Class 8 Exam > Class 8 Notes > Mathematics (Maths) Class 8 > RS Aggarwal Solutions: Exercise 10A - Profit & Loss
RS Aggarwal Solutions: Exercise 10A - Profit & Loss | Mathematics (Maths) Class 8 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
Question:1
Find the gain or loss per cent when:
i
CP = Rs 620 and SP = Rs 713
ii
CP = Rs 675 and SP = Rs 630
iii
CP = Rs 345 and SP = Rs 372.60
iv
CP = Rs 80 and SP = Rs 76.80
Solution:
i CP = Rs. 620 SP = Rs. 713Since SP > CP, there is a gain. Gain = 713 - 620 = Rs. 93Gain percentage =
gain
CP
×100 % =
93
620
×100 % = 15 %
ii
CP = Rs 675 SP = Rs 630Since SP < CP, there is a loss. Loss = 675 - 630 = Rs. 45Loss percentage =
Loss
CP
×100 % =
45
675
×100 % = 6
2
3
%
iii
CP = Rs. 345 SP = Rs. 372. 60Since SP > CP, there is a gain. Gain = 372. 60 - 345 = Rs. 27. 6Gain percentage =
gain
CP
×100 % =
27.6
345
×100 % =
2760
345
%
iv
CP = Rs 80 SP = Rs 76. 80Since SP < CP, there is a loss. Loss = 80 - 76. 80 = Rs. 3. 2Loss percentage =
loss
CP
×100 % =
3.2
80
×100 % =
32
80
×
Question:2
Find the selling price when:
i
CP = Rs 1650 and gain% = 4%
ii
CP = Rs 915 and gain% = 6
2
3
%
iii
CP = Rs 875 and loss% = 12%
iv
CP = Rs 645 and loss% = 13
1
3
%
Solution:
i
CP = Rs. 1650Gain percentage = 4 %SP =
(100+gain %)
100
×CP =
(100+4)
100
×1650 =
104×1650
100
= Rs. 1716
ii
CP = Rs. 915Gain percentage = 6
2
3
% =
20
3
%SP =
(100+gain %)
100
×CP =
100+
20
3
100
×915 =
320
3
100
×915 =
320
3
×
1
100
×915 = Rs. 976
iii
CP = Rs. 875Loss percentage = 12 %SP =
(100-loss %)
100
×CP =
(100-12)
100
×875 =
77000
100
= Rs. 770
iv
CP = Rs. 645Loss percentage = 13
1
3
% =
40
3
%SP =
(100-loss %)
100
×CP =
100-
40
3
100
×645 =
300-40
3
100
×645 =
260
3
×
1
100
×645 = Rs. 559
Question:3
Find the cost price when:
i
SP = Rs 1596 and gain% = 12%
ii
SP = Rs 2431 and loss% = 6
1
2
%
iii
SP = Rs 657.60 and loss% = 4%
iv
SP = Rs 34.40 and gain% = 7
1
2
%
( ) ( ) ( )
( ) ( )
( ) ( ) ( )
( ) ( ) (
( ) ( )
( ) ( )
( ) ( )
( ) ( )
Page 2
Question:1
Find the gain or loss per cent when:
i
CP = Rs 620 and SP = Rs 713
ii
CP = Rs 675 and SP = Rs 630
iii
CP = Rs 345 and SP = Rs 372.60
iv
CP = Rs 80 and SP = Rs 76.80
Solution:
i CP = Rs. 620 SP = Rs. 713Since SP > CP, there is a gain. Gain = 713 - 620 = Rs. 93Gain percentage =
gain
CP
×100 % =
93
620
×100 % = 15 %
ii
CP = Rs 675 SP = Rs 630Since SP < CP, there is a loss. Loss = 675 - 630 = Rs. 45Loss percentage =
Loss
CP
×100 % =
45
675
×100 % = 6
2
3
%
iii
CP = Rs. 345 SP = Rs. 372. 60Since SP > CP, there is a gain. Gain = 372. 60 - 345 = Rs. 27. 6Gain percentage =
gain
CP
×100 % =
27.6
345
×100 % =
2760
345
%
iv
CP = Rs 80 SP = Rs 76. 80Since SP < CP, there is a loss. Loss = 80 - 76. 80 = Rs. 3. 2Loss percentage =
loss
CP
×100 % =
3.2
80
×100 % =
32
80
×
Question:2
Find the selling price when:
i
CP = Rs 1650 and gain% = 4%
ii
CP = Rs 915 and gain% = 6
2
3
%
iii
CP = Rs 875 and loss% = 12%
iv
CP = Rs 645 and loss% = 13
1
3
%
Solution:
i
CP = Rs. 1650Gain percentage = 4 %SP =
(100+gain %)
100
×CP =
(100+4)
100
×1650 =
104×1650
100
= Rs. 1716
ii
CP = Rs. 915Gain percentage = 6
2
3
% =
20
3
%SP =
(100+gain %)
100
×CP =
100+
20
3
100
×915 =
320
3
100
×915 =
320
3
×
1
100
×915 = Rs. 976
iii
CP = Rs. 875Loss percentage = 12 %SP =
(100-loss %)
100
×CP =
(100-12)
100
×875 =
77000
100
= Rs. 770
iv
CP = Rs. 645Loss percentage = 13
1
3
% =
40
3
%SP =
(100-loss %)
100
×CP =
100-
40
3
100
×645 =
300-40
3
100
×645 =
260
3
×
1
100
×645 = Rs. 559
Question:3
Find the cost price when:
i
SP = Rs 1596 and gain% = 12%
ii
SP = Rs 2431 and loss% = 6
1
2
%
iii
SP = Rs 657.60 and loss% = 4%
iv
SP = Rs 34.40 and gain% = 7
1
2
%
( ) ( ) ( )
( ) ( )
( ) ( ) ( )
( ) ( ) (
( ) ( )
( ) ( )
( ) ( )
( ) ( )
Solution:
i SP = Rs. 1596Gain percentage = 12 %CP =
100
(100+gain %)
×SP =
100
(100+12)
×1596 = Rs. 1425
ii
SP = Rs. 2431 Loss percentage = 6
1
2
% =
13
2
%CP =
100
(100-loss %)
×SP =
100
100-
13
2
×2431 =
100×2
187
×2431 = Rs. 2600
iii
SP = Rs. 657. 60 Loss percentage = 4 %CP =
100
(100-loss %)
×SP =
100
(100-4)
×657. 60 = Rs. 685
iv
SP = Rs. 34. 40 Gain percentage = 7
1
2
% =
15
2
%CP =
100
(100+gain %)
×SP =
100
100+
15
2
×34. 40 =
100×2
215
×34. 40 = Rs. 32
Question:4
Manjit bought an iron safe for 12160 and paid 340 for its transportation. Then, he sold it for 12875. Find his gain per cent
Solution:
CP of the iron safe = 12,160
Money spent on transportation = 340
Total CP = 12,160 + 340 = 12,500
SP of the iron safe = 12,875
Profit = SP - CP = 12,875 - 12,500 = 375
? Profit% =
Profit
CP
×100 %
=
375
12500
×100 % = 3 %
Question:5
Robin purchased an old car for Rs 73500. He spent Rs 10300 on repairs and paid Rs 2600 for its insurance. Then he sold it to a mechanic for Rs 84240. What was his percentage gain or
loss?
Solution:
CP of the car = Rs. 73500Repairs = Rs. 10300Insurance = Rs. 2600Total CP = 73500 +10300 +2600 = Rs. 86400SP = Rs. 84240Since SP < CP, Robin has a loss. Loss = 86400 -84240
Question:6
Hari bought 20 kg of rice at 36 per kg and 25 kg of rice at 32 per kg. He mixed the two varieties and sold the mixture at 38 per kg. Find his gain per cent in the whole transaction.
Solution:
Total cost of rice of 1st variety = 36/kg × 20 kg = 720
Total cost of rice of 2nd variety = 32/kg × 25 kg = 800
Total cost of the two rice varieties = 720 + 800 = 1,520
Total quantity of the two rice varieties = 20 kg + 25 kg = 45 kg
Selling price of the mixture of two rice = 38/kg × 45 kg = 1,710
Gain = SP - CP = 1,710 - 1,520 = 190
Gain% =
Gain
CP
×100 % =
190
1520
×100 % = 12
1
2
%
Question:7
Coffee costing Rs 250 per kg was mixed with chicory costing Rs 75 per kg in the ratio 5 : 2 for a certain blend. If the mixture was sold at Rs 230 per kg, find the gain or loss per cent.
Solution:
Let 5 kg of coffee be mixed with 2 kg of chicory. CP of the mixture = Rs 250 ×5 +75 ×2 = Rs 1250 +150 = Rs. 1400SP of the mixture = Rs 7 ×230 = Rs. 1610Since SP > CP, there
Question:8
If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain per cent earned by the dealer.
Solution:
Let Rs x be the SP of each bottle and Rs y be the CP of each bottle. SP of 16 bottles = CP of 17 bottles ? 16x = 17y ?
x
y
=
17
16
Gain per bottle = SP -CP = Rs x -y ? Gain percentage =
Question:9
The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss per cent.
Solution:
Let Rs x be the CP of one candle and Rs. y be the SP of one candle. Now, CP of 12 candles = SP of 15 candles ? 12x = 15y ?
y
x
=
12
15
Loss = CP -SP = Rs x -y ? Loss percentage =
Question:10
By selling 130 cassettes, a man gains an amount equal to the selling price of 5 cassettes. Find the gain per cent.
Solution:
It is given that,
Gain = SP of 5 cassettes .....1
( )
( )
( )
( ) ( ) ( )
( )
( )
Page 3
Question:1
Find the gain or loss per cent when:
i
CP = Rs 620 and SP = Rs 713
ii
CP = Rs 675 and SP = Rs 630
iii
CP = Rs 345 and SP = Rs 372.60
iv
CP = Rs 80 and SP = Rs 76.80
Solution:
i CP = Rs. 620 SP = Rs. 713Since SP > CP, there is a gain. Gain = 713 - 620 = Rs. 93Gain percentage =
gain
CP
×100 % =
93
620
×100 % = 15 %
ii
CP = Rs 675 SP = Rs 630Since SP < CP, there is a loss. Loss = 675 - 630 = Rs. 45Loss percentage =
Loss
CP
×100 % =
45
675
×100 % = 6
2
3
%
iii
CP = Rs. 345 SP = Rs. 372. 60Since SP > CP, there is a gain. Gain = 372. 60 - 345 = Rs. 27. 6Gain percentage =
gain
CP
×100 % =
27.6
345
×100 % =
2760
345
%
iv
CP = Rs 80 SP = Rs 76. 80Since SP < CP, there is a loss. Loss = 80 - 76. 80 = Rs. 3. 2Loss percentage =
loss
CP
×100 % =
3.2
80
×100 % =
32
80
×
Question:2
Find the selling price when:
i
CP = Rs 1650 and gain% = 4%
ii
CP = Rs 915 and gain% = 6
2
3
%
iii
CP = Rs 875 and loss% = 12%
iv
CP = Rs 645 and loss% = 13
1
3
%
Solution:
i
CP = Rs. 1650Gain percentage = 4 %SP =
(100+gain %)
100
×CP =
(100+4)
100
×1650 =
104×1650
100
= Rs. 1716
ii
CP = Rs. 915Gain percentage = 6
2
3
% =
20
3
%SP =
(100+gain %)
100
×CP =
100+
20
3
100
×915 =
320
3
100
×915 =
320
3
×
1
100
×915 = Rs. 976
iii
CP = Rs. 875Loss percentage = 12 %SP =
(100-loss %)
100
×CP =
(100-12)
100
×875 =
77000
100
= Rs. 770
iv
CP = Rs. 645Loss percentage = 13
1
3
% =
40
3
%SP =
(100-loss %)
100
×CP =
100-
40
3
100
×645 =
300-40
3
100
×645 =
260
3
×
1
100
×645 = Rs. 559
Question:3
Find the cost price when:
i
SP = Rs 1596 and gain% = 12%
ii
SP = Rs 2431 and loss% = 6
1
2
%
iii
SP = Rs 657.60 and loss% = 4%
iv
SP = Rs 34.40 and gain% = 7
1
2
%
( ) ( ) ( )
( ) ( )
( ) ( ) ( )
( ) ( ) (
( ) ( )
( ) ( )
( ) ( )
( ) ( )
Solution:
i SP = Rs. 1596Gain percentage = 12 %CP =
100
(100+gain %)
×SP =
100
(100+12)
×1596 = Rs. 1425
ii
SP = Rs. 2431 Loss percentage = 6
1
2
% =
13
2
%CP =
100
(100-loss %)
×SP =
100
100-
13
2
×2431 =
100×2
187
×2431 = Rs. 2600
iii
SP = Rs. 657. 60 Loss percentage = 4 %CP =
100
(100-loss %)
×SP =
100
(100-4)
×657. 60 = Rs. 685
iv
SP = Rs. 34. 40 Gain percentage = 7
1
2
% =
15
2
%CP =
100
(100+gain %)
×SP =
100
100+
15
2
×34. 40 =
100×2
215
×34. 40 = Rs. 32
Question:4
Manjit bought an iron safe for 12160 and paid 340 for its transportation. Then, he sold it for 12875. Find his gain per cent
Solution:
CP of the iron safe = 12,160
Money spent on transportation = 340
Total CP = 12,160 + 340 = 12,500
SP of the iron safe = 12,875
Profit = SP - CP = 12,875 - 12,500 = 375
? Profit% =
Profit
CP
×100 %
=
375
12500
×100 % = 3 %
Question:5
Robin purchased an old car for Rs 73500. He spent Rs 10300 on repairs and paid Rs 2600 for its insurance. Then he sold it to a mechanic for Rs 84240. What was his percentage gain or
loss?
Solution:
CP of the car = Rs. 73500Repairs = Rs. 10300Insurance = Rs. 2600Total CP = 73500 +10300 +2600 = Rs. 86400SP = Rs. 84240Since SP < CP, Robin has a loss. Loss = 86400 -84240
Question:6
Hari bought 20 kg of rice at 36 per kg and 25 kg of rice at 32 per kg. He mixed the two varieties and sold the mixture at 38 per kg. Find his gain per cent in the whole transaction.
Solution:
Total cost of rice of 1st variety = 36/kg × 20 kg = 720
Total cost of rice of 2nd variety = 32/kg × 25 kg = 800
Total cost of the two rice varieties = 720 + 800 = 1,520
Total quantity of the two rice varieties = 20 kg + 25 kg = 45 kg
Selling price of the mixture of two rice = 38/kg × 45 kg = 1,710
Gain = SP - CP = 1,710 - 1,520 = 190
Gain% =
Gain
CP
×100 % =
190
1520
×100 % = 12
1
2
%
Question:7
Coffee costing Rs 250 per kg was mixed with chicory costing Rs 75 per kg in the ratio 5 : 2 for a certain blend. If the mixture was sold at Rs 230 per kg, find the gain or loss per cent.
Solution:
Let 5 kg of coffee be mixed with 2 kg of chicory. CP of the mixture = Rs 250 ×5 +75 ×2 = Rs 1250 +150 = Rs. 1400SP of the mixture = Rs 7 ×230 = Rs. 1610Since SP > CP, there
Question:8
If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain per cent earned by the dealer.
Solution:
Let Rs x be the SP of each bottle and Rs y be the CP of each bottle. SP of 16 bottles = CP of 17 bottles ? 16x = 17y ?
x
y
=
17
16
Gain per bottle = SP -CP = Rs x -y ? Gain percentage =
Question:9
The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss per cent.
Solution:
Let Rs x be the CP of one candle and Rs. y be the SP of one candle. Now, CP of 12 candles = SP of 15 candles ? 12x = 15y ?
y
x
=
12
15
Loss = CP -SP = Rs x -y ? Loss percentage =
Question:10
By selling 130 cassettes, a man gains an amount equal to the selling price of 5 cassettes. Find the gain per cent.
Solution:
It is given that,
Gain = SP of 5 cassettes .....1
( )
( )
( )
( ) ( ) ( )
( )
( )
Gain = SP of 130 cassettes - CP of 130 cassettes
? SP of 5 cassettes = SP of 130 cassettes - CP of 130 cassettes
From(1)
? CP of 130 cassettes = SP of 125 cassettes .....2
Let the CP of 1 cassettte be x.
? CP of 125 cassettes = 125x
CP of 130 cassettes = 130x
SP of 125 cassettes = CP of 130 cassettes
From(2)
? SP of 125 cassettes = 130x
Now, gain% =
SP-CP
CP
×100 % =
(130x-125x)
125x
×100 %
=
5x
125x
×100 % = 4 %
Thus, the gain percent is 4%.
Question:11
By selling 45 lemons, a vendor loses a sum equal to the selling price of 3 lemons. Find his loss per cent.
Solution:
Let Rs x be the SP of one lemon. SP of 45 lemons = Rs. 45xLoss = SP of 3 lemons = Rs. 3xBut loss = CP -SPCP = loss +SP = 3x +45x = Rs. 48x ? Loss percentage =
loss
CP
×100 % =
Question:12
Oranges are bought at 6 for 20 and sold at 4 for 18. Find the gain or loss per cent.
Solution:
LCM of 6 and 4 = 12
Let the number of oranges bought be 12.
CP of 6 oranges = 20
So, CP of 1 orange =
20
6
=
10
3
CP of 12 orange = 12 ×
10
3
= 40
SP of 4 oranges = 18
SP of 1 orange =
18
4
=
9
2
SP of 12 oranges = 12 ×
9
2
= 54
Here, SP of 12 oranges > CP of 12 oranges.
Profit = SP - CP = 54 - 40 = 14
? Profit% =
Profit
CP
×100 % =
14
40
×100 % = 35 %
Question:13
A vendor purchased bananas at 40 per dozen and sold them at 10 for 36. Find his gain or loss per cent.
Solution:
LCM of 12 and 10 = 60
Let the number of banana bought be 60.
CP of 12 banana = 40
? CP of 1 banana =
40
12
=
10
3
? CP of 60 bananas = 60 ×
10
3
= 200
SP of 10 bananas = 36
? SP of 1 banana =
36
10
=
18
5
? SP of 60 bananas = 60 ×
18
5
= 216
Here, SP of 60 bananas > CP of 60 bananas.
Profit = SP - CP = 216 - 200 = 16
? Profit% =
Profit
CP
×100 % =
16
200
×100 = 8 %
Question:14
A man bought apples at 10 for 75 and sold them at 75 per dozen. Find his loss per cent.
Solution:
LCM of 10 and 12 = 60
Let the number of apples bought be 60.
CP of 10 oranges = 75
? CP of 1 orange =
75
10
? CP of 60 orange = 60 ×
75
10
= 450
SP of 12 oranges = 75
? SP of 1 orange =
75
12
? SP of 60 oranges = 60 ×
75
12
= 375
( )
Page 4
Question:1
Find the gain or loss per cent when:
i
CP = Rs 620 and SP = Rs 713
ii
CP = Rs 675 and SP = Rs 630
iii
CP = Rs 345 and SP = Rs 372.60
iv
CP = Rs 80 and SP = Rs 76.80
Solution:
i CP = Rs. 620 SP = Rs. 713Since SP > CP, there is a gain. Gain = 713 - 620 = Rs. 93Gain percentage =
gain
CP
×100 % =
93
620
×100 % = 15 %
ii
CP = Rs 675 SP = Rs 630Since SP < CP, there is a loss. Loss = 675 - 630 = Rs. 45Loss percentage =
Loss
CP
×100 % =
45
675
×100 % = 6
2
3
%
iii
CP = Rs. 345 SP = Rs. 372. 60Since SP > CP, there is a gain. Gain = 372. 60 - 345 = Rs. 27. 6Gain percentage =
gain
CP
×100 % =
27.6
345
×100 % =
2760
345
%
iv
CP = Rs 80 SP = Rs 76. 80Since SP < CP, there is a loss. Loss = 80 - 76. 80 = Rs. 3. 2Loss percentage =
loss
CP
×100 % =
3.2
80
×100 % =
32
80
×
Question:2
Find the selling price when:
i
CP = Rs 1650 and gain% = 4%
ii
CP = Rs 915 and gain% = 6
2
3
%
iii
CP = Rs 875 and loss% = 12%
iv
CP = Rs 645 and loss% = 13
1
3
%
Solution:
i
CP = Rs. 1650Gain percentage = 4 %SP =
(100+gain %)
100
×CP =
(100+4)
100
×1650 =
104×1650
100
= Rs. 1716
ii
CP = Rs. 915Gain percentage = 6
2
3
% =
20
3
%SP =
(100+gain %)
100
×CP =
100+
20
3
100
×915 =
320
3
100
×915 =
320
3
×
1
100
×915 = Rs. 976
iii
CP = Rs. 875Loss percentage = 12 %SP =
(100-loss %)
100
×CP =
(100-12)
100
×875 =
77000
100
= Rs. 770
iv
CP = Rs. 645Loss percentage = 13
1
3
% =
40
3
%SP =
(100-loss %)
100
×CP =
100-
40
3
100
×645 =
300-40
3
100
×645 =
260
3
×
1
100
×645 = Rs. 559
Question:3
Find the cost price when:
i
SP = Rs 1596 and gain% = 12%
ii
SP = Rs 2431 and loss% = 6
1
2
%
iii
SP = Rs 657.60 and loss% = 4%
iv
SP = Rs 34.40 and gain% = 7
1
2
%
( ) ( ) ( )
( ) ( )
( ) ( ) ( )
( ) ( ) (
( ) ( )
( ) ( )
( ) ( )
( ) ( )
Solution:
i SP = Rs. 1596Gain percentage = 12 %CP =
100
(100+gain %)
×SP =
100
(100+12)
×1596 = Rs. 1425
ii
SP = Rs. 2431 Loss percentage = 6
1
2
% =
13
2
%CP =
100
(100-loss %)
×SP =
100
100-
13
2
×2431 =
100×2
187
×2431 = Rs. 2600
iii
SP = Rs. 657. 60 Loss percentage = 4 %CP =
100
(100-loss %)
×SP =
100
(100-4)
×657. 60 = Rs. 685
iv
SP = Rs. 34. 40 Gain percentage = 7
1
2
% =
15
2
%CP =
100
(100+gain %)
×SP =
100
100+
15
2
×34. 40 =
100×2
215
×34. 40 = Rs. 32
Question:4
Manjit bought an iron safe for 12160 and paid 340 for its transportation. Then, he sold it for 12875. Find his gain per cent
Solution:
CP of the iron safe = 12,160
Money spent on transportation = 340
Total CP = 12,160 + 340 = 12,500
SP of the iron safe = 12,875
Profit = SP - CP = 12,875 - 12,500 = 375
? Profit% =
Profit
CP
×100 %
=
375
12500
×100 % = 3 %
Question:5
Robin purchased an old car for Rs 73500. He spent Rs 10300 on repairs and paid Rs 2600 for its insurance. Then he sold it to a mechanic for Rs 84240. What was his percentage gain or
loss?
Solution:
CP of the car = Rs. 73500Repairs = Rs. 10300Insurance = Rs. 2600Total CP = 73500 +10300 +2600 = Rs. 86400SP = Rs. 84240Since SP < CP, Robin has a loss. Loss = 86400 -84240
Question:6
Hari bought 20 kg of rice at 36 per kg and 25 kg of rice at 32 per kg. He mixed the two varieties and sold the mixture at 38 per kg. Find his gain per cent in the whole transaction.
Solution:
Total cost of rice of 1st variety = 36/kg × 20 kg = 720
Total cost of rice of 2nd variety = 32/kg × 25 kg = 800
Total cost of the two rice varieties = 720 + 800 = 1,520
Total quantity of the two rice varieties = 20 kg + 25 kg = 45 kg
Selling price of the mixture of two rice = 38/kg × 45 kg = 1,710
Gain = SP - CP = 1,710 - 1,520 = 190
Gain% =
Gain
CP
×100 % =
190
1520
×100 % = 12
1
2
%
Question:7
Coffee costing Rs 250 per kg was mixed with chicory costing Rs 75 per kg in the ratio 5 : 2 for a certain blend. If the mixture was sold at Rs 230 per kg, find the gain or loss per cent.
Solution:
Let 5 kg of coffee be mixed with 2 kg of chicory. CP of the mixture = Rs 250 ×5 +75 ×2 = Rs 1250 +150 = Rs. 1400SP of the mixture = Rs 7 ×230 = Rs. 1610Since SP > CP, there
Question:8
If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain per cent earned by the dealer.
Solution:
Let Rs x be the SP of each bottle and Rs y be the CP of each bottle. SP of 16 bottles = CP of 17 bottles ? 16x = 17y ?
x
y
=
17
16
Gain per bottle = SP -CP = Rs x -y ? Gain percentage =
Question:9
The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss per cent.
Solution:
Let Rs x be the CP of one candle and Rs. y be the SP of one candle. Now, CP of 12 candles = SP of 15 candles ? 12x = 15y ?
y
x
=
12
15
Loss = CP -SP = Rs x -y ? Loss percentage =
Question:10
By selling 130 cassettes, a man gains an amount equal to the selling price of 5 cassettes. Find the gain per cent.
Solution:
It is given that,
Gain = SP of 5 cassettes .....1
( )
( )
( )
( ) ( ) ( )
( )
( )
Gain = SP of 130 cassettes - CP of 130 cassettes
? SP of 5 cassettes = SP of 130 cassettes - CP of 130 cassettes
From(1)
? CP of 130 cassettes = SP of 125 cassettes .....2
Let the CP of 1 cassettte be x.
? CP of 125 cassettes = 125x
CP of 130 cassettes = 130x
SP of 125 cassettes = CP of 130 cassettes
From(2)
? SP of 125 cassettes = 130x
Now, gain% =
SP-CP
CP
×100 % =
(130x-125x)
125x
×100 %
=
5x
125x
×100 % = 4 %
Thus, the gain percent is 4%.
Question:11
By selling 45 lemons, a vendor loses a sum equal to the selling price of 3 lemons. Find his loss per cent.
Solution:
Let Rs x be the SP of one lemon. SP of 45 lemons = Rs. 45xLoss = SP of 3 lemons = Rs. 3xBut loss = CP -SPCP = loss +SP = 3x +45x = Rs. 48x ? Loss percentage =
loss
CP
×100 % =
Question:12
Oranges are bought at 6 for 20 and sold at 4 for 18. Find the gain or loss per cent.
Solution:
LCM of 6 and 4 = 12
Let the number of oranges bought be 12.
CP of 6 oranges = 20
So, CP of 1 orange =
20
6
=
10
3
CP of 12 orange = 12 ×
10
3
= 40
SP of 4 oranges = 18
SP of 1 orange =
18
4
=
9
2
SP of 12 oranges = 12 ×
9
2
= 54
Here, SP of 12 oranges > CP of 12 oranges.
Profit = SP - CP = 54 - 40 = 14
? Profit% =
Profit
CP
×100 % =
14
40
×100 % = 35 %
Question:13
A vendor purchased bananas at 40 per dozen and sold them at 10 for 36. Find his gain or loss per cent.
Solution:
LCM of 12 and 10 = 60
Let the number of banana bought be 60.
CP of 12 banana = 40
? CP of 1 banana =
40
12
=
10
3
? CP of 60 bananas = 60 ×
10
3
= 200
SP of 10 bananas = 36
? SP of 1 banana =
36
10
=
18
5
? SP of 60 bananas = 60 ×
18
5
= 216
Here, SP of 60 bananas > CP of 60 bananas.
Profit = SP - CP = 216 - 200 = 16
? Profit% =
Profit
CP
×100 % =
16
200
×100 = 8 %
Question:14
A man bought apples at 10 for 75 and sold them at 75 per dozen. Find his loss per cent.
Solution:
LCM of 10 and 12 = 60
Let the number of apples bought be 60.
CP of 10 oranges = 75
? CP of 1 orange =
75
10
? CP of 60 orange = 60 ×
75
10
= 450
SP of 12 oranges = 75
? SP of 1 orange =
75
12
? SP of 60 oranges = 60 ×
75
12
= 375
( )
Here, CP of 60 oranges > SP of 60 oranges.
Loss = CP - SP = 450 - 375 = 75
? Loss% =
Loss
CP
×100 % =
75
450
×100 % = 16
2
3
%
Question:15
A man purchased some eggs at 3 for 16 and sold them at 5 for 36. Thus, he gained 168 in all. How many eggs did he purchase?
Solution:
Let the number of eggs purchased be x.
CP of 3 eggs = 16
? CP of 1 egg =
16
3
? CP of x eggs =
16
3
x
SP of 5 eggs = 36
? SP of 1 egg =
36
5
? SP of x eggs =
36
5
x
Gain = SP - CP = 168
?
36
5
x -
16
3
x = 168 ?
28
15
x = 168 ? x =
168×15
28
? x = 90
Hence, the man purchased 90 eggs.
Question:16
A dealer sold a camera for Rs 1080 gaining
1
8
of its cost price. Find i
the cost price of the camera, and ii
the gain per cent earned by the dealer.
Solution:
SP of the camera = Rs. 1080Let Rs x be the CP. Gain = Rs.
1
8
x . . . i Also, gain = SP -CP = Rs. 1080 -x . . . ii From i and ii , we have:
1
8
x = 1080 -x ? x = 8640
Question:17
Meenakshi sells a pen for Rs 54 and loses
1
10
of her outlay. Find i
the cost price of the pen, and ii
the loss per cent.
Solution:
SP of the pen = Rs. 54Let Rs x be the CP of the pen. Loss = Rs.
x
10
SP = CP -Loss = x -
x
10
= Rs.
9x
10
Now, we have
9x
10
= 54 ? x = 54 ×
10
9
? x = 60 ? CP of the pen = Rs. 60Now, loss =
Question:18
A dealer gets 940 more if instead of selling a table at a loss of 10%, it is sold at a gain of 10%. Find the cost price of the table.
Solution:
Let the cost price be x.
Loss = 10% of x =
10
100
x =
x
10
SP in case of loss = CP - Loss = x -
x
10
=
9x
10
Gain =10% of x =
10
100
x =
x
10
SP in case of profit = CP + Profit = x +
x
10
=
11x
10
It is given that dealer gets 940 more if sold at a profit of 10% instead of loss of 10%.
? SP in case of profit - SP in case of loss = 940
?
11x
10
-
9x
10
= 940 ?
2x
10
= 940 ? x = 4700
Hence, the cost price of the table is 4,700.
Question:19
A dealer gets Rs 56 less if instead of selling a chair at a gain of 15%, it is sold at a gain of 8%. Find the cost price of the chair.
Solution:
Let Rs x be the CP. Gain
1
percentage =
gain 1
CP
×100 % ? 15 =
gain 1
x
×100 ? Gain
1
= Rs
15x
100
Again, gain
2
percentage =
gain 2
CP
×100 % ? 8 =
gain 2
x
×100 ? Gain
2
= Rs
8x
100
According to the question
Question:20
A cycle was sold at a gain of 10%. Had it been sold for 260 more, the gain would have been 14%. Find the cost price of the cycle.
Solution:
Let the CP be x.
SP when gain is 10% = x +
10
100
x =
110
100
x
SP when gain is 14% = x +
14
100
x =
114
100
x
Difference in SP = SP when gain is 14% - SP when gain is 10% = 260
( ) ( ) ( ) ( ) ( )
( ) ( )
Page 5
Question:1
Find the gain or loss per cent when:
i
CP = Rs 620 and SP = Rs 713
ii
CP = Rs 675 and SP = Rs 630
iii
CP = Rs 345 and SP = Rs 372.60
iv
CP = Rs 80 and SP = Rs 76.80
Solution:
i CP = Rs. 620 SP = Rs. 713Since SP > CP, there is a gain. Gain = 713 - 620 = Rs. 93Gain percentage =
gain
CP
×100 % =
93
620
×100 % = 15 %
ii
CP = Rs 675 SP = Rs 630Since SP < CP, there is a loss. Loss = 675 - 630 = Rs. 45Loss percentage =
Loss
CP
×100 % =
45
675
×100 % = 6
2
3
%
iii
CP = Rs. 345 SP = Rs. 372. 60Since SP > CP, there is a gain. Gain = 372. 60 - 345 = Rs. 27. 6Gain percentage =
gain
CP
×100 % =
27.6
345
×100 % =
2760
345
%
iv
CP = Rs 80 SP = Rs 76. 80Since SP < CP, there is a loss. Loss = 80 - 76. 80 = Rs. 3. 2Loss percentage =
loss
CP
×100 % =
3.2
80
×100 % =
32
80
×
Question:2
Find the selling price when:
i
CP = Rs 1650 and gain% = 4%
ii
CP = Rs 915 and gain% = 6
2
3
%
iii
CP = Rs 875 and loss% = 12%
iv
CP = Rs 645 and loss% = 13
1
3
%
Solution:
i
CP = Rs. 1650Gain percentage = 4 %SP =
(100+gain %)
100
×CP =
(100+4)
100
×1650 =
104×1650
100
= Rs. 1716
ii
CP = Rs. 915Gain percentage = 6
2
3
% =
20
3
%SP =
(100+gain %)
100
×CP =
100+
20
3
100
×915 =
320
3
100
×915 =
320
3
×
1
100
×915 = Rs. 976
iii
CP = Rs. 875Loss percentage = 12 %SP =
(100-loss %)
100
×CP =
(100-12)
100
×875 =
77000
100
= Rs. 770
iv
CP = Rs. 645Loss percentage = 13
1
3
% =
40
3
%SP =
(100-loss %)
100
×CP =
100-
40
3
100
×645 =
300-40
3
100
×645 =
260
3
×
1
100
×645 = Rs. 559
Question:3
Find the cost price when:
i
SP = Rs 1596 and gain% = 12%
ii
SP = Rs 2431 and loss% = 6
1
2
%
iii
SP = Rs 657.60 and loss% = 4%
iv
SP = Rs 34.40 and gain% = 7
1
2
%
( ) ( ) ( )
( ) ( )
( ) ( ) ( )
( ) ( ) (
( ) ( )
( ) ( )
( ) ( )
( ) ( )
Solution:
i SP = Rs. 1596Gain percentage = 12 %CP =
100
(100+gain %)
×SP =
100
(100+12)
×1596 = Rs. 1425
ii
SP = Rs. 2431 Loss percentage = 6
1
2
% =
13
2
%CP =
100
(100-loss %)
×SP =
100
100-
13
2
×2431 =
100×2
187
×2431 = Rs. 2600
iii
SP = Rs. 657. 60 Loss percentage = 4 %CP =
100
(100-loss %)
×SP =
100
(100-4)
×657. 60 = Rs. 685
iv
SP = Rs. 34. 40 Gain percentage = 7
1
2
% =
15
2
%CP =
100
(100+gain %)
×SP =
100
100+
15
2
×34. 40 =
100×2
215
×34. 40 = Rs. 32
Question:4
Manjit bought an iron safe for 12160 and paid 340 for its transportation. Then, he sold it for 12875. Find his gain per cent
Solution:
CP of the iron safe = 12,160
Money spent on transportation = 340
Total CP = 12,160 + 340 = 12,500
SP of the iron safe = 12,875
Profit = SP - CP = 12,875 - 12,500 = 375
? Profit% =
Profit
CP
×100 %
=
375
12500
×100 % = 3 %
Question:5
Robin purchased an old car for Rs 73500. He spent Rs 10300 on repairs and paid Rs 2600 for its insurance. Then he sold it to a mechanic for Rs 84240. What was his percentage gain or
loss?
Solution:
CP of the car = Rs. 73500Repairs = Rs. 10300Insurance = Rs. 2600Total CP = 73500 +10300 +2600 = Rs. 86400SP = Rs. 84240Since SP < CP, Robin has a loss. Loss = 86400 -84240
Question:6
Hari bought 20 kg of rice at 36 per kg and 25 kg of rice at 32 per kg. He mixed the two varieties and sold the mixture at 38 per kg. Find his gain per cent in the whole transaction.
Solution:
Total cost of rice of 1st variety = 36/kg × 20 kg = 720
Total cost of rice of 2nd variety = 32/kg × 25 kg = 800
Total cost of the two rice varieties = 720 + 800 = 1,520
Total quantity of the two rice varieties = 20 kg + 25 kg = 45 kg
Selling price of the mixture of two rice = 38/kg × 45 kg = 1,710
Gain = SP - CP = 1,710 - 1,520 = 190
Gain% =
Gain
CP
×100 % =
190
1520
×100 % = 12
1
2
%
Question:7
Coffee costing Rs 250 per kg was mixed with chicory costing Rs 75 per kg in the ratio 5 : 2 for a certain blend. If the mixture was sold at Rs 230 per kg, find the gain or loss per cent.
Solution:
Let 5 kg of coffee be mixed with 2 kg of chicory. CP of the mixture = Rs 250 ×5 +75 ×2 = Rs 1250 +150 = Rs. 1400SP of the mixture = Rs 7 ×230 = Rs. 1610Since SP > CP, there
Question:8
If the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find the gain per cent earned by the dealer.
Solution:
Let Rs x be the SP of each bottle and Rs y be the CP of each bottle. SP of 16 bottles = CP of 17 bottles ? 16x = 17y ?
x
y
=
17
16
Gain per bottle = SP -CP = Rs x -y ? Gain percentage =
Question:9
The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss per cent.
Solution:
Let Rs x be the CP of one candle and Rs. y be the SP of one candle. Now, CP of 12 candles = SP of 15 candles ? 12x = 15y ?
y
x
=
12
15
Loss = CP -SP = Rs x -y ? Loss percentage =
Question:10
By selling 130 cassettes, a man gains an amount equal to the selling price of 5 cassettes. Find the gain per cent.
Solution:
It is given that,
Gain = SP of 5 cassettes .....1
( )
( )
( )
( ) ( ) ( )
( )
( )
Gain = SP of 130 cassettes - CP of 130 cassettes
? SP of 5 cassettes = SP of 130 cassettes - CP of 130 cassettes
From(1)
? CP of 130 cassettes = SP of 125 cassettes .....2
Let the CP of 1 cassettte be x.
? CP of 125 cassettes = 125x
CP of 130 cassettes = 130x
SP of 125 cassettes = CP of 130 cassettes
From(2)
? SP of 125 cassettes = 130x
Now, gain% =
SP-CP
CP
×100 % =
(130x-125x)
125x
×100 %
=
5x
125x
×100 % = 4 %
Thus, the gain percent is 4%.
Question:11
By selling 45 lemons, a vendor loses a sum equal to the selling price of 3 lemons. Find his loss per cent.
Solution:
Let Rs x be the SP of one lemon. SP of 45 lemons = Rs. 45xLoss = SP of 3 lemons = Rs. 3xBut loss = CP -SPCP = loss +SP = 3x +45x = Rs. 48x ? Loss percentage =
loss
CP
×100 % =
Question:12
Oranges are bought at 6 for 20 and sold at 4 for 18. Find the gain or loss per cent.
Solution:
LCM of 6 and 4 = 12
Let the number of oranges bought be 12.
CP of 6 oranges = 20
So, CP of 1 orange =
20
6
=
10
3
CP of 12 orange = 12 ×
10
3
= 40
SP of 4 oranges = 18
SP of 1 orange =
18
4
=
9
2
SP of 12 oranges = 12 ×
9
2
= 54
Here, SP of 12 oranges > CP of 12 oranges.
Profit = SP - CP = 54 - 40 = 14
? Profit% =
Profit
CP
×100 % =
14
40
×100 % = 35 %
Question:13
A vendor purchased bananas at 40 per dozen and sold them at 10 for 36. Find his gain or loss per cent.
Solution:
LCM of 12 and 10 = 60
Let the number of banana bought be 60.
CP of 12 banana = 40
? CP of 1 banana =
40
12
=
10
3
? CP of 60 bananas = 60 ×
10
3
= 200
SP of 10 bananas = 36
? SP of 1 banana =
36
10
=
18
5
? SP of 60 bananas = 60 ×
18
5
= 216
Here, SP of 60 bananas > CP of 60 bananas.
Profit = SP - CP = 216 - 200 = 16
? Profit% =
Profit
CP
×100 % =
16
200
×100 = 8 %
Question:14
A man bought apples at 10 for 75 and sold them at 75 per dozen. Find his loss per cent.
Solution:
LCM of 10 and 12 = 60
Let the number of apples bought be 60.
CP of 10 oranges = 75
? CP of 1 orange =
75
10
? CP of 60 orange = 60 ×
75
10
= 450
SP of 12 oranges = 75
? SP of 1 orange =
75
12
? SP of 60 oranges = 60 ×
75
12
= 375
( )
Here, CP of 60 oranges > SP of 60 oranges.
Loss = CP - SP = 450 - 375 = 75
? Loss% =
Loss
CP
×100 % =
75
450
×100 % = 16
2
3
%
Question:15
A man purchased some eggs at 3 for 16 and sold them at 5 for 36. Thus, he gained 168 in all. How many eggs did he purchase?
Solution:
Let the number of eggs purchased be x.
CP of 3 eggs = 16
? CP of 1 egg =
16
3
? CP of x eggs =
16
3
x
SP of 5 eggs = 36
? SP of 1 egg =
36
5
? SP of x eggs =
36
5
x
Gain = SP - CP = 168
?
36
5
x -
16
3
x = 168 ?
28
15
x = 168 ? x =
168×15
28
? x = 90
Hence, the man purchased 90 eggs.
Question:16
A dealer sold a camera for Rs 1080 gaining
1
8
of its cost price. Find i
the cost price of the camera, and ii
the gain per cent earned by the dealer.
Solution:
SP of the camera = Rs. 1080Let Rs x be the CP. Gain = Rs.
1
8
x . . . i Also, gain = SP -CP = Rs. 1080 -x . . . ii From i and ii , we have:
1
8
x = 1080 -x ? x = 8640
Question:17
Meenakshi sells a pen for Rs 54 and loses
1
10
of her outlay. Find i
the cost price of the pen, and ii
the loss per cent.
Solution:
SP of the pen = Rs. 54Let Rs x be the CP of the pen. Loss = Rs.
x
10
SP = CP -Loss = x -
x
10
= Rs.
9x
10
Now, we have
9x
10
= 54 ? x = 54 ×
10
9
? x = 60 ? CP of the pen = Rs. 60Now, loss =
Question:18
A dealer gets 940 more if instead of selling a table at a loss of 10%, it is sold at a gain of 10%. Find the cost price of the table.
Solution:
Let the cost price be x.
Loss = 10% of x =
10
100
x =
x
10
SP in case of loss = CP - Loss = x -
x
10
=
9x
10
Gain =10% of x =
10
100
x =
x
10
SP in case of profit = CP + Profit = x +
x
10
=
11x
10
It is given that dealer gets 940 more if sold at a profit of 10% instead of loss of 10%.
? SP in case of profit - SP in case of loss = 940
?
11x
10
-
9x
10
= 940 ?
2x
10
= 940 ? x = 4700
Hence, the cost price of the table is 4,700.
Question:19
A dealer gets Rs 56 less if instead of selling a chair at a gain of 15%, it is sold at a gain of 8%. Find the cost price of the chair.
Solution:
Let Rs x be the CP. Gain
1
percentage =
gain 1
CP
×100 % ? 15 =
gain 1
x
×100 ? Gain
1
= Rs
15x
100
Again, gain
2
percentage =
gain 2
CP
×100 % ? 8 =
gain 2
x
×100 ? Gain
2
= Rs
8x
100
According to the question
Question:20
A cycle was sold at a gain of 10%. Had it been sold for 260 more, the gain would have been 14%. Find the cost price of the cycle.
Solution:
Let the CP be x.
SP when gain is 10% = x +
10
100
x =
110
100
x
SP when gain is 14% = x +
14
100
x =
114
100
x
Difference in SP = SP when gain is 14% - SP when gain is 10% = 260
( ) ( ) ( ) ( ) ( )
( ) ( )
?
114x
100
-
110x
100
= 260 ?
4x
100
= 260 ? x = 6500
Hence, the CP of the cycle is 6,500.
Question:21
Sonu buys 40 kg of wheat at 12.50 per kg and 30 kg of wheat at 14 per kg. At what rate per kg should he sell the mixture to gain 5% on the whole?
Solution:
40 kg of wheat is bought for 12.50/kg.
? CP of 40 kg of wheat = 40 × 12.50 = 500
30 kg of wheat is bought for 14/kg.
? CP of 30 kg of wheat = 30 × 14 = 420
Total CP = 500 + 420 = 920
Profit = 5% of CP = 5% of 920 =
5
100
×920 = 46
Let the SP be x.
Profit = SP - CP
? x - 920 = 46
? x = 966
SP of 70 kg wheat = 966
? SP of 1 kg wheat =
966
70
= 13. 80
Thus, the selling price of the mixture is 13.80/kg.
Question:22
Wasim bought two cricket bats for 840 and 360 respectively. He sells the first bat at a gain of 15% and the second one at a loss of 5%. Find his gain or loss per cent in the whole
transaction.
Solution:
CP of the first bat = 840
Profit% on the first bat = 15%
? Profit = 15% of 840 =
15
100
×840 = 126
SP of the first bat = 840 + 126 = 966
CP of the second bat = 360
Loss = 5% of 360 =
5
100
×360 = 18
SP of the second bat = 360 - 18 = 342
Total CP of two bats = CP of first bat + CP of second bat = 840 + 360 = 1,200
Total SP of two bats = SP of first bat + SP of second bat = 966 + 342 = 1,308
Here, Total SP of two bats > Total CP of two bats.
Gain = Total SP of two bats - Total CP of two bats = 1,308 - 1,200 = 108
? Gain% in the whole transaction =
Gain
Total CP of two bats
×100 %
=
108
1200
×100 = 9 %
Question:23
Hema bought two pairs of jeans for 1450 each. She sold one of them at a gain of 8% and the other at a loss of 4%. Find her gain or loss per cent in the whole transaction.
Solution:
CP of first jeans = 1,450
Profit = 8% of CP =
8
100
×1450 = 116
SP of first jeans = 1,450 + 116 = 1,566
CP of second jeans = 1,450
Loss = 4% of CP =
4
100
×1450 = 58
SP of second jeans = 1450 - 58 = 1,392
Total CP of two jeans = CP of first jeans + CP of second jeans = 1,450 + 1,450 = 2,900
Total SP of two jeans = SP of first jeans + SP of second jeans = 1,566 + 1,392 = 2,958
Here, Total SP of two jeans > Total CP of two jeans.
Gain = Total SP of two jeans - Total CP of two jeans = 2,958 - 2,900 = 58
? Gain% =
Gain
Total CP of two jeans
×100 % =
58
2900
×100 % = 2 %
Question:24
A grocer purchased 200 kg of rice at Rs 25 per kg. He sold 80 kg of it at a gain of 10% and 40 kg at a loss of 4%. At what rate per kg should he sell the remainder to gain 8% on his total
investment?
Solution:
CP of 1 kg of rice = Rs 25
C.P of 200 kg rice= Rs (200 ×25) = Rs 5000
CP of 80 kg of rice=Rs (25 ×80) = Rs 2000
CP of 40 kg of rice = Rs (25 ×40) = Rs 1000
SP of 80 kg of rice =
100+gain%
100
×CP = Rs
110
100
×2000 = Rs 2200
SP of 40 kg rice =
100-loss%
100
×CP = Rs
96
100
×1000 = Rs 960
SP of 200 kg rice =
100+gain%
100
×CP = Rs
108
100
×5000 = Rs 5400
Read More
|
79 videos|408 docs|31 tests
|
FAQs on RS Aggarwal Solutions: Exercise 10A - Profit & Loss - Mathematics (Maths) Class 8
| 1. What is the formula to calculate profit percentage? |  |
Ans. The formula to calculate the profit percentage is:
Profit Percentage = (Profit / Cost Price) x 100
| 2. How do I calculate the cost price when I know the selling price and profit percentage? | |
Ans. To calculate the cost price when you know the selling price and profit percentage, you can use the following formula:
Cost Price = (Selling Price x 100) / (100 + Profit Percentage)
| 3. How can I find the selling price when I know the cost price and profit percentage? | |
Ans. To find the selling price when you know the cost price and profit percentage, you can use the following formula:
Selling Price = Cost Price + (Cost Price x Profit Percentage / 100)
| 4. What is the difference between profit and profit percentage? | |
Ans. Profit is the amount of money gained after deducting the cost price from the selling price. Profit percentage, on the other hand, is the profit expressed as a percentage of the cost price.
| 5. Can you explain the concept of loss in profit and loss? | |
Ans. Loss in profit and loss refers to the situation where the selling price is less than the cost price. It occurs when there is a decrease in the value of an asset or when the expenses exceed the earnings. Loss is calculated by subtracting the selling price from the cost price.
Related Exams
About this Document
|
4.83/5 Rating |
|
Dec 22, 2024 Last updated |
Document Description: RS Aggarwal Solutions: Exercise 10A - Profit & Loss for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation.
The notes and questions for RS Aggarwal Solutions: Exercise 10A - Profit & Loss have been prepared according to the Class 8 exam syllabus. Information about RS Aggarwal Solutions: Exercise 10A - Profit & Loss covers topics
like and RS Aggarwal Solutions: Exercise 10A - Profit & Loss Example, for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RS Aggarwal Solutions: Exercise 10A - Profit & Loss.
Introduction of RS Aggarwal Solutions: Exercise 10A - Profit & Loss in English is available as part of our Mathematics (Maths) Class 8
for Class 8 & RS Aggarwal Solutions: Exercise 10A - Profit & Loss in Hindi for Mathematics (Maths) Class 8 course.
Download more important topics related with notes, lectures and mock test series for Class 8
Exam by signing up for free. Class 8: RS Aggarwal Solutions: Exercise 10A - Profit & Loss | Mathematics (Maths) Class 8
Description
Full syllabus notes, lecture & questions for RS Aggarwal Solutions: Exercise 10A - Profit & Loss | Mathematics (Maths) Class 8 - Class 8 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 8 | Best notes, free PDF download
Information about RS Aggarwal Solutions: Exercise 10A - Profit & Loss
In this doc you can find the meaning of RS Aggarwal Solutions: Exercise 10A - Profit & Loss defined & explained in the simplest way possible. Besides explaining types of
RS Aggarwal Solutions: Exercise 10A - Profit & Loss theory, EduRev gives you an ample number of questions to practice RS Aggarwal Solutions: Exercise 10A - Profit & Loss tests, examples and also practice Class 8
tests
|
Explore Courses for Class 8 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Objective type Questions
,Summary
,Free
,Semester Notes
,video lectures
,Extra Questions
,RS Aggarwal Solutions: Exercise 10A - Profit & Loss | Mathematics (Maths) Class 8
,mock tests for examination
,Exam
,study material
,MCQs
,Previous Year Questions with Solutions
,ppt
,Sample Paper
,Viva Questions
,RS Aggarwal Solutions: Exercise 10A - Profit & Loss | Mathematics (Maths) Class 8
,practice quizzes
,shortcuts and tricks
,Important questions
,past year papers
,RS Aggarwal Solutions: Exercise 10A - Profit & Loss | Mathematics (Maths) Class 8
;
Additional Information about RS Aggarwal Solutions: Exercise 10A - Profit & Loss for Class 8 Preparation
RS Aggarwal Solutions: Exercise 10A - Profit & Loss Free PDF Download
The RS Aggarwal Solutions: Exercise 10A - Profit & Loss is an invaluable resource that delves deep into the core of the Class 8 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RS Aggarwal Solutions: Exercise 10A - Profit & Loss now and kickstart your journey towards success in the Class 8 exam.
Importance of RS Aggarwal Solutions: Exercise 10A - Profit & Loss
The importance of RS Aggarwal Solutions: Exercise 10A - Profit & Loss cannot be overstated, especially for Class 8 aspirants.
This document holds the key to success in the Class 8 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RS Aggarwal Solutions: Exercise 10A - Profit & Loss Notes
RS Aggarwal Solutions: Exercise 10A - Profit & Loss Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RS Aggarwal Solutions: Exercise 10A - Profit & Loss.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RS Aggarwal Solutions: Exercise 10A - Profit & Loss Notes on EduRev are your ultimate resource for success.
RS Aggarwal Solutions: Exercise 10A - Profit & Loss Class 8 Questions
The "RS Aggarwal Solutions: Exercise 10A - Profit & Loss Class 8 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 8 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RS Aggarwal Solutions: Exercise 10A - Profit & Loss on the App
Students of Class 8 can study RS Aggarwal Solutions: Exercise 10A - Profit & Loss alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RS Aggarwal Solutions: Exercise 10A - Profit & Loss,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RS Aggarwal Solutions: Exercise 10A - Profit & Loss is prepared as per the latest Class 8 syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup