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ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
Page 2


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
Page 3


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
1. Apply Kirchhoff’s current and voltage
laws to write the circuit equation.
2. If the equation contains integrals,
differentiate each term in the equation
to produce a pure differential equation.
3. Assume a solution of the form K
1
+
K
2
e
st
.
Page 4


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
1. Apply Kirchhoff’s current and voltage
laws to write the circuit equation.
2. If the equation contains integrals,
differentiate each term in the equation
to produce a pure differential equation.
3. Assume a solution of the form K
1
+
K
2
e
st
.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
4. Substitute the solution into the
differential equation to determine the
values of K
1
and s . (Alternatively, we
can determine K
1
by solving the circuit
in steady state)
5. Use the initial conditions to
determine the value of K
2
.
6. Write the final solution.
Page 5


ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RC/RL Circuits
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Circuits
The steps involved in solving
simple circuits containing dc
sources, resistances, and one
energy-storage element
(inductance or capacitance) are:
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
1. Apply Kirchhoff’s current and voltage
laws to write the circuit equation.
2. If the equation contains integrals,
differentiate each term in the equation
to produce a pure differential equation.
3. Assume a solution of the form K
1
+
K
2
e
st
.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
4. Substitute the solution into the
differential equation to determine the
values of K
1
and s . (Alternatively, we
can determine K
1
by solving the circuit
in steady state)
5. Use the initial conditions to
determine the value of K
2
.
6. Write the final solution.
ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Fourth Edition, by Allan R. Hambley, ©2008 Pearson Education, Inc.
RL Transient Analysis
Find i(t) and the voltage v(t)
Apply KVL around the loop:
0 ) ( ) ( = + + - t v R t i V
S
i(t)= 0 for t < 0 since the switch is open prior to t = 0
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FAQs on PPT: RC - RL Circuits - Basic Electrical Technology - Electrical Engineering (EE)

1. What is the difference between an RC circuit and an RL circuit?
Ans. An RC circuit consists of a resistor and a capacitor, while an RL circuit consists of a resistor and an inductor. The main difference between the two is the presence of a capacitor in an RC circuit and an inductor in an RL circuit.
2. How does an RC circuit work?
Ans. In an RC circuit, the resistor and capacitor are connected in series or parallel. When a voltage is applied to the circuit, the capacitor charges up, storing electrical energy. As the capacitor charges, the current flowing through the circuit decreases until it reaches a steady state. The time it takes for the capacitor to charge is determined by the resistance and capacitance values in the circuit.
3. What is the time constant of an RC circuit?
Ans. The time constant of an RC circuit is the time it takes for the voltage across the capacitor to reach approximately 63.2% of its maximum value when charging or discharging. It is calculated by multiplying the resistance (R) and the capacitance (C) in the circuit.
4. How does an RL circuit work?
Ans. In an RL circuit, the resistor and inductor are connected in series or parallel. When a voltage is applied to the circuit, the inductor resists the change in current, causing it to build up gradually. As the current increases, the voltage across the inductor decreases until it reaches a steady state. The time it takes for the current to reach its maximum value is determined by the inductance and resistance values in the circuit.
5. What is the time constant of an RL circuit?
Ans. The time constant of an RL circuit is the time it takes for the current in the circuit to reach approximately 63.2% of its maximum value when the voltage is suddenly applied or removed. It is calculated by dividing the inductance (L) by the resistance (R) in the circuit.
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