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Page 1
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: D
Decimal number represented by point A on the number line is 1.9
2. Correct answer: D
Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1
3. Correct answer: C
Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m
4. Correct answer: B
Cost of n such books will be 10n.
5. Correct answer: B
3 : 4 :: x : 8
3x
48
?
Gives, 4x = 24 ? x = 6
6. Correct answer: A
A rectangle has two lines of symmetry.
7. Correct answer: A
Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30
Page 2
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: D
Decimal number represented by point A on the number line is 1.9
2. Correct answer: D
Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1
3. Correct answer: C
Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m
4. Correct answer: B
Cost of n such books will be 10n.
5. Correct answer: B
3 : 4 :: x : 8
3x
48
?
Gives, 4x = 24 ? x = 6
6. Correct answer: A
A rectangle has two lines of symmetry.
7. Correct answer: A
Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30
CBSE VI | Mathematics
Sample Paper 2 – Solution
8. Correct answer: A
The given number 8.6 can be written as
9. Correct answer: B
Value at y = 1 is 4(1) + 12 = 16
10. Correct answer: A
Alphabet H has 2 lines of symmetry
11. Correct answer: B
9 multiplied to k and then 1 is added.
12. Correct answer: B
0.1254 < 01257 < 0.1258 < 01259
Section B
13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =
Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g
14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118
Page 3
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: D
Decimal number represented by point A on the number line is 1.9
2. Correct answer: D
Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1
3. Correct answer: C
Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m
4. Correct answer: B
Cost of n such books will be 10n.
5. Correct answer: B
3 : 4 :: x : 8
3x
48
?
Gives, 4x = 24 ? x = 6
6. Correct answer: A
A rectangle has two lines of symmetry.
7. Correct answer: A
Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30
CBSE VI | Mathematics
Sample Paper 2 – Solution
8. Correct answer: A
The given number 8.6 can be written as
9. Correct answer: B
Value at y = 1 is 4(1) + 12 = 16
10. Correct answer: A
Alphabet H has 2 lines of symmetry
11. Correct answer: B
9 multiplied to k and then 1 is added.
12. Correct answer: B
0.1254 < 01257 < 0.1258 < 01259
Section B
13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =
Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g
14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118
CBSE VI | Mathematics
Sample Paper 2 – Solution
15. Let the length of the fourth side be x cm.
Perimeter = 130 cm
30 + 40 + 25 + x = 130 cm
95 + x = 130 cm
x = 130 – 95
x = 35 cm
Therefore, length of the fourth side is 35 cm.
16. Number of ball in smaller boxes = x
Number of balls in the larger box = 2 × number of balls in small Box + balls left over
= 2x + 10
17. Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9
18. Length of rectangular field = 20 m
Breadth of the rectangular field = 15 m
The ratio of the breadth to the length is 15 : 20
Now,
15 15 5 3
15:20 3: 4
20 20 5 4
?
? ? ? ?
?
Thus, the required ratio is 3 : 4.
19. Steps of construction:
1. Draw a line segment AB of any length and mark a point P on it.
2. Taking P as centre and any radius draw two arcs one on left side of P and other
on right side of P, which cut AB at Q and R.
3. Taking Q and R as a centre draw two arcs and let them intersect at S.
4. Join PS.
5. PS is the required perpendicular of AB.
Page 4
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: D
Decimal number represented by point A on the number line is 1.9
2. Correct answer: D
Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1
3. Correct answer: C
Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m
4. Correct answer: B
Cost of n such books will be 10n.
5. Correct answer: B
3 : 4 :: x : 8
3x
48
?
Gives, 4x = 24 ? x = 6
6. Correct answer: A
A rectangle has two lines of symmetry.
7. Correct answer: A
Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30
CBSE VI | Mathematics
Sample Paper 2 – Solution
8. Correct answer: A
The given number 8.6 can be written as
9. Correct answer: B
Value at y = 1 is 4(1) + 12 = 16
10. Correct answer: A
Alphabet H has 2 lines of symmetry
11. Correct answer: B
9 multiplied to k and then 1 is added.
12. Correct answer: B
0.1254 < 01257 < 0.1258 < 01259
Section B
13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =
Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g
14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118
CBSE VI | Mathematics
Sample Paper 2 – Solution
15. Let the length of the fourth side be x cm.
Perimeter = 130 cm
30 + 40 + 25 + x = 130 cm
95 + x = 130 cm
x = 130 – 95
x = 35 cm
Therefore, length of the fourth side is 35 cm.
16. Number of ball in smaller boxes = x
Number of balls in the larger box = 2 × number of balls in small Box + balls left over
= 2x + 10
17. Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9
18. Length of rectangular field = 20 m
Breadth of the rectangular field = 15 m
The ratio of the breadth to the length is 15 : 20
Now,
15 15 5 3
15:20 3: 4
20 20 5 4
?
? ? ? ?
?
Thus, the required ratio is 3 : 4.
19. Steps of construction:
1. Draw a line segment AB of any length and mark a point P on it.
2. Taking P as centre and any radius draw two arcs one on left side of P and other
on right side of P, which cut AB at Q and R.
3. Taking Q and R as a centre draw two arcs and let them intersect at S.
4. Join PS.
5. PS is the required perpendicular of AB.
CBSE VI | Mathematics
Sample Paper 2 – Solution
20. Subtract 74.5 from 91
Hence, 16.5 should be added to 74.5 to get 91.
21. a. y + 7
b.
a
23
22. The complete image is as below:
23. (a) Number of students whose favourite colour is blue = 30.
(b) Number of students whose favourite colour is green = 45
Number of students whose favourite colour is red = 25
Thus, required number of students = 45 – 2 5 = 20
24. Speed of the bus = v km per hour
Distance travelled by the bus in 10 hours = 10v km
According to the question,
Distance from Delhi to Mumbai
= Distance travelled by bus in 10 hours + 80 km
= 10v km + 80 km
= (10v + 80) km
Section C
25. Total balls = 55
Blue balls = 25
Remaining balls are = 55 – 25 = 30
Given that remaining balls are in the ratio of 2 : 1.
Let these balls be 2x and 1x respectively.
? 2x + 1x = 30
? 3x = 30 ? x = 10
Thus, number of other two balls are
2x = 2 × 10 = 20 and 1x = 1 × 10 = 10
Ratio of sum of other two balls to the blue balls
30 6
6:5
25 5
? ? ?
Page 5
CBSE VI | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VI Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: D
Decimal number represented by point A on the number line is 1.9
2. Correct answer: D
Number of students who like hockey = 14
Number of students who like football = 13
Difference = 14 – 13 = 1
3. Correct answer: C
Perimeter of a square = 4 × side
70 = 4 × side
Side =
70
4
= 17.5 m
4. Correct answer: B
Cost of n such books will be 10n.
5. Correct answer: B
3 : 4 :: x : 8
3x
48
?
Gives, 4x = 24 ? x = 6
6. Correct answer: A
A rectangle has two lines of symmetry.
7. Correct answer: A
Cost of k chocolates = 6k
Then, cost of 5 chocolates = 6 × 5 = Rs. 30
CBSE VI | Mathematics
Sample Paper 2 – Solution
8. Correct answer: A
The given number 8.6 can be written as
9. Correct answer: B
Value at y = 1 is 4(1) + 12 = 16
10. Correct answer: A
Alphabet H has 2 lines of symmetry
11. Correct answer: B
9 multiplied to k and then 1 is added.
12. Correct answer: B
0.1254 < 01257 < 0.1258 < 01259
Section B
13. Weight of an empty cylinder = 18.075 kg
Weight of the gas filled in it = 12.350 kg
Total weight =
Hence, the total weight of the cylinder filled with gas = 30.425 kg = 30 kg 425 g
14. This data can be represented in a tabular form as shown below:
Standard VI Girls Boys Total
Div A 10 12 22
Div. B 6 20 26
Div. C 18 12 30
Div. D 16 24 40
Total 50 68 118
CBSE VI | Mathematics
Sample Paper 2 – Solution
15. Let the length of the fourth side be x cm.
Perimeter = 130 cm
30 + 40 + 25 + x = 130 cm
95 + x = 130 cm
x = 130 – 95
x = 35 cm
Therefore, length of the fourth side is 35 cm.
16. Number of ball in smaller boxes = x
Number of balls in the larger box = 2 × number of balls in small Box + balls left over
= 2x + 10
17. Point A represents 0.8
Point B represents 1.3
Point C represents 2.2
Point D represents 2.9
18. Length of rectangular field = 20 m
Breadth of the rectangular field = 15 m
The ratio of the breadth to the length is 15 : 20
Now,
15 15 5 3
15:20 3: 4
20 20 5 4
?
? ? ? ?
?
Thus, the required ratio is 3 : 4.
19. Steps of construction:
1. Draw a line segment AB of any length and mark a point P on it.
2. Taking P as centre and any radius draw two arcs one on left side of P and other
on right side of P, which cut AB at Q and R.
3. Taking Q and R as a centre draw two arcs and let them intersect at S.
4. Join PS.
5. PS is the required perpendicular of AB.
CBSE VI | Mathematics
Sample Paper 2 – Solution
20. Subtract 74.5 from 91
Hence, 16.5 should be added to 74.5 to get 91.
21. a. y + 7
b.
a
23
22. The complete image is as below:
23. (a) Number of students whose favourite colour is blue = 30.
(b) Number of students whose favourite colour is green = 45
Number of students whose favourite colour is red = 25
Thus, required number of students = 45 – 2 5 = 20
24. Speed of the bus = v km per hour
Distance travelled by the bus in 10 hours = 10v km
According to the question,
Distance from Delhi to Mumbai
= Distance travelled by bus in 10 hours + 80 km
= 10v km + 80 km
= (10v + 80) km
Section C
25. Total balls = 55
Blue balls = 25
Remaining balls are = 55 – 25 = 30
Given that remaining balls are in the ratio of 2 : 1.
Let these balls be 2x and 1x respectively.
? 2x + 1x = 30
? 3x = 30 ? x = 10
Thus, number of other two balls are
2x = 2 × 10 = 20 and 1x = 1 × 10 = 10
Ratio of sum of other two balls to the blue balls
30 6
6:5
25 5
? ? ?
CBSE VI | Mathematics
Sample Paper 2 – Solution
26.
1. Maximum rainfall occurred in city B, i.e., 25 × 10 = 250 cm
2. Minimum rainfall was in city F that is 25 × 1 = 25 cm
3. Difference between rainfalls of city A and F = (7 – 1) × 25 = 150 cm
27. The steps of construction are as follows:
1. Draw right angle triangle ABC with right angle at B.
2. Construct perpendicular bisectors of sides AB and BC.
3. Let the point of intersection of the perpendiculars be P.
4. By observing this point P lies on hypotenuse AC.
28. Total area of tiles must be equal to the area of the floor of the room.
Length = 15 m and Breadth = 16 m
Area of the floor = length × breadth = 15 × 16 = 240 sq. m
Area of one rectangular tile = length × breadth = 1.5 × 1 = 1.5 sq. m
Area of floor 240
Number of tiles required 160
Area of one tile 1.5
? ? ? ?
29. Number of girls in the class = 35
Number of boys in the class = 45
Total number of students = 35 + 45 = 80
Ratio of boys to girls = 45 : 35 = 9 : 7 (dividing by 5)
Ratio of boys to total number of students = 45 : 80 = 9 : 16
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FAQs on Class 6 Math: CBSE Sample Question Paper Solutions Term II – 2 - Mathematics (Maths) Class 6
| 1. What is the format of the CBSE Class 6 Math Term II – 2 exam? |  |
Ans. The CBSE Class 6 Math Term II – 2 exam is usually conducted in a written format, where students are required to answer a set of questions on paper.
| 2. How many marks are allotted for the CBSE Class 6 Math Term II – 2 exam? | |
Ans. The CBSE Class 6 Math Term II – 2 exam is generally marked out of 80 marks, with each question carrying a specific weightage depending on its complexity and difficulty level.
| 3. What are the important topics to focus on for the CBSE Class 6 Math Term II – 2 exam? | |
Ans. Some important topics to focus on for the CBSE Class 6 Math Term II – 2 exam are fractions, decimals, basic geometry, measurement, data handling, and basic algebraic expressions. It is essential to have a clear understanding of these topics to perform well in the exam.
| 4. Are there any sample question papers available for the CBSE Class 6 Math Term II – 2 exam? | |
Ans. Yes, CBSE provides sample question papers for the Class 6 Math Term II – 2 exam. These sample papers can be accessed online or obtained from the official CBSE website. Practicing these sample papers can help students familiarize themselves with the exam pattern and gain confidence.
| 5. How can I prepare effectively for the CBSE Class 6 Math Term II – 2 exam? | |
Ans. To prepare effectively for the CBSE Class 6 Math Term II – 2 exam, it is important to revise the concepts thoroughly, practice solving different types of questions, and solve previous years' question papers. Additionally, creating a study schedule, seeking help from teachers or classmates, and using online resources can also aid in effective preparation.
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