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Page 1 G e n e r a l I n s t r u c t i o n : T h i s q u e s t i o n p a p e r h a s b e e n d i v i d e d i n t o 4 s e c t i o n s . S e c A c o n t a i n s 1 0 q u e s t i o n s o f 1 m a r k e a c h S e c B c o n t a i n s 8 q u e s t i o n s o f 2 m a r k s e a c h S e c C c o n t a i n s 8 q u e s t i o n s o f 3 m a r k s e a c h S e c D c o n t a i n s 4 q u e s t i o n s o f 5 m a r k s e a c h I n t e r n a l c h o i c e s h a v e b e e n p r o v i d e d i n s o m e q u e s t i o n s . A t t e m p t o n l y o n e o p t i o n i n s u c h q u e s t i o n s S E C T I O N – A 1 . E x p r e s s i n e x p o n e n t i a l f o r m : 6 × 6 × 6 × 6 × 6 2 . C a n y o u h a v e a t r i a n g l e w i t h t w o r i g h t a n g l e s . 3 . A r e a o f a c i r c l e w i t h r a d i u s r = … … … … 4 . W r i t e t h e c o e f f i c i e n t o f x i n t h e e x p r e s s i o n 1 3 y 2 – 8 y x . 5 . W r i t e t h e n a m e o f e q u a l a n g l e s i n t h e g i v e n f i g u r e . 6 . H o w m a n y m e d i a n s c a n b e d r a w n i n a t r i a n g l e ? 7 . W r i t e t w o p o i n t s l o c a t e d o n t h e t r i a n g l e i n t h e g i v e n f i g u r e . Page 2 G e n e r a l I n s t r u c t i o n : T h i s q u e s t i o n p a p e r h a s b e e n d i v i d e d i n t o 4 s e c t i o n s . S e c A c o n t a i n s 1 0 q u e s t i o n s o f 1 m a r k e a c h S e c B c o n t a i n s 8 q u e s t i o n s o f 2 m a r k s e a c h S e c C c o n t a i n s 8 q u e s t i o n s o f 3 m a r k s e a c h S e c D c o n t a i n s 4 q u e s t i o n s o f 5 m a r k s e a c h I n t e r n a l c h o i c e s h a v e b e e n p r o v i d e d i n s o m e q u e s t i o n s . A t t e m p t o n l y o n e o p t i o n i n s u c h q u e s t i o n s S E C T I O N – A 1 . E x p r e s s i n e x p o n e n t i a l f o r m : 6 × 6 × 6 × 6 × 6 2 . C a n y o u h a v e a t r i a n g l e w i t h t w o r i g h t a n g l e s . 3 . A r e a o f a c i r c l e w i t h r a d i u s r = … … … … 4 . W r i t e t h e c o e f f i c i e n t o f x i n t h e e x p r e s s i o n 1 3 y 2 – 8 y x . 5 . W r i t e t h e n a m e o f e q u a l a n g l e s i n t h e g i v e n f i g u r e . 6 . H o w m a n y m e d i a n s c a n b e d r a w n i n a t r i a n g l e ? 7 . W r i t e t w o p o i n t s l o c a t e d o n t h e t r i a n g l e i n t h e g i v e n f i g u r e . 8 . W h a t i s t h e p e r i m e t e r o f a s q u a r e w i t h s i d e 2 . 5 c m ? 9 . I s ? A B C ? ? D E F 1 0 . W r i t e t h e n a m e ( t y p e ) o f t h e g i v e n t r i a n g l e o n t h e b a s i s o f i t s a n g l e s . S E C T I O N – B 1 1 . A d d x a n d 5 x – 7 a n d – 3 x + 6 1 2 . F i n d t h e r a t i o o f : 1 5 k g t o 2 1 0 g 1 3 . F i n d t h e v a l u e o f e x t e r i o r a n g l e x i n t h e g i v e n f i g u r e . 1 4 . F i n d t h e c i r c u m f e r e n c e o f a c i r c l e w i t h d i a m e t e r 3 . 5 c m . 1 5 . I f ? P Q R ? ? X Y Z a ) ? P = . . . . . . . . . . . . . . Page 3 G e n e r a l I n s t r u c t i o n : T h i s q u e s t i o n p a p e r h a s b e e n d i v i d e d i n t o 4 s e c t i o n s . S e c A c o n t a i n s 1 0 q u e s t i o n s o f 1 m a r k e a c h S e c B c o n t a i n s 8 q u e s t i o n s o f 2 m a r k s e a c h S e c C c o n t a i n s 8 q u e s t i o n s o f 3 m a r k s e a c h S e c D c o n t a i n s 4 q u e s t i o n s o f 5 m a r k s e a c h I n t e r n a l c h o i c e s h a v e b e e n p r o v i d e d i n s o m e q u e s t i o n s . A t t e m p t o n l y o n e o p t i o n i n s u c h q u e s t i o n s S E C T I O N – A 1 . E x p r e s s i n e x p o n e n t i a l f o r m : 6 × 6 × 6 × 6 × 6 2 . C a n y o u h a v e a t r i a n g l e w i t h t w o r i g h t a n g l e s . 3 . A r e a o f a c i r c l e w i t h r a d i u s r = … … … … 4 . W r i t e t h e c o e f f i c i e n t o f x i n t h e e x p r e s s i o n 1 3 y 2 – 8 y x . 5 . W r i t e t h e n a m e o f e q u a l a n g l e s i n t h e g i v e n f i g u r e . 6 . H o w m a n y m e d i a n s c a n b e d r a w n i n a t r i a n g l e ? 7 . W r i t e t w o p o i n t s l o c a t e d o n t h e t r i a n g l e i n t h e g i v e n f i g u r e . 8 . W h a t i s t h e p e r i m e t e r o f a s q u a r e w i t h s i d e 2 . 5 c m ? 9 . I s ? A B C ? ? D E F 1 0 . W r i t e t h e n a m e ( t y p e ) o f t h e g i v e n t r i a n g l e o n t h e b a s i s o f i t s a n g l e s . S E C T I O N – B 1 1 . A d d x a n d 5 x – 7 a n d – 3 x + 6 1 2 . F i n d t h e r a t i o o f : 1 5 k g t o 2 1 0 g 1 3 . F i n d t h e v a l u e o f e x t e r i o r a n g l e x i n t h e g i v e n f i g u r e . 1 4 . F i n d t h e c i r c u m f e r e n c e o f a c i r c l e w i t h d i a m e t e r 3 . 5 c m . 1 5 . I f ? P Q R ? ? X Y Z a ) ? P = . . . . . . . . . . . . . . b ) . . . . . . . . . . . . . . . . = ? Z c ) P Q = … … … … … … … d ) … … … … … … … = X Z 1 6 . F i l l i n t h e b l a n k s w i t h t h e c o r r e c t s y m b o l o u t o f > , < o r = : a ) b ) 1 7 . F i n d t h e a r e a o f t h e p a r a l l e l o g r a m i n t h e g i v e n f i g u r e . 1 8 . I d e n t i f y p a i r s o f l i k e t e r m s : a ) 7 x , 1 2 y b ) 1 5 x , - 2 1 x c ) - 4 a b , 7 b a d ) 3 x y , 3 x O R C l a s s i f y t h e f o l l o w i n g i n t o m o n o m i a l s , b i n o m i a l s a n d t r i n o m i a l s : a ) 4 8 a b ) 5 x 2 y + 3 x y 2 c ) 3 p q 2 – p q + 1 d ) 5 m n – 6 S E C T I O N – C 1 9 . S i m p l i f y a n d e x p r e s s i n e x p o n e n t i a l f o r m : Page 4 G e n e r a l I n s t r u c t i o n : T h i s q u e s t i o n p a p e r h a s b e e n d i v i d e d i n t o 4 s e c t i o n s . S e c A c o n t a i n s 1 0 q u e s t i o n s o f 1 m a r k e a c h S e c B c o n t a i n s 8 q u e s t i o n s o f 2 m a r k s e a c h S e c C c o n t a i n s 8 q u e s t i o n s o f 3 m a r k s e a c h S e c D c o n t a i n s 4 q u e s t i o n s o f 5 m a r k s e a c h I n t e r n a l c h o i c e s h a v e b e e n p r o v i d e d i n s o m e q u e s t i o n s . A t t e m p t o n l y o n e o p t i o n i n s u c h q u e s t i o n s S E C T I O N – A 1 . E x p r e s s i n e x p o n e n t i a l f o r m : 6 × 6 × 6 × 6 × 6 2 . C a n y o u h a v e a t r i a n g l e w i t h t w o r i g h t a n g l e s . 3 . A r e a o f a c i r c l e w i t h r a d i u s r = … … … … 4 . W r i t e t h e c o e f f i c i e n t o f x i n t h e e x p r e s s i o n 1 3 y 2 – 8 y x . 5 . W r i t e t h e n a m e o f e q u a l a n g l e s i n t h e g i v e n f i g u r e . 6 . H o w m a n y m e d i a n s c a n b e d r a w n i n a t r i a n g l e ? 7 . W r i t e t w o p o i n t s l o c a t e d o n t h e t r i a n g l e i n t h e g i v e n f i g u r e . 8 . W h a t i s t h e p e r i m e t e r o f a s q u a r e w i t h s i d e 2 . 5 c m ? 9 . I s ? A B C ? ? D E F 1 0 . W r i t e t h e n a m e ( t y p e ) o f t h e g i v e n t r i a n g l e o n t h e b a s i s o f i t s a n g l e s . S E C T I O N – B 1 1 . A d d x a n d 5 x – 7 a n d – 3 x + 6 1 2 . F i n d t h e r a t i o o f : 1 5 k g t o 2 1 0 g 1 3 . F i n d t h e v a l u e o f e x t e r i o r a n g l e x i n t h e g i v e n f i g u r e . 1 4 . F i n d t h e c i r c u m f e r e n c e o f a c i r c l e w i t h d i a m e t e r 3 . 5 c m . 1 5 . I f ? P Q R ? ? X Y Z a ) ? P = . . . . . . . . . . . . . . b ) . . . . . . . . . . . . . . . . = ? Z c ) P Q = … … … … … … … d ) … … … … … … … = X Z 1 6 . F i l l i n t h e b l a n k s w i t h t h e c o r r e c t s y m b o l o u t o f > , < o r = : a ) b ) 1 7 . F i n d t h e a r e a o f t h e p a r a l l e l o g r a m i n t h e g i v e n f i g u r e . 1 8 . I d e n t i f y p a i r s o f l i k e t e r m s : a ) 7 x , 1 2 y b ) 1 5 x , - 2 1 x c ) - 4 a b , 7 b a d ) 3 x y , 3 x O R C l a s s i f y t h e f o l l o w i n g i n t o m o n o m i a l s , b i n o m i a l s a n d t r i n o m i a l s : a ) 4 8 a b ) 5 x 2 y + 3 x y 2 c ) 3 p q 2 – p q + 1 d ) 5 m n – 6 S E C T I O N – C 1 9 . S i m p l i f y a n d e x p r e s s i n e x p o n e n t i a l f o r m : 2 0 . I n t h e f i g u r e , A B = A C a n d A D i s t h e b i s e c t o r o f ? B A C . a ) S t a t e t h r e e p a i r s o f e q u a l p a r t s i n t r i a n g l e s A D B a n d A D C . b ) I s ? A D B ? ? A D C ? G i v e r e a s o n s . 2 1 . T h e a r e a o s a r e c t a n g u l a r s h e e t i s 5 0 0 c m 2 . I f t h e l e n g t h o f t h e s h e e t i s 2 5 c m , w h a t i s i t s w i d t h ? A l s o , f i n d t h e p e r i m e t e r o f t h e r e c t a n g u l a r s h e e t . 2 2 . F i n d t h e v a l u e o f a 2 + a b + b 2 a t a = 2 , b = ( - 2 ) 2 3 . M e e t a s a v e R s . 4 0 0 / - f r o m h e r s a l a r y . I f t h i s i s 1 0 % o f h e r s a l a r y , w h a t i s h e r s a l a r y ? 2 4 . ? A B C i s r i g h t a n g l e a t C . I f A C = 5 c m , B C = 1 2 c m , F i n d t h e l e n g t h o f A B . 2 5 . T h e m i n u t e h a n d o f a c i r c u l a r c l o c k i s 1 5 c m l o n g . H o w f a r d o e s t h e t i p o f t h e m i n u t e h a n d m o v e i n 1 h o u r ? ( T a k e p = 3 . 1 4 ) 2 6 . I d e n t i f y t h e t e r m s a n d t h e i r f a c t o r s i n t h e f o l l o w i n g e x p r e s s i o n . S h o w t h e f a c t o r s b y t r e e d i a g r a m : 4 x 2 – 3 x y S E C T I O N D 2 7 . C o n s t r u c t ? A B C w i t h B C = 7 . 5 c m , A C = 5 c m a n d m ? C = 6 0 ° . W r i t e s t e p s o f c o n s t r u c t i o n a l s o . 2 8 . R a v i b o u g h t a T V f o r R s . 1 2 , 0 0 0 a n d s o l d i t a t a p r o f i t o f 1 0 % . H e p u r c h a s e d w o o l e n c l o t h e s f o r t h e c h i l d r e n o f h i s p o o r n e i g h b o u r f r o m t h e p r o f i t m o n e y . F i n d o u t : a ) T h e s e l l i n g p r i c e o f t h e T V . b ) T h e a m o u n t o f p r o f i t r e c e i v e d . c ) W h a t v a l u e s d i d R a v i d e p i c t e d h e r e ? Page 5 G e n e r a l I n s t r u c t i o n : T h i s q u e s t i o n p a p e r h a s b e e n d i v i d e d i n t o 4 s e c t i o n s . S e c A c o n t a i n s 1 0 q u e s t i o n s o f 1 m a r k e a c h S e c B c o n t a i n s 8 q u e s t i o n s o f 2 m a r k s e a c h S e c C c o n t a i n s 8 q u e s t i o n s o f 3 m a r k s e a c h S e c D c o n t a i n s 4 q u e s t i o n s o f 5 m a r k s e a c h I n t e r n a l c h o i c e s h a v e b e e n p r o v i d e d i n s o m e q u e s t i o n s . A t t e m p t o n l y o n e o p t i o n i n s u c h q u e s t i o n s S E C T I O N – A 1 . E x p r e s s i n e x p o n e n t i a l f o r m : 6 × 6 × 6 × 6 × 6 2 . C a n y o u h a v e a t r i a n g l e w i t h t w o r i g h t a n g l e s . 3 . A r e a o f a c i r c l e w i t h r a d i u s r = … … … … 4 . W r i t e t h e c o e f f i c i e n t o f x i n t h e e x p r e s s i o n 1 3 y 2 – 8 y x . 5 . W r i t e t h e n a m e o f e q u a l a n g l e s i n t h e g i v e n f i g u r e . 6 . H o w m a n y m e d i a n s c a n b e d r a w n i n a t r i a n g l e ? 7 . W r i t e t w o p o i n t s l o c a t e d o n t h e t r i a n g l e i n t h e g i v e n f i g u r e . 8 . W h a t i s t h e p e r i m e t e r o f a s q u a r e w i t h s i d e 2 . 5 c m ? 9 . I s ? A B C ? ? D E F 1 0 . W r i t e t h e n a m e ( t y p e ) o f t h e g i v e n t r i a n g l e o n t h e b a s i s o f i t s a n g l e s . S E C T I O N – B 1 1 . A d d x a n d 5 x – 7 a n d – 3 x + 6 1 2 . F i n d t h e r a t i o o f : 1 5 k g t o 2 1 0 g 1 3 . F i n d t h e v a l u e o f e x t e r i o r a n g l e x i n t h e g i v e n f i g u r e . 1 4 . F i n d t h e c i r c u m f e r e n c e o f a c i r c l e w i t h d i a m e t e r 3 . 5 c m . 1 5 . I f ? P Q R ? ? X Y Z a ) ? P = . . . . . . . . . . . . . . b ) . . . . . . . . . . . . . . . . = ? Z c ) P Q = … … … … … … … d ) … … … … … … … = X Z 1 6 . F i l l i n t h e b l a n k s w i t h t h e c o r r e c t s y m b o l o u t o f > , < o r = : a ) b ) 1 7 . F i n d t h e a r e a o f t h e p a r a l l e l o g r a m i n t h e g i v e n f i g u r e . 1 8 . I d e n t i f y p a i r s o f l i k e t e r m s : a ) 7 x , 1 2 y b ) 1 5 x , - 2 1 x c ) - 4 a b , 7 b a d ) 3 x y , 3 x O R C l a s s i f y t h e f o l l o w i n g i n t o m o n o m i a l s , b i n o m i a l s a n d t r i n o m i a l s : a ) 4 8 a b ) 5 x 2 y + 3 x y 2 c ) 3 p q 2 – p q + 1 d ) 5 m n – 6 S E C T I O N – C 1 9 . S i m p l i f y a n d e x p r e s s i n e x p o n e n t i a l f o r m : 2 0 . I n t h e f i g u r e , A B = A C a n d A D i s t h e b i s e c t o r o f ? B A C . a ) S t a t e t h r e e p a i r s o f e q u a l p a r t s i n t r i a n g l e s A D B a n d A D C . b ) I s ? A D B ? ? A D C ? G i v e r e a s o n s . 2 1 . T h e a r e a o s a r e c t a n g u l a r s h e e t i s 5 0 0 c m 2 . I f t h e l e n g t h o f t h e s h e e t i s 2 5 c m , w h a t i s i t s w i d t h ? A l s o , f i n d t h e p e r i m e t e r o f t h e r e c t a n g u l a r s h e e t . 2 2 . F i n d t h e v a l u e o f a 2 + a b + b 2 a t a = 2 , b = ( - 2 ) 2 3 . M e e t a s a v e R s . 4 0 0 / - f r o m h e r s a l a r y . I f t h i s i s 1 0 % o f h e r s a l a r y , w h a t i s h e r s a l a r y ? 2 4 . ? A B C i s r i g h t a n g l e a t C . I f A C = 5 c m , B C = 1 2 c m , F i n d t h e l e n g t h o f A B . 2 5 . T h e m i n u t e h a n d o f a c i r c u l a r c l o c k i s 1 5 c m l o n g . H o w f a r d o e s t h e t i p o f t h e m i n u t e h a n d m o v e i n 1 h o u r ? ( T a k e p = 3 . 1 4 ) 2 6 . I d e n t i f y t h e t e r m s a n d t h e i r f a c t o r s i n t h e f o l l o w i n g e x p r e s s i o n . S h o w t h e f a c t o r s b y t r e e d i a g r a m : 4 x 2 – 3 x y S E C T I O N D 2 7 . C o n s t r u c t ? A B C w i t h B C = 7 . 5 c m , A C = 5 c m a n d m ? C = 6 0 ° . W r i t e s t e p s o f c o n s t r u c t i o n a l s o . 2 8 . R a v i b o u g h t a T V f o r R s . 1 2 , 0 0 0 a n d s o l d i t a t a p r o f i t o f 1 0 % . H e p u r c h a s e d w o o l e n c l o t h e s f o r t h e c h i l d r e n o f h i s p o o r n e i g h b o u r f r o m t h e p r o f i t m o n e y . F i n d o u t : a ) T h e s e l l i n g p r i c e o f t h e T V . b ) T h e a m o u n t o f p r o f i t r e c e i v e d . c ) W h a t v a l u e s d i d R a v i d e p i c t e d h e r e ? 2 9 . F r o m t h e s u m o f 4 + 3 x a n d 5 – 4 x + 2 x 2 , S u b t r a c t t h e s u m o f 3 x 2 – 5 x a n d – x 2 + 2 x + 5 O R S i m p l i f y t h e e x p r e s s i o n 2 ( a 2 + a b ) + 3 – a b a n d f i n d i t s v a l u e a t a = 5 , b = - 3 . 3 0 . A p a t h 2 . 5 m w i d e i s b u i l t a l o n g t h e b o r d e r i n s i d e a s q u a r e g a r d e n o f s i d e 5 0 m . F i n d : a ) t h e a r e a o f t h e p a t h b ) t h e c o s t o f p l a n t i n g g r a s s i n t h e r e m a i n i n g p o r t i o n o f t h e g a r d e n a t t h e r a t e o f R s . 2 0 p e r m 2 .Read More
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FAQs on Class 7 Math: CBSE Past Year Paper - 11 - Mathematics (Maths) Class 7
| 1. What are the topics covered in the CBSE Class 7 Math exam? |  |
Ans. The CBSE Class 7 Math exam covers various topics such as integers, fractions and decimals, data handling, algebraic expressions, equations, lines and angles, triangles, congruence of triangles, comparing quantities, rational numbers, and more.
| 2. How can I prepare for the CBSE Class 7 Math exam effectively? | |
Ans. To prepare for the CBSE Class 7 Math exam effectively, you can follow these tips:
- Understand the concepts thoroughly by referring to your textbook and other study materials.
- Practice solving different types of problems from each topic.
- Make a study schedule and allocate time for regular practice.
- Solve previous year question papers and sample papers to understand the exam pattern and improve time management.
- Seek help from your teacher or classmates if you have any doubts.
- Revise the topics regularly to strengthen your understanding.
| 3. Are there any important formulas or theorems that I should remember for the CBSE Class 7 Math exam? | |
Ans. Yes, there are some important formulas and theorems that you should remember for the CBSE Class 7 Math exam. Some of them include:
- Pythagoras theorem: In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
- Area of a triangle: The area of a triangle can be calculated using the formula: 1/2 * base * height.
- Area of a circle: The area of a circle can be calculated using the formula: π * radius^2.
- Formula for finding the nth term of an arithmetic sequence: nth term = a + (n-1)d, where 'a' is the first term and 'd' is the common difference.
| 4. How can I improve my problem-solving skills for the CBSE Class 7 Math exam? | |
Ans. To improve your problem-solving skills for the CBSE Class 7 Math exam, you can follow these strategies:
- Understand the problem statement thoroughly and identify the given information.
- Break down the problem into smaller parts if necessary.
- Use appropriate mathematical concepts or formulas to solve the problem.
- Practice solving a variety of problems from different topics to enhance your problem-solving abilities.
- Analyze your mistakes and learn from them.
- Work on developing logical reasoning and critical thinking skills by engaging in activities like puzzles and brain teasers.
| 5. What are some recommended resources for CBSE Class 7 Math exam preparation? | |
Ans. Some recommended resources for CBSE Class 7 Math exam preparation are:
- NCERT Class 7 Math textbook
- NCERT Exemplar problems for Class 7 Math
- RD Sharma Class 7 Math textbook
- Oswaal CBSE Question Bank Class 7 Mathematics
- Previous year question papers and sample papers
- Online platforms or educational websites that offer practice questions and interactive learning materials for Class 7 Math.
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Dec 23, 2024 Last updated |
Document Description: Class 7 Math: CBSE Past Year Paper - 11 for Class 7 2024 is part of Mathematics (Maths) Class 7 preparation.
The notes and questions for Class 7 Math: CBSE Past Year Paper - 11 have been prepared according to the Class 7 exam syllabus. Information about Class 7 Math: CBSE Past Year Paper - 11 covers topics
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Full syllabus notes, lecture & questions for Class 7 Math: CBSE Past Year Paper - 11 | Mathematics (Maths) Class 7 - Class 7 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 7 | Best notes, free PDF download
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Additional Information about Class 7 Math: CBSE Past Year Paper - 11 for Class 7 Preparation
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The content of Class 7 Math: CBSE Past Year Paper - 11 is prepared as per the latest Class 7 syllabus.
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