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Test: Coulomb Law - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test Electromagnetic Fields Theory (EMFT) - Test: Coulomb Law

Test: Coulomb Law for Electrical Engineering (EE) 2024 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Coulomb Law questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Coulomb Law MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Coulomb Law below.
Solutions of Test: Coulomb Law questions in English are available as part of our Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) & Test: Coulomb Law solutions in Hindi for Electromagnetic Fields Theory (EMFT) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Coulomb Law | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study Electromagnetic Fields Theory (EMFT) for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Coulomb Law - Question 1

Coulomb is the unit of which quantity?

Detailed Solution for Test: Coulomb Law - Question 1

Answer: b
Explanation: The standard unit of charge is Coulomb. One coulomb is defined as the 1 Newton of force applied on 1 unit of electric field

Test: Coulomb Law - Question 2

Coulomb law is employed in

Detailed Solution for Test: Coulomb Law - Question 2

Answer: a
Explanation: Coulomb law is applied to static charges. It states that force between any two point charges is proportional to the product of the charges and inversely proportional to square of the distance between them. Thus it is employed in electrostatics.

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Test: Coulomb Law - Question 3

Find the force between 2C and -1C separated by a distance 1m in air(in newton). 

Detailed Solution for Test: Coulomb Law - Question 3

Answer: b
Explanation: F = q1q2/(4∏εor2) = -2 X 9/(10-9 X 12) = -18 X 109.

Test: Coulomb Law - Question 4

Two charges 1C and -4C exists in air. What is the direction of force?

Detailed Solution for Test: Coulomb Law - Question 4

Answer: c
Explanation: Since the charges are unlike, the force will be attractive. Thus the force directs from 1C to -4C.

Test: Coulomb Law - Question 5

Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10-4 N,

Detailed Solution for Test: Coulomb Law - Question 5

Answer: d
Explanation: 1 stat coulomb = 1/(3 X 109) C
F = (1.998 X 1.2488 X 10-16)/(4∏ X 8.854 X 10-12 X 2.2 X (7.5 X 10-2)2) = 1.815 X 10-4 N.

Test: Coulomb Law - Question 6

Find the force between two charges when they are brought in contact and separated by 4cm apart, charges are 2nC and -1nC, in μN.

Detailed Solution for Test: Coulomb Law - Question 6

Answer: c
Explanation: Before the charges are brought into contact, F = 11.234 μN.
After charges are brought into contact and then separated, charge on each sphere is, (q1 + q2)/2 = 0.5nC
On calculating the force with q1 = q2 = 0.5nC, F = 1.404μN.

Test: Coulomb Law - Question 7

The Coulomb law is an implication of which law?

Detailed Solution for Test: Coulomb Law - Question 7

Answer: b
Explanation: The Coulomb law can be formulated from the Gauss law, using the divergence theorem. Thus it is an implication of Gauss law.

Test: Coulomb Law - Question 8

Two small diameter 10gm dielectric balls can slide freely on a vertical channel. Each carry a negative charge of 1μC. Find the separation between the balls if the lower ball is restrained from moving.

Detailed Solution for Test: Coulomb Law - Question 8

Answer: c
Explanation: F = mg = 10 X 10-3 X 9.81 = 9.81 X 10-2 N.
On calculating r by substituting charges, we get r = 0.3m.

Test: Coulomb Law - Question 9

A charge of 2 X 10-7 C is acted upon by a force of 0.1N. Determine the distance to the other charge of 4.5 X 10-7 C, both the charges are in vacuum.

Detailed Solution for Test: Coulomb Law - Question 9

Answer: d
Explanation: F = q1q2/(4∏εor2) , substituting q1, q2 and F, r2 = q1q2/(4∏εoF) =
We get r = 0.09m.

Test: Coulomb Law - Question 10

For a charge Q1, the effect of charge Q2 on Q1 will be,

Detailed Solution for Test: Coulomb Law - Question 10

Answer: b
Explanation: The force of two charges with respect with each other is given by F1 and F2. Thus F1 + F2 = 0 and F1 = -F2.

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