JEE Exam > JEE Notes > Mathematics (Maths) Class 12 > CBSE Past Year Paper Session (2014) Solutions, Math Class 12
CBSE Past Year Paper Session (2014) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
CBSE Board
Class XII Mathematics
Board Paper 2014 Solution
Delhi
SECTION – A
1. Given that
2
AA ? .
We need to find the value of
? ?
3
7A I A , where I is the identity matrix. ??
Thus,
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ?
? ?
3
3 2 2 3
3
3 2 2 3 2 2 2
3
2
3
3
3
7A I A 7A I 3I A 3IA A
7A I A 7A I 3A 3A A A I I,I A A,IA A
7A I A 7A I 3A 3A A A A
7A I A 7A I 3A 3A A
7A I A 7A I 7A
7A I A I
? ? ? ? ? ? ?
?? ? ? ? ? ? ? ? ? ? ? ? ?
??
?? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ?
2. Given that
x y z 1 4
2x y w 0 5
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
We need to find the value of x + y.
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
?
? ? ?
??
ij ij
x y z 1 4
2x y w 0 5
Two matrices A and B are equal to each other, if they have the same dimensions
and the same elements a b , for i = 1,2,...,n and j = 1,2,...,m.
x y 1...(1)
2x y 0...(2)
Equa ?
? ? ?
??
tion (2) (1) is x = 1
Substituting the value of x = 1 in equation (1), we have
1 y 1
y2
Therefore, x + y = 1 + 2 = 3
Page 2
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
CBSE Board
Class XII Mathematics
Board Paper 2014 Solution
Delhi
SECTION – A
1. Given that
2
AA ? .
We need to find the value of
? ?
3
7A I A , where I is the identity matrix. ??
Thus,
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ?
? ?
3
3 2 2 3
3
3 2 2 3 2 2 2
3
2
3
3
3
7A I A 7A I 3I A 3IA A
7A I A 7A I 3A 3A A A I I,I A A,IA A
7A I A 7A I 3A 3A A A A
7A I A 7A I 3A 3A A
7A I A 7A I 7A
7A I A I
? ? ? ? ? ? ?
?? ? ? ? ? ? ? ? ? ? ? ? ?
??
?? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ?
2. Given that
x y z 1 4
2x y w 0 5
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
We need to find the value of x + y.
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
?
? ? ?
??
ij ij
x y z 1 4
2x y w 0 5
Two matrices A and B are equal to each other, if they have the same dimensions
and the same elements a b , for i = 1,2,...,n and j = 1,2,...,m.
x y 1...(1)
2x y 0...(2)
Equa ?
? ? ?
??
tion (2) (1) is x = 1
Substituting the value of x = 1 in equation (1), we have
1 y 1
y2
Therefore, x + y = 1 + 2 = 3
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
3.
11
Given that tan x tan y and xy<1.
4
??
?
??
? ?
11
1
1
We need to find the value of x+y+xy.
tan x tan y
4
xy
tan xy 1
1 xy 4
xy
tan tan tan
1 xy 4
xy
1
1 xy
x y 1 xy
x y xy 1
??
?
?
?
??
?? ??
? ? ?
??
?
??
?? ???? ??
??
?? ?? ??
?
?? ?? ??
?
??
?
? ? ? ?
? ? ? ?
4. Given that
3x 7 8 7
2 4 6 4
?
?
.
We need to find the value of x
? ?
3x 7 8 7
2 4 6 4
12x 14 32 42
12x 14 10
12x 10 14
12x 24
x2
?
?
? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
? ? ?
Page 3
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
CBSE Board
Class XII Mathematics
Board Paper 2014 Solution
Delhi
SECTION – A
1. Given that
2
AA ? .
We need to find the value of
? ?
3
7A I A , where I is the identity matrix. ??
Thus,
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ?
? ?
3
3 2 2 3
3
3 2 2 3 2 2 2
3
2
3
3
3
7A I A 7A I 3I A 3IA A
7A I A 7A I 3A 3A A A I I,I A A,IA A
7A I A 7A I 3A 3A A A A
7A I A 7A I 3A 3A A
7A I A 7A I 7A
7A I A I
? ? ? ? ? ? ?
?? ? ? ? ? ? ? ? ? ? ? ? ?
??
?? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ?
2. Given that
x y z 1 4
2x y w 0 5
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
We need to find the value of x + y.
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
?
? ? ?
??
ij ij
x y z 1 4
2x y w 0 5
Two matrices A and B are equal to each other, if they have the same dimensions
and the same elements a b , for i = 1,2,...,n and j = 1,2,...,m.
x y 1...(1)
2x y 0...(2)
Equa ?
