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Page 1
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Arrange the numbers in place-value chart:
Cr T L L T Th Th H T O
4 7 8 9 6 3 0 4
4 7 8 9 6 3 4 0
Clearly both numbers have 8 digits.
At crores, ten lakhs, lakhs, ten thousands, thousands and hundeds place both have
the same digits i.e. 4, 7, 8, 9, 6, 3 respectively.
But at tens place, first number has 0 and second number has 4.
Clearly, 0 < 4
Hence
47896304 < 47896340
2. Correct answer: B
To add 0 and 4 on number line, move 4 steps to the right of 0.
3. Correct answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000
4. Correct answer: A
Since,
Therefore, 36 = 2 × 2 × 3 × 3
Page 2
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Arrange the numbers in place-value chart:
Cr T L L T Th Th H T O
4 7 8 9 6 3 0 4
4 7 8 9 6 3 4 0
Clearly both numbers have 8 digits.
At crores, ten lakhs, lakhs, ten thousands, thousands and hundeds place both have
the same digits i.e. 4, 7, 8, 9, 6, 3 respectively.
But at tens place, first number has 0 and second number has 4.
Clearly, 0 < 4
Hence
47896304 < 47896340
2. Correct answer: B
To add 0 and 4 on number line, move 4 steps to the right of 0.
3. Correct answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000
4. Correct answer: A
Since,
Therefore, 36 = 2 × 2 × 3 × 3
CBSE VI | Mathematics
Sample Paper 2 – Solution
5. Correct answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
6. Correct answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
7. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 – 1 = 999999.
8. Correct answer: B
On a number line, –110 lies next to –111 on the right.
Therefore, the successor of –111 is –110.
9. Correct answer: A
The given fraction is
Dividing the numerator and denominator by 3, we get
Thus,
is equivalent to .
10. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence by 6.
The number 653 is neither divisible by 3 nor by 2 and hence not by 6.
Now, consider the number 531.
Since, the sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
But it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
11. Correct answer: B
12. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
Page 3
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Arrange the numbers in place-value chart:
Cr T L L T Th Th H T O
4 7 8 9 6 3 0 4
4 7 8 9 6 3 4 0
Clearly both numbers have 8 digits.
At crores, ten lakhs, lakhs, ten thousands, thousands and hundeds place both have
the same digits i.e. 4, 7, 8, 9, 6, 3 respectively.
But at tens place, first number has 0 and second number has 4.
Clearly, 0 < 4
Hence
47896304 < 47896340
2. Correct answer: B
To add 0 and 4 on number line, move 4 steps to the right of 0.
3. Correct answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000
4. Correct answer: A
Since,
Therefore, 36 = 2 × 2 × 3 × 3
CBSE VI | Mathematics
Sample Paper 2 – Solution
5. Correct answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
6. Correct answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
7. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 – 1 = 999999.
8. Correct answer: B
On a number line, –110 lies next to –111 on the right.
Therefore, the successor of –111 is –110.
9. Correct answer: A
The given fraction is
Dividing the numerator and denominator by 3, we get
Thus,
is equivalent to .
10. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence by 6.
The number 653 is neither divisible by 3 nor by 2 and hence not by 6.
Now, consider the number 531.
Since, the sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
But it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
11. Correct answer: B
12. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
CBSE VI | Mathematics
Sample Paper 2 – Solution
Section B
13.
T Cr Cr T L L T Th Th H T O
(i)
7 0 7 0 7 5
(ii)
5 3 6 1 8 4 9 3
i. Seven lakh seven thousand seventy five.
ii. Five crore thirty-six lakh eighteen thousand four hundred ninety three.
14.
1. Two lines in the same plane which never intersect are called parallel lines.
2. Parallel lines remain the same distance apart over their entire length.
15.
i. Going 6 m to the West
ii. A withdrawal of Rs 100
iii. 10 km below sea level
iv. Spending Rs 500
16. Population of the village = 13295
Increase in population= Average growth - 1 = 399.
Population in the successive year = 13295 + 399 = 13694
17.
Prime factorisation of 455 is 5 × 7 × 13
Therefore, the dimensions of the cuboid are 5 cm, 7 cm, 13 cm.
Page 4
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Arrange the numbers in place-value chart:
Cr T L L T Th Th H T O
4 7 8 9 6 3 0 4
4 7 8 9 6 3 4 0
Clearly both numbers have 8 digits.
At crores, ten lakhs, lakhs, ten thousands, thousands and hundeds place both have
the same digits i.e. 4, 7, 8, 9, 6, 3 respectively.
But at tens place, first number has 0 and second number has 4.
Clearly, 0 < 4
Hence
47896304 < 47896340
2. Correct answer: B
To add 0 and 4 on number line, move 4 steps to the right of 0.
3. Correct answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000
4. Correct answer: A
Since,
Therefore, 36 = 2 × 2 × 3 × 3
CBSE VI | Mathematics
Sample Paper 2 – Solution
5. Correct answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
6. Correct answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
7. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 – 1 = 999999.
8. Correct answer: B
On a number line, –110 lies next to –111 on the right.
Therefore, the successor of –111 is –110.
9. Correct answer: A
The given fraction is
Dividing the numerator and denominator by 3, we get
Thus,
is equivalent to .
10. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence by 6.
The number 653 is neither divisible by 3 nor by 2 and hence not by 6.
Now, consider the number 531.
Since, the sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
But it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
11. Correct answer: B
12. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
CBSE VI | Mathematics
Sample Paper 2 – Solution
Section B
13.
T Cr Cr T L L T Th Th H T O
(i)
7 0 7 0 7 5
(ii)
5 3 6 1 8 4 9 3
i. Seven lakh seven thousand seventy five.
ii. Five crore thirty-six lakh eighteen thousand four hundred ninety three.
14.
1. Two lines in the same plane which never intersect are called parallel lines.
2. Parallel lines remain the same distance apart over their entire length.
15.
i. Going 6 m to the West
ii. A withdrawal of Rs 100
iii. 10 km below sea level
iv. Spending Rs 500
16. Population of the village = 13295
Increase in population= Average growth - 1 = 399.
Population in the successive year = 13295 + 399 = 13694
17.
Prime factorisation of 455 is 5 × 7 × 13
Therefore, the dimensions of the cuboid are 5 cm, 7 cm, 13 cm.
CBSE VI | Mathematics
Sample Paper 2 – Solution
18. The opposite sides of a parallelogram are parallel and equal.
Therefore, LM = NO
19. 90, 91, 92, 93, 94, 95, 96 are the required numbers.
20. Number of circles in step 1 = 3 = 1 × 2 + 1
Number of circles in step 2 = 5 = 2 × 2 + 1
Thus, we can observe that the number of circles is obtained by multiplying the step
number by 2 and then adding 1.
Therefore, number of circles in the 100
th
step = (100 × 2) + 1 = 201
21.
20570 = 2 × 5 × 11 × 11 × 17
22. Anna is 7 feet above sea level.
She jumps 3 feet down and walks another 2 feet down. Total distance travelled
downwards = 3 + 2 = 5 feet.
23. (–13) + (–19) + (+15) + (–10)
= –13 – 19 + 15 – 10
= –13 – 19 – 10 + 15
= –42 + 15
= –27
24. 21397 can be estimated as 21000
27807 can be estimated as 28000
42305 can be estimated as 42000
On adding, we get 21000 + 28000 + 42000 = 91000
Page 5
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Arrange the numbers in place-value chart:
Cr T L L T Th Th H T O
4 7 8 9 6 3 0 4
4 7 8 9 6 3 4 0
Clearly both numbers have 8 digits.
At crores, ten lakhs, lakhs, ten thousands, thousands and hundeds place both have
the same digits i.e. 4, 7, 8, 9, 6, 3 respectively.
But at tens place, first number has 0 and second number has 4.
Clearly, 0 < 4
Hence
47896304 < 47896340
2. Correct answer: B
To add 0 and 4 on number line, move 4 steps to the right of 0.
3. Correct answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000
4. Correct answer: A
Since,
Therefore, 36 = 2 × 2 × 3 × 3
CBSE VI | Mathematics
Sample Paper 2 – Solution
5. Correct answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
6. Correct answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
7. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 – 1 = 999999.
8. Correct answer: B
On a number line, –110 lies next to –111 on the right.
Therefore, the successor of –111 is –110.
9. Correct answer: A
The given fraction is
Dividing the numerator and denominator by 3, we get
Thus,
is equivalent to .
10. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence by 6.
The number 653 is neither divisible by 3 nor by 2 and hence not by 6.
Now, consider the number 531.
Since, the sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
But it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
11. Correct answer: B
12. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
CBSE VI | Mathematics
Sample Paper 2 – Solution
Section B
13.
T Cr Cr T L L T Th Th H T O
(i)
7 0 7 0 7 5
(ii)
5 3 6 1 8 4 9 3
i. Seven lakh seven thousand seventy five.
ii. Five crore thirty-six lakh eighteen thousand four hundred ninety three.
14.
1. Two lines in the same plane which never intersect are called parallel lines.
2. Parallel lines remain the same distance apart over their entire length.
15.
i. Going 6 m to the West
ii. A withdrawal of Rs 100
iii. 10 km below sea level
iv. Spending Rs 500
16. Population of the village = 13295
Increase in population= Average growth - 1 = 399.
Population in the successive year = 13295 + 399 = 13694
17.
Prime factorisation of 455 is 5 × 7 × 13
Therefore, the dimensions of the cuboid are 5 cm, 7 cm, 13 cm.
CBSE VI | Mathematics
Sample Paper 2 – Solution
18. The opposite sides of a parallelogram are parallel and equal.
Therefore, LM = NO
19. 90, 91, 92, 93, 94, 95, 96 are the required numbers.
20. Number of circles in step 1 = 3 = 1 × 2 + 1
Number of circles in step 2 = 5 = 2 × 2 + 1
Thus, we can observe that the number of circles is obtained by multiplying the step
number by 2 and then adding 1.
Therefore, number of circles in the 100
th
step = (100 × 2) + 1 = 201
21.
20570 = 2 × 5 × 11 × 11 × 17
22. Anna is 7 feet above sea level.
She jumps 3 feet down and walks another 2 feet down. Total distance travelled
downwards = 3 + 2 = 5 feet.
23. (–13) + (–19) + (+15) + (–10)
= –13 – 19 + 15 – 10
= –13 – 19 – 10 + 15
= –42 + 15
= –27
24. 21397 can be estimated as 21000
27807 can be estimated as 28000
42305 can be estimated as 42000
On adding, we get 21000 + 28000 + 42000 = 91000
CBSE VI | Mathematics
Sample Paper 2 – Solution
Section C
25. C stands for 100
D stands for 500
V stands for 5
I stands for 1
X stands for 10
M stands for 1000
In ascending order, the numbers can be arranged as
1 < 5 < 10 < 100 < 500 < 1000
Thus, the given roman numerals can be arranged in ascending order as
I, V, X, C, D, M
26. First we find the LCM of 48, 60, 72.
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
72 = 2 × 2 × 2 × 3 × 3
LCM = 2 × 2 × 2 × 2 × 3 × 3 × 5 = 720
Hence, they will meet after = 2 rounds.
27. The given fractions are .
LCM of 2, 3, 6, 9 = (2 x 3 x 3) = 18
So, we convert each of the given fractions into an equivalent fraction with 18 as the
denominator.
Thus, we have:
Hence, the like fractions are
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FAQs on Class 6 Math: CBSE Sample Question Paper Solutions Term I – 2 - Mathematics (Maths) Class 6
| 1. What is the format of the CBSE Class 6 Math Sample Question Paper for Term I? |  |
Ans. The CBSE Class 6 Math Sample Question Paper for Term I usually follows the format of multiple-choice questions, short answer questions, and long answer questions. It is designed to assess the students' understanding of the concepts taught in the first term.
| 2. How can I access the CBSE Class 6 Math Sample Question Paper for Term I? | |
Ans. The CBSE Class 6 Math Sample Question Paper for Term I can be accessed through various sources such as the official CBSE website, educational websites, or by asking your school for a copy. It is important to practice with the sample question paper to get an idea of the exam pattern and prepare effectively.
| 3. Are the CBSE Class 6 Math Sample Question Papers for Term I available in multiple languages? | |
Ans. Yes, the CBSE Class 6 Math Sample Question Papers for Term I are available in multiple languages, including the language of the article title. CBSE provides question papers in different languages to cater to the diverse student population across the country.
| 4. How can I use the CBSE Class 6 Math Sample Question Paper to prepare for the exam? | |
Ans. You can use the CBSE Class 6 Math Sample Question Paper to practice and assess your knowledge and understanding of the subject. Start by solving the sample paper under exam-like conditions to get acquainted with the time limit. Identify your weak areas and focus on improving them through additional study and practice.
| 5. Are the CBSE Class 6 Math Sample Question Papers for Term I aligned with the syllabus? | |
Ans. Yes, the CBSE Class 6 Math Sample Question Papers for Term I are designed to align with the syllabus provided by the CBSE board. They cover the topics and concepts taught in the first term, ensuring that students can assess their understanding and prepare accordingly.
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