Fill in the blanks: |
Card: 1 / 30 |
7.2 days (LCM(12,18) = 36; A’s rate = 36/12 = 3, B’s rate = 36/18 = 2; Total rate = 3+2 = 5; Work done in 36/5 = 7.2 days) |
Card: 2 / 30 |
True or False: If the number of workers doubles, the time required to complete the work is always reduced by half. |
Card: 3 / 30 |
False (Only true if efficiency remains constant and there are no diminishing returns in productivity) |
Card: 4 / 30 |
Riddle: A tap fills a tank in 6 hours, and a leak empties the tank in 8 hours. If both are open together, the tank will be filled in ___ hours. |
Card: 5 / 30 |
24 hours (Filling rate = 1/6, Leak rate = 1/8; Net rate = 1/6 - 1/8 = 1/24 → Tank fills in 24 hours) |
Card: 6 / 30 |
Fill in the blanks: |
Card: 7 / 30 |
1/3 (A’s rate = 1/15, B’s rate = 1/10, Combined rate = (1/15 + 1/10) = 1/6; Work done in 5 days = 5/6; Remaining = 1 - 5/6 = 1/3) |
Card: 8 / 30 |
True or False: If A and B can together finish a work in 10 days, and A alone can do it in 16 days, then B alone can do it in 20 days. |
Card: 9 / 30 |
False (Using formula 1/B = 1/10 - 1/16 = 3/80 → B alone takes 80/3 days ≈ 26.67 days, not 20 days) |
Card: 10 / 30 |
Fill in the blanks: |
Card: 11 / 30 |
5.33 days (or 16/3 days) (If B is 50% more efficient, his rate is 1.5 × A’s; Time = 8/1.5 = 16/3 ≈ 5.33 days) |
Card: 12 / 30 |
Riddle: Three pipes A, B, and C can fill a tank in 12 hours, 15 hours, and 20 hours, respectively. If all three are opened together, the tank will be filled in ___ hours. |
Card: 13 / 30 |
5.45 hours (or 60/11 hours) (Rates: A = 1/12, B = 1/15, C = 1/20; Total rate = (1/12 + 1/15 + 1/20) = 11/60; Time = 60/11 ≈ 5.45 hours) |
Card: 14 / 30 |
True or False: If three workers can complete a task in 9 days, then the number of days required for one worker to complete the same task alone is 27 days. |
Card: 15 / 30 |
True (Total work = 3 workers × 9 days = 27 worker-days; Time for 1 worker = 27 days) |
Card: 16 / 30 |
Fill in the blanks: |
Card: 17 / 30 |
16 days (Using the equation 1/A + 1/B + 1/C = (1/20 + 1/30 + 1/40) = 1/16 → Work done in 16 days) |
Card: 18 / 30 |
A group of 4 men can complete a work in 16 days. If 2 more men join, the work will be completed in ___ days. |
Card: 19 / 30 |
Fill in the blanks: A, B, and C together finish a work in 10 days. If A alone takes 20 days and B alone takes 30 days, then C alone will take ___ days. |
Card: 21 / 30 |
True or False: If a task takes 12 hours with 6 workers, it will always take 6 hours with 12 workers. |
Card: 23 / 30 |
False (Only true if efficiency remains constant and no other factors affect productivity) |
Card: 24 / 30 |
Riddle: A can do a work in 9 days, and B in 18 days. If they work together but B leaves after 3 days, the total time required to complete the work is ___ days. |
Card: 25 / 30 |
6 days (A’s rate = 1/9, B’s rate = 1/18; Combined for 3 days = (1/9 + 1/18) × 3 = 1/2; Remaining work = 1/2; A alone = 1/2 × 9 = 4.5 days; Total = 3 + 4.5 = 6 days) |
Card: 26 / 30 |
Fill in the blanks: Two pipes fill a tank in 12 min and 18 min, while a third pipe empties it in 36 min. The net time to fill the tank when all three work together is ___ min. |
Card: 27 / 30 |
True or False: If A is twice as fast as B, and both together take 16 days, then A alone will take 24 days. |
Card: 29 / 30 |
False (Using formula: If A = 2B, then 1/A + 1/B = 1/16 → 1/2x + 1/x = 1/16 → x = 24; A = 12 days, not 24) |
Card: 30 / 30 |
![]() Completed! Keep practicing to master all of them. |