? ? ?
??
tion (2) (1) is x = 1
Substituting the value of x = 1 in equation (1), we have
1 y 1
y2
Therefore, x + y = 1 + 2 = 3
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
3.
11
Given that tan x tan y and xy<1.
4
??
?
??
? ?
11
1
1
We need to find the value of x+y+xy.
tan x tan y
4
xy
tan xy 1
1 xy 4
xy
tan tan tan
1 xy 4
xy
1
1 xy
x y 1 xy
x y xy 1
??
?
?
?
??
?? ??
? ? ?
??
?
??
?? ???? ??
??
?? ?? ??
?
?? ?? ??
?
??
?
? ? ? ?
? ? ? ?
4. Given that
3x 7 8 7
2 4 6 4
?
?
.
We need to find the value of x
? ?
3x 7 8 7
2 4 6 4
12x 14 32 42
12x 14 10
12x 10 14
12x 24
x2
?
?
? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
? ? ?
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
5. Since differentiation operation is the inverse operation of integration, we have
? ? sin ? ? f x x x
Let ? ?
0
sin ?
?
x
f x t tdt
Let us do this by integration by parts.
Therefore assume u = t; du = dt
sin
cos
?
??
??
tdt dv
tv
? ? ? ? ? ?
? ?
? ? ? ?
0
0
Therefore,
= t cos cos
cos sin
Differentiating the above function with respect to x,
f x sin cos cos sin
?? ? ? ?
??
? ? ? ?
??? ? ? ? ? ? ?
??
?
x
x
f x t t dt
f x x x x C
x x x x x x
6. Since the vectors are parallel, we have
? ?
ab
3i 2j 9k i 2pj 3k
3i 2j 9k i 2 pj 3 k
Comparing the respective coefficients, we have
3;
2 p 2
2 3 p 2
1
p
3
??
? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ?
? ? ?
? ? ?
? ? ? ? ?
?
??
7. ? ? The set of natural numbers, N = 1, 2, 3, 4, 5, 6....
? ? ? ?
? ? ? ? ? ? ? ?
? ?
? ?
The relation is given as
R = x, y : 2 8
Thus, R = 6, 1 , 4, 2 , 2, 3
Domain = 6, 4, 2
Range = 1, 2, 3
?? xy
Page 4
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
CBSE Board
Class XII Mathematics
Board Paper 2014 Solution
Delhi
SECTION – A
1. Given that
2
AA ? .
We need to find the value of
? ?
3
7A I A , where I is the identity matrix. ??
Thus,
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ?
? ?
3
3 2 2 3
3
3 2 2 3 2 2 2
3
2
3
3
3
7A I A 7A I 3I A 3IA A
7A I A 7A I 3A 3A A A I I,I A A,IA A
7A I A 7A I 3A 3A A A A
7A I A 7A I 3A 3A A
7A I A 7A I 7A
7A I A I
? ? ? ? ? ? ?
?? ? ? ? ? ? ? ? ? ? ? ? ?
??
?? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ?
2. Given that
x y z 1 4
2x y w 0 5
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
We need to find the value of x + y.
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
?
? ? ?
??
ij ij
x y z 1 4
2x y w 0 5
Two matrices A and B are equal to each other, if they have the same dimensions
and the same elements a b , for i = 1,2,...,n and j = 1,2,...,m.
x y 1...(1)
2x y 0...(2)
Equa ?
? ? ?
??
tion (2) (1) is x = 1
Substituting the value of x = 1 in equation (1), we have
1 y 1
y2
Therefore, x + y = 1 + 2 = 3
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
3.
11
Given that tan x tan y and xy<1.
4
??
?
??
? ?
11
1
1
We need to find the value of x+y+xy.
tan x tan y
4
xy
tan xy 1
1 xy 4
xy
tan tan tan
1 xy 4
xy
1
1 xy
x y 1 xy
x y xy 1
??
?
?
?
??
?? ??
? ? ?
??
?
??
?? ???? ??
??
?? ?? ??
?
?? ?? ??
?
??
?
? ? ? ?
? ? ? ?
4. Given that
3x 7 8 7
2 4 6 4
?
?
.
We need to find the value of x
? ?
3x 7 8 7
2 4 6 4
12x 14 32 42
12x 14 10
12x 10 14
12x 24
x2
?
?
? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
? ? ?
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
5. Since differentiation operation is the inverse operation of integration, we have
? ? sin ? ? f x x x
Let ? ?
0
sin ?
?
x
f x t tdt
Let us do this by integration by parts.
