JEE Exam > JEE Notes > Mathematics (Maths) Class 12 > CBSE Past Year Paper Session (2016) Solutions, Math Class 12
CBSE Past Year Paper Session (2016) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
CBSE XII | Mathematics
Board Paper 2016 – Solution
CBSE Board
Class XII Mathematics
Board Paper – 2016 Solution
SECTION – A
1. Consider the given matrix
T
2
cos sin
A0
2 sin cos
A A 2 I
cos sin cos sin 1 0
2
sin cos sin cos 0 1
2cos 0 2 0
0 2cos
02
2cos 2
21
cos
2
2
4
?? ?? ?
? ? ? ?
??
? ? ?
??
??
? ? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ? ?
??
? ??
???
??
?
????
??
??
? ? ?
?
??
2. |3 A | = k |A|
|3 A | = 27|A|
k = 27
3. for unique solution |A| ? 0
2 2 1 3 3 1
1
1 1 1
2 1 -1 0
3 2 k
C C C ; C C C
1 0 0
2 -1 -3 0
3 -1 k-3
expansion along R
(k 3) 3 0
k 3 3 0
k0
?
? ? ? ?
?
? ? ? ?
? ? ? ?
?
Page 2
CBSE XII | Mathematics
Board Paper 2016 – Solution
CBSE Board
Class XII Mathematics
Board Paper – 2016 Solution
SECTION – A
1. Consider the given matrix
T
2
cos sin
A0
2 sin cos
A A 2 I
cos sin cos sin 1 0
2
sin cos sin cos 0 1
2cos 0 2 0
0 2cos
02
2cos 2
21
cos
2
2
4
?? ?? ?
? ? ? ?
??
? ? ?
??
??
? ? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ? ?
??
? ??
???
??
?
????
??
??
? ? ?
?
??
2. |3 A | = k |A|
|3 A | = 27|A|
k = 27
3. for unique solution |A| ? 0
2 2 1 3 3 1
1
1 1 1
2 1 -1 0
3 2 k
C C C ; C C C
1 0 0
2 -1 -3 0
3 -1 k-3
expansion along R
(k 3) 3 0
k 3 3 0
k0
?
? ? ? ?
?
? ? ? ?
? ? ? ?
?
CBSE XII | Mathematics
Board Paper 2016 – Solution
4. r (2i j k) 5 0
? ? ?
? ? ?
?
??
?
??
??
? ? ?
? ? ? ?
? ? ?
in Cartesian form
2x + y - z - 5=0
2x + y - z = 5
2x y z
1
5 5 5
x y z
1
5/2 5 5
5
Intercept cutt of on the axes ,5, 5
2
x y z
1
a b c
5
a b 5 c 5
2
a b c 5/2
5. (i 3j 9k) (3i j k) 0
n
n
i j k
1 3 9 0
3
i(3 9 ) j( 27) k( 9) 0
3 9 0 ...(1)
27 0 ...(2)
9 0 ...(3)
by eq (2) & (3) 27 and 9
, value satisfy the eq (1)
So 27, 9
6. a 4i j k, b 2i 2j k
a b (4i j k) (2i 2j k)
6i 3j 2k
ab
unit vector parallel to (a b)=
ab
6i 3j 2k
36 9 4
6i 3j 2k
49
6 3 2
i j k
7 7 7
Page 3
CBSE XII | Mathematics
Board Paper 2016 – Solution
CBSE Board
Class XII Mathematics
Board Paper – 2016 Solution
SECTION – A
1. Consider the given matrix
T
2
cos sin
A0
2 sin cos
A A 2 I
cos sin cos sin 1 0
2
sin cos sin cos 0 1
2cos 0 2 0
0 2cos
02
2cos 2
21
cos
2
2
4
?? ?? ?
? ? ? ?
??
? ? ?
??
??
? ? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ? ?
??
? ??
???
??
?
????
??
??
? ? ?
?
??
2. |3 A | = k |A|
|3 A | = 27|A|
k = 27
3. for unique solution |A| ? 0
2 2 1 3 3 1
1
1 1 1
2 1 -1 0
3 2 k
C C C ; C C C
1 0 0
2 -1 -3 0
3 -1 k-3
expansion along R
(k 3) 3 0
k 3 3 0
k0
?
? ? ? ?
?
? ? ? ?
? ? ? ?
?
CBSE XII | Mathematics
Board Paper 2016 – Solution
4. r (2i j k) 5 0
? ? ?
? ? ?
?
??
?
??
??
? ? ?
? ? ? ?
? ? ?
in Cartesian form
2x + y - z - 5=0
2x + y - z = 5
2x y z
1
5 5 5
x y z
1
5/2 5 5
5
Intercept cutt of on the axes ,5, 5
2
x y z
1
a b c
5
a b 5 c 5
2
a b c 5/2
5. (i 3j 9k) (3i j k) 0
n
n
i j k
1 3 9 0
3
i(3 9 ) j( 27) k( 9) 0
3 9 0 ...(1)
27 0 ...(2)
9 0 ...(3)
by eq (2) & (3) 27 and 9
, value satisfy the eq (1)
So 27, 9
6. a 4i j k, b 2i 2j k
a b (4i j k) (2i 2j k)
6i 3j 2k
ab
unit vector parallel to (a b)=
ab
6i 3j 2k
36 9 4
6i 3j 2k
49
6 3 2
i j k
7 7 7
CBSE XII | Mathematics
Board Paper 2016 – Solution
SECTION – B
7.
? ? ? ?
? ? ? ?
? ? ? ? ?
1 1 1 1
Given that tan x 1 tan x tan x 1 tan 3x
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ? ? ?
??
??
? ? ?
?
?
? ? ? ? ? ?
? ??
??
??
?
??
? ??
??
??
?
??
??
? ? ?
? ? ? ?
??
??
? ? ?
??
??
??
?
??
??
??
?
1 1 1 1
-1 1 1
-1 1 1
1 1 1
1
2
tan x 1 tan x 1 tan 3x tan x...(1)
AB
We know that, tan A tan B tan
1 AB
AB
and tan A tan B tan
1 AB
x 1 x 1
Thus, tan x 1 tan x 1 tan
1 x 1 x 1
2x
tan
1 x 1
tan
??
??
?
??
1
2
2x
....(2)
2x
? ?
1 1 1
1
2
11
22
22
22
22
2
2
3x x
Similarly,tan 3x tan x tan
1 3x x
2x
tan ....(3)
1 3x
From equations (1), (2) and (3), we have,
2x 2x
tan tan
2 x 1 3x
2x 2x
2 x 1 3x
11
2 x 1 3x
2 x 1 3x
4x 1
1
x
? ? ?
?
??
??
?
?? ??
??
?
??
??
?
??
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ?
??
??
??
??
? ? ? ?
??
??
4
1
x
2
? ? ?
Page 4
CBSE XII | Mathematics
Board Paper 2016 – Solution
CBSE Board
Class XII Mathematics
Board Paper – 2016 Solution
SECTION – A
1. Consider the given matrix
T
2
cos sin
A0
2 sin cos
A A 2 I
cos sin cos sin 1 0
2
sin cos sin cos 0 1
2cos 0 2 0
0 2cos
02
2cos 2
21
cos
2
2
4
?? ?? ?
? ? ? ?
??
? ? ?
??
??
? ? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ? ?
??
? ??
???
??
?
????
??
??
? ? ?
?
??
2. |3 A | = k |A|
|3 A | = 27|A|
k = 27
3. for unique solution |A| ? 0
2 2 1 3 3 1
1
1 1 1
2 1 -1 0
3 2 k
C C C ; C C C
1 0 0
2 -1 -3 0
3 -1 k-3
expansion along R
(k 3) 3 0
k 3 3 0
k0
?
? ? ? ?
?
? ? ? ?
? ? ? ?
?
CBSE XII | Mathematics
Board Paper 2016 – Solution
4. r (2i j k) 5 0
? ? ?
? ? ?
?
??
?
??
??
? ? ?
? ? ? ?
? ? ?
in Cartesian form
2x + y - z - 5=0
2x + y - z = 5
2x y z
1
5 5 5
x y z
1
5/2 5 5
5
Intercept cutt of on the axes ,5, 5
2
x y z
1
a b c
5
a b 5 c 5
2
a b c 5/2
5. (i 3j 9k) (3i j k) 0
n
n
i j k
1 3 9 0
3
i(3 9 ) j( 27) k( 9) 0
3 9 0 ...(1)
27 0 ...(2)
9 0 ...(3)
by eq (2) & (3) 27 and 9
, value satisfy the eq (1)
So 27, 9
6. a 4i j k, b 2i 2j k
a b (4i j k) (2i 2j k)
6i 3j 2k
ab
unit vector parallel to (a b)=
ab
6i 3j 2k
36 9 4
6i 3j 2k
49
6 3 2
i j k
7 7 7
CBSE XII | Mathematics
Board Paper 2016 – Solution
SECTION – B
7.
? ? ? ?
? ? ? ?
? ? ? ? ?
1 1 1 1
Given that tan x 1 tan x tan x 1 tan 3x
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ? ? ?
??
??
? ? ?
?
?
? ? ? ? ? ?
? ??
??
??
?
??
? ??
??
??
?
??
??
? ? ?
? ? ? ?
??
??
? ? ?
??
??
??
?
??
??
??
?
1 1 1 1
-1 1 1
-1 1 1
1 1 1
1
2
tan x 1 tan x 1 tan 3x tan x...(1)
AB
We know that, tan A tan B tan
1 AB
AB
and tan A tan B tan
1 AB
x 1 x 1
Thus, tan x 1 tan x 1 tan
1 x 1 x 1
2x
tan
1 x 1
tan
??
??
?
??
1
2
2x
....(2)
2x
? ?
1 1 1
1
2
11
22
22
22
22
2
2
3x x
Similarly,tan 3x tan x tan
1 3x x
2x
tan ....(3)
1 3x
From equations (1), (2) and (3), we have,
2x 2x
tan tan
2 x 1 3x
2x 2x
2 x 1 3x
11
2 x 1 3x
2 x 1 3x
4x 1
1
x
? ? ?
?
??
??
?
?? ??
??
?
??
??
?
??
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ?
??
??
??
??
? ? ? ?
??
??
4
1
x
2
? ? ?
CBSE XII | Mathematics
Board Paper 2016 – Solution
OR
? ? ? ?
?
??
?? ? ??
?
??
??
??
??
??
? ??
??
??
?
??
??
?
??
?
? ??
?
?
?? ? ??
? ?
????
?
??
??
?? ??
3
-1 1
22
-1 1 1
3
22
-1
3
22
Consider the left hand side
6x 8x 4x
L.H.S=tan tan
1 12x 1 4x
We know that,
AB
tan A tan B tan
1 AB
6x 8x 4x
1 12x 1 4x
Thus, L.H.S tan
6x 8x 4x
1
1 12x 1 4x
? ? ? ? ? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ?
? ? ? ?
? ? ? ? ? ?
? ? ? ?
? ? ? ? ? ?
? ? ? ?
?
?
?
?
??
? ? ? ?
??
?? ??
???
?
??
?
??
??
??
??
??
? ? ? ?
??
?? ??
???
? ? ? ?
??
??
??
??
??
? ? ? ?
?
? ? ?
3 2 2
22
-1
3
22
3 2 2
22
-1
2 2 3
22
3 2 2
-1
22
6x 8x 1 4x 4x 1 12x
1 12x 1 4x
tan
4x 6x 8x
1
1 12x 1 4x
6x 8x 1 4x 4x 1 12x
1 12x 1 4x
tan
1 12x 1 4x 4x 6x 8x
1 12x 1 4x
6x 8x 1 4x 4x 1 12x
tan
1 12x 1 4x
? ?
??
??
??
?
??
?? ? ? ? ? ?
?
??
? ? ? ? ?
??
?? ??
?
??
??
??
3
3 3 5 3
-1
2 2 4 2 4
53
-1
42
4x 6x 8x
6x 24x 8x 32x 4x 48x
tan
1 4x 12x 48x 24x 32x
32x 16x 2x
tan
16x 8x 1
? ?
??
??
??
?
?? ??
??
?
42
-1
42
-1
2x 16x 8x 1
tan
16x 8x 1
tan 2x
Thus, L.H.S=R.H.S
Page 5
CBSE XII | Mathematics
Board Paper 2016 – Solution
CBSE Board
Class XII Mathematics
Board Paper – 2016 Solution
SECTION – A
1. Consider the given matrix
T
2
cos sin
A0
2 sin cos
A A 2 I
cos sin cos sin 1 0
2
sin cos sin cos 0 1
2cos 0 2 0
0 2cos
02
2cos 2
21
cos
2
2
4
?? ?? ?
? ? ? ?
??
? ? ?
??
??
? ? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ? ?
??
? ??
???
??
?
????
??
??
? ? ?
?
??
2. |3 A | = k |A|
|3 A | = 27|A|
k = 27
3. for unique solution |A| ? 0
2 2 1 3 3 1
1
1 1 1
2 1 -1 0
3 2 k
C C C ; C C C
1 0 0
2 -1 -3 0
3 -1 k-3
expansion along R
(k 3) 3 0
k 3 3 0
k0
?
? ? ? ?
?
? ? ? ?
? ? ? ?
?
CBSE XII | Mathematics
Board Paper 2016 – Solution
4. r (2i j k) 5 0
? ? ?
? ? ?
?
??
?
??
??
? ? ?
? ? ? ?
? ? ?
in Cartesian form
2x + y - z - 5=0
2x + y - z = 5
2x y z
1
5 5 5
x y z
1
5/2 5 5
5
Intercept cutt of on the axes ,5, 5
2
x y z
1
a b c
5
a b 5 c 5
2
a b c 5/2
5. (i 3j 9k) (3i j k) 0
n
n
i j k
1 3 9 0
3
i(3 9 ) j( 27) k( 9) 0
3 9 0 ...(1)
27 0 ...(2)
9 0 ...(3)
by eq (2) & (3) 27 and 9
, value satisfy the eq (1)
So 27, 9
6. a 4i j k, b 2i 2j k
a b (4i j k) (2i 2j k)
6i 3j 2k
ab
unit vector parallel to (a b)=
ab
6i 3j 2k
36 9 4
6i 3j 2k
49
6 3 2
i j k
7 7 7
CBSE XII | Mathematics
Board Paper 2016 – Solution
SECTION – B
7.
? ? ? ?
? ? ? ?
? ? ? ? ?
1 1 1 1
Given that tan x 1 tan x tan x 1 tan 3x
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ? ? ?
??
??
? ? ?
?
?
? ? ? ? ? ?
? ??
??
??
?
??
? ??
??
??
?
??
??
? ? ?
? ? ? ?
??
??
? ? ?
??
??
??
?
??
??
??
?
1 1 1 1
-1 1 1
-1 1 1
1 1 1
1
2
tan x 1 tan x 1 tan 3x tan x...(1)
AB
We know that, tan A tan B tan
1 AB
AB
and tan A tan B tan
1 AB
x 1 x 1
Thus, tan x 1 tan x 1 tan
1 x 1 x 1
2x
tan
1 x 1
tan
??
??
?
??
1
2
2x
....(2)
2x
? ?
1 1 1
1
2
11
22
22
22
22
2
2
3x x
Similarly,tan 3x tan x tan
1 3x x
2x
tan ....(3)
1 3x
From equations (1), (2) and (3), we have,
2x 2x
tan tan
2 x 1 3x
2x 2x
2 x 1 3x
11
2 x 1 3x
2 x 1 3x
4x 1
1
x
? ? ?
?
??
??
?
?? ??
??
?
??
??
?
??
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ?
??
??
??
??
? ? ? ?
??
??
4
1
x
2
? ? ?
CBSE XII | Mathematics
Board Paper 2016 – Solution
OR
? ? ? ?
?
??
?? ? ??
?
??
??
??
??
??
? ??
??
??
?
??
??
?
??
?
? ??
?
?
?? ? ??
? ?
????
?
??
??
?? ??
3
-1 1
22
-1 1 1
3
22
-1
3
22
Consider the left hand side
6x 8x 4x
L.H.S=tan tan
1 12x 1 4x
We know that,
AB
tan A tan B tan
1 AB
6x 8x 4x
1 12x 1 4x
Thus, L.H.S tan
6x 8x 4x
1
1 12x 1 4x
? ? ? ? ? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ?
? ? ? ?
? ? ? ? ? ?
? ? ? ?
? ? ? ? ? ?
? ? ? ?
?
?
?
?
??
? ? ? ?
??
?? ??
???
?
??
?
??
??
??
??
??
? ? ? ?
??
?? ??
???
? ? ? ?
??
??
??
??
??
? ? ? ?
?
? ? ?
3 2 2
22
-1
3
22
3 2 2
22
-1
2 2 3
22
3 2 2
-1
22
6x 8x 1 4x 4x 1 12x
1 12x 1 4x
tan
4x 6x 8x
1
1 12x 1 4x
6x 8x 1 4x 4x 1 12x
1 12x 1 4x
tan
1 12x 1 4x 4x 6x 8x
1 12x 1 4x
6x 8x 1 4x 4x 1 12x
tan
1 12x 1 4x
? ?
??
??
??
?
??
?? ? ? ? ? ?
?
??
? ? ? ? ?
??
?? ??
?
??
??
??
3
3 3 5 3
-1
2 2 4 2 4
53
-1
42
4x 6x 8x
6x 24x 8x 32x 4x 48x
tan
1 4x 12x 48x 24x 32x
32x 16x 2x
tan
16x 8x 1
? ?
??
??
??
?
?? ??
??
?
42
-1
42
-1
2x 16x 8x 1
tan
16x 8x 1
tan 2x
Thus, L.H.S=R.H.S
CBSE XII | Mathematics
Board Paper 2016 – Solution
8. Let charges for typing one English page be Rs. x.
Letcharges for typing one Hindi page be Rs.y.
Thus from the given statements, we have,
10x+3y=145
3x+10y=180
Thus the above system can be written as,
10 3 x 145
3 10 y 180
10 3
AX B, where, A=
3 10
? ? ? ? ? ?
?
? ? ? ? ? ?
? ? ? ? ? ?
??
-1
-1 -1
-1
-1
-1
x 145
,X and B=
y 180
Multiply A on both the sides, we have,
A AX A B
IX A B
X A B
Thus, we need to find the inverse of the matrix A.
a b d b 1
We know that, if P= then P
c d ad bc
? ? ? ? ? ?
?
? ? ? ? ? ?
? ? ? ? ? ?
??
??
??
? ??
?
??
?
??
-1
ca
10 3 1
Thus, A
10 10 3 3 3 10
10 3 1
100 9 3 10
10 3 1
91 3 10
10 3 145 1
Therefore,X
91 3 10 180
10 145 3 180 1
91 3 145 10 180
910 1
91 1365
10
15
x 10
y 15
??
??
?
??
? ??
?
??
? ? ? ?
??
? ??
?
??
??
??
? ??
?
??
?
??
? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
? ? ? ??
?
??
? ? ? ?
??
??
?
??
??
??
?
??
??
??
??
??
??
x 10 and y=15
??
??
??
??
Amount taken from Shyam = 2 × 5 = Rs.10
Actual rate = 15 × 5 =75
Difference amount = Rs.75 – Rs.10 = Rs.65
Rs. 65 less was charged from the poor boy Shyam.
Humanity and sympathy are reflected in this problem.
Read More
|
204 videos|290 docs|139 tests
|
FAQs on CBSE Past Year Paper Session (2016) Solutions, Math Class 12 - Mathematics (Maths) Class 12 - JEE
| 1. What is the CBSE Past Year Paper Session? |  |
Ans. The CBSE Past Year Paper Session refers to a series of practice sessions where students solve past year question papers of CBSE exams. These sessions help students to get familiar with the exam pattern, understand the type of questions asked, and assess their preparation level.
| 2. Why is solving past year papers important for the Math Class 12 exam? | |
Ans. Solving past year papers for the Math Class 12 exam is crucial as it allows students to gain a clear understanding of the exam pattern, marking scheme, and the level of difficulty. It helps them identify their weak areas and work on them, build confidence, and be well-prepared for the actual exam.
| 3. How can I access the CBSE Past Year Paper Session for Math Class 12? | |
Ans. The CBSE Past Year Paper Session for Math Class 12 can be accessed through various platforms. One can find these papers on the official CBSE website, educational websites, or purchase books specifically designed for practicing past year papers. Additionally, some coaching institutes and online learning platforms also provide access to these papers.
| 4. Are the solutions provided for the CBSE Past Year Paper Session accurate and reliable? | |
Ans. Yes, the solutions provided for the CBSE Past Year Paper Session are generally accurate and reliable. However, it is recommended to cross-verify the solutions with the help of subject teachers or experts. Sometimes, there may be different approaches or methods to solve a particular question, and it is essential to understand the concepts rather than just relying on the answers.
| 5. Can practicing past year papers guarantee good marks in the Math Class 12 exam? | |
Ans. Practicing past year papers alone cannot guarantee good marks in the Math Class 12 exam. While solving these papers is an essential part of the preparation process, it is equally important to understand the concepts, practice regularly, and revise the entire syllabus. Past year papers serve as a tool to evaluate preparation and identify areas that need improvement, but overall preparation and understanding of the subject are crucial for scoring well in the exam.
Related Exams
About this Document
|
4.67/5 Rating |
|
Nov 22, 2024 Last updated |
Document Description: CBSE Past Year Paper Session (2016) Solutions, Math Class 12 for JEE 2024 is part of Mathematics (Maths) Class 12 preparation.
The notes and questions for CBSE Past Year Paper Session (2016) Solutions, Math Class 12 have been prepared according to the JEE exam syllabus. Information about CBSE Past Year Paper Session (2016) Solutions, Math Class 12 covers topics
like and CBSE Past Year Paper Session (2016) Solutions, Math Class 12 Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for CBSE Past Year Paper Session (2016) Solutions, Math Class 12.
Introduction of CBSE Past Year Paper Session (2016) Solutions, Math Class 12 in English is available as part of our Mathematics (Maths) Class 12
for JEE & CBSE Past Year Paper Session (2016) Solutions, Math Class 12 in Hindi for Mathematics (Maths) Class 12 course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: CBSE Past Year Paper Session (2016) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE
Description
Full syllabus notes, lecture & questions for CBSE Past Year Paper Session (2016) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE - JEE | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 12 | Best notes, free PDF download
Information about CBSE Past Year Paper Session (2016) Solutions, Math Class 12
In this doc you can find the meaning of CBSE Past Year Paper Session (2016) Solutions, Math Class 12 defined & explained in the simplest way possible. Besides explaining types of
CBSE Past Year Paper Session (2016) Solutions, Math Class 12 theory, EduRev gives you an ample number of questions to practice CBSE Past Year Paper Session (2016) Solutions, Math Class 12 tests, examples and also practice JEE
tests
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Viva Questions
,Sample Paper
,Extra Questions
,CBSE Past Year Paper Session (2016) Solutions
,Objective type Questions
,MCQs
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,CBSE Past Year Paper Session (2016) Solutions
,Free
,Previous Year Questions with Solutions
,Important questions
,shortcuts and tricks
,ppt
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,Semester Notes
,CBSE Past Year Paper Session (2016) Solutions
,video lectures
,mock tests for examination
,past year papers
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,Summary
,study material
,Exam
,practice quizzes
;
Additional Information about CBSE Past Year Paper Session (2016) Solutions, Math Class 12 for JEE Preparation
CBSE Past Year Paper Session (2016) Solutions, Math Class 12 Free PDF Download
The CBSE Past Year Paper Session (2016) Solutions, Math Class 12 is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the CBSE Past Year Paper Session (2016) Solutions, Math Class 12 now and kickstart your journey towards success in the JEE exam.
Importance of CBSE Past Year Paper Session (2016) Solutions, Math Class 12
The importance of CBSE Past Year Paper Session (2016) Solutions, Math Class 12 cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
CBSE Past Year Paper Session (2016) Solutions, Math Class 12 Notes
CBSE Past Year Paper Session (2016) Solutions, Math Class 12 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to CBSE Past Year Paper Session (2016) Solutions, Math Class 12.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, CBSE Past Year Paper Session (2016) Solutions, Math Class 12 Notes on EduRev are your ultimate resource for success.
CBSE Past Year Paper Session (2016) Solutions, Math Class 12 JEE Questions
The "CBSE Past Year Paper Session (2016) Solutions, Math Class 12 JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study CBSE Past Year Paper Session (2016) Solutions, Math Class 12 on the App
Students of JEE can study CBSE Past Year Paper Session (2016) Solutions, Math Class 12 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the CBSE Past Year Paper Session (2016) Solutions, Math Class 12,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of CBSE Past Year Paper Session (2016) Solutions, Math Class 12 is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup