All Courses
Get the App Signup / Login
Sign in Open App
JEE Exam  >  JEE Notes  >  DC Pandey Solutions for JEE Physics  >  DC Pandey Solutions (JEE Main): Current Electricity- 2

DC Pandey Solutions (JEE Main): Current Electricity- 2 | DC Pandey Solutions for JEE Physics PDF Download

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


Exercises 
For JEE Main 
Q 31.  An ideal voltmeter V is connected to a 2.0 ? resistor and a battery with emf 5.0 V and internal 
resistance 0.5 ? as shown in figure : 
 
  (a) What is the current in the 2.0 ? resistor? 
  (b) What is the terminal voltage of the battery? 
  (c) What is the reading of the voltmeter? 
Q 32.  The potential difference across the terminals of a battery is 8.4 V when there is a current of 1.50 A 
in the battery from the negative to the positive terminal. When the current is 3.50 A in the reverse 
direction, the potential difference becomes 9.4 V. 
  (a) What is the internal resistance of the battery? 
  (b) What is the emf of the battery? 
Q 33.  A battery of emf 2.0 V and internal resistance 0.10 ? is being charged with a current of 5.0 A. 
Find the potential difference between the terminals of the battery? 
Q 34.  Find the currents in different resistors shown in figure. 
 
  Electrical Measuring Instruments 
Q 35.  A resistance box, a battery and a galvanometer of resistance G ohm are connected in series. If the 
galvanometer is shunted by resistance of S ohm, find the change in resistance in the box required 
to maintain the current from the battery unchanged. 
Q 36.  Determine the resistance r if an ammeter shows a current of I = 5 A and a voltmeter 100 V. The 
internal resistance of the voltmeter is R = 2,500 ?. 
 
Q 37.  In the circuit, a voltmeter reads 30 V when it is connected across 400 ? resistance. Calculate what 
the same voltmeter will read when it is connected across the 300 ? resistance? 
Page 2


Exercises 
For JEE Main 
Q 31.  An ideal voltmeter V is connected to a 2.0 ? resistor and a battery with emf 5.0 V and internal 
resistance 0.5 ? as shown in figure : 
 
  (a) What is the current in the 2.0 ? resistor? 
  (b) What is the terminal voltage of the battery? 
  (c) What is the reading of the voltmeter? 
Q 32.  The potential difference across the terminals of a battery is 8.4 V when there is a current of 1.50 A 
in the battery from the negative to the positive terminal. When the current is 3.50 A in the reverse 
direction, the potential difference becomes 9.4 V. 
  (a) What is the internal resistance of the battery? 
  (b) What is the emf of the battery? 
Q 33.  A battery of emf 2.0 V and internal resistance 0.10 ? is being charged with a current of 5.0 A. 
Find the potential difference between the terminals of the battery? 
Q 34.  Find the currents in different resistors shown in figure. 
 
  Electrical Measuring Instruments 
Q 35.  A resistance box, a battery and a galvanometer of resistance G ohm are connected in series. If the 
galvanometer is shunted by resistance of S ohm, find the change in resistance in the box required 
to maintain the current from the battery unchanged. 
Q 36.  Determine the resistance r if an ammeter shows a current of I = 5 A and a voltmeter 100 V. The 
internal resistance of the voltmeter is R = 2,500 ?. 
 
Q 37.  In the circuit, a voltmeter reads 30 V when it is connected across 400 ? resistance. Calculate what 
the same voltmeter will read when it is connected across the 300 ? resistance? 
 
Q 38.  Resistances R
1
 and R
2
, each 60 ?, are connected in series. The potential difference between points 
A and B is 120 V. Find the reading of voltmeter connected between points C and D if its 
resistance r = 120 ?. 
 
Q 39.  A moving coil galvanometer of resistance 20 ? gives a full scale deflection when a current of 1 
mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the 
shunt of 0.005 ? only is available. What resistance should be connected in series with the 
galvanometer coil? 
Q 40.  In a potentiometer experiment it is found that no current passes through the galvanometer when 
the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is 
shunted by a resistance of 5 ? a balance is obtained when the cell is connected across 0.4 m of the 
wire. Find the internal resistance of the cell. 
Q 41.  A cell of emf 3.4 V and internal resistance 3 ?, is connected to an ammeter having resistance 2 ? 
and to an external resistance of 100 ?. When a voltmeter is connected across the 100 ?. resistance 
the ammeter reading is 0.04 A. Find the voltage read by the voltmeter and its resistance. Had the 
voltmeter been an ideal one what would have been its reading? 
Q 42.  The potentiometer wire AB shown in figure is 40 cm long. Where the free end of the galvanometer 
should be connected on AB so that the galvanometer may show zero deflection? 
 
Q 43.  The resistance R
G
 of the coil of a pivoted-coil galvanometer is 9.36 ? and a current of 0.0224 A 
causes it to deflect full scale. We want to convert this galvanometer to an ammeter reading 20.0 A 
Page 3


Exercises 
For JEE Main 
Q 31.  An ideal voltmeter V is connected to a 2.0 ? resistor and a battery with emf 5.0 V and internal 
resistance 0.5 ? as shown in figure : 
 
  (a) What is the current in the 2.0 ? resistor? 
  (b) What is the terminal voltage of the battery? 
  (c) What is the reading of the voltmeter? 
Q 32.  The potential difference across the terminals of a battery is 8.4 V when there is a current of 1.50 A 
in the battery from the negative to the positive terminal. When the current is 3.50 A in the reverse 
direction, the potential difference becomes 9.4 V. 
  (a) What is the internal resistance of the battery? 
  (b) What is the emf of the battery? 
Q 33.  A battery of emf 2.0 V and internal resistance 0.10 ? is being charged with a current of 5.0 A. 
Find the potential difference between the terminals of the battery? 
Q 34.  Find the currents in different resistors shown in figure. 
 
  Electrical Measuring Instruments 
Q 35.  A resistance box, a battery and a galvanometer of resistance G ohm are connected in series. If the 
galvanometer is shunted by resistance of S ohm, find the change in resistance in the box required 
to maintain the current from the battery unchanged. 
Q 36.  Determine the resistance r if an ammeter shows a current of I = 5 A and a voltmeter 100 V. The 
internal resistance of the voltmeter is R = 2,500 ?. 
 
Q 37.  In the circuit, a voltmeter reads 30 V when it is connected across 400 ? resistance. Calculate what 
the same voltmeter will read when it is connected across the 300 ? resistance? 
 
Q 38.  Resistances R
1
 and R
2
, each 60 ?, are connected in series. The potential difference between points 
A and B is 120 V. Find the reading of voltmeter connected between points C and D if its 
resistance r = 120 ?. 
 
Q 39.  A moving coil galvanometer of resistance 20 ? gives a full scale deflection when a current of 1 
mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the 
shunt of 0.005 ? only is available. What resistance should be connected in series with the 
galvanometer coil? 
Q 40.  In a potentiometer experiment it is found that no current passes through the galvanometer when 
the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is 
shunted by a resistance of 5 ? a balance is obtained when the cell is connected across 0.4 m of the 
wire. Find the internal resistance of the cell. 
Q 41.  A cell of emf 3.4 V and internal resistance 3 ?, is connected to an ammeter having resistance 2 ? 
and to an external resistance of 100 ?. When a voltmeter is connected across the 100 ?. resistance 
the ammeter reading is 0.04 A. Find the voltage read by the voltmeter and its resistance. Had the 
voltmeter been an ideal one what would have been its reading? 
Q 42.  The potentiometer wire AB shown in figure is 40 cm long. Where the free end of the galvanometer 
should be connected on AB so that the galvanometer may show zero deflection? 
 
Q 43.  The resistance R
G
 of the coil of a pivoted-coil galvanometer is 9.36 ? and a current of 0.0224 A 
causes it to deflect full scale. We want to convert this galvanometer to an ammeter reading 20.0 A 
full scale. The only shunt available has a resistance of 0.0250 ?. What resistance R must be 
connected in series with the coil of galvanometer? 
 
Q 44.  (a) A voltmeter with resistance R
V
 is connected across the terminals of a battery of emf E and 
internal resistance r. Find the potential difference measured by the voltmeter. 
(b) If E = 7.50 V and r = 0.45 ?, find the minimum value of the voltmeter resistance R
V
 so that the 
voltmeter reading is within 1.0% of the emf of the battery. 
  (c) Explain why your answer in part (b) represents a minimum value. 
Q 45.  (a) An ammeter with resistance R
A
 is connected in series with a resistor R and a battery of emf e 
and internal resistance r. The current measured by the ammeter is I
A
. Find the current through the 
circuit if the ammeter is removed so that the battery and the resistor form a complete circuit. 
Express your answer in terms of I
A
 , r, R
A
 and R. The more "ideal" the ammeter, the smaller the 
difference between this current and the current I
A
. 
(b) If R = 3.80 ?, ? = 7.50 V and r = 0.45 ?, find the maximum value of the ammeter resistance 
R
A
 so that I
A
 is within 99% of the current in the circuit when the ammeter is absent. 
  (c) Explain why your answer in part (b) represents a maximum value. 
  Heating Effects of Current 
Q 46.  Each of three resistors in figure has a resistance of 2.4 ? and can dissipate a maximum of 36 W 
without becoming excessively heated. What is the maximum power the circuit can dissipate? 
 
Q 47.  A 120 V house circuit has the following light bulbs switched on : 40 W, 60 W and 75 W. Find the 
equivalent resistance of these bulbs. 
Q 48.  A storage battery with emf 2.6 V loaded with external resistance produces a current 1 A. In this 
case, the potential difference between the terminals of the storage battery equals 2 V. Find the 
thermal power generated in the battery and the net power supplied by the battery for external 
circuit.. 
Q 49.  In the circuit shown in figure E
1
 = 7 V, E
2
 = 1V, R
1
 = 2 ?, R
2
 = 2 ? and R
3
 = 3 ? respectively. Find 
the power supplied by the two batteries. 
 
Q 50.  Assume that the batteries in figure have negligible internal resistance. Find : 
Page 4


Exercises 
For JEE Main 
Q 31.  An ideal voltmeter V is connected to a 2.0 ? resistor and a battery with emf 5.0 V and internal 
resistance 0.5 ? as shown in figure : 
 
  (a) What is the current in the 2.0 ? resistor? 
  (b) What is the terminal voltage of the battery? 
  (c) What is the reading of the voltmeter? 
Q 32.  The potential difference across the terminals of a battery is 8.4 V when there is a current of 1.50 A 
in the battery from the negative to the positive terminal. When the current is 3.50 A in the reverse 
direction, the potential difference becomes 9.4 V. 
  (a) What is the internal resistance of the battery? 
  (b) What is the emf of the battery? 
Q 33.  A battery of emf 2.0 V and internal resistance 0.10 ? is being charged with a current of 5.0 A. 
Find the potential difference between the terminals of the battery? 
Q 34.  Find the currents in different resistors shown in figure. 
 
  Electrical Measuring Instruments 
Q 35.  A resistance box, a battery and a galvanometer of resistance G ohm are connected in series. If the 
galvanometer is shunted by resistance of S ohm, find the change in resistance in the box required 
to maintain the current from the battery unchanged. 
Q 36.  Determine the resistance r if an ammeter shows a current of I = 5 A and a voltmeter 100 V. The 
internal resistance of the voltmeter is R = 2,500 ?. 
 
Q 37.  In the circuit, a voltmeter reads 30 V when it is connected across 400 ? resistance. Calculate what 
the same voltmeter will read when it is connected across the 300 ? resistance? 
 
Q 38.  Resistances R
1
 and R
2
, each 60 ?, are connected in series. The potential difference between points 
A and B is 120 V. Find the reading of voltmeter connected between points C and D if its 
resistance r = 120 ?. 
 
Q 39.  A moving coil galvanometer of resistance 20 ? gives a full scale deflection when a current of 1 
mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the 
shunt of 0.005 ? only is available. What resistance should be connected in series with the 
galvanometer coil? 
Q 40.  In a potentiometer experiment it is found that no current passes through the galvanometer when 
the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is 
shunted by a resistance of 5 ? a balance is obtained when the cell is connected across 0.4 m of the 
wire. Find the internal resistance of the cell. 
Q 41.  A cell of emf 3.4 V and internal resistance 3 ?, is connected to an ammeter having resistance 2 ? 
and to an external resistance of 100 ?. When a voltmeter is connected across the 100 ?. resistance 
the ammeter reading is 0.04 A. Find the voltage read by the voltmeter and its resistance. Had the 
voltmeter been an ideal one what would have been its reading? 
Q 42.  The potentiometer wire AB shown in figure is 40 cm long. Where the free end of the galvanometer 
should be connected on AB so that the galvanometer may show zero deflection? 
 
Q 43.  The resistance R
G
 of the coil of a pivoted-coil galvanometer is 9.36 ? and a current of 0.0224 A 
causes it to deflect full scale. We want to convert this galvanometer to an ammeter reading 20.0 A 
full scale. The only shunt available has a resistance of 0.0250 ?. What resistance R must be 
connected in series with the coil of galvanometer? 
 
Q 44.  (a) A voltmeter with resistance R
V
 is connected across the terminals of a battery of emf E and 
internal resistance r. Find the potential difference measured by the voltmeter. 
(b) If E = 7.50 V and r = 0.45 ?, find the minimum value of the voltmeter resistance R
V
 so that the 
voltmeter reading is within 1.0% of the emf of the battery. 
  (c) Explain why your answer in part (b) represents a minimum value. 
Q 45.  (a) An ammeter with resistance R
A
 is connected in series with a resistor R and a battery of emf e 
and internal resistance r. The current measured by the ammeter is I
A
. Find the current through the 
circuit if the ammeter is removed so that the battery and the resistor form a complete circuit. 
Express your answer in terms of I
A
 , r, R
A
 and R. The more "ideal" the ammeter, the smaller the 
difference between this current and the current I
A
. 
(b) If R = 3.80 ?, ? = 7.50 V and r = 0.45 ?, find the maximum value of the ammeter resistance 
R
A
 so that I
A
 is within 99% of the current in the circuit when the ammeter is absent. 
  (c) Explain why your answer in part (b) represents a maximum value. 
  Heating Effects of Current 
Q 46.  Each of three resistors in figure has a resistance of 2.4 ? and can dissipate a maximum of 36 W 
without becoming excessively heated. What is the maximum power the circuit can dissipate? 
 
Q 47.  A 120 V house circuit has the following light bulbs switched on : 40 W, 60 W and 75 W. Find the 
equivalent resistance of these bulbs. 
Q 48.  A storage battery with emf 2.6 V loaded with external resistance produces a current 1 A. In this 
case, the potential difference between the terminals of the storage battery equals 2 V. Find the 
thermal power generated in the battery and the net power supplied by the battery for external 
circuit.. 
Q 49.  In the circuit shown in figure E
1
 = 7 V, E
2
 = 1V, R
1
 = 2 ?, R
2
 = 2 ? and R
3
 = 3 ? respectively. Find 
the power supplied by the two batteries. 
 
Q 50.  Assume that the batteries in figure have negligible internal resistance. Find : 
 
  (a) the current in the circuit, 
  (b) the power dissipated in each resistor and 
  (c) the power of each battery, stating whether energy is supplied by or absorbed by it. 
Q 51.  In the circuit shown in figure, find : 
 
  (a) the rate of conversion of internal (chemical) energy to electrical energy within the battery 
(b) the rate of dissipation of electrical energy in the battery 
(c) the rate of dissipation of electrical energy in the external resistor. 
Q 52.  Three resistors having resistances of 1.60 ?, 2.40 ? and 4.80 ? are connected in parallel to a 28.0 
V battery that has negligible internal resistance. Find : 
  (a) the equivalent resistance of the combination. 
  (b) the current in each resistor. 
  (c) the total current through the battery. 
  (d) the voltage across each resistor. 
  (e) the power dissipated in each resistor. 
(f) which resistor dissipates the maximum power the one with the greatest resistance or the least 
resistance? Explain why this should be. 
Q 53.  (a) The power of resistor is the maximum power the resistor can safely dissipate without too rise 
in temperature. The power rating of a 15 k ? resistor is 5.0 W. What is the maximum allowable 
potential difference across the terminals of the resistor? 
(b) A 9.0 k ? resistor is to be connected across a 120 V potential difference. What power rating is 
required? 
  Equivalent Resistance 
  Note Attempt this after reading article 22.9.  
Q 54.  Find the equivalent resistance between points A and B in the following circuits : 
Page 5


Exercises 
For JEE Main 
Q 31.  An ideal voltmeter V is connected to a 2.0 ? resistor and a battery with emf 5.0 V and internal 
resistance 0.5 ? as shown in figure : 
 
  (a) What is the current in the 2.0 ? resistor? 
  (b) What is the terminal voltage of the battery? 
  (c) What is the reading of the voltmeter? 
Q 32.  The potential difference across the terminals of a battery is 8.4 V when there is a current of 1.50 A 
in the battery from the negative to the positive terminal. When the current is 3.50 A in the reverse 
direction, the potential difference becomes 9.4 V. 
  (a) What is the internal resistance of the battery? 
  (b) What is the emf of the battery? 
Q 33.  A battery of emf 2.0 V and internal resistance 0.10 ? is being charged with a current of 5.0 A. 
Find the potential difference between the terminals of the battery? 
Q 34.  Find the currents in different resistors shown in figure. 
 
  Electrical Measuring Instruments 
Q 35.  A resistance box, a battery and a galvanometer of resistance G ohm are connected in series. If the 
galvanometer is shunted by resistance of S ohm, find the change in resistance in the box required 
to maintain the current from the battery unchanged. 
Q 36.  Determine the resistance r if an ammeter shows a current of I = 5 A and a voltmeter 100 V. The 
internal resistance of the voltmeter is R = 2,500 ?. 
 
Q 37.  In the circuit, a voltmeter reads 30 V when it is connected across 400 ? resistance. Calculate what 
the same voltmeter will read when it is connected across the 300 ? resistance? 
 
Q 38.  Resistances R
1
 and R
2
, each 60 ?, are connected in series. The potential difference between points 
A and B is 120 V. Find the reading of voltmeter connected between points C and D if its 
resistance r = 120 ?. 
 
Q 39.  A moving coil galvanometer of resistance 20 ? gives a full scale deflection when a current of 1 
mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the 
shunt of 0.005 ? only is available. What resistance should be connected in series with the 
galvanometer coil? 
Q 40.  In a potentiometer experiment it is found that no current passes through the galvanometer when 
the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is 
shunted by a resistance of 5 ? a balance is obtained when the cell is connected across 0.4 m of the 
wire. Find the internal resistance of the cell. 
Q 41.  A cell of emf 3.4 V and internal resistance 3 ?, is connected to an ammeter having resistance 2 ? 
and to an external resistance of 100 ?. When a voltmeter is connected across the 100 ?. resistance 
the ammeter reading is 0.04 A. Find the voltage read by the voltmeter and its resistance. Had the 
voltmeter been an ideal one what would have been its reading? 
Q 42.  The potentiometer wire AB shown in figure is 40 cm long. Where the free end of the galvanometer 
should be connected on AB so that the galvanometer may show zero deflection? 
 
Q 43.  The resistance R
G
 of the coil of a pivoted-coil galvanometer is 9.36 ? and a current of 0.0224 A 
causes it to deflect full scale. We want to convert this galvanometer to an ammeter reading 20.0 A 
full scale. The only shunt available has a resistance of 0.0250 ?. What resistance R must be 
connected in series with the coil of galvanometer? 
 
Q 44.  (a) A voltmeter with resistance R
V
 is connected across the terminals of a battery of emf E and 
internal resistance r. Find the potential difference measured by the voltmeter. 
(b) If E = 7.50 V and r = 0.45 ?, find the minimum value of the voltmeter resistance R
V
 so that the 
voltmeter reading is within 1.0% of the emf of the battery. 
  (c) Explain why your answer in part (b) represents a minimum value. 
Q 45.  (a) An ammeter with resistance R
A
 is connected in series with a resistor R and a battery of emf e 
and internal resistance r. The current measured by the ammeter is I
A
. Find the current through the 
circuit if the ammeter is removed so that the battery and the resistor form a complete circuit. 
Express your answer in terms of I
A
 , r, R
A
 and R. The more "ideal" the ammeter, the smaller the 
difference between this current and the current I
A
. 
(b) If R = 3.80 ?, ? = 7.50 V and r = 0.45 ?, find the maximum value of the ammeter resistance 
R
A
 so that I
A
 is within 99% of the current in the circuit when the ammeter is absent. 
  (c) Explain why your answer in part (b) represents a maximum value. 
  Heating Effects of Current 
Q 46.  Each of three resistors in figure has a resistance of 2.4 ? and can dissipate a maximum of 36 W 
without becoming excessively heated. What is the maximum power the circuit can dissipate? 
 
Q 47.  A 120 V house circuit has the following light bulbs switched on : 40 W, 60 W and 75 W. Find the 
equivalent resistance of these bulbs. 
Q 48.  A storage battery with emf 2.6 V loaded with external resistance produces a current 1 A. In this 
case, the potential difference between the terminals of the storage battery equals 2 V. Find the 
thermal power generated in the battery and the net power supplied by the battery for external 
circuit.. 
Q 49.  In the circuit shown in figure E
1
 = 7 V, E
2
 = 1V, R
1
 = 2 ?, R
2
 = 2 ? and R
3
 = 3 ? respectively. Find 
the power supplied by the two batteries. 
 
Q 50.  Assume that the batteries in figure have negligible internal resistance. Find : 
 
  (a) the current in the circuit, 
  (b) the power dissipated in each resistor and 
  (c) the power of each battery, stating whether energy is supplied by or absorbed by it. 
Q 51.  In the circuit shown in figure, find : 
 
  (a) the rate of conversion of internal (chemical) energy to electrical energy within the battery 
(b) the rate of dissipation of electrical energy in the battery 
(c) the rate of dissipation of electrical energy in the external resistor. 
Q 52.  Three resistors having resistances of 1.60 ?, 2.40 ? and 4.80 ? are connected in parallel to a 28.0 
V battery that has negligible internal resistance. Find : 
  (a) the equivalent resistance of the combination. 
  (b) the current in each resistor. 
  (c) the total current through the battery. 
  (d) the voltage across each resistor. 
  (e) the power dissipated in each resistor. 
(f) which resistor dissipates the maximum power the one with the greatest resistance or the least 
resistance? Explain why this should be. 
Q 53.  (a) The power of resistor is the maximum power the resistor can safely dissipate without too rise 
in temperature. The power rating of a 15 k ? resistor is 5.0 W. What is the maximum allowable 
potential difference across the terminals of the resistor? 
(b) A 9.0 k ? resistor is to be connected across a 120 V potential difference. What power rating is 
required? 
  Equivalent Resistance 
  Note Attempt this after reading article 22.9.  
Q 54.  Find the equivalent resistance between points A and B in the following circuits : 
  (a)    (b)  
  (c)   (d) 
  (e)    (f) 
  (g)  
Q 55.  What will be the change in the resistance of a circuit between A and F consisting of five identical 
conductors, if two similar conductors are added as shown by the dashed line in figure? 
 
Q 56.  Find R
AB
 in the circuit, shown in figure.
Read More
209 docs
Join Course for Free

Top Courses for JEE

FAQs on DC Pandey Solutions (JEE Main): Current Electricity- 2 - DC Pandey Solutions for JEE Physics

1. What is the importance of studying current electricity in JEE Main?
Ans. Studying current electricity is important in JEE Main because it is a fundamental topic in physics and has a wide range of applications in various fields such as electronics, power generation, and transmission. Many questions related to current electricity are asked in the JEE Main exam, and having a strong understanding of this topic can significantly contribute to a student's overall score.
2. How can I prepare effectively for the current electricity section in JEE Main?
Ans. To prepare effectively for the current electricity section in JEE Main, it is important to understand the basic concepts and principles. Start by studying the fundamental laws like Ohm's law, Kirchhoff's laws, and the concept of resistance. Practice solving numerical problems to enhance problem-solving skills. Refer to reliable study materials like the book "Current Electricity: JEE Main(Part - 2) - Physics, Solution by DC Pandey JEE" mentioned in the article. Additionally, solving previous years' question papers and taking mock tests can help in gaining confidence and improving time management skills.
3. What are some common topics or subtopics related to current electricity that are frequently asked in JEE Main?
Ans. Some common topics or subtopics related to current electricity frequently asked in JEE Main include: - Ohm's law and its applications - Kirchhoff's laws and their applications - Series and parallel combinations of resistors - Wheatstone bridge and its applications - Electrical power and energy - Potentiometer and its applications - Heating effect of electric current - Combination of cells - RC circuits and time constant - Magnetic effects of electric current It is crucial to have a strong understanding of these topics and be able to solve numerical problems related to them.
4. Are there any specific tips to solve numerical problems in the current electricity section of JEE Main?
Ans. Yes, here are some tips to solve numerical problems in the current electricity section of JEE Main: 1. Understand the given problem statement and identify what is being asked. 2. Draw a clear circuit diagram, if not provided, to visualize the problem better. 3. Apply the relevant laws and principles, such as Ohm's law or Kirchhoff's laws, to set up equations for unknown quantities. 4. Simplify the equations by rearranging them or using mathematical techniques. 5. Substitute the given values into the equations and solve for the unknowns. 6. Check the units and dimensions of the final answer to ensure accuracy. 7. Practice solving a variety of numerical problems to enhance problem-solving skills and speed.
5. Can I solely rely on the book "Current Electricity: JEE Main(Part - 2) - Physics, Solution by DC Pandey JEE" for preparing the current electricity section in JEE Main?
Ans. While the book "Current Electricity: JEE Main(Part - 2) - Physics, Solution by DC Pandey JEE" can be a valuable resource for preparing the current electricity section in JEE Main, it is recommended to use it in conjunction with other reliable study materials and resources. JEE Main is a competitive exam that requires a comprehensive understanding of various topics, so it is beneficial to refer to multiple sources to gain a well-rounded knowledge base. Additionally, solving previous years' question papers, taking mock tests, and seeking guidance from teachers or mentors can further enhance your preparation.
Related Exams
JEE
About this Document
4.78/5 Rating
Dec 26, 2024 Last updated
Document Description: DC Pandey Solutions (JEE Main): Current Electricity- 2 for JEE 2024 is part of DC Pandey Solutions for JEE Physics preparation. The notes and questions for DC Pandey Solutions (JEE Main): Current Electricity- 2 have been prepared according to the JEE exam syllabus. Information about DC Pandey Solutions (JEE Main): Current Electricity- 2 covers topics like and DC Pandey Solutions (JEE Main): Current Electricity- 2 Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for DC Pandey Solutions (JEE Main): Current Electricity- 2.
Introduction of DC Pandey Solutions (JEE Main): Current Electricity- 2 in English is available as part of our DC Pandey Solutions for JEE Physics for JEE & DC Pandey Solutions (JEE Main): Current Electricity- 2 in Hindi for DC Pandey Solutions for JEE Physics course. Download more important topics related with notes, lectures and mock test series for JEE Exam by signing up for free. JEE: DC Pandey Solutions (JEE Main): Current Electricity- 2 | DC Pandey Solutions for JEE Physics
Description
Full syllabus notes, lecture & questions for DC Pandey Solutions (JEE Main): Current Electricity- 2 | DC Pandey Solutions for JEE Physics - JEE | Plus excerises question with solution to help you revise complete syllabus for DC Pandey Solutions for JEE Physics | Best notes, free PDF download
Information about DC Pandey Solutions (JEE Main): Current Electricity- 2
In this doc you can find the meaning of DC Pandey Solutions (JEE Main): Current Electricity- 2 defined & explained in the simplest way possible. Besides explaining types of DC Pandey Solutions (JEE Main): Current Electricity- 2 theory, EduRev gives you an ample number of questions to practice DC Pandey Solutions (JEE Main): Current Electricity- 2 tests, examples and also practice JEE tests
Explore Courses for JEE exam

Top Courses for JEE

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

shortcuts and tricks

,

Extra Questions

,

past year papers

,

Important questions

,

MCQs

,

practice quizzes

,

Sample Paper

,

DC Pandey Solutions (JEE Main): Current Electricity- 2 | DC Pandey Solutions for JEE Physics

,

Previous Year Questions with Solutions

,

Exam

,

Viva Questions

,

video lectures

,

mock tests for examination

,

Objective type Questions

,

DC Pandey Solutions (JEE Main): Current Electricity- 2 | DC Pandey Solutions for JEE Physics

,

DC Pandey Solutions (JEE Main): Current Electricity- 2 | DC Pandey Solutions for JEE Physics

,

ppt

,

pdf

,

study material

,

Summary

,

Free

,

Semester Notes

;
Additional Information about DC Pandey Solutions (JEE Main): Current Electricity- 2 for JEE Preparation

DC Pandey Solutions (JEE Main): Current Electricity- 2 Free PDF Download

The DC Pandey Solutions (JEE Main): Current Electricity- 2 is an invaluable resource that delves deep into the core of the JEE exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the DC Pandey Solutions (JEE Main): Current Electricity- 2 now and kickstart your journey towards success in the JEE exam.

Importance of DC Pandey Solutions (JEE Main): Current Electricity- 2

The importance of DC Pandey Solutions (JEE Main): Current Electricity- 2 cannot be overstated, especially for JEE aspirants. This document holds the key to success in the JEE exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

DC Pandey Solutions (JEE Main): Current Electricity- 2 Notes

DC Pandey Solutions (JEE Main): Current Electricity- 2 Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to DC Pandey Solutions (JEE Main): Current Electricity- 2. It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, DC Pandey Solutions (JEE Main): Current Electricity- 2 Notes on EduRev are your ultimate resource for success.

DC Pandey Solutions (JEE Main): Current Electricity- 2 JEE Questions

The "DC Pandey Solutions (JEE Main): Current Electricity- 2 JEE Questions" guide is a valuable resource for all aspiring students preparing for the JEE exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study DC Pandey Solutions (JEE Main): Current Electricity- 2 on the App

Students of JEE can study DC Pandey Solutions (JEE Main): Current Electricity- 2 alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the DC Pandey Solutions (JEE Main): Current Electricity- 2, students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of DC Pandey Solutions (JEE Main): Current Electricity- 2 is prepared as per the latest JEE syllabus.
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup