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Test: Electric Field due to Continuous Charge Distribution


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5 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Electric Field due to Continuous Charge Distribution

Test: Electric Field due to Continuous Charge Distribution for Electrical Engineering (EE) 2023 is part of Electromagnetic Fields Theory (EMFT) preparation. The Test: Electric Field due to Continuous Charge Distribution questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Electric Field due to Continuous Charge Distribution MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Electric Field due to Continuous Charge Distribution below.
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Test: Electric Field due to Continuous Charge Distribution - Question 1

An infinitely long uniform charge of density 30 nC/m is located at y = 3, z = 4. The field intensity at (0, 5, 1) is E. Now, what is the field intensity at (2, 5, 1)?

Detailed Solution for Test: Electric Field due to Continuous Charge Distribution - Question 1

Concept:
The magnitude of electric field intensity at a point P due to infinitely long uniform charge density λ is

r → the perpendicular distance from the point to the infinitely long charge density
Analysis:
Here, the point (0, 5, 1) and (2, 5, 1)
r is the same and is equal to

∴ the electric field will be same in both the cases.

Test: Electric Field due to Continuous Charge Distribution - Question 2

The electric flux lines 

Detailed Solution for Test: Electric Field due to Continuous Charge Distribution - Question 2

Electric flux lines originate from positive charges and terminate at negative charges as shown:​

Note:
It is the magnetic field lines that form a closed loop as shown:

Test: Electric Field due to Continuous Charge Distribution - Question 3

The electric field E at (1, 1, -1) due to three charge distributions – 10nC/m2 at plane x = 2, 15 nC/m2 at plane y = -3 and 10 π nc/m line charge at x = 0, z = 2 is

Detailed Solution for Test: Electric Field due to Continuous Charge Distribution - Question 3

The electric charge distributions are as shown below

The filed due to plane

The field due to plane

The field due to line charge

is the unit vector along perpendicular to the line charge passing through P.


∴ Total electric field E = E1 + E2 + E3  

*Answer can only contain numeric values
Test: Electric Field due to Continuous Charge Distribution - Question 4

The electric field at a distance of 2 m from an infinite line charge of charge density 4 nC/m is ______V/m. 


Detailed Solution for Test: Electric Field due to Continuous Charge Distribution - Question 4

The electric due to an infinite line charge is given by

Test: Electric Field due to Continuous Charge Distribution - Question 5

Let  Q1 = 4μ C be located at P1(3,11,8) while Q2 = -5μC is at P2(6,15,8).The force F­2 on Q2 will be

Detailed Solution for Test: Electric Field due to Continuous Charge Distribution - Question 5

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