Test: Electric Field due to Continuous Charge Distribution
5 Questions MCQ Test Electromagnetic Fields Theory (EMFT) | Test: Electric Field due to Continuous Charge Distribution
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An infinitely long uniform charge of density 30 nC/m is located at y = 3, z = 4. The field intensity at (0, 5, 1) is E. Now, what is the field intensity at (2, 5, 1)?
Concept:
The magnitude of electric field intensity at a point P due to infinitely long uniform charge density λ is
r → the perpendicular distance from the point to the infinitely long charge density
Analysis:
Here, the point (0, 5, 1) and (2, 5, 1)
r is the same and is equal to
∴ the electric field will be same in both the cases.
The electric flux lines
Electric flux lines originate from positive charges and terminate at negative charges as shown:
Note:
It is the magnetic field lines that form a closed loop as shown:
The electric field E at (1, 1, -1) due to three charge distributions – 10nC/m2 at plane x = 2, 15 nC/m2 at plane y = -3 and 10 π nc/m line charge at x = 0, z = 2 is
The electric charge distributions are as shown below
The filed due to plane
The field due to plane
The field due to line charge
is the unit vector along perpendicular to the line charge passing through P.
∴ Total electric field E = E1 + E2 + E3
The electric field at a distance of 2 m from an infinite line charge of charge density 4 nC/m is ______V/m.
The electric due to an infinite line charge is given by
Let Q1 = 4μ C be located at P1(3,11,8) while Q2 = -5μC is at P2(6,15,8).The force F2 on Q2 will be
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