Visualising Shapes - EXERCISE 19.2 | Mathematics (Maths) Class 8 PDF Download

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RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
EXERCISE 19.2                                                  PAGE NO: 19.12 
 
1. Which among of the following are nets for a cube? 
 
Solution: 
Figure (iv), (v), (vi) are the nets for a cube. 
 
2. Name the polyhedron that can be made by folding each net: 
 
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RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
EXERCISE 19.2                                                  PAGE NO: 19.12 
 
1. Which among of the following are nets for a cube? 
 
Solution: 
Figure (iv), (v), (vi) are the nets for a cube. 
 
2. Name the polyhedron that can be made by folding each net: 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes
Solution: 
(i) From figure (i), a Square pyramid can be made by folding each net.
(ii) From figure (ii), a Triangular prism can be made by folding each net.
(iii) From figure (iii), a Triangular prism can be made by folding each net.
(iv) From figure (iv), a Hexagonal prism can be made by folding each net.
(v) From figure (v), a Hexagonal pyramid can be made by folding each net.
(vi) From figure (vi), a Cuboid can be made by folding each net.
3. Dice are cubes where the numbers on the opposite faces must total 7. Which of the
following are dice?
Solution: 
Figure (i), is a dice. Since the sum of numbers on opposite faces is 7 (3 + 4 = 7 and 6 + 1 
= 7). 
4. Draw nets for each of the following polyhedrons:
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RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
EXERCISE 19.2                                                  PAGE NO: 19.12 
 
1. Which among of the following are nets for a cube? 
 
Solution: 
Figure (iv), (v), (vi) are the nets for a cube. 
 
2. Name the polyhedron that can be made by folding each net: 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes
Solution: 
(i) From figure (i), a Square pyramid can be made by folding each net.
(ii) From figure (ii), a Triangular prism can be made by folding each net.
(iii) From figure (iii), a Triangular prism can be made by folding each net.
(iv) From figure (iv), a Hexagonal prism can be made by folding each net.
(v) From figure (v), a Hexagonal pyramid can be made by folding each net.
(vi) From figure (vi), a Cuboid can be made by folding each net.
3. Dice are cubes where the numbers on the opposite faces must total 7. Which of the
following are dice?
Solution: 
Figure (i), is a dice. Since the sum of numbers on opposite faces is 7 (3 + 4 = 7 and 6 + 1 
= 7). 
4. Draw nets for each of the following polyhedrons:
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
 
Solution: 
(i) The net pattern for cube is  
 
(ii) The pattern for triangular prism is  
 
(iii) The net pattern for hexagonal prism is  
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RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
EXERCISE 19.2                                                  PAGE NO: 19.12 
 
1. Which among of the following are nets for a cube? 
 
Solution: 
Figure (iv), (v), (vi) are the nets for a cube. 
 
2. Name the polyhedron that can be made by folding each net: 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes
Solution: 
(i) From figure (i), a Square pyramid can be made by folding each net.
(ii) From figure (ii), a Triangular prism can be made by folding each net.
(iii) From figure (iii), a Triangular prism can be made by folding each net.
(iv) From figure (iv), a Hexagonal prism can be made by folding each net.
(v) From figure (v), a Hexagonal pyramid can be made by folding each net.
(vi) From figure (vi), a Cuboid can be made by folding each net.
3. Dice are cubes where the numbers on the opposite faces must total 7. Which of the
following are dice?
Solution: 
Figure (i), is a dice. Since the sum of numbers on opposite faces is 7 (3 + 4 = 7 and 6 + 1 
= 7). 
4. Draw nets for each of the following polyhedrons:
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
 
Solution: 
(i) The net pattern for cube is  
 
(ii) The pattern for triangular prism is  
 
(iii) The net pattern for hexagonal prism is  
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
 
(iv) The net pattern for pentagonal pyramid is  
 
 
5. Match the following figures: 
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RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
EXERCISE 19.2                                                  PAGE NO: 19.12 
 
1. Which among of the following are nets for a cube? 
 
Solution: 
Figure (iv), (v), (vi) are the nets for a cube. 
 
2. Name the polyhedron that can be made by folding each net: 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes
Solution: 
(i) From figure (i), a Square pyramid can be made by folding each net.
(ii) From figure (ii), a Triangular prism can be made by folding each net.
(iii) From figure (iii), a Triangular prism can be made by folding each net.
(iv) From figure (iv), a Hexagonal prism can be made by folding each net.
(v) From figure (v), a Hexagonal pyramid can be made by folding each net.
(vi) From figure (vi), a Cuboid can be made by folding each net.
3. Dice are cubes where the numbers on the opposite faces must total 7. Which of the
following are dice?
Solution: 
Figure (i), is a dice. Since the sum of numbers on opposite faces is 7 (3 + 4 = 7 and 6 + 1 
= 7). 
4. Draw nets for each of the following polyhedrons:
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
 
Solution: 
(i) The net pattern for cube is  
 
(ii) The pattern for triangular prism is  
 
(iii) The net pattern for hexagonal prism is  
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
 
(iv) The net pattern for pentagonal pyramid is  
 
 
5. Match the following figures: 
 
 
 
 
RD Sharma Solutions for Class 8 Maths Chapter 19 – 
Visualising Shapes 
 
 
Solution: 
(a)-(iv) Because multiplication of numbers on adjacent faces are equal, where 6×4 = 24 
and 4×4 = 16 
 
 
(b)-(i) Because multiplication of numbers on adjacent faces are equal, where 3×3 = 9 and 
8×3 = 24 
 
 
(c)-(ii) Because multiplication of numbers on adjacent faces are equal, where 6×4 = 24 
and 6×3 = 18 
 
 
(d)-(iii) Because multiplication of numbers on adjacent faces are equal, where 3×3 = 9 
and 3×9 = 27