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Page 1
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
EXERCISE 14.1 PAGE NO: 14.4
1. Find the compound interest when principal = Rs 3000, rate = 5% per annum and
time = 2 years.
Solution:
Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
? Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
2. What will be the compound interest on Rs. 4000 in two years when rate of
interest is 5% per annum?
Solution:
Given details are,
Principal (p) = Rs 4000
Rate (r) = 5%
Time = 2years
By using the formula,
A = P (1 + R/100)
n
= 4000 (1 + 5/100)
2
= 4000 (105/100)
2
= Rs 4410
? Compound Interest = A – P = Rs 4410 – Rs 4000 = Rs 410
3. Rohit deposited Rs. 8000 with a finance company for 3 years at an interest of 15%
per annum. What is the compound interest that Rohit gets after 3 years?
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 15%
Time = 3years
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 15/100)
3
Page 2
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
EXERCISE 14.1 PAGE NO: 14.4
1. Find the compound interest when principal = Rs 3000, rate = 5% per annum and
time = 2 years.
Solution:
Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
? Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
2. What will be the compound interest on Rs. 4000 in two years when rate of
interest is 5% per annum?
Solution:
Given details are,
Principal (p) = Rs 4000
Rate (r) = 5%
Time = 2years
By using the formula,
A = P (1 + R/100)
n
= 4000 (1 + 5/100)
2
= 4000 (105/100)
2
= Rs 4410
? Compound Interest = A – P = Rs 4410 – Rs 4000 = Rs 410
3. Rohit deposited Rs. 8000 with a finance company for 3 years at an interest of 15%
per annum. What is the compound interest that Rohit gets after 3 years?
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 15%
Time = 3years
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 15/100)
3
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
= 8000 (115/100)
3
= Rs 12167
? Compound Interest = A – P = Rs 12167 – Rs 8000 = Rs 4167
4. Find the compound interest on Rs. 1000 at the rate of 8% per annum for 1 ½
years when interest is compounded half yearly.
Solution:
Given details are,
Principal (p) = Rs 1000
Rate (r) = 8%
Time = 1 ½ years = 3/2 × 2 = 3 half years
By using the formula,
A = P (1 + R/200)
2n
= 1000 (1 + 8/200)
3
= 1000 (208/200)
3
= Rs 1124.86
? Compound Interest = A – P = Rs 1124.86 – Rs 1000 = Rs 124.86
5. Find the compound interest on Rs. 160000 for one year at the rate of 20% per
annum, if the interest is compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 160000
Rate (r) = 20% = 20/4 = 5% (for quarter year)
Time = 1year = 1 × 4 = 4 quarters
By using the formula,
A = P (1 + R/100)
n
= 160000 (1 + 5/100)
4
= 160000 (105/100)
4
= Rs 194481
? Compound Interest = A – P = Rs 194481 – Rs 160000 = Rs 34481
6. Swati took a loan of Rs. 16000 against her insurance policy at the rate of 12 ½ %
per annum. Calculate the total compound interest payable by Swati after 3 years.
Solution:
Given details are,
Principal (p) = Rs 16000
Rate (r) = 12 ½ % = 12.5%
Time = 3years
Page 3
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
EXERCISE 14.1 PAGE NO: 14.4
1. Find the compound interest when principal = Rs 3000, rate = 5% per annum and
time = 2 years.
Solution:
Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
? Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
2. What will be the compound interest on Rs. 4000 in two years when rate of
interest is 5% per annum?
Solution:
Given details are,
Principal (p) = Rs 4000
Rate (r) = 5%
Time = 2years
By using the formula,
A = P (1 + R/100)
n
= 4000 (1 + 5/100)
2
= 4000 (105/100)
2
= Rs 4410
? Compound Interest = A – P = Rs 4410 – Rs 4000 = Rs 410
3. Rohit deposited Rs. 8000 with a finance company for 3 years at an interest of 15%
per annum. What is the compound interest that Rohit gets after 3 years?
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 15%
Time = 3years
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 15/100)
3
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
= 8000 (115/100)
3
= Rs 12167
? Compound Interest = A – P = Rs 12167 – Rs 8000 = Rs 4167
4. Find the compound interest on Rs. 1000 at the rate of 8% per annum for 1 ½
years when interest is compounded half yearly.
Solution:
Given details are,
Principal (p) = Rs 1000
Rate (r) = 8%
Time = 1 ½ years = 3/2 × 2 = 3 half years
By using the formula,
A = P (1 + R/200)
2n
= 1000 (1 + 8/200)
3
= 1000 (208/200)
3
= Rs 1124.86
? Compound Interest = A – P = Rs 1124.86 – Rs 1000 = Rs 124.86
5. Find the compound interest on Rs. 160000 for one year at the rate of 20% per
annum, if the interest is compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 160000
Rate (r) = 20% = 20/4 = 5% (for quarter year)
Time = 1year = 1 × 4 = 4 quarters
By using the formula,
A = P (1 + R/100)
n
= 160000 (1 + 5/100)
4
= 160000 (105/100)
4
= Rs 194481
? Compound Interest = A – P = Rs 194481 – Rs 160000 = Rs 34481
6. Swati took a loan of Rs. 16000 against her insurance policy at the rate of 12 ½ %
per annum. Calculate the total compound interest payable by Swati after 3 years.
Solution:
Given details are,
Principal (p) = Rs 16000
Rate (r) = 12 ½ % = 12.5%
Time = 3years
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
By using the formula,
A = P (1 + R/100)
n
= 16000 (1 + 12.5/100)
3
= 16000 (112.5/100)
3
= Rs 22781.25
? Compound Interest = A – P = Rs 22781.25 – Rs 16000 = Rs 6781.25
7. Roma borrowed Rs. 64000 from a bank for 1 ½ years at the rate of 10% per
annum. Compare the total compound interest payable by Roma after 1 ½ years, if
the interest is compounded half-yearly.
Solution:
Given details are,
Principal (p) = Rs 64000
Rate (r) = 10 % = 10/2 % (for half a year)
Time = 1 ½ years = 3/2 × 2 = 3 (half year)
By using the formula,
A = P (1 + R/100)
n
= 64000 (1 + 10/2×100)
3
= 64000 (210/200)
3
= Rs 74088
? Compound Interest = A – P = Rs 74088 – Rs 64000 = Rs 10088
8. Mewa lal borrowed Rs. 20000 from his friend Rooplal at 18% per annum simple
interest. He lent it to Rampal at the same rate but compounded annually. Find his
gain after 2 years.
Solution:
Given details are,
Principal (p) = Rs 20000
Rate (r) = 18 %
Time = 2 years
By using the formula,
Interest amount Mewa lal has to pay,
By using the formula,
Simple interest = P×T×R/100
= (20000×18×2)/100 = 7200
Interest amount Rampal has to pay to Mewa lal,
By using the formula,
A = P (1 + R/100)
n
Page 4
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
EXERCISE 14.1 PAGE NO: 14.4
1. Find the compound interest when principal = Rs 3000, rate = 5% per annum and
time = 2 years.
Solution:
Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
? Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
2. What will be the compound interest on Rs. 4000 in two years when rate of
interest is 5% per annum?
Solution:
Given details are,
Principal (p) = Rs 4000
Rate (r) = 5%
Time = 2years
By using the formula,
A = P (1 + R/100)
n
= 4000 (1 + 5/100)
2
= 4000 (105/100)
2
= Rs 4410
? Compound Interest = A – P = Rs 4410 – Rs 4000 = Rs 410
3. Rohit deposited Rs. 8000 with a finance company for 3 years at an interest of 15%
per annum. What is the compound interest that Rohit gets after 3 years?
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 15%
Time = 3years
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 15/100)
3
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
= 8000 (115/100)
3
= Rs 12167
? Compound Interest = A – P = Rs 12167 – Rs 8000 = Rs 4167
4. Find the compound interest on Rs. 1000 at the rate of 8% per annum for 1 ½
years when interest is compounded half yearly.
Solution:
Given details are,
Principal (p) = Rs 1000
Rate (r) = 8%
Time = 1 ½ years = 3/2 × 2 = 3 half years
By using the formula,
A = P (1 + R/200)
2n
= 1000 (1 + 8/200)
3
= 1000 (208/200)
3
= Rs 1124.86
? Compound Interest = A – P = Rs 1124.86 – Rs 1000 = Rs 124.86
5. Find the compound interest on Rs. 160000 for one year at the rate of 20% per
annum, if the interest is compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 160000
Rate (r) = 20% = 20/4 = 5% (for quarter year)
Time = 1year = 1 × 4 = 4 quarters
By using the formula,
A = P (1 + R/100)
n
= 160000 (1 + 5/100)
4
= 160000 (105/100)
4
= Rs 194481
? Compound Interest = A – P = Rs 194481 – Rs 160000 = Rs 34481
6. Swati took a loan of Rs. 16000 against her insurance policy at the rate of 12 ½ %
per annum. Calculate the total compound interest payable by Swati after 3 years.
Solution:
Given details are,
Principal (p) = Rs 16000
Rate (r) = 12 ½ % = 12.5%
Time = 3years
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
By using the formula,
A = P (1 + R/100)
n
= 16000 (1 + 12.5/100)
3
= 16000 (112.5/100)
3
= Rs 22781.25
? Compound Interest = A – P = Rs 22781.25 – Rs 16000 = Rs 6781.25
7. Roma borrowed Rs. 64000 from a bank for 1 ½ years at the rate of 10% per
annum. Compare the total compound interest payable by Roma after 1 ½ years, if
the interest is compounded half-yearly.
Solution:
Given details are,
Principal (p) = Rs 64000
Rate (r) = 10 % = 10/2 % (for half a year)
Time = 1 ½ years = 3/2 × 2 = 3 (half year)
By using the formula,
A = P (1 + R/100)
n
= 64000 (1 + 10/2×100)
3
= 64000 (210/200)
3
= Rs 74088
? Compound Interest = A – P = Rs 74088 – Rs 64000 = Rs 10088
8. Mewa lal borrowed Rs. 20000 from his friend Rooplal at 18% per annum simple
interest. He lent it to Rampal at the same rate but compounded annually. Find his
gain after 2 years.
Solution:
Given details are,
Principal (p) = Rs 20000
Rate (r) = 18 %
Time = 2 years
By using the formula,
Interest amount Mewa lal has to pay,
By using the formula,
Simple interest = P×T×R/100
= (20000×18×2)/100 = 7200
Interest amount Rampal has to pay to Mewa lal,
By using the formula,
A = P (1 + R/100)
n
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
= 20000 (1 + 18/100)
2
= 20000 (118/100)
2
= Rs 27848 – 20000 (principal amount)
= Rs 7848
? Mewa lal gain = Rs (7848 - 7200) = Rs 648
9. Find the compound interest on Rs. 8000 for 9 months at 20% per annum
compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 20 % = 20/4 = 5% (for quarterly)
Time = 9 months = 9/3 = 3 (for quarter year)
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 5/100)
3
= 8000 (105/100)
3
= Rs 9261
? Compound Interest = A – P = Rs 9261 – Rs 8000 = Rs 1261
10. Find the compound interest at the rate of 10% per annum for two years on that
principal which in two years at the rate of 10% per annum given Rs. 200 as simple
interest.
Solution:
Given details are,
Simple interest (SI) = Rs 200
Rate (r) = 10 %
Time = 2 years
So, by using the formula,
Simple interest = P×T×R/100
P = (SI × 100)/ T×R
= (200 × 100) / 2 × 10
= 20000/20
= Rs 1000
Now,
Rate of compound interest = 10%
Time = 2years
Page 5
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
EXERCISE 14.1 PAGE NO: 14.4
1. Find the compound interest when principal = Rs 3000, rate = 5% per annum and
time = 2 years.
Solution:
Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
? Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
2. What will be the compound interest on Rs. 4000 in two years when rate of
interest is 5% per annum?
Solution:
Given details are,
Principal (p) = Rs 4000
Rate (r) = 5%
Time = 2years
By using the formula,
A = P (1 + R/100)
n
= 4000 (1 + 5/100)
2
= 4000 (105/100)
2
= Rs 4410
? Compound Interest = A – P = Rs 4410 – Rs 4000 = Rs 410
3. Rohit deposited Rs. 8000 with a finance company for 3 years at an interest of 15%
per annum. What is the compound interest that Rohit gets after 3 years?
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 15%
Time = 3years
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 15/100)
3
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
= 8000 (115/100)
3
= Rs 12167
? Compound Interest = A – P = Rs 12167 – Rs 8000 = Rs 4167
4. Find the compound interest on Rs. 1000 at the rate of 8% per annum for 1 ½
years when interest is compounded half yearly.
Solution:
Given details are,
Principal (p) = Rs 1000
Rate (r) = 8%
Time = 1 ½ years = 3/2 × 2 = 3 half years
By using the formula,
A = P (1 + R/200)
2n
= 1000 (1 + 8/200)
3
= 1000 (208/200)
3
= Rs 1124.86
? Compound Interest = A – P = Rs 1124.86 – Rs 1000 = Rs 124.86
5. Find the compound interest on Rs. 160000 for one year at the rate of 20% per
annum, if the interest is compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 160000
Rate (r) = 20% = 20/4 = 5% (for quarter year)
Time = 1year = 1 × 4 = 4 quarters
By using the formula,
A = P (1 + R/100)
n
= 160000 (1 + 5/100)
4
= 160000 (105/100)
4
= Rs 194481
? Compound Interest = A – P = Rs 194481 – Rs 160000 = Rs 34481
6. Swati took a loan of Rs. 16000 against her insurance policy at the rate of 12 ½ %
per annum. Calculate the total compound interest payable by Swati after 3 years.
Solution:
Given details are,
Principal (p) = Rs 16000
Rate (r) = 12 ½ % = 12.5%
Time = 3years
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
By using the formula,
A = P (1 + R/100)
n
= 16000 (1 + 12.5/100)
3
= 16000 (112.5/100)
3
= Rs 22781.25
? Compound Interest = A – P = Rs 22781.25 – Rs 16000 = Rs 6781.25
7. Roma borrowed Rs. 64000 from a bank for 1 ½ years at the rate of 10% per
annum. Compare the total compound interest payable by Roma after 1 ½ years, if
the interest is compounded half-yearly.
Solution:
Given details are,
Principal (p) = Rs 64000
Rate (r) = 10 % = 10/2 % (for half a year)
Time = 1 ½ years = 3/2 × 2 = 3 (half year)
By using the formula,
A = P (1 + R/100)
n
= 64000 (1 + 10/2×100)
3
= 64000 (210/200)
3
= Rs 74088
? Compound Interest = A – P = Rs 74088 – Rs 64000 = Rs 10088
8. Mewa lal borrowed Rs. 20000 from his friend Rooplal at 18% per annum simple
interest. He lent it to Rampal at the same rate but compounded annually. Find his
gain after 2 years.
Solution:
Given details are,
Principal (p) = Rs 20000
Rate (r) = 18 %
Time = 2 years
By using the formula,
Interest amount Mewa lal has to pay,
By using the formula,
Simple interest = P×T×R/100
= (20000×18×2)/100 = 7200
Interest amount Rampal has to pay to Mewa lal,
By using the formula,
A = P (1 + R/100)
n
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
= 20000 (1 + 18/100)
2
= 20000 (118/100)
2
= Rs 27848 – 20000 (principal amount)
= Rs 7848
? Mewa lal gain = Rs (7848 - 7200) = Rs 648
9. Find the compound interest on Rs. 8000 for 9 months at 20% per annum
compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 8000
Rate (r) = 20 % = 20/4 = 5% (for quarterly)
Time = 9 months = 9/3 = 3 (for quarter year)
By using the formula,
A = P (1 + R/100)
n
= 8000 (1 + 5/100)
3
= 8000 (105/100)
3
= Rs 9261
? Compound Interest = A – P = Rs 9261 – Rs 8000 = Rs 1261
10. Find the compound interest at the rate of 10% per annum for two years on that
principal which in two years at the rate of 10% per annum given Rs. 200 as simple
interest.
Solution:
Given details are,
Simple interest (SI) = Rs 200
Rate (r) = 10 %
Time = 2 years
So, by using the formula,
Simple interest = P×T×R/100
P = (SI × 100)/ T×R
= (200 × 100) / 2 × 10
= 20000/20
= Rs 1000
Now,
Rate of compound interest = 10%
Time = 2years
RD Sharma Solutions for Class 8 Maths Chapter 14 –
Compound Interest
By using the formula,
A = P (1 + R/100)
n
= 1000 (1 + 10/100)
2
= 1000 (110/100)
2
= Rs 1210
? Compound Interest = A – P = Rs 1210 – Rs 1000 = Rs 210
11. Find the compound interest on Rs. 64000 for 1 year at the rate of 10% per
annum compounded quarterly.
Solution:
Given details are,
Principal (p) = Rs 64000
Rate (r) = 10 % = 10/4 % (for quarterly)
Time = 1year = 1× 4 = 4 (for quarter in a year)
By using the formula,
A = P (1 + R/100)
n
= 64000 (1 + 10/4×100)
4
= 64000 (410/400)
4
= Rs 70644.03
? Compound Interest = A – P = Rs 70644.03 – Rs 64000 = Rs 6644.03
12. Ramesh deposited Rs. 7500 in a bank which pays him 12% interest per annum
compounded quarterly. What is the amount which he receives after 9 months.
Solution:
Given details are,
Principal (p) = Rs 7500
Rate (r) = 12 % = 12/4 = 3 % (for quarterly)
Time = 9 months = 9/12years = 9/12 × 4 = 3 (for quarter in a year)
By using the formula,
A = P (1 + R/100)
n
= 7500 (1 + 3/100)
3
= 7500 (103/100)
3
= Rs 8195.45
? Required amount is Rs 8195.45
13. Anil borrowed a sum of Rs. 9600 to install a hand pump in his dairy. If the rate
of interest is 5 ½ % per annum compounded annually, determine the compound
interest which Anil will have to pay after 3 years.
Solution:
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The "Compound Interest - EXERCISE 14.1 Class 8 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 8 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
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The content of Compound Interest - EXERCISE 14.1 is prepared as per the latest Class 8 syllabus.
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