NEET Exam > NEET Notes > Additional Study Material for NEET > CBSE Physics Past year paper (Solutions) - 2016, Class 12
CBSE Physics Past year paper (Solutions) - 2016, Class 12 | Additional Study Material for NEET PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
CBSE XII | PHYSICS
Board Paper – Solution
CBSE
Class XII Physics
Board Paper – 2016 Solution
SECTION – A
1. The frequencies of the side bands produced are
?
?
? ? ?
? ? ?
?
??
?
3
Maximum frequency: 5 kHz 2 MHz
5 10 MHz 2 MHz
0.005 2 2.005 MHz
Minimum frequency: 2 MHz 5 kHz
2 MHz 0.005 MHz
1.995 MHz
2. A particle moves along a curved path if it moves in the presence of a magnetic
field.
Now, when there is an angular projection, i.e. when the velocity of the particle is
at an angle with respect to the magnetic field, then the particle will move in a
helical path.
The vertical component (vsin ?) will be perpendicular to the field and hence will
rotate the particle in a circular path. However, the horizontal component (vcos ?)
will move the particle in a straight line path. So, the cumulative motion of the
particle is a helix.
3. The mobility of a charge carrier is defined as the drift velocity per unit electric
field.
??
?
?
?
?
? ? ?
d
d
v
E
eE
Now, v
m
Where, is the relaxation time
e
m
4. The work done in moving a charge along any circular path is zero. So, to move a
point charge Q around a circular arc of radius ‘r’ at the centre of which another
point charge ‘q’ is located, no work has to be done.
5. During fog, the light coming from an object is partly deflected by the particles of
the fog and does not reach the eye of the observer. Thus, the objects are not
seen clearly.
The phenomenon is called scattering of light.
Page 2
CBSE XII | PHYSICS
Board Paper – Solution
CBSE
Class XII Physics
Board Paper – 2016 Solution
SECTION – A
1. The frequencies of the side bands produced are
?
?
? ? ?
? ? ?
?
??
?
3
Maximum frequency: 5 kHz 2 MHz
5 10 MHz 2 MHz
0.005 2 2.005 MHz
Minimum frequency: 2 MHz 5 kHz
2 MHz 0.005 MHz
1.995 MHz
2. A particle moves along a curved path if it moves in the presence of a magnetic
field.
Now, when there is an angular projection, i.e. when the velocity of the particle is
at an angle with respect to the magnetic field, then the particle will move in a
helical path.
The vertical component (vsin ?) will be perpendicular to the field and hence will
rotate the particle in a circular path. However, the horizontal component (vcos ?)
will move the particle in a straight line path. So, the cumulative motion of the
particle is a helix.
3. The mobility of a charge carrier is defined as the drift velocity per unit electric
field.
??
?
?
?
?
? ? ?
d
d
v
E
eE
Now, v
m
Where, is the relaxation time
e
m
4. The work done in moving a charge along any circular path is zero. So, to move a
point charge Q around a circular arc of radius ‘r’ at the centre of which another
point charge ‘q’ is located, no work has to be done.
5. During fog, the light coming from an object is partly deflected by the particles of
the fog and does not reach the eye of the observer. Thus, the objects are not
seen clearly.
The phenomenon is called scattering of light.
CBSE XII | PHYSICS
Board Paper – Solution
SECTION – B
6. The H
?
line in the emission spectrum of the hydrogen atom is obtained when the
electron transition takes place between n = 2 to n = 1.
?
?
?
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ? ? ? ? ?
??
??
? ? ? ? ?
? ? ? ?
th
n
2
21
22
21
2
21
19
21
19
21
We know that the energy in n level is
13.6
E
n
13.6 13.6
EE
21
13.6
E E 13.6
2
13
E E 13.6 1 13.6 10.2 eV
44
E E 10.2 1.6 10 J
E E 16.32 10 J
Now, this difference in energ
?
?
? ? ? ?
? ?
? ? ? ?
?
? ? ? ?
21
19
21
34
15
y gives the energy of the photon emitted
E E h
EE 16.32 10
h 6.63 10
2.46 10 Hz
OR
The electron in the hydrogen atom jumps from n
2
= ? to n
1
= 1.
Now, we know that
??
??
??
??
??
?
??
??
? ? ? ? ? ?
??
??
??
? ? ? ? ? ? ?
?
? ? ?
22
12
77
8 10
7
o
1 1 1
R
nn
1 1 1
1.097 10 1.097 10
1
1
9.116 10 m 911.6 10 m
1.097 10
911.6 A
Page 3
CBSE XII | PHYSICS
Board Paper – Solution
CBSE
Class XII Physics
Board Paper – 2016 Solution
SECTION – A
1. The frequencies of the side bands produced are
?
?
? ? ?
? ? ?
?
??
?
3
Maximum frequency: 5 kHz 2 MHz
5 10 MHz 2 MHz
0.005 2 2.005 MHz
Minimum frequency: 2 MHz 5 kHz
2 MHz 0.005 MHz
1.995 MHz
2. A particle moves along a curved path if it moves in the presence of a magnetic
field.
Now, when there is an angular projection, i.e. when the velocity of the particle is
at an angle with respect to the magnetic field, then the particle will move in a
helical path.
The vertical component (vsin ?) will be perpendicular to the field and hence will
rotate the particle in a circular path. However, the horizontal component (vcos ?)
will move the particle in a straight line path. So, the cumulative motion of the
particle is a helix.
3. The mobility of a charge carrier is defined as the drift velocity per unit electric
field.
??
?
?
?
?
? ? ?
d
d
v
E
eE
Now, v
m
Where, is the relaxation time
e
m
4. The work done in moving a charge along any circular path is zero. So, to move a
point charge Q around a circular arc of radius ‘r’ at the centre of which another
point charge ‘q’ is located, no work has to be done.
5. During fog, the light coming from an object is partly deflected by the particles of
the fog and does not reach the eye of the observer. Thus, the objects are not
seen clearly.
The phenomenon is called scattering of light.
CBSE XII | PHYSICS
Board Paper – Solution
SECTION – B
6. The H
?
line in the emission spectrum of the hydrogen atom is obtained when the
electron transition takes place between n = 2 to n = 1.
?
?
?
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ? ? ? ? ?
??
??
? ? ? ? ?
? ? ? ?
th
n
2
21
22
21
2
21
19
21
19
21
We know that the energy in n level is
13.6
E
n
13.6 13.6
EE
21
13.6
E E 13.6
2
13
E E 13.6 1 13.6 10.2 eV
44
E E 10.2 1.6 10 J
E E 16.32 10 J
Now, this difference in energ
?
?
? ? ? ?
? ?
? ? ? ?
?
? ? ? ?
21
19
21
34
15
y gives the energy of the photon emitted
E E h
EE 16.32 10
h 6.63 10
2.46 10 Hz
OR
The electron in the hydrogen atom jumps from n
2
= ? to n
1
= 1.
Now, we know that
??
??
??
??
??
?
??
??
? ? ? ? ? ?
??
??
??
? ? ? ? ? ? ?
?
? ? ?
22
12
77
8 10
7
o
1 1 1
R
nn
1 1 1
1.097 10 1.097 10
1
1
9.116 10 m 911.6 10 m
1.097 10
911.6 A
CBSE XII | PHYSICS
Board Paper – Solution
7. The drift speed is
?
d
I
v
neA
Now, we know that the current is given from Ohm’s law as
??
?
?
??
??
??
??
? ? ?
? ? ?
? ? ? ? ? ?
? ? ? ? ?
d
d
d
d
28 19 4
5
V
I
R
V
v
RneA
V
RA
nev
V RA
nev l l
RA
Now, resistivity is given as
l
V
nev l
5
8 10 1.6 10 2.5 10 0.1
1.56 10 m
8.
(i) The de Broglie wavelength is related to the accelerating potential as
?
??
? ? ? ?
?
?
??
? ? ?
??
?
? ? ? ?
?
??
? ? ? ?
p
pp
p
p p p p
p
h
2meV
h
2m e V
h
And,
2m e V
2m e V m e
h
h
2m e V m e
Now, mass and charge of particle is greater than that of proton.
for the same potential difference.
(ii) The kinetic energy is related to accelerating potential as
??
??
?
?
??
?
??
?
pp
pp
p
K.E. eV
K.E. e V
And, K.E. e V
K.E. e
K.E. e
Since, the charge on proton is less than that on alpha particle,
K.E. K.E. for the same potential difference.
Page 4
CBSE XII | PHYSICS
Board Paper – Solution
CBSE
Class XII Physics
Board Paper – 2016 Solution
SECTION – A
1. The frequencies of the side bands produced are
?
?
? ? ?
? ? ?
?
??
?
3
Maximum frequency: 5 kHz 2 MHz
5 10 MHz 2 MHz
0.005 2 2.005 MHz
Minimum frequency: 2 MHz 5 kHz
2 MHz 0.005 MHz
1.995 MHz
2. A particle moves along a curved path if it moves in the presence of a magnetic
field.
Now, when there is an angular projection, i.e. when the velocity of the particle is
at an angle with respect to the magnetic field, then the particle will move in a
helical path.
The vertical component (vsin ?) will be perpendicular to the field and hence will
rotate the particle in a circular path. However, the horizontal component (vcos ?)
will move the particle in a straight line path. So, the cumulative motion of the
particle is a helix.
3. The mobility of a charge carrier is defined as the drift velocity per unit electric
field.
??
?
?
?
?
? ? ?
d
d
v
E
eE
Now, v
m
Where, is the relaxation time
e
m
4. The work done in moving a charge along any circular path is zero. So, to move a
point charge Q around a circular arc of radius ‘r’ at the centre of which another
point charge ‘q’ is located, no work has to be done.
5. During fog, the light coming from an object is partly deflected by the particles of
the fog and does not reach the eye of the observer. Thus, the objects are not
seen clearly.
The phenomenon is called scattering of light.
CBSE XII | PHYSICS
Board Paper – Solution
SECTION – B
6. The H
?
line in the emission spectrum of the hydrogen atom is obtained when the
electron transition takes place between n = 2 to n = 1.
?
?
?
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ? ? ? ? ?
??
??
? ? ? ? ?
? ? ? ?
th
n
2
21
22
21
2
21
19
21
19
21
We know that the energy in n level is
13.6
E
n
13.6 13.6
EE
21
13.6
E E 13.6
2
13
E E 13.6 1 13.6 10.2 eV
44
E E 10.2 1.6 10 J
E E 16.32 10 J
Now, this difference in energ
?
?
? ? ? ?
? ?
? ? ? ?
?
? ? ? ?
21
19
21
34
15
y gives the energy of the photon emitted
E E h
EE 16.32 10
h 6.63 10
2.46 10 Hz
OR
The electron in the hydrogen atom jumps from n
2
= ? to n
1
= 1.
Now, we know that
??
??
??
??
??
?
??
??
? ? ? ? ? ?
??
??
??
? ? ? ? ? ? ?
?
? ? ?
22
12
77
8 10
7
o
1 1 1
R
nn
1 1 1
1.097 10 1.097 10
1
1
9.116 10 m 911.6 10 m
1.097 10
911.6 A
CBSE XII | PHYSICS
Board Paper – Solution
7. The drift speed is
?
d
I
v
neA
Now, we know that the current is given from Ohm’s law as
??
?
?
??
??
??
??
? ? ?
? ? ?
? ? ? ? ? ?
? ? ? ? ?
d
d
d
d
28 19 4
5
V
I
R
V
v
RneA
V
RA
nev
V RA
nev l l
RA
Now, resistivity is given as
l
V
nev l
5
8 10 1.6 10 2.5 10 0.1
1.56 10 m
8.
(i) The de Broglie wavelength is related to the accelerating potential as
?
??
? ? ? ?
?
?
??
? ? ?
??
?
? ? ? ?
?
??
? ? ? ?
p
pp
p
p p p p
p
h
2meV
h
2m e V
h
And,
2m e V
2m e V m e
h
h
2m e V m e
Now, mass and charge of particle is greater than that of proton.
for the same potential difference.
(ii) The kinetic energy is related to accelerating potential as
??
??
?
?
??
?
??
?
pp
pp
p
K.E. eV
K.E. e V
And, K.E. e V
K.E. e
K.E. e
Since, the charge on proton is less than that on alpha particle,
K.E. K.E. for the same potential difference.
CBSE XII | PHYSICS
Board Paper – Solution
9. The angle of the prism is A = 60 ?. It is also given that AQ = AR.
Therefore, the angles opposite to these two sides are also equal.
? ? ?
? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ? ? ? ? ?
? ? ? ?
12
12
AQR ARQ
Now, for a triangle
A AQR ARQ 180
AQR ARQ 60
r r 30 ( AQO ARO 90 )
r r 60
When r
1
and r
2
are equal, we have i = e.
Now, according to Snell’s law,
??
? ? ? ? ?
? ? ?
1
1
sini
sinr
3
sini sinr 3 sin30
2
i 60
Now, the angle of deviation ? is
? ? ? ?
? ? ? ? ?
? ? ? ?
i e A
60 60 60
60
10. The baseband signal is not transmitted directly because
(i) Its higher wavelength (low frequency) will require the size of the antenna or
aerial used for transmission to be very high.
(ii) For linear antenna (length l), the power radiated is proportional to
??
??
?
??
2
1
, and
hence, the effective power radiated by a long wavelength baseband signal would
be small.
Page 5
CBSE XII | PHYSICS
Board Paper – Solution
CBSE
Class XII Physics
Board Paper – 2016 Solution
SECTION – A
1. The frequencies of the side bands produced are
?
?
? ? ?
? ? ?
?
??
?
3
Maximum frequency: 5 kHz 2 MHz
5 10 MHz 2 MHz
0.005 2 2.005 MHz
Minimum frequency: 2 MHz 5 kHz
2 MHz 0.005 MHz
1.995 MHz
2. A particle moves along a curved path if it moves in the presence of a magnetic
field.
Now, when there is an angular projection, i.e. when the velocity of the particle is
at an angle with respect to the magnetic field, then the particle will move in a
helical path.
The vertical component (vsin ?) will be perpendicular to the field and hence will
rotate the particle in a circular path. However, the horizontal component (vcos ?)
will move the particle in a straight line path. So, the cumulative motion of the
particle is a helix.
3. The mobility of a charge carrier is defined as the drift velocity per unit electric
field.
??
?
?
?
?
? ? ?
d
d
v
E
eE
Now, v
m
Where, is the relaxation time
e
m
4. The work done in moving a charge along any circular path is zero. So, to move a
point charge Q around a circular arc of radius ‘r’ at the centre of which another
point charge ‘q’ is located, no work has to be done.
5. During fog, the light coming from an object is partly deflected by the particles of
the fog and does not reach the eye of the observer. Thus, the objects are not
seen clearly.
The phenomenon is called scattering of light.
CBSE XII | PHYSICS
Board Paper – Solution
SECTION – B
6. The H
?
line in the emission spectrum of the hydrogen atom is obtained when the
electron transition takes place between n = 2 to n = 1.
?
?
?
?
??
? ? ? ?
?
? ? ? ?
??
? ? ? ? ? ? ? ?
??
??
? ? ? ? ?
? ? ? ?
th
n
2
21
22
21
2
21
19
21
19
21
We know that the energy in n level is
13.6
E
n
13.6 13.6
EE
21
13.6
E E 13.6
2
13
E E 13.6 1 13.6 10.2 eV
44
E E 10.2 1.6 10 J
E E 16.32 10 J
Now, this difference in energ
?
?
? ? ? ?
? ?
? ? ? ?
?
? ? ? ?
21
19
21
34
15
y gives the energy of the photon emitted
E E h
EE 16.32 10
h 6.63 10
2.46 10 Hz
OR
The electron in the hydrogen atom jumps from n
2
= ? to n
1
= 1.
Now, we know that
??
??
??
??
??
?
??
??
? ? ? ? ? ?
??
??
??
? ? ? ? ? ? ?
?
? ? ?
22
12
77
8 10
7
o
1 1 1
R
nn
1 1 1
1.097 10 1.097 10
1
1
9.116 10 m 911.6 10 m
1.097 10
911.6 A
CBSE XII | PHYSICS
Board Paper – Solution
7. The drift speed is
?
d
I
v
neA
Now, we know that the current is given from Ohm’s law as
??
?
?
??
??
??
??
? ? ?
? ? ?
? ? ? ? ? ?
? ? ? ? ?
d
d
d
d
28 19 4
5
V
I
R
V
v
RneA
V
RA
nev
V RA
nev l l
RA
Now, resistivity is given as
l
V
nev l
5
8 10 1.6 10 2.5 10 0.1
1.56 10 m
8.
(i) The de Broglie wavelength is related to the accelerating potential as
?
??
? ? ? ?
?
?
??
? ? ?
??
?
? ? ? ?
?
??
? ? ? ?
p
pp
p
p p p p
p
h
2meV
h
2m e V
h
And,
2m e V
2m e V m e
h
h
2m e V m e
Now, mass and charge of particle is greater than that of proton.
for the same potential difference.
(ii) The kinetic energy is related to accelerating potential as
??
??
?
?
??
?
??
?
pp
pp
p
K.E. eV
K.E. e V
And, K.E. e V
K.E. e
K.E. e
Since, the charge on proton is less than that on alpha particle,
K.E. K.E. for the same potential difference.
CBSE XII | PHYSICS
Board Paper – Solution
9. The angle of the prism is A = 60 ?. It is also given that AQ = AR.
Therefore, the angles opposite to these two sides are also equal.
? ? ?
? ? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ? ? ? ? ?
? ? ? ?
12
12
AQR ARQ
Now, for a triangle
A AQR ARQ 180
AQR ARQ 60
r r 30 ( AQO ARO 90 )
r r 60
When r
1
and r
2
are equal, we have i = e.
Now, according to Snell’s law,
??
? ? ? ? ?
? ? ?
1
1
sini
sinr
3
sini sinr 3 sin30
2
i 60
Now, the angle of deviation ? is
? ? ? ?
? ? ? ? ?
? ? ? ?
i e A
60 60 60
60
10. The baseband signal is not transmitted directly because
(i) Its higher wavelength (low frequency) will require the size of the antenna or
aerial used for transmission to be very high.
(ii) For linear antenna (length l), the power radiated is proportional to
??
??
?
??
2
1
, and
hence, the effective power radiated by a long wavelength baseband signal would
be small.
CBSE XII | PHYSICS
Board Paper – Solution
SECTION – C
11.
(i) The distance between the object and the screen (image) is 100 cm.
Now, for the first position of the lens:
?
??
? ? ? ? ?
? ? ?
uu
v 100 u
1 1 1 1 1
...... (1)
f 100 u u 100 u u
Now, for the second position of the lens:
? ?
??
? ? ?
? ? ? ? ?
? ? ? ??
u u 20
v 100 u 20
1 1 1 1 1
...... (2)
f 80 u 80 u u 20 u 20
Therefore, from equations (1) and (2), we get
? ? ? ? ? ?
? ? ? ? ? ?
? ? ? ? ? ?
? ? ?
? ? ?
? ? ? ?
? ? ?
? ? ? ? ?
??
? ? ?
??
??
? ? ?
? ? ? ? ?
? ? ? ? ?
??
??
? ? ? ? ? ?
22
1 1 1 1
100 u u 80 u u 20
1 1 1 1
100 u 80 u u 20 u
80 u 100 u u u 20
100 u 80 u u u 20
20 20
100 u 80 u u u 20
u u 20 100 u 80 u
u 20u 8000 180u u
200u 8000
u 40 cm
v 100 u 100 40 60 cm
Therefore, from the lens for
? ? ? ? ? ?
?
?
? ? ?
??
mula
1 1 1 1 1 1 1
f v u 60 40 60 40
1 2 3 5
f 120 120
f 24 cm
Read More
|
26 videos|287 docs|64 tests
|
FAQs on CBSE Physics Past year paper (Solutions) - 2016, Class 12 - Additional Study Material for NEET
| 1. What is the format of the CBSE Physics exam for Class 12 in 2016? |  |
Ans. The CBSE Physics exam for Class 12 in 2016 had a total of 26 questions divided into two sections - A and B. Section A had 8 questions of 1 mark each, 10 questions of 2 marks each, and 3 questions of 3 marks each. Section B had 5 questions of 5 marks each. The total marks for the exam were 70.
| 2. How can I access the CBSE Physics past year paper solutions for Class 12, 2016? | |
Ans. The CBSE Physics past year paper solutions for Class 12, 2016 can be accessed through various online platforms. You can search for them on educational websites, forums, or even on the official CBSE website. These solutions are available in PDF format and can be downloaded for free.
| 3. What are some important topics to focus on while preparing for the CBSE Physics exam for Class 12, 2016? | |
Ans. Some important topics to focus on while preparing for the CBSE Physics exam for Class 12, 2016 include electrostatics, current electricity, magnetic effects of current and magnetism, electromagnetic induction and alternating currents, optics, dual nature of matter and radiation, atoms and nuclei, and electronic devices. These topics carry significant weightage in the exam and require thorough understanding and practice.
| 4. Are the CBSE Physics past year paper solutions for Class 12, 2016 helpful for exam preparation? | |
Ans. Yes, the CBSE Physics past year paper solutions for Class 12, 2016 are extremely helpful for exam preparation. By going through these solutions, you can understand the question pattern, marking scheme, and the approach to solving different types of questions. It also helps in identifying the areas where you need to improve and provides a good practice for time management during the actual exam.
| 5. Can I expect similar questions from the CBSE Physics past year paper for Class 12, 2016 in the upcoming exams? | |
Ans. While it is not guaranteed that the exact same questions will be repeated, studying the CBSE Physics past year paper for Class 12, 2016 can give you an idea of the type of questions and their level of difficulty that can be expected in the upcoming exams. It helps in familiarizing yourself with the exam pattern and allows you to practice solving similar questions, which can enhance your preparation and boost your confidence.
About this Document
|
4.63/5 Rating |
|
Oct 24, 2024 Last updated |
Document Description: CBSE Physics Past year paper (Solutions) - 2016, Class 12 for NEET 2024 is part of Additional Study Material for NEET preparation.
The notes and questions for CBSE Physics Past year paper (Solutions) - 2016, Class 12 have been prepared according to the NEET exam syllabus. Information about CBSE Physics Past year paper (Solutions) - 2016, Class 12 covers topics
like and CBSE Physics Past year paper (Solutions) - 2016, Class 12 Example, for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for CBSE Physics Past year paper (Solutions) - 2016, Class 12.
Introduction of CBSE Physics Past year paper (Solutions) - 2016, Class 12 in English is available as part of our Additional Study Material for NEET
for NEET & CBSE Physics Past year paper (Solutions) - 2016, Class 12 in Hindi for Additional Study Material for NEET course.
Download more important topics related with notes, lectures and mock test series for NEET
Exam by signing up for free. NEET: CBSE Physics Past year paper (Solutions) - 2016, Class 12 | Additional Study Material for NEET
Description
Full syllabus notes, lecture & questions for CBSE Physics Past year paper (Solutions) - 2016, Class 12 | Additional Study Material for NEET - NEET | Plus excerises question with solution to help you revise complete syllabus for Additional Study Material for NEET | Best notes, free PDF download
Information about CBSE Physics Past year paper (Solutions) - 2016, Class 12
In this doc you can find the meaning of CBSE Physics Past year paper (Solutions) - 2016, Class 12 defined & explained in the simplest way possible. Besides explaining types of
CBSE Physics Past year paper (Solutions) - 2016, Class 12 theory, EduRev gives you an ample number of questions to practice CBSE Physics Past year paper (Solutions) - 2016, Class 12 tests, examples and also practice NEET
tests
|
Explore Courses for NEET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Summary
,shortcuts and tricks
,practice quizzes
,past year papers
,Sample Paper
,Free
,CBSE Physics Past year paper (Solutions) - 2016
,MCQs
,Class 12 | Additional Study Material for NEET
,Class 12 | Additional Study Material for NEET
,Important questions
,Class 12 | Additional Study Material for NEET
,video lectures
,Objective type Questions
,Semester Notes
,Exam
,Extra Questions
,mock tests for examination
,CBSE Physics Past year paper (Solutions) - 2016
,CBSE Physics Past year paper (Solutions) - 2016
,ppt
,Previous Year Questions with Solutions
,Viva Questions
,study material
;
Additional Information about CBSE Physics Past year paper (Solutions) - 2016, Class 12 for NEET Preparation
CBSE Physics Past year paper (Solutions) - 2016, Class 12 Free PDF Download
The CBSE Physics Past year paper (Solutions) - 2016, Class 12 is an invaluable resource that delves deep into the core of the NEET exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the CBSE Physics Past year paper (Solutions) - 2016, Class 12 now and kickstart your journey towards success in the NEET exam.
Importance of CBSE Physics Past year paper (Solutions) - 2016, Class 12
The importance of CBSE Physics Past year paper (Solutions) - 2016, Class 12 cannot be overstated, especially for NEET aspirants.
This document holds the key to success in the NEET exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
CBSE Physics Past year paper (Solutions) - 2016, Class 12 Notes
CBSE Physics Past year paper (Solutions) - 2016, Class 12 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to CBSE Physics Past year paper (Solutions) - 2016, Class 12.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, CBSE Physics Past year paper (Solutions) - 2016, Class 12 Notes on EduRev are your ultimate resource for success.
CBSE Physics Past year paper (Solutions) - 2016, Class 12 NEET Questions
The "CBSE Physics Past year paper (Solutions) - 2016, Class 12 NEET Questions" guide is a valuable resource for all aspiring students preparing for the
NEET exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study CBSE Physics Past year paper (Solutions) - 2016, Class 12 on the App
Students of NEET can study CBSE Physics Past year paper (Solutions) - 2016, Class 12 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the CBSE Physics Past year paper (Solutions) - 2016, Class 12,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of CBSE Physics Past year paper (Solutions) - 2016, Class 12 is prepared as per the latest NEET syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup