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Ratio & Proportion (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 7 PDF Download

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Exercise 9.2        Page No: 9.10 
 
1. Which ratio is larger in the following pairs? 
(i) 3: 4 or 9: 16 
(ii) 15: 16 or 24: 25 
(iii) 4: 7 or 5: 8 
(iv) 9: 20 or 8: 13 
(v) 1: 2 or 13: 27 
 
Solution: 
(i) Given 3: 4 or 9: 16 
LCM for 4 and 16 is 16 
3: 4 can be written as = 3/4 
3/4 × (4/4) = 12/16 
And we have 9/16 
Clearly 12 > 9 
Therefore 3: 4 > 9: 16 
 
(ii) Given 15: 16 or 24: 25 
LCM for 16 and 25 is 400 
15: 16 can be written as = 15/16 
15/16 × (25/25) = 375/400 
And we have 24/25 
24/25 × (16/16) = 384/400 
Clearly 384 > 375 
Therefore 15: 16 < 24: 25 
 
(iii) Given 4: 7 or 5: 8 
LCM for 7 and 8 is 56 
4: 7 can be written as = 4/7 
4/7 × (8/8) = 32/56 
And we have 5/8 
5/8 × (7/7) = 35/56 
Clearly 35 > 32 
Therefore 4: 7 < 5: 8 
 
Page 2


  
 
 
 
 
  
 
Exercise 9.2        Page No: 9.10 
 
1. Which ratio is larger in the following pairs? 
(i) 3: 4 or 9: 16 
(ii) 15: 16 or 24: 25 
(iii) 4: 7 or 5: 8 
(iv) 9: 20 or 8: 13 
(v) 1: 2 or 13: 27 
 
Solution: 
(i) Given 3: 4 or 9: 16 
LCM for 4 and 16 is 16 
3: 4 can be written as = 3/4 
3/4 × (4/4) = 12/16 
And we have 9/16 
Clearly 12 > 9 
Therefore 3: 4 > 9: 16 
 
(ii) Given 15: 16 or 24: 25 
LCM for 16 and 25 is 400 
15: 16 can be written as = 15/16 
15/16 × (25/25) = 375/400 
And we have 24/25 
24/25 × (16/16) = 384/400 
Clearly 384 > 375 
Therefore 15: 16 < 24: 25 
 
(iii) Given 4: 7 or 5: 8 
LCM for 7 and 8 is 56 
4: 7 can be written as = 4/7 
4/7 × (8/8) = 32/56 
And we have 5/8 
5/8 × (7/7) = 35/56 
Clearly 35 > 32 
Therefore 4: 7 < 5: 8 
 
  
 
 
 
 
  
 
(iv) Given 9: 20 or 8: 13 
LCM for 20 and 13 is 260 
9: 20 can be written as = 9/20 
9/20 × (13/13) = 117/260 
And we have 8/13 
8/13 × (20/20) = 160/260 
Clearly 160 > 117 
Therefore 9: 20 < 8: 13 
 
(v) Given 1: 2 or 13: 27 
LCM for 2 and 27 is 54 
1: 2 can be written as = 1/2 
1/2 × (27/27) = 27/54 
And we have 13/27 
13/27 × (2/2) = 26/54 
Clearly 27 > 26 
Therefore 1: 2 > 13: 27 
 
2. Give the equivalent ratios of 6: 8. 
 
Solution: 
Given 6: 8 
By multiplying both numerator and denominator by 2 we equivalent ratios 
6/8 × (2/2) = 12/16 
And also by dividing both numerator and denominator by 2 we equivalent ratios 
(6/2)/ (8/2) = 3/4 
Two equivalent ratios are 3: 4 = 12: 16 
 
3.  Fill in the following blanks: 
12/20 = …. /5 = 9/…. 
 
Solution: 
12/20 = 3/5 = 9/15 
 
Explanation: 
Consider 12/20 = …. /5 
Let unknown value be x 
Page 3


  
 
 
 
 
  
 
Exercise 9.2        Page No: 9.10 
 
1. Which ratio is larger in the following pairs? 
(i) 3: 4 or 9: 16 
(ii) 15: 16 or 24: 25 
(iii) 4: 7 or 5: 8 
(iv) 9: 20 or 8: 13 
(v) 1: 2 or 13: 27 
 
Solution: 
(i) Given 3: 4 or 9: 16 
LCM for 4 and 16 is 16 
3: 4 can be written as = 3/4 
3/4 × (4/4) = 12/16 
And we have 9/16 
Clearly 12 > 9 
Therefore 3: 4 > 9: 16 
 
(ii) Given 15: 16 or 24: 25 
LCM for 16 and 25 is 400 
15: 16 can be written as = 15/16 
15/16 × (25/25) = 375/400 
And we have 24/25 
24/25 × (16/16) = 384/400 
Clearly 384 > 375 
Therefore 15: 16 < 24: 25 
 
(iii) Given 4: 7 or 5: 8 
LCM for 7 and 8 is 56 
4: 7 can be written as = 4/7 
4/7 × (8/8) = 32/56 
And we have 5/8 
5/8 × (7/7) = 35/56 
Clearly 35 > 32 
Therefore 4: 7 < 5: 8 
 
  
 
 
 
 
  
 
(iv) Given 9: 20 or 8: 13 
LCM for 20 and 13 is 260 
9: 20 can be written as = 9/20 
9/20 × (13/13) = 117/260 
And we have 8/13 
8/13 × (20/20) = 160/260 
Clearly 160 > 117 
Therefore 9: 20 < 8: 13 
 
(v) Given 1: 2 or 13: 27 
LCM for 2 and 27 is 54 
1: 2 can be written as = 1/2 
1/2 × (27/27) = 27/54 
And we have 13/27 
13/27 × (2/2) = 26/54 
Clearly 27 > 26 
Therefore 1: 2 > 13: 27 
 
2. Give the equivalent ratios of 6: 8. 
 
Solution: 
Given 6: 8 
By multiplying both numerator and denominator by 2 we equivalent ratios 
6/8 × (2/2) = 12/16 
And also by dividing both numerator and denominator by 2 we equivalent ratios 
(6/2)/ (8/2) = 3/4 
Two equivalent ratios are 3: 4 = 12: 16 
 
3.  Fill in the following blanks: 
12/20 = …. /5 = 9/…. 
 
Solution: 
12/20 = 3/5 = 9/15 
 
Explanation: 
Consider 12/20 = …. /5 
Let unknown value be x 
  
 
 
 
 
  
 
Therefore 12/20 = x/5 
On cross multiplying 
x = 60/20 
x = 3 
Consider 12/20 = 9/…. 
Let the unknown value be y 
Therefore 12/20 = 9/y 
On cross multiplying we get 
y = 180/12 
y = 15 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
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FAQs on Ratio & Proportion (Exercise 9.2) RD Sharma Solutions - Mathematics (Maths) Class 7

1. What are the basic concepts of ratio and proportion?
Ans. Ratio is the comparison of two quantities of the same kind using division. Proportion is an equation that states that two ratios are equal.
2. How can I simplify ratios?
Ans. To simplify a ratio, divide both terms of the ratio by their greatest common factor (GCF). This will give you the simplest form of the ratio.
3. How do I find the missing term in a proportion?
Ans. To find the missing term in a proportion, cross-multiply the known terms and then solve for the unknown term. This is done by multiplying the numerator of one ratio by the denominator of the other ratio and setting the products equal to each other.
4. Can ratios and proportions be used in real-life situations?
Ans. Yes, ratios and proportions are used in a variety of real-life situations. For example, they can be used to determine ingredient amounts in a recipe, calculate distances on a map, or solve problems involving time and speed.
5. What are some common mistakes to avoid when working with ratios and proportions?
Ans. Some common mistakes to avoid include forgetting to simplify ratios, cross-multiplying incorrectly, and misinterpreting the meaning of the ratio or proportion in the given context. It is important to carefully read and understand the problem before attempting to solve it using ratios and proportions.
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