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Page 1
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
CBSE
Class VIII Mathematics
Sample Paper – 3 Solution
Time: 3 hours Total Marks: 80
Section A
1. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
2. Correct answer: B
20
20% of x=
100 5
x
x ?
3. Correct answer: A
Five vertices.
4. Correct option : A
?
196 2
484
?
1
7
2
?
?
1
7
11
11
5. Correct answer: B
0 and 1
6. Correct answer: A
1
3
= 1
Thus, the natural number 1 is equal to its cube.
7. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
8. Correct option: A
6 17 29
2
12 34 29
17 34
2
k
k
kk
k
k
?
?
? ? ?
??
??
Page 2
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
CBSE
Class VIII Mathematics
Sample Paper – 3 Solution
Time: 3 hours Total Marks: 80
Section A
1. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
2. Correct answer: B
20
20% of x=
100 5
x
x ?
3. Correct answer: A
Five vertices.
4. Correct option : A
?
196 2
484
?
1
7
2
?
?
1
7
11
11
5. Correct answer: B
0 and 1
6. Correct answer: A
1
3
= 1
Thus, the natural number 1 is equal to its cube.
7. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
8. Correct option: A
6 17 29
2
12 34 29
17 34
2
k
k
kk
k
k
?
?
? ? ?
??
??
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
9. Correct answer: C
The given shape has 12 edges.
10. Correct answer: D
Sales tax =
4
380 15.20
100
??
11. Correct option: C
? ? ? ? ? ? ? ? ?
22
484 2 2 11 11 2 11 2 11 22
12. Correct option: B
?
?
? ? ?
14 441
22
22 441
.693
14
x
x Rs
Section B
(Questions 8 to 11 carry 2 marks each)
13. The number
2
5
lies between 0 and 1.
Draw a number line. Mark points O and A to represent 0 and 1, respectively.
Divide OA into 5 equal parts (equal to the denominator of
2
5
).The second point, Q,
represents the rational number
2
5
.
14. Steps of construction:
a) Draw AC = 8 cm.
b) Draw perpendicular bisector XY of AC meeting AC at O.
c) From O cut off OD =
1
2
× 6 cm = 3 cm along OX and OB =
1
2
× 6 cm =3 cm along OY.
d) Join AB, BC, CD and DA.
Page 3
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
CBSE
Class VIII Mathematics
Sample Paper – 3 Solution
Time: 3 hours Total Marks: 80
Section A
1. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
2. Correct answer: B
20
20% of x=
100 5
x
x ?
3. Correct answer: A
Five vertices.
4. Correct option : A
?
196 2
484
?
1
7
2
?
?
1
7
11
11
5. Correct answer: B
0 and 1
6. Correct answer: A
1
3
= 1
Thus, the natural number 1 is equal to its cube.
7. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
8. Correct option: A
6 17 29
2
12 34 29
17 34
2
k
k
kk
k
k
?
?
? ? ?
??
??
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
9. Correct answer: C
The given shape has 12 edges.
10. Correct answer: D
Sales tax =
4
380 15.20
100
??
11. Correct option: C
? ? ? ? ? ? ? ? ?
22
484 2 2 11 11 2 11 2 11 22
12. Correct option: B
?
?
? ? ?
14 441
22
22 441
.693
14
x
x Rs
Section B
(Questions 8 to 11 carry 2 marks each)
13. The number
2
5
lies between 0 and 1.
Draw a number line. Mark points O and A to represent 0 and 1, respectively.
Divide OA into 5 equal parts (equal to the denominator of
2
5
).The second point, Q,
represents the rational number
2
5
.
14. Steps of construction:
a) Draw AC = 8 cm.
b) Draw perpendicular bisector XY of AC meeting AC at O.
c) From O cut off OD =
1
2
× 6 cm = 3 cm along OX and OB =
1
2
× 6 cm =3 cm along OY.
d) Join AB, BC, CD and DA.
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
ABCD is the required rhombus.
15. We have,
Number of vertices (V) = 8
Number of edges (E) = 12
Let, number of faces = F
Since every polyhedron satisfy Euler's formula, therefore
F + V = E + 2
Or, F + 8 = 12 + 2
Or, F = 14 - 8 = 6
Hence, the number of faces are 6.
16. We have:
(a + b)
2
= a
2
+ b
2
+ 2abTaking, a = -20 and b = -5, we get
(-25)
2
= {-20 + (-5)}
2
= (-20)
2
+ (-5)
2
+ 2(-20)(-5)
= 400 + 25 + 200 = 625
17. From the graph, it is clear that 5 students favoured orange and 1 student favoured
green.
Now, 5 – 1 = 4
Therefore, 4 more students favoured orange colour than green.
18. Since ABCD is an isosceles trapezoidal, we have AD = BC
Therefore, AD = BC = 4 cm.
Now the perimeter of given trapezium
= AB + BC + CD + DA
= 12 + 4 + 8 + 4
= 28
Page 4
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
CBSE
Class VIII Mathematics
Sample Paper – 3 Solution
Time: 3 hours Total Marks: 80
Section A
1. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
2. Correct answer: B
20
20% of x=
100 5
x
x ?
3. Correct answer: A
Five vertices.
4. Correct option : A
?
196 2
484
?
1
7
2
?
?
1
7
11
11
5. Correct answer: B
0 and 1
6. Correct answer: A
1
3
= 1
Thus, the natural number 1 is equal to its cube.
7. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
8. Correct option: A
6 17 29
2
12 34 29
17 34
2
k
k
kk
k
k
?
?
? ? ?
??
??
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
9. Correct answer: C
The given shape has 12 edges.
10. Correct answer: D
Sales tax =
4
380 15.20
100
??
11. Correct option: C
? ? ? ? ? ? ? ? ?
22
484 2 2 11 11 2 11 2 11 22
12. Correct option: B
?
?
? ? ?
14 441
22
22 441
.693
14
x
x Rs
Section B
(Questions 8 to 11 carry 2 marks each)
13. The number
2
5
lies between 0 and 1.
Draw a number line. Mark points O and A to represent 0 and 1, respectively.
Divide OA into 5 equal parts (equal to the denominator of
2
5
).The second point, Q,
represents the rational number
2
5
.
14. Steps of construction:
a) Draw AC = 8 cm.
b) Draw perpendicular bisector XY of AC meeting AC at O.
c) From O cut off OD =
1
2
× 6 cm = 3 cm along OX and OB =
1
2
× 6 cm =3 cm along OY.
d) Join AB, BC, CD and DA.
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
ABCD is the required rhombus.
15. We have,
Number of vertices (V) = 8
Number of edges (E) = 12
Let, number of faces = F
Since every polyhedron satisfy Euler's formula, therefore
F + V = E + 2
Or, F + 8 = 12 + 2
Or, F = 14 - 8 = 6
Hence, the number of faces are 6.
16. We have:
(a + b)
2
= a
2
+ b
2
+ 2abTaking, a = -20 and b = -5, we get
(-25)
2
= {-20 + (-5)}
2
= (-20)
2
+ (-5)
2
+ 2(-20)(-5)
= 400 + 25 + 200 = 625
17. From the graph, it is clear that 5 students favoured orange and 1 student favoured
green.
Now, 5 – 1 = 4
Therefore, 4 more students favoured orange colour than green.
18. Since ABCD is an isosceles trapezoidal, we have AD = BC
Therefore, AD = BC = 4 cm.
Now the perimeter of given trapezium
= AB + BC + CD + DA
= 12 + 4 + 8 + 4
= 28
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
Hence, the perimeter of the given trapezium is 28 cm.
19. Original price of the book = Rs. 50
Increased % = 6%
Thus, New Price = Original Price + 6% of Original price
New price = Rs.
6
50 50 .(50 3) .53
100
Rs Rs ? ? ? ? ?
20. Area of square = (5a – 2b)
2
We use the identity (x – y )
2
= x
2
– 2xy + y
2
Taking, x = 5a and y = 2b
We get, (5a – 2b)
2
= (5a)
2
– 2(5a)(2b ) + (2b)=25a
2
– 20ab + 4b
2
21. 82
2
= (80 + 2)
2
In the property (a + b)
2
= a
2
+ b
2
+ 2ab, putting a = 80 and b = 2, we get:
(80 + 2)
2
= 80
2
+ 2
2
+ 2 × 80 × 2
= 6400 + 4 + 320
= 6724
22. Let x be the ten’s digit of the two-digit number.
Then its unit's digit = x + 7.
Number = unit’s digit + 10(ten’s digit) = (x + 7) + 10(x) = 11x + 7.
Sum of the digits = (x + 7) + (x) = 2x + 7.
Given, sum of the digits is half of the whole number.
Therefore,
1
(2 7) (11 7)
2
xx ? ? ?
4x + 14 = 11x + 7
? ? ?
? ? ?
4 11 7 14
77
xx
x
i.e. x = 1
Ten’s digit of the two-digit number is x = 1.
Unit’s digit of the two-digit number = x + 7 = 1 + 7 = 8
Thus, the required number is 18.
23. Let the required number be x. Then,
26% of x = 65
Page 5
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
CBSE
Class VIII Mathematics
Sample Paper – 3 Solution
Time: 3 hours Total Marks: 80
Section A
1. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
2. Correct answer: B
20
20% of x=
100 5
x
x ?
3. Correct answer: A
Five vertices.
4. Correct option : A
?
196 2
484
?
1
7
2
?
?
1
7
11
11
5. Correct answer: B
0 and 1
6. Correct answer: A
1
3
= 1
Thus, the natural number 1 is equal to its cube.
7. Correct answer: D
A rational number is a number of the form
p
q
where q? 0. So, in case of reciprocal of 0,
denominator will be 0.
8. Correct option: A
6 17 29
2
12 34 29
17 34
2
k
k
kk
k
k
?
?
? ? ?
??
??
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
9. Correct answer: C
The given shape has 12 edges.
10. Correct answer: D
Sales tax =
4
380 15.20
100
??
11. Correct option: C
? ? ? ? ? ? ? ? ?
22
484 2 2 11 11 2 11 2 11 22
12. Correct option: B
?
?
? ? ?
14 441
22
22 441
.693
14
x
x Rs
Section B
(Questions 8 to 11 carry 2 marks each)
13. The number
2
5
lies between 0 and 1.
Draw a number line. Mark points O and A to represent 0 and 1, respectively.
Divide OA into 5 equal parts (equal to the denominator of
2
5
).The second point, Q,
represents the rational number
2
5
.
14. Steps of construction:
a) Draw AC = 8 cm.
b) Draw perpendicular bisector XY of AC meeting AC at O.
c) From O cut off OD =
1
2
× 6 cm = 3 cm along OX and OB =
1
2
× 6 cm =3 cm along OY.
d) Join AB, BC, CD and DA.
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
ABCD is the required rhombus.
15. We have,
Number of vertices (V) = 8
Number of edges (E) = 12
Let, number of faces = F
Since every polyhedron satisfy Euler's formula, therefore
F + V = E + 2
Or, F + 8 = 12 + 2
Or, F = 14 - 8 = 6
Hence, the number of faces are 6.
16. We have:
(a + b)
2
= a
2
+ b
2
+ 2abTaking, a = -20 and b = -5, we get
(-25)
2
= {-20 + (-5)}
2
= (-20)
2
+ (-5)
2
+ 2(-20)(-5)
= 400 + 25 + 200 = 625
17. From the graph, it is clear that 5 students favoured orange and 1 student favoured
green.
Now, 5 – 1 = 4
Therefore, 4 more students favoured orange colour than green.
18. Since ABCD is an isosceles trapezoidal, we have AD = BC
Therefore, AD = BC = 4 cm.
Now the perimeter of given trapezium
= AB + BC + CD + DA
= 12 + 4 + 8 + 4
= 28
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
Hence, the perimeter of the given trapezium is 28 cm.
19. Original price of the book = Rs. 50
Increased % = 6%
Thus, New Price = Original Price + 6% of Original price
New price = Rs.
6
50 50 .(50 3) .53
100
Rs Rs ? ? ? ? ?
20. Area of square = (5a – 2b)
2
We use the identity (x – y )
2
= x
2
– 2xy + y
2
Taking, x = 5a and y = 2b
We get, (5a – 2b)
2
= (5a)
2
– 2(5a)(2b ) + (2b)=25a
2
– 20ab + 4b
2
21. 82
2
= (80 + 2)
2
In the property (a + b)
2
= a
2
+ b
2
+ 2ab, putting a = 80 and b = 2, we get:
(80 + 2)
2
= 80
2
+ 2
2
+ 2 × 80 × 2
= 6400 + 4 + 320
= 6724
22. Let x be the ten’s digit of the two-digit number.
Then its unit's digit = x + 7.
Number = unit’s digit + 10(ten’s digit) = (x + 7) + 10(x) = 11x + 7.
Sum of the digits = (x + 7) + (x) = 2x + 7.
Given, sum of the digits is half of the whole number.
Therefore,
1
(2 7) (11 7)
2
xx ? ? ?
4x + 14 = 11x + 7
? ? ?
? ? ?
4 11 7 14
77
xx
x
i.e. x = 1
Ten’s digit of the two-digit number is x = 1.
Unit’s digit of the two-digit number = x + 7 = 1 + 7 = 8
Thus, the required number is 18.
23. Let the required number be x. Then,
26% of x = 65
CBSE VIII | Mathematics
Sample Paper – 3 Solutions
26
65
100
100
65
26
250
x
x
x
??
??
? ? ?
??
??
??
Hence, the required number is 250.
24.
(by commutativity)
(by distributivity)
Section C
25. Here, at unit's place A × 5 = A
That is we need to search for a number, which when multiplied to 5 gives the same unit
place.
Such a number is 5 or 0, as 5 × 5 = 25 or 0 × 5 = 0
Case (1) Taking 5 in place of A, we get
2
B A
5
C B 5
?
Here, B can take the value 2, which satisfy the condition, taking, B = 2, we get
2
2 5
5
1 2 5
?
Thus, A = 5, B = 2 and C = 1
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FAQs on Class 8 Math: CBSE Sample Question Paper Solutions Term I – 3 - Mathematics (Maths) Class 8
| 1. What is the format of the CBSE Class 8 Math Sample Question Paper for Term I? |  |
Ans. The CBSE Class 8 Math Sample Question Paper for Term I typically follows the format of multiple-choice questions, short answer questions, and long answer questions. It is designed to assess the students' understanding of various mathematical concepts.
| 2. How can I prepare for the CBSE Class 8 Math Term I exam? | |
Ans. To prepare for the CBSE Class 8 Math Term I exam, it is important to thoroughly study the textbook and practice solving a variety of mathematical problems. Additionally, reviewing previous years' question papers and participating in mock tests can help in familiarizing oneself with the exam pattern and improving time management skills.
| 3. Are there any specific topics that are frequently asked in the CBSE Class 8 Math Term I exam? | |
Ans. While the CBSE Class 8 Math Term I exam covers a wide range of topics, certain concepts are often emphasized and frequently asked. These include rational numbers, linear equations, exponents and powers, quadrilaterals, practical geometry, and data handling. It is advisable to focus on these topics while preparing for the exam.
| 4. How can I improve my problem-solving skills for the CBSE Class 8 Math Term I exam? | |
Ans. Improving problem-solving skills for the CBSE Class 8 Math Term I exam requires regular practice. It is important to understand the concepts thoroughly and apply them to solve different types of problems. Working on sample question papers, solving puzzles and brain teasers, and seeking help from teachers or classmates can also help in enhancing problem-solving abilities.
| 5. Are there any online resources available for practicing CBSE Class 8 Math Term I sample papers? | |
Ans. Yes, there are several online platforms and websites that provide CBSE Class 8 Math Term I sample papers for practice. Some popular resources include the official CBSE website, educational websites, and online learning platforms. These resources offer a wide range of sample papers, solutions, and additional practice material to help students prepare effectively for the exam.
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