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Page 1
CBSE VI | Mathematics
Sample Paper 5 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 5 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct Answer: A
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3
2. Correct Answer: D
932, 923, 239, 293, 329, 392.
3. Correct Answer: C
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1
and 139.
4. Correct Answer: A
5. Correct Answer: D
The HCF of 15 and 27 is 3. Hence,
6. Correct Answer: B
To add 4 on number line, move 4 steps to the right of 0.
7. Correct Answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000.
Page 2
CBSE VI | Mathematics
Sample Paper 5 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 5 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct Answer: A
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3
2. Correct Answer: D
932, 923, 239, 293, 329, 392.
3. Correct Answer: C
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1
and 139.
4. Correct Answer: A
5. Correct Answer: D
The HCF of 15 and 27 is 3. Hence,
6. Correct Answer: B
To add 4 on number line, move 4 steps to the right of 0.
7. Correct Answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000.
CBSE VI | Mathematics
Sample Paper 5 – Solution
8. Correct Answer: A
Thus, 36 = 2 × 2 × 3 × 3
9. Correct Answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
10. Correct Answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
One and only one line passes through any two given points.
11. Correct Answer: B
267 can be estimated as 270.
132 can be estimated as 130.
Thus the required estimated sum = 270 + 130 = 400
12. Correct Answer: B
10 = 2 × 5
18 = 2 × 3 × 3
HCF of 10 and 18 is 2.
Thus, 2 is the required number.
Section B
13. Place value of 9 at the Ten Lakhs place = 9000000
Place value of 9 at the hundreds place = 900
Difference = 9000000 – 900 = 8999100
14. The number of vertices in the given shapes:
i. Sphere : 0
ii. Cylinder : 0
Page 3
CBSE VI | Mathematics
Sample Paper 5 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 5 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct Answer: A
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3
2. Correct Answer: D
932, 923, 239, 293, 329, 392.
3. Correct Answer: C
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1
and 139.
4. Correct Answer: A
5. Correct Answer: D
The HCF of 15 and 27 is 3. Hence,
6. Correct Answer: B
To add 4 on number line, move 4 steps to the right of 0.
7. Correct Answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000.
CBSE VI | Mathematics
Sample Paper 5 – Solution
8. Correct Answer: A
Thus, 36 = 2 × 2 × 3 × 3
9. Correct Answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
10. Correct Answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
One and only one line passes through any two given points.
11. Correct Answer: B
267 can be estimated as 270.
132 can be estimated as 130.
Thus the required estimated sum = 270 + 130 = 400
12. Correct Answer: B
10 = 2 × 5
18 = 2 × 3 × 3
HCF of 10 and 18 is 2.
Thus, 2 is the required number.
Section B
13. Place value of 9 at the Ten Lakhs place = 9000000
Place value of 9 at the hundreds place = 900
Difference = 9000000 – 900 = 8999100
14. The number of vertices in the given shapes:
i. Sphere : 0
ii. Cylinder : 0
CBSE VI | Mathematics
Sample Paper 5 – Solution
15. Anna is 7 feet above sea level. She jumps 3 feet down and walks another 2 feet down.
Total distance travelled downwards = 3 + 2 = 5 feet.
16. (–13) + (–19) + (+15) + (–10)
= –13 – 19 + 15 – 10
= –13 – 19 – 10 + 15
= –42 + 15
= –27
17. A 9-digit numeral in Indian system = 94,50,27,983
In International system,
945,027,983 - Nine hundred forty five million twenty seven thousand nine hundred
eighty three.
18. Two lines in the same plane which never intersect are called parallel lines.
Parallel lines maintain the same distance apart over their entire length.
19. Population of the village = 13295
Increase in population= Average growth – 1 = 399
Population in the successive year = 13295 + 399 = 13694
20. Prime factorisation of 455 = 5 × 7 × 13
Therefore, the dimensions of the cuboid are
5 cm, 7 cm, 13 cm.
Page 4
CBSE VI | Mathematics
Sample Paper 5 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 5 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct Answer: A
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3
2. Correct Answer: D
932, 923, 239, 293, 329, 392.
3. Correct Answer: C
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1
and 139.
4. Correct Answer: A
5. Correct Answer: D
The HCF of 15 and 27 is 3. Hence,
6. Correct Answer: B
To add 4 on number line, move 4 steps to the right of 0.
7. Correct Answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000.
CBSE VI | Mathematics
Sample Paper 5 – Solution
8. Correct Answer: A
Thus, 36 = 2 × 2 × 3 × 3
9. Correct Answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
10. Correct Answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
One and only one line passes through any two given points.
11. Correct Answer: B
267 can be estimated as 270.
132 can be estimated as 130.
Thus the required estimated sum = 270 + 130 = 400
12. Correct Answer: B
10 = 2 × 5
18 = 2 × 3 × 3
HCF of 10 and 18 is 2.
Thus, 2 is the required number.
Section B
13. Place value of 9 at the Ten Lakhs place = 9000000
Place value of 9 at the hundreds place = 900
Difference = 9000000 – 900 = 8999100
14. The number of vertices in the given shapes:
i. Sphere : 0
ii. Cylinder : 0
CBSE VI | Mathematics
Sample Paper 5 – Solution
15. Anna is 7 feet above sea level. She jumps 3 feet down and walks another 2 feet down.
Total distance travelled downwards = 3 + 2 = 5 feet.
16. (–13) + (–19) + (+15) + (–10)
= –13 – 19 + 15 – 10
= –13 – 19 – 10 + 15
= –42 + 15
= –27
17. A 9-digit numeral in Indian system = 94,50,27,983
In International system,
945,027,983 - Nine hundred forty five million twenty seven thousand nine hundred
eighty three.
18. Two lines in the same plane which never intersect are called parallel lines.
Parallel lines maintain the same distance apart over their entire length.
19. Population of the village = 13295
Increase in population= Average growth – 1 = 399
Population in the successive year = 13295 + 399 = 13694
20. Prime factorisation of 455 = 5 × 7 × 13
Therefore, the dimensions of the cuboid are
5 cm, 7 cm, 13 cm.
CBSE VI | Mathematics
Sample Paper 5 – Solution
21. L.C.M. of 24, 45 and 54 = 2 × 2 × 2 × 3 × 3 × 3 × 5 = 1080
22.
21
53
72
?
37 7
72
37 2 7 7
7 2 2 7
74 49
14 14
123
14
11
8
14
??
??
??
??
??
?
?
23. Subtracting a negative number is the same as adding its positive integer.
? 7 – (–3) = 7 + 3 = 10
24. To find the H.C.F of 77, 105 and 231.
77 = 7 × 11
105 = 3 × 5 × 7
231 = 3 × 7 × 11
Hence, H.C.F of 77, 105 and 231 is = 7
Page 5
CBSE VI | Mathematics
Sample Paper 5 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 5 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct Answer: A
1 – 2 + 3 – 4 + 5 = 1 + 3 + 5 – 2 – 4 = 9 – 6 = 3
2. Correct Answer: D
932, 923, 239, 293, 329, 392.
3. Correct Answer: C
Out of the given numbers, 139 is a prime number as it has only two factors, namely, 1
and 139.
4. Correct Answer: A
5. Correct Answer: D
The HCF of 15 and 27 is 3. Hence,
6. Correct Answer: B
To add 4 on number line, move 4 steps to the right of 0.
7. Correct Answer: D
Estimate the product by rounding off 52 to its nearest tens and 188 to its nearest
hundreds.
52 can be rounded off to its nearest tens as 50 and 188 can be rounded off to its
nearest hundreds as 200.
So, the required estimation of the product is 50 × 200 = 10000.
CBSE VI | Mathematics
Sample Paper 5 – Solution
8. Correct Answer: A
Thus, 36 = 2 × 2 × 3 × 3
9. Correct Answer: D
13 + (12 – 6 × 3) = 13 + (12 – 18) = 13 – 6 = 7
10. Correct Answer: B
NO and PQ can be extended indefinitely on both sides, so they are lines. On extending,
it can be seen that they would meet at a point. Hence, they are intersecting lines.
One and only one line passes through any two given points.
11. Correct Answer: B
267 can be estimated as 270.
132 can be estimated as 130.
Thus the required estimated sum = 270 + 130 = 400
12. Correct Answer: B
10 = 2 × 5
18 = 2 × 3 × 3
HCF of 10 and 18 is 2.
Thus, 2 is the required number.
Section B
13. Place value of 9 at the Ten Lakhs place = 9000000
Place value of 9 at the hundreds place = 900
Difference = 9000000 – 900 = 8999100
14. The number of vertices in the given shapes:
i. Sphere : 0
ii. Cylinder : 0
CBSE VI | Mathematics
Sample Paper 5 – Solution
15. Anna is 7 feet above sea level. She jumps 3 feet down and walks another 2 feet down.
Total distance travelled downwards = 3 + 2 = 5 feet.
16. (–13) + (–19) + (+15) + (–10)
= –13 – 19 + 15 – 10
= –13 – 19 – 10 + 15
= –42 + 15
= –27
17. A 9-digit numeral in Indian system = 94,50,27,983
In International system,
945,027,983 - Nine hundred forty five million twenty seven thousand nine hundred
eighty three.
18. Two lines in the same plane which never intersect are called parallel lines.
Parallel lines maintain the same distance apart over their entire length.
19. Population of the village = 13295
Increase in population= Average growth – 1 = 399
Population in the successive year = 13295 + 399 = 13694
20. Prime factorisation of 455 = 5 × 7 × 13
Therefore, the dimensions of the cuboid are
5 cm, 7 cm, 13 cm.
CBSE VI | Mathematics
Sample Paper 5 – Solution
21. L.C.M. of 24, 45 and 54 = 2 × 2 × 2 × 3 × 3 × 3 × 5 = 1080
22.
21
53
72
?
37 7
72
37 2 7 7
7 2 2 7
74 49
14 14
123
14
11
8
14
??
??
??
??
??
?
?
23. Subtracting a negative number is the same as adding its positive integer.
? 7 – (–3) = 7 + 3 = 10
24. To find the H.C.F of 77, 105 and 231.
77 = 7 × 11
105 = 3 × 5 × 7
231 = 3 × 7 × 11
Hence, H.C.F of 77, 105 and 231 is = 7
CBSE VI | Mathematics
Sample Paper 5 – Solution
Section C
25. To solve using number line start with –8, move 12 steps right and then back 2 steps as
shown below:
So, we reach at 2, therefore (–8 + 12 – 2) = 2
26. AC, AD, BD, BE and CE are diagonals.
27. Temperature in the morning = –14
o
F
Drop in temperature is written as –7
o
F
Temperature at present = –14
o
F + (–7
o
F) = –14
o
F – 7
o
F = –21
o
F
28. Rs. 13550 estimated to nearest thousands = Rs. 14000
Rs. 26788 estimated to nearest thousands = Rs. 27000
Total estimated money (to be received) = Rs. (14000 + 27000) = Rs. 41000
He has to pay Rs. 37000.
And 41000 > 37000
Therefore, he will be able to pay to his supplier with the money received.
29. First we find the LCM of 48, 60, 72.
48 = 2 × 2 × 2 × 2 × 3
60 = 2 × 2 × 3 × 5
72 = 2 × 2 × 2 × 3 × 3
LCM = 2 × 2 × 2 × 2 × 3 × 3 × 5 = 720
Hence, they will meet after = 2 rounds.
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FAQs on Class 6 Math: CBSE Sample Question Paper Solutions Term I – 5 - Mathematics (Maths) Class 6
| 1. What is the format of the CBSE Sample Question Paper for Class 6 Math Term I? |  |
Ans. The CBSE Sample Question Paper for Class 6 Math Term I is designed to assess students' understanding of the concepts taught in the first term. It includes multiple-choice questions, short answer questions, and long answer questions.
| 2. How many questions are there in the CBSE Sample Question Paper for Class 6 Math Term I? | |
Ans. The number of questions in the CBSE Sample Question Paper for Class 6 Math Term I may vary, but typically it consists of around 30 to 35 questions.
| 3. What topics are covered in the CBSE Sample Question Paper for Class 6 Math Term I? | |
Ans. The CBSE Sample Question Paper for Class 6 Math Term I covers various topics such as numbers, basic operations, fractions, decimals, geometry, mensuration, data handling, etc.
| 4. How can I prepare for the CBSE Class 6 Math Term I exam using the sample question paper? | |
Ans. To prepare for the CBSE Class 6 Math Term I exam using the sample question paper, you can start by familiarizing yourself with the question paper format and the types of questions asked. Practice solving the sample papers to improve your speed and accuracy in answering different types of questions.
| 5. Are the solutions to the CBSE Sample Question Paper for Class 6 Math Term I available? | |
Ans. Yes, the solutions to the CBSE Sample Question Paper for Class 6 Math Term I are available. You can find them in various study materials, online platforms, or by referring to the answer key provided by your school or teacher.
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