Therefore assume u = t; du = dt
sin
cos
?
??
??
tdt dv
tv
? ? ? ? ? ?
? ?
? ? ? ?
0
0
Therefore,
= t cos cos
cos sin
Differentiating the above function with respect to x,
f x sin cos cos sin
?? ? ? ?
??
? ? ? ?
??? ? ? ? ? ? ?
??
?
x
x
f x t t dt
f x x x x C
x x x x x x
6. Since the vectors are parallel, we have
? ?
ab
3i 2j 9k i 2pj 3k
3i 2j 9k i 2 pj 3 k
Comparing the respective coefficients, we have
3;
2 p 2
2 3 p 2
1
p
3
??
? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ?
? ? ?
? ? ?
? ? ? ? ?
?
??
7. ? ? The set of natural numbers, N = 1, 2, 3, 4, 5, 6....
? ? ? ?
? ? ? ? ? ? ? ?
? ?
? ?
The relation is given as
R = x, y : 2 8
Thus, R = 6, 1 , 4, 2 , 2, 3
Domain = 6, 4, 2
Range = 1, 2, 3
?? xy
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
8. Given that the cartesian equation of the line as
? ? ? ? ? ?
? ?
3 4 2 6
5 7 4
That is,
3 4 2 3
5 7 4
4
33
5 7 2
? ? ?
??
? ? ? ? ?
??
??
??
? ? ? ?
?
?
x y z
x y z
y
xz
Any point on the line is of the form:
5 3,7 4,2 3
Thus, the vector equation is of the form:
r , where is the position vector of any
point on the line and b is the vector parallel to the lin
? ? ? ?
?? a b a
? ? ?
?
? ? ? ? ? ?
? ?
e.
Therefore, the vector equation is
r 5 3 7 4 2 3
r 5 7 2 3 4 3
r 3 4 3 5 7 2
? ? ? ? ? ? ?
? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ?
i j k
i j k i j k
i j k i j k
? ? ?
? ? ?
?
9.
a
2
0
dx
Given that
4+x 8
?
?
?
a
2
0
-1
0
We need to find the value of a.
dx
Let I=
4+x 8
1
Thus, I= tan
2 2 8
?
??
?
??
??
?
?
?
a
x
1
1
1
1
tan
2 2 8
tan 2
28
tan
24
1
2
2
?
?
?
??
? ? ?
??
??
??
?
?
?
a
a
a
a
a
Page 5
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
CBSE Board
Class XII Mathematics
Board Paper 2014 Solution
Delhi
SECTION – A
1. Given that
2
AA ? .
We need to find the value of
? ?
3
7A I A , where I is the identity matrix. ??
Thus,
? ? ? ?
? ? ? ?
? ? ? ?
? ?
? ?
? ?
3
3 2 2 3
3
3 2 2 3 2 2 2
3
2
3
3
3
7A I A 7A I 3I A 3IA A
7A I A 7A I 3A 3A A A I I,I A A,IA A
7A I A 7A I 3A 3A A A A
7A I A 7A I 3A 3A A
7A I A 7A I 7A
7A I A I
? ? ? ? ? ? ?
?? ? ? ? ? ? ? ? ? ? ? ? ?
??
?? ? ? ? ? ? ? ? ? ?
??
? ? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ?
2. Given that
x y z 1 4
2x y w 0 5
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
We need to find the value of x + y.
?? ? ? ? ?
?
? ? ? ?
?
? ? ? ?
?
? ? ?
??
ij ij
x y z 1 4
2x y w 0 5
Two matrices A and B are equal to each other, if they have the same dimensions
and the same elements a b , for i = 1,2,...,n and j = 1,2,...,m.
x y 1...(1)
2x y 0...(2)
Equa ?
? ? ?
??
tion (2) (1) is x = 1
Substituting the value of x = 1 in equation (1), we have
1 y 1
y2
Therefore, x + y = 1 + 2 = 3
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
3.
11
Given that tan x tan y and xy<1.
4
??
?
??
? ?
11
1
1
We need to find the value of x+y+xy.
tan x tan y
4
xy
tan xy 1
1 xy 4
xy
tan tan tan
1 xy 4
xy
1
1 xy
x y 1 xy
x y xy 1
??
?
?
?
??
?? ??
? ? ?
??
?
??
?? ???? ??
??
?? ?? ??
?
?? ?? ??
?
??
?
? ? ? ?
? ? ? ?
4. Given that
3x 7 8 7
2 4 6 4
?
?
.
We need to find the value of x
? ?
3x 7 8 7
2 4 6 4
12x 14 32 42
12x 14 10
12x 10 14
12x 24
x2
?
?
? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
? ? ?
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
5. Since differentiation operation is the inverse operation of integration, we have
? ? sin ? ? f x x x
Let ? ?
0
sin ?
?
x
f x t tdt
Let us do this by integration by parts.
Therefore assume u = t; du = dt
sin
cos
?
??
??
tdt dv
tv
? ? ? ? ? ?
? ?
? ? ? ?
0
0
Therefore,
= t cos cos
cos sin
Differentiating the above function with respect to x,
f x sin cos cos sin
?? ? ? ?
??
? ? ? ?
??? ? ? ? ? ? ?
??
?
x
x
f x t t dt
f x x x x C
x x x x x x
6. Since the vectors are parallel, we have
? ?
ab
3i 2j 9k i 2pj 3k
3i 2j 9k i 2 pj 3 k
Comparing the respective coefficients, we have
3;
2 p 2
2 3 p 2
1
p
3
??
? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ?
? ? ?
? ? ?
? ? ? ? ?
?
??
7. ? ? The set of natural numbers, N = 1, 2, 3, 4, 5, 6....
? ? ? ?
? ? ? ? ? ? ? ?
? ?
? ?
The relation is given as
R = x, y : 2 8
Thus, R = 6, 1 , 4, 2 , 2, 3
Domain = 6, 4, 2
Range = 1, 2, 3
?? xy
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
8. Given that the cartesian equation of the line as
? ? ? ? ? ?
? ?
3 4 2 6
5 7 4
That is,
3 4 2 3
5 7 4
4
33
5 7 2
? ? ?
??
? ? ? ? ?
??
??
??
? ? ? ?
?
?
x y z
x y z
y
xz
Any point on the line is of the form:
5 3,7 4,2 3
Thus, the vector equation is of the form:
r , where is the position vector of any
point on the line and b is the vector parallel to the lin
? ? ? ?
?? a b a
? ? ?
?
? ? ? ? ? ?
? ?
e.
Therefore, the vector equation is
r 5 3 7 4 2 3
r 5 7 2 3 4 3
r 3 4 3 5 7 2
? ? ? ? ? ? ?
? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ?
i j k
i j k i j k
i j k i j k
? ? ?
? ? ?
?
9.
a
2
0
dx
Given that
4+x 8
?
?
?
a
2
0
-1
0
We need to find the value of a.
dx
Let I=
4+x 8
1
Thus, I= tan
2 2 8
?
??
?
??
??
?
?
?
a
x
1
1
1
1
tan
2 2 8
tan 2
28
tan
24
1
2
2
?
?
?
??
? ? ?
??
??
??
?
?
?
a
a
a
a
a
CBSE XII | Mathematics
Board Paper 2014 – Delhi Set 3 Solution
10. Given that a and b are two perpendicular vectors.
Thus, a b 0
Also given that, a b 13 and a =5.
We need to find the value of b.
??
??
2
2 2 2
2
22
2
2
2
Consider a b :
a b = a 2 a b b
13 5 2 0 b
169 25 b
b 169 25
b 144
b 12
?
? ? ? ?
? ? ? ?
??
??
?
?
Read More
|
204 videos|290 docs|139 tests
|
FAQs on CBSE Past Year Paper Session (2014) Solutions, Math Class 12 - Mathematics (Maths) Class 12 - JEE
| 1. What is the CBSE Past Year Paper Session? |  |
Ans. The CBSE Past Year Paper Session refers to a study session where students can practice and solve previous year question papers of the Central Board of Secondary Education (CBSE) exams. It helps students in familiarizing themselves with the exam pattern and marking scheme, and also allows them to assess their preparation level.
| 2. How can solving past year papers help in preparing for the Math Class 12 CBSE exam? | |
Ans. Solving past year papers can be extremely beneficial in preparing for the Math Class 12 CBSE exam. It gives students an idea about the type of questions asked in the exam, helps them understand the weightage given to different topics, and enables them to practice time management. Additionally, analyzing their performance in these papers can highlight areas of weakness that need more attention.
| 3. Where can I find the solutions for the CBSE Past Year Paper Session (2014) for Math Class 12? | |
Ans. You can find the solutions for the CBSE Past Year Paper Session (2014) for Math Class 12 in various sources. You can check online educational platforms, official CBSE websites, or refer to specialized study materials or guidebooks that provide solutions for past year papers. Additionally, you can seek help from your teachers or academic mentors for guidance in finding the solutions.
| 4. How can solving CBSE past year papers improve my exam performance? | |
Ans. Solving CBSE past year papers can significantly improve your exam performance in several ways. It helps you in gaining familiarity with the exam pattern, allows you to practice and refine your problem-solving skills, boosts your confidence, and reduces exam anxiety. By solving these papers, you can also identify common mistakes and rectify them, ultimately enhancing your overall understanding of the subject and improving your chances of scoring better in the actual exam.
| 5. Are the solutions provided for the CBSE Past Year Paper Session (2014) accurate and reliable? | |
Ans. The accuracy and reliability of the solutions for the CBSE Past Year Paper Session (2014) may vary depending on the source you refer to. It is advisable to cross-verify the solutions with trusted reference materials or consult with subject experts to ensure their correctness. Additionally, you can compare your solutions with those provided by reputable sources to gain further confidence in their accuracy.
Related Exams
About this Document
|
4.60/5 Rating |
|
Nov 22, 2024 Last updated |
Document Description: CBSE Past Year Paper Session (2014) Solutions, Math Class 12 for JEE 2024 is part of Mathematics (Maths) Class 12 preparation.
The notes and questions for CBSE Past Year Paper Session (2014) Solutions, Math Class 12 have been prepared according to the JEE exam syllabus. Information about CBSE Past Year Paper Session (2014) Solutions, Math Class 12 covers topics
like and CBSE Past Year Paper Session (2014) Solutions, Math Class 12 Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for CBSE Past Year Paper Session (2014) Solutions, Math Class 12.
Introduction of CBSE Past Year Paper Session (2014) Solutions, Math Class 12 in English is available as part of our Mathematics (Maths) Class 12
for JEE & CBSE Past Year Paper Session (2014) Solutions, Math Class 12 in Hindi for Mathematics (Maths) Class 12 course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: CBSE Past Year Paper Session (2014) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE
Description
Full syllabus notes, lecture & questions for CBSE Past Year Paper Session (2014) Solutions, Math Class 12 | Mathematics (Maths) Class 12 - JEE - JEE | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 12 | Best notes, free PDF download
Information about CBSE Past Year Paper Session (2014) Solutions, Math Class 12
In this doc you can find the meaning of CBSE Past Year Paper Session (2014) Solutions, Math Class 12 defined & explained in the simplest way possible. Besides explaining types of
CBSE Past Year Paper Session (2014) Solutions, Math Class 12 theory, EduRev gives you an ample number of questions to practice CBSE Past Year Paper Session (2014) Solutions, Math Class 12 tests, examples and also practice JEE
tests
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Sample Paper
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,CBSE Past Year Paper Session (2014) Solutions
,CBSE Past Year Paper Session (2014) Solutions
,Important questions
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,study material
,Extra Questions
,Objective type Questions
,Previous Year Questions with Solutions
,Exam
,Semester Notes
,Viva Questions
,Math Class 12 | Mathematics (Maths) Class 12 - JEE
,Summary
,mock tests for examination
,past year papers
,MCQs
,shortcuts and tricks
,Free
,practice quizzes
,video lectures
,CBSE Past Year Paper Session (2014) Solutions
,ppt
;
Additional Information about CBSE Past Year Paper Session (2014) Solutions, Math Class 12 for JEE Preparation
CBSE Past Year Paper Session (2014) Solutions, Math Class 12 Free PDF Download
The CBSE Past Year Paper Session (2014) Solutions, Math Class 12 is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the CBSE Past Year Paper Session (2014) Solutions, Math Class 12 now and kickstart your journey towards success in the JEE exam.
Importance of CBSE Past Year Paper Session (2014) Solutions, Math Class 12
The importance of CBSE Past Year Paper Session (2014) Solutions, Math Class 12 cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
CBSE Past Year Paper Session (2014) Solutions, Math Class 12 Notes
CBSE Past Year Paper Session (2014) Solutions, Math Class 12 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to CBSE Past Year Paper Session (2014) Solutions, Math Class 12.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, CBSE Past Year Paper Session (2014) Solutions, Math Class 12 Notes on EduRev are your ultimate resource for success.
CBSE Past Year Paper Session (2014) Solutions, Math Class 12 JEE Questions
The "CBSE Past Year Paper Session (2014) Solutions, Math Class 12 JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study CBSE Past Year Paper Session (2014) Solutions, Math Class 12 on the App
Students of JEE can study CBSE Past Year Paper Session (2014) Solutions, Math Class 12 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the CBSE Past Year Paper Session (2014) Solutions, Math Class 12,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of CBSE Past Year Paper Session (2014) Solutions, Math Class 12 is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup