Calculate the angle of wrap if diameter of the two pulleys are 550mm and 300mm. Also the centre distance is 2800mm.
Explanation: ὰ=180 – 2sin¯¹(D-d/2C).
Calculate the arc of contact if diameter of the two pulleys are 550mm and 300mm. Also the centre distance is 2800mm.
Explanation: ὰ=180 – 2sin¯¹(D-d/2C). Factor=1+ (1.04-1)(180-174.8)/(180-170).
Calculate the belt length if diameter of the two pulleys are 550mm and 300mm. Also the centre distance is 2800mm.
Explanation: L=2C + π(D+d)/2 + (D-d)²/4C.
Crowns are never mounted on the pulley.
Explanation: Crowns are used to avoid slip in case of misalignment or non-parallelism.
In a cast iron pulley minor axis is generally kept in the plane of rotation.
Explanation: Keeping minor axis in plane of rotation increases the cross section.
The number of V belts required for a given application are given by (ignoring correction factor for arc of contact and belt length) Transmitted power/kW rating of single belt x Industrial Service Factor.
Explanation: It is given by Transmitted power x Industrial Service Factor /kW rating of single belt.
The pitch diameter of bigger pulley D in terms of small diameter d is given by
Explanation: Product of diameter and speed of pulley is constant.
If maximum tension in the belt is 900N and allowable belt load is 500N. Calculate the number of belts required to transmit power.
Explanation: No of belts=900/500.
The belt tension is maximum when velocity of belt is 0.
Explanation: P₁-mv²/P₂-mv²=e^(fa/sinθ/2). Hence belt tension is maximum when v=0.
If belt tension in the two sides is 730N and 140N and belt is moving with a velocity of 10m/s, calculate the power transmitted.