Engineering problems of practical interest are involved with heat exchange between two or more surfaces, and this exchange is strongly dependent upon
(i) Radiative properties
(ii) Temperature levels
(iii) Surface geometrics
Identify the correct statements
For black surface, it is necessary to determine what portion of radiation emitted by one will be intercepted by the other.
The fraction of the radiative energy that is diffused from one surface element and strikes the other surface directly with no intervening reflections is called
(i) Radiation shape factor
(ii) Geometrical factor
(iii) Configuration factor
Choose the correct answer
Radiation shape factor, geometrical factor and configuration factor are all same.
The interchange factor is also known as
The interchange factor is also known as equivalent emissivity.
For the same type of shapes, the value of radiation shape factor will be higher when
Obviously the value of radiation shape factor will be higher when surfaces are larger and held closer.
A thin shield of emissivity E_{ 3} on both sides is placed between two infinite parallel plates of emissivities E_{ 1} and E _{2} and temperatures T _{1 }and T _{2}. If E_{ 1 }= E_{ 2} = E _{3}, then the fraction radiant energy transfer without shield takes the value
The ratio of radiant energy transfer without and with shield is given by
(1/E _{1} + 1/E _{2 }– 1)/ [(1/E _{1} + 1/E _{3 }– 1) + (1/E _{3} + 1/E _{2 }– 1)].
The grey body shape factor for radiant heat exchange between a small body (emissivity = 0.4) in a large enclosure (emissivity = 0.5) is
(F) _{12} = 1/ (1 – E_{ 1} + 1 + 0).
Two long parallel surfaces, each of emissivity 0.7 are at different temperatures and accordingly have radiation exchange between them. It is desired to reduce 75% of this radiant heat transfer by inserting thin parallel shields of equal emissivity 0.7 on both sides. What should be the number of shields?
Without shields/with shield = 1/N + 1.
An enclosure consists of four surfaces 1, 2, 3 and 4. The view factors for radiation heat transfers are
F _{11} = 0.1
F _{12} = 0.4
F _{13} = 0.25
The surface areas A _{1} and A_{ 2} are 4 m^{2} and 2 m^{2}. The view factor F _{41} is
F _{11} + F _{12 }+ F _{13 }+ F _{14} = 1.
The value of shape factor depends on how many factors?
Geometry and orientation.
Find the shape factor F_{12} for the arrangement shown in the figure. The areas A_{1 }and A_{2 }are perpendicular but do not share the common edge
A_{ 5 }= A _{1 }+ A _{3 }and A _{6 }= A _{2 }+ A _{4}. The sequence of the solution is, A _{5} F_{ 56 }= A _{1 }F _{16 }+ A _{3} F _{36}.
Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 




