Class 8 Exam > Class 8 Notes > Mathematics (Maths) Class 8 > Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 | Mathematics (Maths) Class 8 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.1 PAGE NO: 21.8
1. Find the volume of a cuboid whose
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
(ii) length = 1.2 m, breadth = 30 cm, height = 15 cm
(iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.
Solution:
(i) The given details are:
Length of a cuboid = 12 cm
Breadth of a cuboid = 8 cm
Height of a cuboid = 6 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 12 × 8 ×6
= 576 cm
3
(ii) The given details are:
Length of a cuboid = 1.2 m = 120 cm
Breadth of a cuboid = 30 cm
Height of a cuboid = 15 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 120 × 30 × 15
= 54000 cm
3
(iii) The given details are:
Length of a cuboid = 15 cm
Breadth of a cuboid = 2.5 dm = 25 cm
Height of a cuboid = 8 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 15 × 25 × 8
= 3000 cm
3
2. Find the volume of a cube whose side is
(i) 4 cm (ii) 8 cm
(iii) 1.5 dm (iv) 1.2 m
(v) 25 mm
Solution:
Page 2
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.1 PAGE NO: 21.8
1. Find the volume of a cuboid whose
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
(ii) length = 1.2 m, breadth = 30 cm, height = 15 cm
(iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.
Solution:
(i) The given details are:
Length of a cuboid = 12 cm
Breadth of a cuboid = 8 cm
Height of a cuboid = 6 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 12 × 8 ×6
= 576 cm
3
(ii) The given details are:
Length of a cuboid = 1.2 m = 120 cm
Breadth of a cuboid = 30 cm
Height of a cuboid = 15 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 120 × 30 × 15
= 54000 cm
3
(iii) The given details are:
Length of a cuboid = 15 cm
Breadth of a cuboid = 2.5 dm = 25 cm
Height of a cuboid = 8 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 15 × 25 × 8
= 3000 cm
3
2. Find the volume of a cube whose side is
(i) 4 cm (ii) 8 cm
(iii) 1.5 dm (iv) 1.2 m
(v) 25 mm
Solution:
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
(i) Given details are,
Side of cube = 4 cm
Volume of cube = (side)
3
= 4
3
= 64 cm
3
(ii) Given details are,
Side of cube = 8 cm
Volume of cube = (side)
3
= 8
3
= 512 cm
3
(iii) Given details are,
Side of cube = 1.5 dm
Volume of cube = (side)
3
= 1.5
3
= 3.375 dm
3
= 3375 cm
3
(iv) Given details are,
Side of cube = 1.2 m
Volume of cube = (side)
3
= 1.2
3
= 1.728 m
3
(v) Given details are,
Side of cube = 25 mm
Volume of cube = (side)
3
= 25
3
= 15625 mm
3
= 15.625 cm
3
3. Find the height of a cuboid of volume 100 cm
3
, whose length and breadth are 5 cm
and 4 cm respectively.
Solution:
Given details are,
Volume of a cuboid = 100 cm
3
Length of a cuboid = 5 cm
Breadth of a cuboid = 4 cm
Let height of cuboid be ‘h’ cm
We know that, l × b × h = 100cm
h = 100/( l × b)
= 100/(5×4)
= 5cm
4. A cuboidal vessel is 10 cm long and 5 cm wide. How high it must be made to hold
Page 3
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.1 PAGE NO: 21.8
1. Find the volume of a cuboid whose
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
(ii) length = 1.2 m, breadth = 30 cm, height = 15 cm
(iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.
Solution:
(i) The given details are:
Length of a cuboid = 12 cm
Breadth of a cuboid = 8 cm
Height of a cuboid = 6 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 12 × 8 ×6
= 576 cm
3
(ii) The given details are:
Length of a cuboid = 1.2 m = 120 cm
Breadth of a cuboid = 30 cm
Height of a cuboid = 15 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 120 × 30 × 15
= 54000 cm
3
(iii) The given details are:
Length of a cuboid = 15 cm
Breadth of a cuboid = 2.5 dm = 25 cm
Height of a cuboid = 8 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 15 × 25 × 8
= 3000 cm
3
2. Find the volume of a cube whose side is
(i) 4 cm (ii) 8 cm
(iii) 1.5 dm (iv) 1.2 m
(v) 25 mm
Solution:
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
(i) Given details are,
Side of cube = 4 cm
Volume of cube = (side)
3
= 4
3
= 64 cm
3
(ii) Given details are,
Side of cube = 8 cm
Volume of cube = (side)
3
= 8
3
= 512 cm
3
(iii) Given details are,
Side of cube = 1.5 dm
Volume of cube = (side)
3
= 1.5
3
= 3.375 dm
3
= 3375 cm
3
(iv) Given details are,
Side of cube = 1.2 m
Volume of cube = (side)
3
= 1.2
3
= 1.728 m
3
(v) Given details are,
Side of cube = 25 mm
Volume of cube = (side)
3
= 25
3
= 15625 mm
3
= 15.625 cm
3
3. Find the height of a cuboid of volume 100 cm
3
, whose length and breadth are 5 cm
and 4 cm respectively.
Solution:
Given details are,
Volume of a cuboid = 100 cm
3
Length of a cuboid = 5 cm
Breadth of a cuboid = 4 cm
Let height of cuboid be ‘h’ cm
We know that, l × b × h = 100cm
h = 100/( l × b)
= 100/(5×4)
= 5cm
4. A cuboidal vessel is 10 cm long and 5 cm wide. How high it must be made to hold
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
300 cm
3
of a liquid?
Solution:
Given details are,
Volume of a liquid in the vessel = 300 cm
3
Length of a cuboidal vessel = 10 cm
Breadth of a cuboidal vessel = 5 cm
Let height of cuboidal vessel be ‘h’ cm
We know that, l × b × h = 300 cm
3
h = 300/(l × b)
= 300/(10×5)
= 6cm
5. A milk container is 8 cm long and 50 cm wide. What should be its height so that it
can hold 4 litres of milk?
Solution:
Given details are,
Volume = 4 litres = 4000 cm
3
Length of a milk container = 8 cm
Breadth of a milk container = 50 cm
Let height of milk container be ‘h’ cm
We know that, l × b × h = 4000 cm
3
h = 4000/ (l × b)
= 4000/ (50×8)
= 10cm
6. A cuboidal wooden block contains 36 cm
3
wood. If it be 4 cm long and 3 cm wide,
find its height.
Solution:
Given details are,
Volume of wooden block = 36 cm
3
Length of the wooden block = 4 cm
Breadth of a wooden block = 3 cm
Let height of wooden block be ‘h’ cm
We know that, l × b × h = 36 cm
3
h = 36/( l × b)
= 36/(4×3)
= 3cm
7. What will happen to the volume of a cube, if its edge is
Page 4
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.1 PAGE NO: 21.8
1. Find the volume of a cuboid whose
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
(ii) length = 1.2 m, breadth = 30 cm, height = 15 cm
(iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.
Solution:
(i) The given details are:
Length of a cuboid = 12 cm
Breadth of a cuboid = 8 cm
Height of a cuboid = 6 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 12 × 8 ×6
= 576 cm
3
(ii) The given details are:
Length of a cuboid = 1.2 m = 120 cm
Breadth of a cuboid = 30 cm
Height of a cuboid = 15 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 120 × 30 × 15
= 54000 cm
3
(iii) The given details are:
Length of a cuboid = 15 cm
Breadth of a cuboid = 2.5 dm = 25 cm
Height of a cuboid = 8 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 15 × 25 × 8
= 3000 cm
3
2. Find the volume of a cube whose side is
(i) 4 cm (ii) 8 cm
(iii) 1.5 dm (iv) 1.2 m
(v) 25 mm
Solution:
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
(i) Given details are,
Side of cube = 4 cm
Volume of cube = (side)
3
= 4
3
= 64 cm
3
(ii) Given details are,
Side of cube = 8 cm
Volume of cube = (side)
3
= 8
3
= 512 cm
3
(iii) Given details are,
Side of cube = 1.5 dm
Volume of cube = (side)
3
= 1.5
3
= 3.375 dm
3
= 3375 cm
3
(iv) Given details are,
Side of cube = 1.2 m
Volume of cube = (side)
3
= 1.2
3
= 1.728 m
3
(v) Given details are,
Side of cube = 25 mm
Volume of cube = (side)
3
= 25
3
= 15625 mm
3
= 15.625 cm
3
3. Find the height of a cuboid of volume 100 cm
3
, whose length and breadth are 5 cm
and 4 cm respectively.
Solution:
Given details are,
Volume of a cuboid = 100 cm
3
Length of a cuboid = 5 cm
Breadth of a cuboid = 4 cm
Let height of cuboid be ‘h’ cm
We know that, l × b × h = 100cm
h = 100/( l × b)
= 100/(5×4)
= 5cm
4. A cuboidal vessel is 10 cm long and 5 cm wide. How high it must be made to hold
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
300 cm
3
of a liquid?
Solution:
Given details are,
Volume of a liquid in the vessel = 300 cm
3
Length of a cuboidal vessel = 10 cm
Breadth of a cuboidal vessel = 5 cm
Let height of cuboidal vessel be ‘h’ cm
We know that, l × b × h = 300 cm
3
h = 300/(l × b)
= 300/(10×5)
= 6cm
5. A milk container is 8 cm long and 50 cm wide. What should be its height so that it
can hold 4 litres of milk?
Solution:
Given details are,
Volume = 4 litres = 4000 cm
3
Length of a milk container = 8 cm
Breadth of a milk container = 50 cm
Let height of milk container be ‘h’ cm
We know that, l × b × h = 4000 cm
3
h = 4000/ (l × b)
= 4000/ (50×8)
= 10cm
6. A cuboidal wooden block contains 36 cm
3
wood. If it be 4 cm long and 3 cm wide,
find its height.
Solution:
Given details are,
Volume of wooden block = 36 cm
3
Length of the wooden block = 4 cm
Breadth of a wooden block = 3 cm
Let height of wooden block be ‘h’ cm
We know that, l × b × h = 36 cm
3
h = 36/( l × b)
= 36/(4×3)
= 3cm
7. What will happen to the volume of a cube, if its edge is
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
(i) halved (ii) trebled?
Solution:
Let us consider edge of a cube be ‘a’ cm
Volume of a cube will be ‘a
3
’cm
(i) When halved
Edge = a/2
Volume = (a/2)
3
= a
3
/2
3
= a
3
/8 = 1/8times
(ii) When trebled
Edge = 3a
Volume = (3a)
3
= 27a
3
= 27times
8. What will happen to the volume of a cuboid if its:
(i) Length is doubled, height is same and breadth is halved?
(ii) Length is doubled, height is doubled and breadth is same?
Solution:
Let us consider,
Length of a cuboid be ‘l’
Breadth of a cuboid be ‘b’
Height of a cuboid be ‘h’
So, Volume of a cuboid = l × b × h
Now,
(i) Length of a cuboid becomes = 2l
Breadth = b/2
Height = h
Volume of cuboid = 2l × b/2 × h = l × b × h (remains same)
(ii) Length of a cuboid becomes = 2l
Breadth = b
Height = 2h
Volume of cuboid = 2l × b × 2h = 4lbh (four times)
9. Three cuboids of dimensions 5 cm × 6cm × 7cm, 4cm × 7cm × 8cm and 2 cm × 3
cm × 13 cm are melted and a cube is made. Find the side of cube.
Solution:
Given details are,
Volume of First cuboid = 5 × 6 × 7 = 210 cm
3
Volume of second cuboid = 4 × 7 × 8 = 224 cm
3
Page 5
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
EXERCISE 21.1 PAGE NO: 21.8
1. Find the volume of a cuboid whose
(i) length = 12 cm, breadth = 8 cm, height = 6 cm
(ii) length = 1.2 m, breadth = 30 cm, height = 15 cm
(iii) length = 15 cm, breadth = 2.5 dm, height = 8 cm.
Solution:
(i) The given details are:
Length of a cuboid = 12 cm
Breadth of a cuboid = 8 cm
Height of a cuboid = 6 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 12 × 8 ×6
= 576 cm
3
(ii) The given details are:
Length of a cuboid = 1.2 m = 120 cm
Breadth of a cuboid = 30 cm
Height of a cuboid = 15 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 120 × 30 × 15
= 54000 cm
3
(iii) The given details are:
Length of a cuboid = 15 cm
Breadth of a cuboid = 2.5 dm = 25 cm
Height of a cuboid = 8 cm
By using the formula
Volume of a cuboid = length × breadth × height
= 15 × 25 × 8
= 3000 cm
3
2. Find the volume of a cube whose side is
(i) 4 cm (ii) 8 cm
(iii) 1.5 dm (iv) 1.2 m
(v) 25 mm
Solution:
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
(i) Given details are,
Side of cube = 4 cm
Volume of cube = (side)
3
= 4
3
= 64 cm
3
(ii) Given details are,
Side of cube = 8 cm
Volume of cube = (side)
3
= 8
3
= 512 cm
3
(iii) Given details are,
Side of cube = 1.5 dm
Volume of cube = (side)
3
= 1.5
3
= 3.375 dm
3
= 3375 cm
3
(iv) Given details are,
Side of cube = 1.2 m
Volume of cube = (side)
3
= 1.2
3
= 1.728 m
3
(v) Given details are,
Side of cube = 25 mm
Volume of cube = (side)
3
= 25
3
= 15625 mm
3
= 15.625 cm
3
3. Find the height of a cuboid of volume 100 cm
3
, whose length and breadth are 5 cm
and 4 cm respectively.
Solution:
Given details are,
Volume of a cuboid = 100 cm
3
Length of a cuboid = 5 cm
Breadth of a cuboid = 4 cm
Let height of cuboid be ‘h’ cm
We know that, l × b × h = 100cm
h = 100/( l × b)
= 100/(5×4)
= 5cm
4. A cuboidal vessel is 10 cm long and 5 cm wide. How high it must be made to hold
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
300 cm
3
of a liquid?
Solution:
Given details are,
Volume of a liquid in the vessel = 300 cm
3
Length of a cuboidal vessel = 10 cm
Breadth of a cuboidal vessel = 5 cm
Let height of cuboidal vessel be ‘h’ cm
We know that, l × b × h = 300 cm
3
h = 300/(l × b)
= 300/(10×5)
= 6cm
5. A milk container is 8 cm long and 50 cm wide. What should be its height so that it
can hold 4 litres of milk?
Solution:
Given details are,
Volume = 4 litres = 4000 cm
3
Length of a milk container = 8 cm
Breadth of a milk container = 50 cm
Let height of milk container be ‘h’ cm
We know that, l × b × h = 4000 cm
3
h = 4000/ (l × b)
= 4000/ (50×8)
= 10cm
6. A cuboidal wooden block contains 36 cm
3
wood. If it be 4 cm long and 3 cm wide,
find its height.
Solution:
Given details are,
Volume of wooden block = 36 cm
3
Length of the wooden block = 4 cm
Breadth of a wooden block = 3 cm
Let height of wooden block be ‘h’ cm
We know that, l × b × h = 36 cm
3
h = 36/( l × b)
= 36/(4×3)
= 3cm
7. What will happen to the volume of a cube, if its edge is
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
(i) halved (ii) trebled?
Solution:
Let us consider edge of a cube be ‘a’ cm
Volume of a cube will be ‘a
3
’cm
(i) When halved
Edge = a/2
Volume = (a/2)
3
= a
3
/2
3
= a
3
/8 = 1/8times
(ii) When trebled
Edge = 3a
Volume = (3a)
3
= 27a
3
= 27times
8. What will happen to the volume of a cuboid if its:
(i) Length is doubled, height is same and breadth is halved?
(ii) Length is doubled, height is doubled and breadth is same?
Solution:
Let us consider,
Length of a cuboid be ‘l’
Breadth of a cuboid be ‘b’
Height of a cuboid be ‘h’
So, Volume of a cuboid = l × b × h
Now,
(i) Length of a cuboid becomes = 2l
Breadth = b/2
Height = h
Volume of cuboid = 2l × b/2 × h = l × b × h (remains same)
(ii) Length of a cuboid becomes = 2l
Breadth = b
Height = 2h
Volume of cuboid = 2l × b × 2h = 4lbh (four times)
9. Three cuboids of dimensions 5 cm × 6cm × 7cm, 4cm × 7cm × 8cm and 2 cm × 3
cm × 13 cm are melted and a cube is made. Find the side of cube.
Solution:
Given details are,
Volume of First cuboid = 5 × 6 × 7 = 210 cm
3
Volume of second cuboid = 4 × 7 × 8 = 224 cm
3
RD Sharma Solutions for Class 8 Maths Chapter 21 – Mensuration –
II (Volumes and Surface Areas of a Cuboid and a Cube)
Volume of third cuboid = 2 × 3 × 13 = 78 cm
3
So, Volume of a cube = 210 + 224 + 78 = 512 cm
3
Let side of a cube be ‘a’
a
3
= 512
? a = 8 cm
10. Find the weight of solid rectangular iron piece of size 50 cm×40cm × 10 cm, if 1
cm
3
of iron weights 8 gm.
Solution:
Given details are,
Dimension of rectangular iron piece = 50cm × 40cm × 10cm
Volume of solid rectangular = 50 × 40 × 10 = 20000 cm
3
Weight of 1 cm
3
iron = 8 gm.
? Weight of 20000 cm
3
iron = 8 × 20000
= 160000 gm.
= 160 kg
11. How many wooden cubical blocks of side 25 cm can be cut from a log of wood of
size 3 m by 75 cm by 50 cm, assuming that there is no wastage?
Solution:
Given details are,
Dimensions of log of wood = 3m × 75cm × 50cm
Side of cubical block = 25cm
We know that,
Number of cubical block that can be made from wooden log =
Volume of wooden block / volume of cubical block
= (300 × 75 × 50) / (25 × 25 × 25)
= 72 blocks
12. A cuboidal block of silver is 9 cm long, 4 cm broad and 3.5 cm in height. From it,
beads of volume 1.5 cm
3
each are to be made. Find the number of beads that can be
made from the block.
Solution:
Given details are,
Length of a cuboidal block of silver = 9cm
Breadth = 4cm
Height = 3.5cm
Volume of a cuboid = l × b × h
= 9 × 4 × 3.5 = 126cm
3
Read More
|
79 videos|408 docs|31 tests
|
Related Exams
About this Document
|
4.82/5 Rating |
|
Dec 24, 2024 Last updated |
Document Description: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation.
The notes and questions for Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 have been prepared according to the Class 8 exam syllabus. Information about Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 covers topics
like and Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Example, for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1.
Introduction of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 in English is available as part of our Mathematics (Maths) Class 8
for Class 8 & Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 in Hindi for Mathematics (Maths) Class 8 course.
Download more important topics related with notes, lectures and mock test series for Class 8
Exam by signing up for free. Class 8: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 | Mathematics (Maths) Class 8
Description
Full syllabus notes, lecture & questions for Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 | Mathematics (Maths) Class 8 - Class 8 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 8 | Best notes, free PDF download
Information about Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1
In this doc you can find the meaning of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 defined & explained in the simplest way possible. Besides explaining types of
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 theory, EduRev gives you an ample number of questions to practice Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 tests, examples and also practice Class 8
tests
|
Explore Courses for Class 8 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
past year papers
,Semester Notes
,Extra Questions
,Objective type Questions
,Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 | Mathematics (Maths) Class 8
,shortcuts and tricks
,ppt
,Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 | Mathematics (Maths) Class 8
,Exam
,Sample Paper
,study material
,Viva Questions
,Summary
,Previous Year Questions with Solutions
,MCQs
,Free
,practice quizzes
,Important questions
,video lectures
,mock tests for examination
,Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 | Mathematics (Maths) Class 8
;
Additional Information about Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 for Class 8 Preparation
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Free PDF Download
The Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 is an invaluable resource that delves deep into the core of the Class 8 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 now and kickstart your journey towards success in the Class 8 exam.
Importance of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1
The importance of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 cannot be overstated, especially for Class 8 aspirants.
This document holds the key to success in the Class 8 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Notes
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Notes on EduRev are your ultimate resource for success.
Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Class 8 Questions
The "Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 Class 8 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 8 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 on the App
Students of Class 8 can study Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - EXERCISE 21.1 is prepared as per the latest Class 8 syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup