JEE Exam > JEE Notes > DC Pandey Solutions for JEE Physics > DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2
DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 | DC Pandey Solutions for JEE Physics PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
More than One Correct Options
Q 1. A mass m of radius r is rolling horizontally without any slip with a linear speed v. It then rolls up
to a height given by
2
3v
4g
(a) the body is identified to be a disc or a solid cylinder
(b) the body is a solid sphere
(c) moment of inertia of the body about instantaneous axis of rotation is
2
3
mr
2
(d) moment of inertia of the body about instantaneous axis of rotation is
2
7
mr
5
Q 2. Four identical rods each of mass m and length lare joined to form a rigid square frame. The frame
lies in the xy plane, with its centre at the origin and the sides parallel to the x and y axes. Its
moment of inertia about
(a) the x-axis is
2
2
ml
3
(b) the z-axis is
2
4
ml
3
(c) an axis parallel to the z-axis and passing through a corner is
2
10
ml
3
(d) one side is
2
5
ml
3
Q 3. A uniform circular ring rolls without slipping on a horizontal surface. At any instant, its position is
as shown in the figure. Then
(a) section ABC has greater kinetic energy than section ADC
(b) section BC has greater kinetic energy than section CD
(c) section BC has the same kinetic energy as section DA
(d) the sections CD and DA have the same kinetic energy
Q 4. A cylinder of radius R is to roll without slipping between two planks as shown in the figure. Then
(a) angular velocity of the cylinder is
v
R
counter clockwise
(b) angular velocity of the cylinder is
2v
R
clockwise
(c) velocity of centre of mass of the cylinder is v towards left
Page 2
More than One Correct Options
Q 1. A mass m of radius r is rolling horizontally without any slip with a linear speed v. It then rolls up
to a height given by
2
3v
4g
(a) the body is identified to be a disc or a solid cylinder
(b) the body is a solid sphere
(c) moment of inertia of the body about instantaneous axis of rotation is
2
3
mr
2
(d) moment of inertia of the body about instantaneous axis of rotation is
2
7
mr
5
Q 2. Four identical rods each of mass m and length lare joined to form a rigid square frame. The frame
lies in the xy plane, with its centre at the origin and the sides parallel to the x and y axes. Its
moment of inertia about
(a) the x-axis is
2
2
ml
3
(b) the z-axis is
2
4
ml
3
(c) an axis parallel to the z-axis and passing through a corner is
2
10
ml
3
(d) one side is
2
5
ml
3
Q 3. A uniform circular ring rolls without slipping on a horizontal surface. At any instant, its position is
as shown in the figure. Then
(a) section ABC has greater kinetic energy than section ADC
(b) section BC has greater kinetic energy than section CD
(c) section BC has the same kinetic energy as section DA
(d) the sections CD and DA have the same kinetic energy
Q 4. A cylinder of radius R is to roll without slipping between two planks as shown in the figure. Then
(a) angular velocity of the cylinder is
v
R
counter clockwise
(b) angular velocity of the cylinder is
2v
R
clockwise
(c) velocity of centre of mass of the cylinder is v towards left
(d) velocity of centre of mass of the cylinder is 2v towards right
Q 5. A uniform rod of mass m = 2 kg and length l = 0.5 m is sliding along two mutually perpendicular
smooth walls with the two ends P and Q having velocities v P = 4 m/s and vQ = 3 m/s as shown.
Then
(a) The angular velocity of rod, ? = 10rad/s, counter clockwise
(b) The angular velocity of rod, ? = 5.0rad/s, counter clockwise
(c) The velocity of centre of mass of rod, vcm = 2.5 m/s
(d) The total kinetic energy of rod,
25
K
3
? joule
Q 6. A wheel is rolling without slipping on a horizontal plane with velocity v an acceleration a of
centre of mass as shown in figure. Acceleration at
(a) A is vertically upwards (b) B may be vertically downwards
(c) C cannot be horizontal (d) a point on the rim may be horizontal leftwards
Q 7. A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m
moving horizontally at right angles to the rod with velocity v collides with one end of the rod and
sticks it. Then
(a) angular velocity of the system after collision is
v
l
(b) angular velocity of the system after collision is
v
2l
(c) the loss in kinetic energy of the system as a whole as a result of the collision is
2
mv
6
(d) the loss in kinetic energy of the system as a whole as a result of the collision is
2
7mv
24
Q 8. A nonuniform ball of radius R and radius of gyration about geometric centre =R/2, is kept on a
frictionless surface. The geometric centre coincides with the centre of mass. The ball is struck
horizontally with a sharp impulse = J. The point of application of the impulse is at a height h
above the surface. Then
Page 3
More than One Correct Options
Q 1. A mass m of radius r is rolling horizontally without any slip with a linear speed v. It then rolls up
to a height given by
2
3v
4g
(a) the body is identified to be a disc or a solid cylinder
(b) the body is a solid sphere
(c) moment of inertia of the body about instantaneous axis of rotation is
2
3
mr
2
(d) moment of inertia of the body about instantaneous axis of rotation is
2
7
mr
5
Q 2. Four identical rods each of mass m and length lare joined to form a rigid square frame. The frame
lies in the xy plane, with its centre at the origin and the sides parallel to the x and y axes. Its
moment of inertia about
(a) the x-axis is
2
2
ml
3
(b) the z-axis is
2
4
ml
3
(c) an axis parallel to the z-axis and passing through a corner is
2
10
ml
3
(d) one side is
2
5
ml
3
Q 3. A uniform circular ring rolls without slipping on a horizontal surface. At any instant, its position is
as shown in the figure. Then
(a) section ABC has greater kinetic energy than section ADC
(b) section BC has greater kinetic energy than section CD
(c) section BC has the same kinetic energy as section DA
(d) the sections CD and DA have the same kinetic energy
Q 4. A cylinder of radius R is to roll without slipping between two planks as shown in the figure. Then
(a) angular velocity of the cylinder is
v
R
counter clockwise
(b) angular velocity of the cylinder is
2v
R
clockwise
(c) velocity of centre of mass of the cylinder is v towards left
(d) velocity of centre of mass of the cylinder is 2v towards right
Q 5. A uniform rod of mass m = 2 kg and length l = 0.5 m is sliding along two mutually perpendicular
smooth walls with the two ends P and Q having velocities v P = 4 m/s and vQ = 3 m/s as shown.
Then
(a) The angular velocity of rod, ? = 10rad/s, counter clockwise
(b) The angular velocity of rod, ? = 5.0rad/s, counter clockwise
(c) The velocity of centre of mass of rod, vcm = 2.5 m/s
(d) The total kinetic energy of rod,
25
K
3
? joule
Q 6. A wheel is rolling without slipping on a horizontal plane with velocity v an acceleration a of
centre of mass as shown in figure. Acceleration at
(a) A is vertically upwards (b) B may be vertically downwards
(c) C cannot be horizontal (d) a point on the rim may be horizontal leftwards
Q 7. A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m
moving horizontally at right angles to the rod with velocity v collides with one end of the rod and
sticks it. Then
(a) angular velocity of the system after collision is
v
l
(b) angular velocity of the system after collision is
v
2l
(c) the loss in kinetic energy of the system as a whole as a result of the collision is
2
mv
6
(d) the loss in kinetic energy of the system as a whole as a result of the collision is
2
7mv
24
Q 8. A nonuniform ball of radius R and radius of gyration about geometric centre =R/2, is kept on a
frictionless surface. The geometric centre coincides with the centre of mass. The ball is struck
horizontally with a sharp impulse = J. The point of application of the impulse is at a height h
above the surface. Then
(a) the ball with slip on surface for all cases (b) the ball will roll purely if h = 5R/4
(c) the ball will roll purely if h = 3R/2 (d) there will be no rotation if h = R
Q 9. A hollow spherical ball is given an initial push up an incline of inclination angle ?.
The ball rolls
purely. Coefficient of static friction between ball and incline = ?. During its upwards journey
(a) friction acts up along the incline (b) (2 tan ?)/5
(c) friction acts down along the incline (d) (2 tan ?)/7
Q 10. A uniform disc of mass m and radius R rotates about a fixed vertical axis passing through its
centre with angular velocity ?. A particle of same mass m and having velocity of 2 ?R towards
centre of the disc collides with the disc moving horizontally and sticks to its rim.
(a) The angular velocity of the disc will become ?/3
(b) The angular velocity of the disc will become 5 ?/3
(c) The impulse on the particle due to disc is
37
mR
3
?
(d) The impulse on the particle due to disc is 2m ?R
Q 11. The end B of the rod AB which makes angle ? with the floor is being pulled with a constant
velocity v0 as shown. The length of the rod is l.
(a) At ? = 37 ?
velocity of end A is
0
4
v
3
downwards
(b) At ? = 37 ? angular velocity of rod is
0
5v
3l
(c) Angular velocity of rod is constant
(d) Velocity of end A is constant
Answers
1. (a,c) 2. (all) 3. (a,b,d) 4. (a,b) 5. (a,c,d) 6. (all) 7. (a,c) 8. (b,d) 9. (a,b) 10. (a,c) 11. (a,b)
Solutions
1.
Page 4
More than One Correct Options
Q 1. A mass m of radius r is rolling horizontally without any slip with a linear speed v. It then rolls up
to a height given by
2
3v
4g
(a) the body is identified to be a disc or a solid cylinder
(b) the body is a solid sphere
(c) moment of inertia of the body about instantaneous axis of rotation is
2
3
mr
2
(d) moment of inertia of the body about instantaneous axis of rotation is
2
7
mr
5
Q 2. Four identical rods each of mass m and length lare joined to form a rigid square frame. The frame
lies in the xy plane, with its centre at the origin and the sides parallel to the x and y axes. Its
moment of inertia about
(a) the x-axis is
2
2
ml
3
(b) the z-axis is
2
4
ml
3
(c) an axis parallel to the z-axis and passing through a corner is
2
10
ml
3
(d) one side is
2
5
ml
3
Q 3. A uniform circular ring rolls without slipping on a horizontal surface. At any instant, its position is
as shown in the figure. Then
(a) section ABC has greater kinetic energy than section ADC
(b) section BC has greater kinetic energy than section CD
(c) section BC has the same kinetic energy as section DA
(d) the sections CD and DA have the same kinetic energy
Q 4. A cylinder of radius R is to roll without slipping between two planks as shown in the figure. Then
(a) angular velocity of the cylinder is
v
R
counter clockwise
(b) angular velocity of the cylinder is
2v
R
clockwise
(c) velocity of centre of mass of the cylinder is v towards left
(d) velocity of centre of mass of the cylinder is 2v towards right
Q 5. A uniform rod of mass m = 2 kg and length l = 0.5 m is sliding along two mutually perpendicular
smooth walls with the two ends P and Q having velocities v P = 4 m/s and vQ = 3 m/s as shown.
Then
(a) The angular velocity of rod, ? = 10rad/s, counter clockwise
(b) The angular velocity of rod, ? = 5.0rad/s, counter clockwise
(c) The velocity of centre of mass of rod, vcm = 2.5 m/s
(d) The total kinetic energy of rod,
25
K
3
? joule
Q 6. A wheel is rolling without slipping on a horizontal plane with velocity v an acceleration a of
centre of mass as shown in figure. Acceleration at
(a) A is vertically upwards (b) B may be vertically downwards
(c) C cannot be horizontal (d) a point on the rim may be horizontal leftwards
Q 7. A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m
moving horizontally at right angles to the rod with velocity v collides with one end of the rod and
sticks it. Then
(a) angular velocity of the system after collision is
v
l
(b) angular velocity of the system after collision is
v
2l
(c) the loss in kinetic energy of the system as a whole as a result of the collision is
2
mv
6
(d) the loss in kinetic energy of the system as a whole as a result of the collision is
2
7mv
24
Q 8. A nonuniform ball of radius R and radius of gyration about geometric centre =R/2, is kept on a
frictionless surface. The geometric centre coincides with the centre of mass. The ball is struck
horizontally with a sharp impulse = J. The point of application of the impulse is at a height h
above the surface. Then
(a) the ball with slip on surface for all cases (b) the ball will roll purely if h = 5R/4
(c) the ball will roll purely if h = 3R/2 (d) there will be no rotation if h = R
Q 9. A hollow spherical ball is given an initial push up an incline of inclination angle ?.
The ball rolls
purely. Coefficient of static friction between ball and incline = ?. During its upwards journey
(a) friction acts up along the incline (b) (2 tan ?)/5
(c) friction acts down along the incline (d) (2 tan ?)/7
Q 10. A uniform disc of mass m and radius R rotates about a fixed vertical axis passing through its
centre with angular velocity ?. A particle of same mass m and having velocity of 2 ?R towards
centre of the disc collides with the disc moving horizontally and sticks to its rim.
(a) The angular velocity of the disc will become ?/3
(b) The angular velocity of the disc will become 5 ?/3
(c) The impulse on the particle due to disc is
37
mR
3
?
(d) The impulse on the particle due to disc is 2m ?R
Q 11. The end B of the rod AB which makes angle ? with the floor is being pulled with a constant
velocity v0 as shown. The length of the rod is l.
(a) At ? = 37 ?
velocity of end A is
0
4
v
3
downwards
(b) At ? = 37 ? angular velocity of rod is
0
5v
3l
(c) Angular velocity of rod is constant
(d) Velocity of end A is constant
Answers
1. (a,c) 2. (all) 3. (a,b,d) 4. (a,b) 5. (a,c,d) 6. (all) 7. (a,c) 8. (b,d) 9. (a,b) 10. (a,c) 11. (a,b)
Solutions
1.
Disc or cylinder I0 = I CM + mR
2
2.
3.
Resultant velocity of particles in region ABC is greater than that in CDA.
So,(KE)ABC>(KE)CDA
Similarly, vBC > v CD ? K BC >K CD
and vCD = vDA ? K CD =KDA
Page 5
More than One Correct Options
Q 1. A mass m of radius r is rolling horizontally without any slip with a linear speed v. It then rolls up
to a height given by
2
3v
4g
(a) the body is identified to be a disc or a solid cylinder
(b) the body is a solid sphere
(c) moment of inertia of the body about instantaneous axis of rotation is
2
3
mr
2
(d) moment of inertia of the body about instantaneous axis of rotation is
2
7
mr
5
Q 2. Four identical rods each of mass m and length lare joined to form a rigid square frame. The frame
lies in the xy plane, with its centre at the origin and the sides parallel to the x and y axes. Its
moment of inertia about
(a) the x-axis is
2
2
ml
3
(b) the z-axis is
2
4
ml
3
(c) an axis parallel to the z-axis and passing through a corner is
2
10
ml
3
(d) one side is
2
5
ml
3
Q 3. A uniform circular ring rolls without slipping on a horizontal surface. At any instant, its position is
as shown in the figure. Then
(a) section ABC has greater kinetic energy than section ADC
(b) section BC has greater kinetic energy than section CD
(c) section BC has the same kinetic energy as section DA
(d) the sections CD and DA have the same kinetic energy
Q 4. A cylinder of radius R is to roll without slipping between two planks as shown in the figure. Then
(a) angular velocity of the cylinder is
v
R
counter clockwise
(b) angular velocity of the cylinder is
2v
R
clockwise
(c) velocity of centre of mass of the cylinder is v towards left
(d) velocity of centre of mass of the cylinder is 2v towards right
Q 5. A uniform rod of mass m = 2 kg and length l = 0.5 m is sliding along two mutually perpendicular
smooth walls with the two ends P and Q having velocities v P = 4 m/s and vQ = 3 m/s as shown.
Then
(a) The angular velocity of rod, ? = 10rad/s, counter clockwise
(b) The angular velocity of rod, ? = 5.0rad/s, counter clockwise
(c) The velocity of centre of mass of rod, vcm = 2.5 m/s
(d) The total kinetic energy of rod,
25
K
3
? joule
Q 6. A wheel is rolling without slipping on a horizontal plane with velocity v an acceleration a of
centre of mass as shown in figure. Acceleration at
(a) A is vertically upwards (b) B may be vertically downwards
(c) C cannot be horizontal (d) a point on the rim may be horizontal leftwards
Q 7. A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m
moving horizontally at right angles to the rod with velocity v collides with one end of the rod and
sticks it. Then
(a) angular velocity of the system after collision is
v
l
(b) angular velocity of the system after collision is
v
2l
(c) the loss in kinetic energy of the system as a whole as a result of the collision is
2
mv
6
(d) the loss in kinetic energy of the system as a whole as a result of the collision is
2
7mv
24
Q 8. A nonuniform ball of radius R and radius of gyration about geometric centre =R/2, is kept on a
frictionless surface. The geometric centre coincides with the centre of mass. The ball is struck
horizontally with a sharp impulse = J. The point of application of the impulse is at a height h
above the surface. Then
(a) the ball with slip on surface for all cases (b) the ball will roll purely if h = 5R/4
(c) the ball will roll purely if h = 3R/2 (d) there will be no rotation if h = R
Q 9. A hollow spherical ball is given an initial push up an incline of inclination angle ?.
The ball rolls
purely. Coefficient of static friction between ball and incline = ?. During its upwards journey
(a) friction acts up along the incline (b) (2 tan ?)/5
(c) friction acts down along the incline (d) (2 tan ?)/7
Q 10. A uniform disc of mass m and radius R rotates about a fixed vertical axis passing through its
centre with angular velocity ?. A particle of same mass m and having velocity of 2 ?R towards
centre of the disc collides with the disc moving horizontally and sticks to its rim.
(a) The angular velocity of the disc will become ?/3
(b) The angular velocity of the disc will become 5 ?/3
(c) The impulse on the particle due to disc is
37
mR
3
?
(d) The impulse on the particle due to disc is 2m ?R
Q 11. The end B of the rod AB which makes angle ? with the floor is being pulled with a constant
velocity v0 as shown. The length of the rod is l.
(a) At ? = 37 ?
velocity of end A is
0
4
v
3
downwards
(b) At ? = 37 ? angular velocity of rod is
0
5v
3l
(c) Angular velocity of rod is constant
(d) Velocity of end A is constant
Answers
1. (a,c) 2. (all) 3. (a,b,d) 4. (a,b) 5. (a,c,d) 6. (all) 7. (a,c) 8. (b,d) 9. (a,b) 10. (a,c) 11. (a,b)
Solutions
1.
Disc or cylinder I0 = I CM + mR
2
2.
3.
Resultant velocity of particles in region ABC is greater than that in CDA.
So,(KE)ABC>(KE)CDA
Similarly, vBC > v CD ? K BC >K CD
and vCD = vDA ? K CD =KDA
4.
u - R ? = v
u + R ? = 3v
? u=2v and R ? = v
5.
6.
Net acceleration at A is vertical, at B it may be vertical, at C it cannot be horizontal and at E it
may be horizontal leftward.
7.
Read More
FAQs on DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 - DC Pandey Solutions for JEE Physics
| 1. What are the conditions for rotational equilibrium? |  |
Ans. In order to have rotational equilibrium, two conditions must be satisfied:
- The net torque acting on the system must be zero.
- The net force acting on the system must be zero.
| 2. How can we calculate the moment of inertia of a rigid body? | |
Ans. The moment of inertia of a rigid body can be calculated using the formula:
I = ∫r²dm
where I is the moment of inertia, r is the perpendicular distance of an infinitesimally small mass element from the axis of rotation, and dm is the mass element.
| 3. What is the difference between angular velocity and angular acceleration? | |
Ans. Angular velocity is a vector quantity that describes the rate of change of angular displacement with respect to time. It is measured in radians per second (rad/s).
Angular acceleration, on the other hand, is the rate of change of angular velocity with respect to time. It is also a vector quantity and is measured in radians per second squared (rad/s²).
| 4. Can you explain the concept of torque? | |
Ans. Torque is the rotational equivalent of force. It is the measure of the tendency of a force to rotate an object about an axis. Mathematically, torque is calculated as the product of force and the perpendicular distance from the axis of rotation to the line of action of the force. It is given by the formula:
τ = r × F
where τ is the torque, r is the lever arm or the perpendicular distance, and F is the force.
| 5. What is the relationship between linear velocity and angular velocity? | |
Ans. The relationship between linear velocity (v) and angular velocity (ω) can be given by the formula:
v = ω × r
where v is the linear velocity, ω is the angular velocity, and r is the distance from the axis of rotation to the point of interest. This formula shows that linear velocity is directly proportional to the angular velocity and the distance from the axis of rotation.
Related Exams
About this Document
|
4.70/5 Rating |
|
Nov 23, 2024 Last updated |
Document Description: DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 for JEE 2024 is part of DC Pandey Solutions for JEE Physics preparation.
The notes and questions for DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 have been prepared according to the JEE exam syllabus. Information about DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 covers topics
like and DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2.
Introduction of DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 in English is available as part of our DC Pandey Solutions for JEE Physics
for JEE & DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 in Hindi for DC Pandey Solutions for JEE Physics course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 | DC Pandey Solutions for JEE Physics
Description
Full syllabus notes, lecture & questions for DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 | DC Pandey Solutions for JEE Physics - JEE | Plus excerises question with solution to help you revise complete syllabus for DC Pandey Solutions for JEE Physics | Best notes, free PDF download
Information about DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2
In this doc you can find the meaning of DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 defined & explained in the simplest way possible. Besides explaining types of
DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 theory, EduRev gives you an ample number of questions to practice DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 tests, examples and also practice JEE
tests
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Summary
,past year papers
,Previous Year Questions with Solutions
,mock tests for examination
,Exam
,Sample Paper
,practice quizzes
,shortcuts and tricks
,video lectures
,Viva Questions
,DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 | DC Pandey Solutions for JEE Physics
,DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 | DC Pandey Solutions for JEE Physics
,ppt
,Important questions
,study material
,Extra Questions
,MCQs
,Free
,DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 | DC Pandey Solutions for JEE Physics
,Objective type Questions
,Semester Notes
;
Additional Information about DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 for JEE Preparation
DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 Free PDF Download
The DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 now and kickstart your journey towards success in the JEE exam.
Importance of DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2
The importance of DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 Notes
DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 Notes on EduRev are your ultimate resource for success.
DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 JEE Questions
The "DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 on the App
Students of JEE can study DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of DC Pandey Solutions (JEE Advance): Mechanics of Rotational Motion- 2 is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup