock Test- 10 for NEET 2025 is part of AIIMS CRE Group B & C Mock Test Series preparation. The AIIMS CRE Electrical JE/AE Mock Test- 10 questions and answers have been prepared according to the NEET exam syllabus.The AIIMS CRE Electrical JE/AE Mock Test- 10 MCQs are made for NEET 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AIIMS CRE Electrical JE/AE Mock Test- 10 below.
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AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 1

What is the angle between the two hands of a clock when the time shown by the clock is 3:30?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 1
when it’s 3:30, the minute hand show the number 6, so we have 90 degrees from number 3 to 6

Every 15 minutes, we have 90 degrees, imply that every 5 minutes gives 90:3=30 degrees,

The hour hand shows 3:30, then the angle from 3:00 to 3:30 is 15 degrees.

Finally, we have the remainder of 90, and 15 is 90–15=75 degrees

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 2

A bus reached Nagpur to Amravati in 2:30 hr with an average speed of 70 km/hr if the average speed increased by 30 km/hr. How much time it will take to cover the same distance.

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 2
Distance = speed *time

= (70 * 150)/60 min

= 175 km

New speed = (70 + 30) km/hr = 100 km/hr

Time = (Distance )/speed

= (175 * 60)/100

= 105 min

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 3

A man deposited a certain amount in a fixed deposit at r % p.α., interest being compounded annually. If the interest accrued for the fourth and fifth years are Rs 13310 and Rs 14641. what is the total interest accrued for the first three years?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 3
The interests accrued each year on compound interest form a geometric progression with 1 , as the first year interest and common ratio of (1 + r/100) Therefore, interests for 1st, 2nd, 3rd, 4th and 5th years will be

I, I(1 + r/100)1, I(1 + r/100)2, I(1 + r/100)3, I(1 + F/100)4 respectively

Given, (1 + r/100)3 = 13310

and (1 + r/100)4 = 14641

2) divided by (1), we get (1 + r/100) = 14641 / 13310 = 1.1

∴ Sum of the first three years interests = 13310 / (1.1)3 + 13310 / (1.1)2 +13310 / (1.1)1

= 13316 / 1.331 + 13316 / 2.21 + 13316 / 2.1

= 10000 + 11000 + 12100

= Rs. 33100

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 4

A 3-phase synchronous motor is started by utilizing the torque developed in

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 4

Damper bars are placed inside rotor to develop starting torque in 3 phase synchronous motor.

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 5

A 3 phase 20kVA load has power factor 0.866. If power is measured by two wattmeter method then find reading of each wattmeter when power factor is lagging –

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 5

P = √3 VlIL
VlIL= 20/√3
Pf is lagging,
So, P= VLILcos(30-ϕ)
= 20/√3×cos(30-30) = 20/√3
P1 = VLILcos(30-ϕ)
= 20/√3×cos(30-30)
= 10/√3

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 6

Which instrument is used to measure the high resistance?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 6
For measurement of high resistance

(1) Megger

(2) Loss-discharge method

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 7

Which of the following circuit conditions does a metal oxide varistor (MOV) protect against?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 7

The varistor is a passive two-terminal solid state semiconductor device that is used to provide protection to electrical and electronic circuits. Unlike the fuse or circuit breaker which offers over-current protection, the varistor provides over-voltage protection by means of voltage-clamping in a similar way to the zener diode.

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 8

An ammeter is obtained by shunting a galvanometer with resistance. What should an additional shunt be connected across it to double the range?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 8

In the first case,

Now let R is connected across the ammeter.

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 9

A circuit element that opposes the change in circuit voltage is

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 9

A capacitor opposes change in voltage while an inductor opposes change in current However, a resistor neither opposes change in voltage nor change in current.

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 10

If the discharge voltage of a thyite arrester is 373 kV RMS and the rated voltage is 211 kV RMS, the discharge factor of the arrester is -

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 10

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 11

For the given V-I characteristic find out the value of dynamic resistance Rac?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 11

Since the dynamic resistance is the reciprocal of line as-

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 12

In an Intrinsic semiconductor ________.

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 12

Semiconductors which are chemically pure, meaning free of impurities, are called Intrinsic Semiconductors or Un doped Semiconductor or i-type Semiconductor. The most common intrinsic semiconductors are Silicon (Si) and Germanium (Ge), which belong to Group IV of the periodic table. The atomic numbers of Si and Ge are 14 and 32.

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 13

A 250 V d.c. shunt motor takes a total current of 20 A. Resistance of shunt field winding is 200 Ω and that of armature is 0.3 Ω  What is the current in the armature?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 13

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 14

In reference to the figure, the voltage waveform v9t) is measured by a PMMC, a PMMC combined with bridge rectifier and a moving iron (MI) instrument. Two lists are prepared thereafter :

Instrument list List of instrument reading
List - II
a. PMMC
b. PMMC rectifier
c. M.I.
List - II
i. 5 V
ii. 2.75 V
iii. 2.5 V
The correct option relating the instruments and their reading is

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 14

PMMC reads average value.
Vavg = area/(time period)
From given waveform
Vavg = (10*4)/16 = 2.5 Volts
PMMC rectifier will read rms value = 2.75 Volts
MI reads true rms value
Vrms = (peak value)/2 (for square wave)
= 10/2 = 5V

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 15

A 100 KVA single phase transformer exhibits maximum efficiency at 80% of full load, and the total loss in the transform under this condition is 1000 W. The ohmic losses at full load will be-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 15

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 16

The resistance of a (125Ω) strain gauge changes by 1 ohm for 4000 microstrainsAC. The gauge factor is-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 16

Hence, the correct option is (B)

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 17

Power factor can be improved by using-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 17
Improving the power factor means reducing the phase difference between voltage and current since the majority of loads are inductive; they require some amount of reactive power for them to function. The capacitor provides this reactive power or bank of capacitors installed parallel to the load.

Hence, the correct option is (A)

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 18

How much current flows in an open circuit?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 18
In an open circuit, the resistance is infinite. Due to infinite resistance, the current is zero as resistance and current are inversely related as per Ohm's Law.

Hence, the correct option is (A).

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 19

A voltmeter, when connected across a DC supply, reads 124 V. When a series combination of the voltmeter and an unknown resistance X is connected across the supply, the meter reads 4V. If the resistance of the voltmeter is. the value of X is-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 19

⇒ X = 1500kΩ = 1.5MΩ

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 20

The voltage (v) vs current (i) curve of the circuit is shown below :

The internal resistance of the source e is-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 20

e = V - 10i

= 24 - 10 = 14Ω

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 21

Three inductors each of 60 mH are connected in delta. The value of inductance of each arm of the equivalent star connection is-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 21

Lab = L/3 = 60/3 x 10-3 = 20mH

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 22

Capacitor preferred when there is high frequency in the circuits is __________.

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 22

Mica capacitors are preferred for high-frequency circuits because they have low ohmic losses and less reactance.
Hence, the correct option is (B).

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 23

A factory takes a steady load of 200 kW at a lagging power factor of 0.8. The tariff is Rs. 100 per kVA of maximum demand per annum plus 5 paise per kWh. The phase advancing plant costs Rs. 500 per kVAR and the annual interest and depreciation together amount to 10%. What is the capacity of the phase advancing plant?

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 23

Capacity of phase advancing plant 
=P[tanϕ1-tanϕ2]
= 200[0.75 - 0.5774]
= 34.52 kVAR

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 24

The average value of the voltage wave v = 110175sin(314t - 250) volts is-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 24
V = 110175sin(314t - 250)

Vaxg = 1100 = 110 V

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 25

Two 1-phase AC motors A and B, operate from a 1000V supply. A consumes 2kW at a power factor of 0.8 (lagging), and B consumes 1 kW at a power factor of 0.5 (lagging). The total current drawn from the supply is approximate-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 25

I = I1I2 = 2.52

I = 4.5A

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 26

The given circuit represents a-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 26
The given circuit represents the Schmitt trigger.
AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 27

Resistance temprature coefficient of copper at 200C at-

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 27
The resistance temperature coefficient of copper at 200C is 0.00393/0C.
AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 28

Find Leq of the circuit shown below

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 28

Delta to star conversion,

Hence, the correct option is (A)

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 29

Find current i2 in the circuit shown below

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 29

Use the current divider circuit method and node analysis method.

Hence, the correct option is (B)

AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 30

The small pockets of air in the high voltage cable provide_____relative permittivity____electric field, and at these sites, the breakdown is likely to be initiated.

Detailed Solution for AIIMS CRE Electrical JE/AE Mock Test- 10 - Question 30
The small pockets of air in high voltage cable provide Low relative permittivity high electric field, and at these sites, the breakdown is likely to be initiated.
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