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Page 1
CBSE VI | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
1.35 =
2. Correct answer: A
Data collected from a group of 40 students is an example of primary data.
3. Correct answer: D
Maximum marks = 47, Minimum marks = 21
Difference = Maximum – Minimum = 47 – 21 = 26
4. Correct answer: D
Perimeter of a square = 4 × length of a side
5. Correct answer: A
Area of a square = side × side = p × p = p
2
6. Correct answer: B
15 : 19 is not equivalent to 50 : 90.
7. Correct answer: C
An isosceles triangle has exactly one line of symmetry.
8. Correct answer: A
Protractor is used to draw and measure angles.
9. Correct answer: C
Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest
value.
10. Correct answer: B
n
8
5
?
is the correct expression.
11. Correct answer: A
Letter H has a horizontal line of symmetry.
Page 2
CBSE VI | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
1.35 =
2. Correct answer: A
Data collected from a group of 40 students is an example of primary data.
3. Correct answer: D
Maximum marks = 47, Minimum marks = 21
Difference = Maximum – Minimum = 47 – 21 = 26
4. Correct answer: D
Perimeter of a square = 4 × length of a side
5. Correct answer: A
Area of a square = side × side = p × p = p
2
6. Correct answer: B
15 : 19 is not equivalent to 50 : 90.
7. Correct answer: C
An isosceles triangle has exactly one line of symmetry.
8. Correct answer: A
Protractor is used to draw and measure angles.
9. Correct answer: C
Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest
value.
10. Correct answer: B
n
8
5
?
is the correct expression.
11. Correct answer: A
Letter H has a horizontal line of symmetry.
CBSE VI | Mathematics
Sample Paper 1 – Solution
12. Correct answer: B
= 5 + 5 + 5 + 5 + 5 + 3 = 28
Section B
13. Cost of a book = Rs. 165.35
Cost of a pen = Rs. 72.00
Cost of a notebook = Rs. 14.85
Total Cost is given by,
Total money to be paid by Preeta = Rs. 252.20
14. (a) Secondary
(b) Primary
15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to
get the measure of one side.
One side of pentagon = 25 cm ÷ 5 cm = 5 cm
16. Let the number of rows be 'n'.
Since there are 11 students in a row and number of rows are n, the Rule is given as,
Number of students in the parade = 11n.
17. Three symmetrical objects are
(i) An electric tube-light
(ii) A water glass
(iii) A fan
18. Steps of construction:
(1) Draw a line l. Mark a point A on a line l.
(2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil
point up to the 4.5 cm mark.
(3) Taking caution that the opening of the compass has not changed, place the
pointer on A and swing an arc to cut l at B.
(4) AB is a line segment of required length.
Page 3
CBSE VI | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
1.35 =
2. Correct answer: A
Data collected from a group of 40 students is an example of primary data.
3. Correct answer: D
Maximum marks = 47, Minimum marks = 21
Difference = Maximum – Minimum = 47 – 21 = 26
4. Correct answer: D
Perimeter of a square = 4 × length of a side
5. Correct answer: A
Area of a square = side × side = p × p = p
2
6. Correct answer: B
15 : 19 is not equivalent to 50 : 90.
7. Correct answer: C
An isosceles triangle has exactly one line of symmetry.
8. Correct answer: A
Protractor is used to draw and measure angles.
9. Correct answer: C
Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest
value.
10. Correct answer: B
n
8
5
?
is the correct expression.
11. Correct answer: A
Letter H has a horizontal line of symmetry.
CBSE VI | Mathematics
Sample Paper 1 – Solution
12. Correct answer: B
= 5 + 5 + 5 + 5 + 5 + 3 = 28
Section B
13. Cost of a book = Rs. 165.35
Cost of a pen = Rs. 72.00
Cost of a notebook = Rs. 14.85
Total Cost is given by,
Total money to be paid by Preeta = Rs. 252.20
14. (a) Secondary
(b) Primary
15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to
get the measure of one side.
One side of pentagon = 25 cm ÷ 5 cm = 5 cm
16. Let the number of rows be 'n'.
Since there are 11 students in a row and number of rows are n, the Rule is given as,
Number of students in the parade = 11n.
17. Three symmetrical objects are
(i) An electric tube-light
(ii) A water glass
(iii) A fan
18. Steps of construction:
(1) Draw a line l. Mark a point A on a line l.
(2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil
point up to the 4.5 cm mark.
(3) Taking caution that the opening of the compass has not changed, place the
pointer on A and swing an arc to cut l at B.
(4) AB is a line segment of required length.
CBSE VI | Mathematics
Sample Paper 1 – Solution
19. Ratio of 30 cm to 4 m
Ratio of 20 sec to 6 minutes
Since,
,
Therefore the given ratio do not form a proportion.
20. To get this answer subtract 27.84 from 84.5
Hence, 56.66 must be subtracted from 84.5 to get 27.84
21. The shaded portion is made up of line segments. It is covered by full and half
squares. We have to calculate the number of fully filled and half filled squares.
? Fully filled squares = 6
? Half-filled squares = 2
Area covered by fully filled square = 6 × 1 = 6 sq. units.
Area covered by half-filled square = 2 ×
1
2
= 1
Therefore, total area = 6 + 1 = 7 sq. units
22. Drawing the relational part the images become as follows:
23. (a) Butterscotch is liked by 5 + 5 + 2 = 12 students.
(b) Chocolate flavor is less favourite.
Page 4
CBSE VI | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
1.35 =
2. Correct answer: A
Data collected from a group of 40 students is an example of primary data.
3. Correct answer: D
Maximum marks = 47, Minimum marks = 21
Difference = Maximum – Minimum = 47 – 21 = 26
4. Correct answer: D
Perimeter of a square = 4 × length of a side
5. Correct answer: A
Area of a square = side × side = p × p = p
2
6. Correct answer: B
15 : 19 is not equivalent to 50 : 90.
7. Correct answer: C
An isosceles triangle has exactly one line of symmetry.
8. Correct answer: A
Protractor is used to draw and measure angles.
9. Correct answer: C
Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest
value.
10. Correct answer: B
n
8
5
?
is the correct expression.
11. Correct answer: A
Letter H has a horizontal line of symmetry.
CBSE VI | Mathematics
Sample Paper 1 – Solution
12. Correct answer: B
= 5 + 5 + 5 + 5 + 5 + 3 = 28
Section B
13. Cost of a book = Rs. 165.35
Cost of a pen = Rs. 72.00
Cost of a notebook = Rs. 14.85
Total Cost is given by,
Total money to be paid by Preeta = Rs. 252.20
14. (a) Secondary
(b) Primary
15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to
get the measure of one side.
One side of pentagon = 25 cm ÷ 5 cm = 5 cm
16. Let the number of rows be 'n'.
Since there are 11 students in a row and number of rows are n, the Rule is given as,
Number of students in the parade = 11n.
17. Three symmetrical objects are
(i) An electric tube-light
(ii) A water glass
(iii) A fan
18. Steps of construction:
(1) Draw a line l. Mark a point A on a line l.
(2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil
point up to the 4.5 cm mark.
(3) Taking caution that the opening of the compass has not changed, place the
pointer on A and swing an arc to cut l at B.
(4) AB is a line segment of required length.
CBSE VI | Mathematics
Sample Paper 1 – Solution
19. Ratio of 30 cm to 4 m
Ratio of 20 sec to 6 minutes
Since,
,
Therefore the given ratio do not form a proportion.
20. To get this answer subtract 27.84 from 84.5
Hence, 56.66 must be subtracted from 84.5 to get 27.84
21. The shaded portion is made up of line segments. It is covered by full and half
squares. We have to calculate the number of fully filled and half filled squares.
? Fully filled squares = 6
? Half-filled squares = 2
Area covered by fully filled square = 6 × 1 = 6 sq. units.
Area covered by half-filled square = 2 ×
1
2
= 1
Therefore, total area = 6 + 1 = 7 sq. units
22. Drawing the relational part the images become as follows:
23. (a) Butterscotch is liked by 5 + 5 + 2 = 12 students.
(b) Chocolate flavor is less favourite.
CBSE VI | Mathematics
Sample Paper 1 – Solution
24. Let the isosceles triangle be ABC, in which AB = AC = 18 cm.
Also perimeter is given 50 cm, we need to find BC.
Perimeter of triangle = 50 cm
AB + AC + BC = 50 cm
? 18 + 18 + x = 50 cm
? 36 + x = 50 cm
? x = 50 – 36 = 14 cm
Therefore, length of third side is 14 cm.
Section C
25. Let the marks of Rohit, Ajay and Vipul be 4x, 5x and 6x respectively.
Given that Ajay's marks = 75
? 5x = 75
75
x 15
5
? ? ?
Hence, marks of Rohit = 4x = 4 × 15 = 60 marks
Marks of Vipul = 6x = 6 × 15 = 90 marks
26.
