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G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s .
W r i t e 	 a n s w e r s 	 n e a t l y 	 a n d 	 l e g i b l y .
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
M a r k s 	 f o r 	 e a c h 	 q u e s t i o n 	 a r e 	 i n d i c a t e d 	 a g a i n s t 	 i t .
1 . 	 a . 	 T h e 	 s t a n d a r d 	 f o r m 	 o f 	 	 i s 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 I 	 t h i n k 	 o f 	 a 	 n u m b e r 	 a n d 	 s u b t r a c t 	 5 	 f r o m 	 f o u r 	 t i m e s 	 t h e 	 n u m b e r . 	 T h e 	 r e s u l t 	 i s 	 3 	 m o r e
t h a n 	 t w i c e 	 t h e 	 n u m b e r 	 t h a t 	 I 	 t h o u g h t 	 o f . 	 T h e 	 n u m b e r 	 i s 	 _ _ _ _ _ _ _ _ _ 	 . ( 1 )
S o l . 	 ( a ) 	
( b ) 	 4
2 . 	 a . 	 ( 2
- 1
	 + 3
- 1
	 + 	 4
- 1
	 + 	 5
- 1
) 0 	 = 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 D i a m e t e r 	 o f 	 t h e 	 s u n 	 i s 	 1 4 0 0 0 	 × 	 1 0
5
m , 	 t h e 	 d i a m e t e r 	 i n 	 s t a n d a r d 	 f o r m 	 i s 	 _ _ _ _ _ _ _ _ _ . ( 1 )
S o l . 	 ( a ) 	 1
( b ) 	 1 . 4 	 × 	 1 0
9
3 . 	 F i n d 	 t h e 	 a r e a 	 o f 	 a 	 r e c t a n g u l a r 	 b o a r d 	 w h i c h 	 i s 	 m 	 l o n g 	 a n d 	 m 	 w i d e . 	 ( 2 )
S o l . 	 L e n g t h 	 o f 	 b o a r d 	
Page 2


G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s .
W r i t e 	 a n s w e r s 	 n e a t l y 	 a n d 	 l e g i b l y .
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
M a r k s 	 f o r 	 e a c h 	 q u e s t i o n 	 a r e 	 i n d i c a t e d 	 a g a i n s t 	 i t .
1 . 	 a . 	 T h e 	 s t a n d a r d 	 f o r m 	 o f 	 	 i s 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 I 	 t h i n k 	 o f 	 a 	 n u m b e r 	 a n d 	 s u b t r a c t 	 5 	 f r o m 	 f o u r 	 t i m e s 	 t h e 	 n u m b e r . 	 T h e 	 r e s u l t 	 i s 	 3 	 m o r e
t h a n 	 t w i c e 	 t h e 	 n u m b e r 	 t h a t 	 I 	 t h o u g h t 	 o f . 	 T h e 	 n u m b e r 	 i s 	 _ _ _ _ _ _ _ _ _ 	 . ( 1 )
S o l . 	 ( a ) 	
( b ) 	 4
2 . 	 a . 	 ( 2
- 1
	 + 3
- 1
	 + 	 4
- 1
	 + 	 5
- 1
) 0 	 = 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 D i a m e t e r 	 o f 	 t h e 	 s u n 	 i s 	 1 4 0 0 0 	 × 	 1 0
5
m , 	 t h e 	 d i a m e t e r 	 i n 	 s t a n d a r d 	 f o r m 	 i s 	 _ _ _ _ _ _ _ _ _ . ( 1 )
S o l . 	 ( a ) 	 1
( b ) 	 1 . 4 	 × 	 1 0
9
3 . 	 F i n d 	 t h e 	 a r e a 	 o f 	 a 	 r e c t a n g u l a r 	 b o a r d 	 w h i c h 	 i s 	 m 	 l o n g 	 a n d 	 m 	 w i d e . 	 ( 2 )
S o l . 	 L e n g t h 	 o f 	 b o a r d 	
W i d t h 	 o f 	 b o a r d 	 	
4 . 	 B y 	 w h a t 	 n u m b e r 	 s h o u l d 	 	 b e 	 m u l t i p l i e d 	 t o 	 g e t 	 t h e 	 p r o d u c t 	 a s 	 ? 	 ( 2 )
S o l . 	 L e t 	 	 b e 	 m u l t i p l i e d 	 b y 	 x
	 	 	 	 	 	 	 	
	 S h o u l d 	 b e 	 m u l t i p l i e d 	 b y 	 	 t o 	 g e t 	
5 . 	 F i n d 	 6 	 r a t i o n a l 	 n u m b e r s 	 b e t w e e n 	 	 a n d 	 	 ( 3 )
S o l . 	
6 	 R a t i o n a l 	 n u m b e r s 	 b e t w e e n 	 - 3 	 a n d 	 5 	 a r e 	 	 ( a n y 	 6 ) 	 ( 3 )
a . 	 S o l v e 	 f o r 	 x 	 : 	 3
3 x + 3
	 = 	 9
x + 4
.
Page 3


G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s .
W r i t e 	 a n s w e r s 	 n e a t l y 	 a n d 	 l e g i b l y .
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
M a r k s 	 f o r 	 e a c h 	 q u e s t i o n 	 a r e 	 i n d i c a t e d 	 a g a i n s t 	 i t .
1 . 	 a . 	 T h e 	 s t a n d a r d 	 f o r m 	 o f 	 	 i s 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 I 	 t h i n k 	 o f 	 a 	 n u m b e r 	 a n d 	 s u b t r a c t 	 5 	 f r o m 	 f o u r 	 t i m e s 	 t h e 	 n u m b e r . 	 T h e 	 r e s u l t 	 i s 	 3 	 m o r e
t h a n 	 t w i c e 	 t h e 	 n u m b e r 	 t h a t 	 I 	 t h o u g h t 	 o f . 	 T h e 	 n u m b e r 	 i s 	 _ _ _ _ _ _ _ _ _ 	 . ( 1 )
S o l . 	 ( a ) 	
( b ) 	 4
2 . 	 a . 	 ( 2
- 1
	 + 3
- 1
	 + 	 4
- 1
	 + 	 5
- 1
) 0 	 = 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 D i a m e t e r 	 o f 	 t h e 	 s u n 	 i s 	 1 4 0 0 0 	 × 	 1 0
5
m , 	 t h e 	 d i a m e t e r 	 i n 	 s t a n d a r d 	 f o r m 	 i s 	 _ _ _ _ _ _ _ _ _ . ( 1 )
S o l . 	 ( a ) 	 1
( b ) 	 1 . 4 	 × 	 1 0
9
3 . 	 F i n d 	 t h e 	 a r e a 	 o f 	 a 	 r e c t a n g u l a r 	 b o a r d 	 w h i c h 	 i s 	 m 	 l o n g 	 a n d 	 m 	 w i d e . 	 ( 2 )
S o l . 	 L e n g t h 	 o f 	 b o a r d 	
W i d t h 	 o f 	 b o a r d 	 	
4 . 	 B y 	 w h a t 	 n u m b e r 	 s h o u l d 	 	 b e 	 m u l t i p l i e d 	 t o 	 g e t 	 t h e 	 p r o d u c t 	 a s 	 ? 	 ( 2 )
S o l . 	 L e t 	 	 b e 	 m u l t i p l i e d 	 b y 	 x
	 	 	 	 	 	 	 	
	 S h o u l d 	 b e 	 m u l t i p l i e d 	 b y 	 	 t o 	 g e t 	
5 . 	 F i n d 	 6 	 r a t i o n a l 	 n u m b e r s 	 b e t w e e n 	 	 a n d 	 	 ( 3 )
S o l . 	
6 	 R a t i o n a l 	 n u m b e r s 	 b e t w e e n 	 - 3 	 a n d 	 5 	 a r e 	 	 ( a n y 	 6 ) 	 ( 3 )
a . 	 S o l v e 	 f o r 	 x 	 : 	 3
3 x + 3
	 = 	 9
x + 4
.
b . 	 F i n d 	 t h e 	 v a l u e 	 o f 	
S o l . 	 ( a ) 	 3
3 x + 3
	 = 	 ( 3
2
)
x + 4
3
3 x + 3
	 = 	 3
2 x + 8
A s 	 b a s e s 	 a r e 	 s a m e 	 e q u a t i o n 	 p o w e r s
3 x 	 + 	 3 	 = 	 2 x 	 + 	 8
( b ) 	 	 	 	 	 	 	 	 	 	
	 	 	 	 	 	 	 	 	
7 . 	 R e e n a 	 w a n t s 	 t o 	 d i s t r i b u t e 	 c h o c o l a t e s 	 o n 	 h e r 	 b i r t h d a y 	 t o 	 c h i l d r e n 	 s t a y i n g 	 i n 	 a n
o r p h a n a g e 	 s o 	 t h a t 	 t h e y 	 a l s o 	 f e e l 	 g o o d . 	 I f 	 t h e 	 c o s t 	 o f 	 a 	 c h o c o l a t e 	 i s 	 ` 1 0 	 a n d 	 t h e r e 	 a r e 	 5 0
c h i l d r e n , 	 h o w 	 m u c h 	 m o n e y 	 w o u l d 	 s h e 	 n e e d , 	 i f 	 s h e 	 g i v e s 	 2 	 c h o c o l a t e s 	 t o 	 e a c h 	 c h i l d ?
E x p l a i n 	 a n y 	 t w o 	 v a l u e s 	 s h o w n 	 b y 	 h e r . 	 ( 3 )
S o l . 	 N u m b e r 	 o f 	 c h i l d r e n 	 = 	 5 0
C h o c o l a t e 	 g i v e n 	 t o 	 e a c h 	 c h i l d r e n 	 = 	 2
T o t a l 	 c h o c o l a t e 	 r e q u i r e d 	 = 	 1 0 0
C o s t 	 o f 	 1 0 0 	 c h o c o l a t e s 	 = 	 1 0 0 	 × 	 1 0 	 = 	 R s 1 0 0 0
V a l u e s : 	 A n y 	 t w o
8 . 	 a . 	 F i n d 	 t h e 	 v a l u e 	 o f 	 x 	 s u c h 	 t h a t 	 ( 3
- 1
	 + 	 6
- 1
	 + 	 9
- 1
	 + 	 1 2
- 1
)
x
	 	 ( 3 )
b . 	 1 	 m i c r o n 	 i s 	 e q u a l 	 t o 	 m . 	 E x p r e s s 	 t h i s 	 s t a t e m e n t 	 i n 	 s t a n d a r d 	 f o r m .
Page 4


G e n e r a l 	 I n s t r u c t i o n :
T h i s 	 q u e s t i o n 	 p a p e r 	 c o n t a i n s 	 8 	 q u e s t i o n s .
W r i t e 	 a n s w e r s 	 n e a t l y 	 a n d 	 l e g i b l y .
A l l 	 t h e 	 q u e s t i o n s 	 a r e 	 c o m p u l s o r y .
M a r k s 	 f o r 	 e a c h 	 q u e s t i o n 	 a r e 	 i n d i c a t e d 	 a g a i n s t 	 i t .
1 . 	 a . 	 T h e 	 s t a n d a r d 	 f o r m 	 o f 	 	 i s 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 I 	 t h i n k 	 o f 	 a 	 n u m b e r 	 a n d 	 s u b t r a c t 	 5 	 f r o m 	 f o u r 	 t i m e s 	 t h e 	 n u m b e r . 	 T h e 	 r e s u l t 	 i s 	 3 	 m o r e
t h a n 	 t w i c e 	 t h e 	 n u m b e r 	 t h a t 	 I 	 t h o u g h t 	 o f . 	 T h e 	 n u m b e r 	 i s 	 _ _ _ _ _ _ _ _ _ 	 . ( 1 )
S o l . 	 ( a ) 	
( b ) 	 4
2 . 	 a . 	 ( 2
- 1
	 + 3
- 1
	 + 	 4
- 1
	 + 	 5
- 1
) 0 	 = 	 _ _ _ _ _ _ _ _ _ _ . 	 ( 1 )
b . 	 D i a m e t e r 	 o f 	 t h e 	 s u n 	 i s 	 1 4 0 0 0 	 × 	 1 0
5
m , 	 t h e 	 d i a m e t e r 	 i n 	 s t a n d a r d 	 f o r m 	 i s 	 _ _ _ _ _ _ _ _ _ . ( 1 )
S o l . 	 ( a ) 	 1
( b ) 	 1 . 4 	 × 	 1 0
9
3 . 	 F i n d 	 t h e 	 a r e a 	 o f 	 a 	 r e c t a n g u l a r 	 b o a r d 	 w h i c h 	 i s 	 m 	 l o n g 	 a n d 	 m 	 w i d e . 	 ( 2 )
S o l . 	 L e n g t h 	 o f 	 b o a r d 	
W i d t h 	 o f 	 b o a r d 	 	
4 . 	 B y 	 w h a t 	 n u m b e r 	 s h o u l d 	 	 b e 	 m u l t i p l i e d 	 t o 	 g e t 	 t h e 	 p r o d u c t 	 a s 	 ? 	 ( 2 )
S o l . 	 L e t 	 	 b e 	 m u l t i p l i e d 	 b y 	 x
	 	 	 	 	 	 	 	
	 S h o u l d 	 b e 	 m u l t i p l i e d 	 b y 	 	 t o 	 g e t 	
5 . 	 F i n d 	 6 	 r a t i o n a l 	 n u m b e r s 	 b e t w e e n 	 	 a n d 	 	 ( 3 )
S o l . 	
6 	 R a t i o n a l 	 n u m b e r s 	 b e t w e e n 	 - 3 	 a n d 	 5 	 a r e 	 	 ( a n y 	 6 ) 	 ( 3 )
a . 	 S o l v e 	 f o r 	 x 	 : 	 3
3 x + 3
	 = 	 9
x + 4
.
b . 	 F i n d 	 t h e 	 v a l u e 	 o f 	
S o l . 	 ( a ) 	 3
3 x + 3
	 = 	 ( 3
2
)
x + 4
3
3 x + 3
	 = 	 3
2 x + 8
A s 	 b a s e s 	 a r e 	 s a m e 	 e q u a t i o n 	 p o w e r s
3 x 	 + 	 3 	 = 	 2 x 	 + 	 8
( b ) 	 	 	 	 	 	 	 	 	 	
	 	 	 	 	 	 	 	 	
7 . 	 R e e n a 	 w a n t s 	 t o 	 d i s t r i b u t e 	 c h o c o l a t e s 	 o n 	 h e r 	 b i r t h d a y 	 t o 	 c h i l d r e n 	 s t a y i n g 	 i n 	 a n
o r p h a n a g e 	 s o 	 t h a t 	 t h e y 	 a l s o 	 f e e l 	 g o o d . 	 I f 	 t h e 	 c o s t 	 o f 	 a 	 c h o c o l a t e 	 i s 	 ` 1 0 	 a n d 	 t h e r e 	 a r e 	 5 0
c h i l d r e n , 	 h o w 	 m u c h 	 m o n e y 	 w o u l d 	 s h e 	 n e e d , 	 i f 	 s h e 	 g i v e s 	 2 	 c h o c o l a t e s 	 t o 	 e a c h 	 c h i l d ?
E x p l a i n 	 a n y 	 t w o 	 v a l u e s 	 s h o w n 	 b y 	 h e r . 	 ( 3 )
S o l . 	 N u m b e r 	 o f 	 c h i l d r e n 	 = 	 5 0
C h o c o l a t e 	 g i v e n 	 t o 	 e a c h 	 c h i l d r e n 	 = 	 2
T o t a l 	 c h o c o l a t e 	 r e q u i r e d 	 = 	 1 0 0
C o s t 	 o f 	 1 0 0 	 c h o c o l a t e s 	 = 	 1 0 0 	 × 	 1 0 	 = 	 R s 1 0 0 0
V a l u e s : 	 A n y 	 t w o
8 . 	 a . 	 F i n d 	 t h e 	 v a l u e 	 o f 	 x 	 s u c h 	 t h a t 	 ( 3
- 1
	 + 	 6
- 1
	 + 	 9
- 1
	 + 	 1 2
- 1
)
x
	 	 ( 3 )
b . 	 1 	 m i c r o n 	 i s 	 e q u a l 	 t o 	 m . 	 E x p r e s s 	 t h i s 	 s t a t e m e n t 	 i n 	 s t a n d a r d 	 f o r m .
S o l . 	 ( a ) 	 	 	 	 	 	 	 	 	 	 	
	 	 	 	 	 	 	 	 	 	 	 	
	
( b ) 	 1 0
- 6
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FAQs on Class 8 Math: CBSE Past Year Paper - 6 - Mathematics (Maths) Class 8

1. What is the CBSE Class 8 Math Past Year Paper - 6?
Ans. The CBSE Class 8 Math Past Year Paper - 6 is a question paper that was given in a previous year's examination for Class 8 students studying under the Central Board of Secondary Education (CBSE).
2. Where can I find the CBSE Class 8 Math Past Year Paper - 6?
Ans. You can find the CBSE Class 8 Math Past Year Paper - 6 on various online platforms, educational websites, or even on the official website of CBSE. These papers are often available for free download or can be purchased from bookstores.
3. Can solving CBSE Class 8 Math Past Year Paper - 6 help in exam preparation?
Ans. Yes, solving CBSE Class 8 Math Past Year Paper - 6 can be extremely beneficial for exam preparation. It allows students to familiarize themselves with the exam pattern, marking scheme, and types of questions asked in previous years. It also helps in identifying weak areas and provides an opportunity to practice solving problems within a time limit.
4. Are the questions in CBSE Class 8 Math Past Year Paper - 6 similar to the actual exam?
Ans. The questions in CBSE Class 8 Math Past Year Paper - 6 are designed to be similar to the ones asked in the actual exam. While the specific questions may differ, the paper aims to assess the same concepts and topics as prescribed in the CBSE Class 8 Math curriculum. Solving these papers can give students a good idea of the level of difficulty and the type of questions they can expect in the exam.
5. How can I use CBSE Class 8 Math Past Year Paper - 6 effectively for revision?
Ans. To use CBSE Class 8 Math Past Year Paper - 6 effectively for revision, start by attempting the paper under exam conditions, i.e., within the given time limit. Once done, evaluate your answers and identify the mistakes or areas where you struggled. Focus on understanding the concepts behind those questions and work on improving your problem-solving skills. Repeat this process with other past year papers to gain confidence and strengthen your preparation for the actual exam.
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