(a) Economics has the most students enrolled.
(b) From lowest to highest: Physics, Chemistry, Psychology, Political Science,
Economics.
(c) From ratio of the number of students enrolled in Economics to the number
enrolled in Chemistry we can state that enrollment in Economics is 2 times
larger than in Chemistry.
27. Steps of construction:
(1) Given AB whose length is not known.
(2) Fix the compasses pointer on A and the pencil end on B. The opening of the
instrument now gives the length of AB .
(3) Draw any line l. Choose a point C on l. Without changing the compasses setting,
place the pointer on C.
(4) Swing an arc that cuts l at a point, say D. Now CD is a copy of AB .
Page 5
CBSE VI | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
1.35 =
2. Correct answer: A
Data collected from a group of 40 students is an example of primary data.
3. Correct answer: D
Maximum marks = 47, Minimum marks = 21
Difference = Maximum – Minimum = 47 – 21 = 26
4. Correct answer: D
Perimeter of a square = 4 × length of a side
5. Correct answer: A
Area of a square = side × side = p × p = p
2
6. Correct answer: B
15 : 19 is not equivalent to 50 : 90.
7. Correct answer: C
An isosceles triangle has exactly one line of symmetry.
8. Correct answer: A
Protractor is used to draw and measure angles.
9. Correct answer: C
Out of the four the one-tenth part of 0.7 is the greatest. Hence, 0.7 has the highest
value.
10. Correct answer: B
n
8
5
?
is the correct expression.
11. Correct answer: A
Letter H has a horizontal line of symmetry.
CBSE VI | Mathematics
Sample Paper 1 – Solution
12. Correct answer: B
= 5 + 5 + 5 + 5 + 5 + 3 = 28
Section B
13. Cost of a book = Rs. 165.35
Cost of a pen = Rs. 72.00
Cost of a notebook = Rs. 14.85
Total Cost is given by,
Total money to be paid by Preeta = Rs. 252.20
14. (a) Secondary
(b) Primary
15. We know that a regular pentagon has 5 sides, so we can divide the perimeter by 5 to
get the measure of one side.
One side of pentagon = 25 cm ÷ 5 cm = 5 cm
16. Let the number of rows be 'n'.
Since there are 11 students in a row and number of rows are n, the Rule is given as,
Number of students in the parade = 11n.
17. Three symmetrical objects are
(i) An electric tube-light
(ii) A water glass
(iii) A fan
18. Steps of construction:
(1) Draw a line l. Mark a point A on a line l.
(2) Place the compass ’ pointer on the 0 mark of the ruler. Open it to place the pencil
point up to the 4.5 cm mark.
(3) Taking caution that the opening of the compass has not changed, place the
pointer on A and swing an arc to cut l at B.
(4) AB is a line segment of required length.
CBSE VI | Mathematics
Sample Paper 1 – Solution
19. Ratio of 30 cm to 4 m
Ratio of 20 sec to 6 minutes
Since,
,
Therefore the given ratio do not form a proportion.
20. To get this answer subtract 27.84 from 84.5
Hence, 56.66 must be subtracted from 84.5 to get 27.84
21. The shaded portion is made up of line segments. It is covered by full and half
squares. We have to calculate the number of fully filled and half filled squares.
? Fully filled squares = 6
? Half-filled squares = 2
Area covered by fully filled square = 6 × 1 = 6 sq. units.
Area covered by half-filled square = 2 ×
1
2
= 1
Therefore, total area = 6 + 1 = 7 sq. units
22. Drawing the relational part the images become as follows:
23. (a) Butterscotch is liked by 5 + 5 + 2 = 12 students.
(b) Chocolate flavor is less favourite.
CBSE VI | Mathematics
Sample Paper 1 – Solution
24. Let the isosceles triangle be ABC, in which AB = AC = 18 cm.
Also perimeter is given 50 cm, we need to find BC.
Perimeter of triangle = 50 cm
AB + AC + BC = 50 cm
? 18 + 18 + x = 50 cm
? 36 + x = 50 cm
? x = 50 – 36 = 14 cm
Therefore, length of third side is 14 cm.
Section C
25. Let the marks of Rohit, Ajay and Vipul be 4x, 5x and 6x respectively.
Given that Ajay's marks = 75
? 5x = 75
75
x 15
5
? ? ?
Hence, marks of Rohit = 4x = 4 × 15 = 60 marks
Marks of Vipul = 6x = 6 × 15 = 90 marks
26.
(a) Economics has the most students enrolled.
(b) From lowest to highest: Physics, Chemistry, Psychology, Political Science,
Economics.
(c) From ratio of the number of students enrolled in Economics to the number
enrolled in Chemistry we can state that enrollment in Economics is 2 times
larger than in Chemistry.
27. Steps of construction:
(1) Given AB whose length is not known.
(2) Fix the compasses pointer on A and the pencil end on B. The opening of the
instrument now gives the length of AB .
(3) Draw any line l. Choose a point C on l. Without changing the compasses setting,
place the pointer on C.
(4) Swing an arc that cuts l at a point, say D. Now CD is a copy of AB .
CBSE VI | Mathematics
Sample Paper 1 – Solution
28. From the figure the smaller rectangles are equal.
Therefore,
Area of one smaller rectangle = length × breadth = 3 × 4 = 12 sq. m
Area of 3 smaller rectangles = 3 × 12 = 36 sq. m
Area of bigger rectangle = length × breadth = 10 × 8 = 80 sq. m
Therefore, area of remaining part = 80 – 36 = 44 sq. m
29. Rate percent per annum is interest given on Rs. 100 for a year.
Let the interest for Rs. 100 per annum be Rs. x.
Principal : Principal :: Interest : Interest
5250 : 100 :: 420 : x
Product of extreme terms = 5250x
Product of the middle terms = 100 × 420 = 42000
5250x 100 420
42000
x8
5250
??
? ? ?
30.
(a) In this case time is unknown and distance is known. Therefore, we proceed as
follows:
6 hours = 6 × 60 minutes = 360 minutes
300 km is covered in 360 minutes
Time required to cover 1 km distance =
360 6
min
300 5
?
Therefore, 280 km can be covered in
6
280 336 minutes 5 hours 36 minutes
5
? ? ?
(b) In this case distance is unknown and time is known. Therefore, we proceed as
follows:
Distance covered in 6 hours = 300 km
Distance covered in 1 hour =
300
50 km
6
?
Therefore, distance covered in 10 hours = 50 × 10 = 500 km.
31. Area of a square wall = side × side = 10 × 10 = 100 sq. m
Area of four square walls = 4 × 100 = 400 sq. m
Cost of painting 1 sq. m of wall = Rs. 20
Therefore, total cost of painting = Rs. 20 × 400 = Rs. 8000
32. (a) In 2009-April, May and in 2010-May, June.
(b) In 2009-May and in 2010-May.
(c) In 2009-June and in 2010-March and May
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FAQs on Class 6 Math: CBSE Sample Question Paper Solutions Term II – 1 - Mathematics (Maths) Class 6
| 1. How can I access CBSE sample question papers for Class 6 Math Term II? |  |
Ans. You can access CBSE sample question papers for Class 6 Math Term II by visiting the official website of the Central Board of Secondary Education (CBSE) or by searching for them on educational websites or online platforms that provide study materials for CBSE students.
| 2. What is the importance of solving CBSE sample question papers for Class 6 Math Term II? | |
Ans. Solving CBSE sample question papers for Class 6 Math Term II is important as it helps students to familiarize themselves with the exam pattern, marking scheme, and types of questions that can be asked in the actual exam. It also helps in identifying areas of weakness and enables students to practice and improve their problem-solving skills.
| 3. Are the CBSE sample question papers for Class 6 Math Term II similar to the actual exam question paper? | |
Ans. Yes, the CBSE sample question papers for Class 6 Math Term II are designed to be similar to the actual exam question paper. They are created by experienced educators and follow the CBSE curriculum and guidelines. Solving these sample papers will give students a good idea of the difficulty level and format of the actual exam.
| 4. Can I rely solely on CBSE sample question papers for Class 6 Math Term II for exam preparation? | |
Ans. While CBSE sample question papers for Class 6 Math Term II are a valuable resource for exam preparation, it is recommended to supplement them with other study materials such as textbooks, reference books, and online tutorials. This will provide a comprehensive understanding of the concepts and ensure better preparation for the exam.
| 5. How can I use CBSE sample question papers for Class 6 Math Term II effectively? | |
Ans. To use CBSE sample question papers for Class 6 Math Term II effectively, start by solving them under exam-like conditions, such as setting a time limit and attempting the questions without any help. Once you complete the paper, evaluate your performance, identify areas of improvement, and work on them. It is also useful to analyze the solutions provided in the sample papers to understand the correct approach to solving different types of questions.
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