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Objective Type Questions: Ratio, Proportion and Unitary Method | Mathematics (Maths) Class 6 PDF Download

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Objective Type Questions                                                    page: 9.19 
Mark the correct alternative in each of the following: 
 
1. A ratio equivalent of 2 : 3 is 
(a) 4 : 3 
(b) 2 : 6 
(c) 6 : 9 
(d) 10 : 9 
Solution: 
 
The option (c) is correct answer. 
We know that 6: 9 when divided by 3 we get 2: 3. 
 
2. The angles of a triangle are in the ratio 1 : 2 : 3. The measure of the largest angle is 
(a) 30° 
(b) 60° 
(c) 90° 
(d) 120° 
Solution: 
 
The option (c) is correct answer. 
We know that the sum of all the angles = 180° 
So the largest angle = 3/ (1 + 2 + 3) × 180  
We get 
Largest angle = 3/6 × 180 = 90° 
 
3. The sides of a triangle are in the ratio 2 : 3 : 5. If its perimeter is 100 cm, the length of its smallest side is 
(a) 2 cm 
(b) 20 cm 
(c) 3 cm 
(d) 5 cm 
Solution: 
 
The option (b) is correct answer. 
We know that the length of smallest side = 100 × 2/ (2 + 3 + 5) = 200/10 = 20 cm 
 
4. Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is 
(a) 63 
(b) 42 
(c) 49 
(d) 72 
Solution: 
 
The option (a) is correct answer. 
Consider x as the largest number 
So we get 
7x + 9x = 112 
16x = 112 
x = 112/16 = 7 
Page 2


 
 
 
 
 
 
Objective Type Questions                                                    page: 9.19 
Mark the correct alternative in each of the following: 
 
1. A ratio equivalent of 2 : 3 is 
(a) 4 : 3 
(b) 2 : 6 
(c) 6 : 9 
(d) 10 : 9 
Solution: 
 
The option (c) is correct answer. 
We know that 6: 9 when divided by 3 we get 2: 3. 
 
2. The angles of a triangle are in the ratio 1 : 2 : 3. The measure of the largest angle is 
(a) 30° 
(b) 60° 
(c) 90° 
(d) 120° 
Solution: 
 
The option (c) is correct answer. 
We know that the sum of all the angles = 180° 
So the largest angle = 3/ (1 + 2 + 3) × 180  
We get 
Largest angle = 3/6 × 180 = 90° 
 
3. The sides of a triangle are in the ratio 2 : 3 : 5. If its perimeter is 100 cm, the length of its smallest side is 
(a) 2 cm 
(b) 20 cm 
(c) 3 cm 
(d) 5 cm 
Solution: 
 
The option (b) is correct answer. 
We know that the length of smallest side = 100 × 2/ (2 + 3 + 5) = 200/10 = 20 cm 
 
4. Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is 
(a) 63 
(b) 42 
(c) 49 
(d) 72 
Solution: 
 
The option (a) is correct answer. 
Consider x as the largest number 
So we get 
7x + 9x = 112 
16x = 112 
x = 112/16 = 7 
 
 
 
 
 
 
Here 
7x = 7 × 7 = 49 
9x = 9 × 7 = 63 
Hence, the largest number is 63. 
 
5. Two ratio 384 : 480 in its simplest form is 
(a) 3 : 5 
(b) 5 : 4 
(c) 4 : 5 
(d) 2 : 5 
Solution: 
 
The option (c) is correct answer. 
384: 480 can be written as 
384/480 = 4/5 when divided by 96 
 
6. If A, B, C, divide Rs 1200 in the ratio 2 : 3 : 5, then B's share is 
(a) Rs 240 
(b) Rs 600 
(c) Rs 380 
(d) Rs 360 
Solution: 
 
The option (d) is correct answer. 
So B’s share = 1200 × 3/ (2 + 3 + 5) 
On further calculation 
B’s share = 1200 × 3/10 = Rs 360 
 
7. If a bus travels 126 km in 3 hours and a train travels 315 km in 5 hours, then the ratio of their speeds is 
(a) 2 : 5 
(b) 2 : 3 
(c) 5 : 2 
(d) 25 : 6 
Solution: 
 
The option (b) is correct answer. 
We know that speed = distance/time 
So the speed of bus = 126/3 = 42 km/h 
Speed of train = 315/5 = 63 km/h 
So the ratio of their speeds = 42: 63 = 2: 3 
 
8. The ratio of male and female employees in a multinational company is 5 : 3. If there are 115 male 
employees in the company, then the number of female employees is 
(a) 96 
(b) 52 
(c) 69 
(d) 66 
Solution: 
 
The option (c) is correct answer. 
Page 3


 
 
 
 
 
 
Objective Type Questions                                                    page: 9.19 
Mark the correct alternative in each of the following: 
 
1. A ratio equivalent of 2 : 3 is 
(a) 4 : 3 
(b) 2 : 6 
(c) 6 : 9 
(d) 10 : 9 
Solution: 
 
The option (c) is correct answer. 
We know that 6: 9 when divided by 3 we get 2: 3. 
 
2. The angles of a triangle are in the ratio 1 : 2 : 3. The measure of the largest angle is 
(a) 30° 
(b) 60° 
(c) 90° 
(d) 120° 
Solution: 
 
The option (c) is correct answer. 
We know that the sum of all the angles = 180° 
So the largest angle = 3/ (1 + 2 + 3) × 180  
We get 
Largest angle = 3/6 × 180 = 90° 
 
3. The sides of a triangle are in the ratio 2 : 3 : 5. If its perimeter is 100 cm, the length of its smallest side is 
(a) 2 cm 
(b) 20 cm 
(c) 3 cm 
(d) 5 cm 
Solution: 
 
The option (b) is correct answer. 
We know that the length of smallest side = 100 × 2/ (2 + 3 + 5) = 200/10 = 20 cm 
 
4. Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is 
(a) 63 
(b) 42 
(c) 49 
(d) 72 
Solution: 
 
The option (a) is correct answer. 
Consider x as the largest number 
So we get 
7x + 9x = 112 
16x = 112 
x = 112/16 = 7 
 
 
 
 
 
 
Here 
7x = 7 × 7 = 49 
9x = 9 × 7 = 63 
Hence, the largest number is 63. 
 
5. Two ratio 384 : 480 in its simplest form is 
(a) 3 : 5 
(b) 5 : 4 
(c) 4 : 5 
(d) 2 : 5 
Solution: 
 
The option (c) is correct answer. 
384: 480 can be written as 
384/480 = 4/5 when divided by 96 
 
6. If A, B, C, divide Rs 1200 in the ratio 2 : 3 : 5, then B's share is 
(a) Rs 240 
(b) Rs 600 
(c) Rs 380 
(d) Rs 360 
Solution: 
 
The option (d) is correct answer. 
So B’s share = 1200 × 3/ (2 + 3 + 5) 
On further calculation 
B’s share = 1200 × 3/10 = Rs 360 
 
7. If a bus travels 126 km in 3 hours and a train travels 315 km in 5 hours, then the ratio of their speeds is 
(a) 2 : 5 
(b) 2 : 3 
(c) 5 : 2 
(d) 25 : 6 
Solution: 
 
The option (b) is correct answer. 
We know that speed = distance/time 
So the speed of bus = 126/3 = 42 km/h 
Speed of train = 315/5 = 63 km/h 
So the ratio of their speeds = 42: 63 = 2: 3 
 
8. The ratio of male and female employees in a multinational company is 5 : 3. If there are 115 male 
employees in the company, then the number of female employees is 
(a) 96 
(b) 52 
(c) 69 
(d) 66 
Solution: 
 
The option (c) is correct answer. 
 
 
 
 
 
 
Consider x as the number of female employees 
So we get 
5/3 = 115/x 
By cross multiplication 
5x = 115 × 3 = 345 
By division 
x = 345/5 = 69 
 
9. Length and width of a field are in the ratio 5 : 3. If the width of the field is 42 m, then its length is 
(a) 50 m 
(b) 70 m 
(c) 80 m 
(d) 100 m 
Solution: 
 
The option (b) is correct answer. 
It is given that length and width of a field = 5: 3 
Consider x m as the length 
Width of the filed = 42 m 
So the length can be written as 
5/3 = x/42 
By cross multiplication 
3x = 42 × 5 = 210 
By division 
x = 210/3 = 70 
 
10. If 57 : x = 51 : 85, then the value of x is 
(a) 95 
(b) 76 
(c) 114 
(d) None of these 
Solution: 
 
The option (a) is correct answer. 
It can be written as 
57/x = 51/85 
By cross multiplication 
57 × 85/51 = x 
So we get 
x = 95 
 
11. The ratio of boys and girls in a school is 12 : 5. If there are 840 girls in the school, then the number of 
boys is 
(a) 1190 
(b) 2380 
(c) 2856 
(d) 2142 
Solution: 
 
The options are not correct. 
Page 4


 
 
 
 
 
 
Objective Type Questions                                                    page: 9.19 
Mark the correct alternative in each of the following: 
 
1. A ratio equivalent of 2 : 3 is 
(a) 4 : 3 
(b) 2 : 6 
(c) 6 : 9 
(d) 10 : 9 
Solution: 
 
The option (c) is correct answer. 
We know that 6: 9 when divided by 3 we get 2: 3. 
 
2. The angles of a triangle are in the ratio 1 : 2 : 3. The measure of the largest angle is 
(a) 30° 
(b) 60° 
(c) 90° 
(d) 120° 
Solution: 
 
The option (c) is correct answer. 
We know that the sum of all the angles = 180° 
So the largest angle = 3/ (1 + 2 + 3) × 180  
We get 
Largest angle = 3/6 × 180 = 90° 
 
3. The sides of a triangle are in the ratio 2 : 3 : 5. If its perimeter is 100 cm, the length of its smallest side is 
(a) 2 cm 
(b) 20 cm 
(c) 3 cm 
(d) 5 cm 
Solution: 
 
The option (b) is correct answer. 
We know that the length of smallest side = 100 × 2/ (2 + 3 + 5) = 200/10 = 20 cm 
 
4. Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is 
(a) 63 
(b) 42 
(c) 49 
(d) 72 
Solution: 
 
The option (a) is correct answer. 
Consider x as the largest number 
So we get 
7x + 9x = 112 
16x = 112 
x = 112/16 = 7 
 
 
 
 
 
 
Here 
7x = 7 × 7 = 49 
9x = 9 × 7 = 63 
Hence, the largest number is 63. 
 
5. Two ratio 384 : 480 in its simplest form is 
(a) 3 : 5 
(b) 5 : 4 
(c) 4 : 5 
(d) 2 : 5 
Solution: 
 
The option (c) is correct answer. 
384: 480 can be written as 
384/480 = 4/5 when divided by 96 
 
6. If A, B, C, divide Rs 1200 in the ratio 2 : 3 : 5, then B's share is 
(a) Rs 240 
(b) Rs 600 
(c) Rs 380 
(d) Rs 360 
Solution: 
 
The option (d) is correct answer. 
So B’s share = 1200 × 3/ (2 + 3 + 5) 
On further calculation 
B’s share = 1200 × 3/10 = Rs 360 
 
7. If a bus travels 126 km in 3 hours and a train travels 315 km in 5 hours, then the ratio of their speeds is 
(a) 2 : 5 
(b) 2 : 3 
(c) 5 : 2 
(d) 25 : 6 
Solution: 
 
The option (b) is correct answer. 
We know that speed = distance/time 
So the speed of bus = 126/3 = 42 km/h 
Speed of train = 315/5 = 63 km/h 
So the ratio of their speeds = 42: 63 = 2: 3 
 
8. The ratio of male and female employees in a multinational company is 5 : 3. If there are 115 male 
employees in the company, then the number of female employees is 
(a) 96 
(b) 52 
(c) 69 
(d) 66 
Solution: 
 
The option (c) is correct answer. 
 
 
 
 
 
 
Consider x as the number of female employees 
So we get 
5/3 = 115/x 
By cross multiplication 
5x = 115 × 3 = 345 
By division 
x = 345/5 = 69 
 
9. Length and width of a field are in the ratio 5 : 3. If the width of the field is 42 m, then its length is 
(a) 50 m 
(b) 70 m 
(c) 80 m 
(d) 100 m 
Solution: 
 
The option (b) is correct answer. 
It is given that length and width of a field = 5: 3 
Consider x m as the length 
Width of the filed = 42 m 
So the length can be written as 
5/3 = x/42 
By cross multiplication 
3x = 42 × 5 = 210 
By division 
x = 210/3 = 70 
 
10. If 57 : x = 51 : 85, then the value of x is 
(a) 95 
(b) 76 
(c) 114 
(d) None of these 
Solution: 
 
The option (a) is correct answer. 
It can be written as 
57/x = 51/85 
By cross multiplication 
57 × 85/51 = x 
So we get 
x = 95 
 
11. The ratio of boys and girls in a school is 12 : 5. If there are 840 girls in the school, then the number of 
boys is 
(a) 1190 
(b) 2380 
(c) 2856 
(d) 2142 
Solution: 
 
The options are not correct. 
 
 
 
 
 
 
Consider x as the number of boys 
Ratio of boys and girls = 12: 5 
It can be written as 
12/5 = x/840 
By cross multiplication 
x = 12/5 × 840 = 2016 
 
12. If 4, a, a, 36 are in proportion, then a = 
(a) 24 
(b) 12 
(c) 3 
(d) 24 
Solution: 
 
The option (b) is correct answer. 
It is given that 4, a, a, 36 are in proportion 
We can write it as 4 : a :: a : 36 
So we get 
4/a = a/36 
By cross multiplication 
4 × 36 = a × a 
We get 
a
2
 = 144  
So a = 12 
 
13. If 5 : 4 : : 30 : x, then the value of x is 
(a) 24 
(b) 12 
(c) 3/2 
(d) 6 
Solution: 
 
The option (a) is correct answer. 
It can be written as 
5/4 = 30/x 
By cross multiplication 
x = 30 × 4/5 = 24 
 
14. If a, b, c, d are in proportion, then 
(a) ab = cd 
(b) ac = bd 
(c) ad = bc 
(d) None of these 
Solution: 
 
The option (c) is correct answer. 
It is given that a, b, c, d are in proportion 
We can write it as a : b :: c : d 
So we get  
a/b = c/d 
Page 5


 
 
 
 
 
 
Objective Type Questions                                                    page: 9.19 
Mark the correct alternative in each of the following: 
 
1. A ratio equivalent of 2 : 3 is 
(a) 4 : 3 
(b) 2 : 6 
(c) 6 : 9 
(d) 10 : 9 
Solution: 
 
The option (c) is correct answer. 
We know that 6: 9 when divided by 3 we get 2: 3. 
 
2. The angles of a triangle are in the ratio 1 : 2 : 3. The measure of the largest angle is 
(a) 30° 
(b) 60° 
(c) 90° 
(d) 120° 
Solution: 
 
The option (c) is correct answer. 
We know that the sum of all the angles = 180° 
So the largest angle = 3/ (1 + 2 + 3) × 180  
We get 
Largest angle = 3/6 × 180 = 90° 
 
3. The sides of a triangle are in the ratio 2 : 3 : 5. If its perimeter is 100 cm, the length of its smallest side is 
(a) 2 cm 
(b) 20 cm 
(c) 3 cm 
(d) 5 cm 
Solution: 
 
The option (b) is correct answer. 
We know that the length of smallest side = 100 × 2/ (2 + 3 + 5) = 200/10 = 20 cm 
 
4. Two numbers are in the ratio 7 : 9. If the sum of the numbers is 112, then the larger number is 
(a) 63 
(b) 42 
(c) 49 
(d) 72 
Solution: 
 
The option (a) is correct answer. 
Consider x as the largest number 
So we get 
7x + 9x = 112 
16x = 112 
x = 112/16 = 7 
 
 
 
 
 
 
Here 
7x = 7 × 7 = 49 
9x = 9 × 7 = 63 
Hence, the largest number is 63. 
 
5. Two ratio 384 : 480 in its simplest form is 
(a) 3 : 5 
(b) 5 : 4 
(c) 4 : 5 
(d) 2 : 5 
Solution: 
 
The option (c) is correct answer. 
384: 480 can be written as 
384/480 = 4/5 when divided by 96 
 
6. If A, B, C, divide Rs 1200 in the ratio 2 : 3 : 5, then B's share is 
(a) Rs 240 
(b) Rs 600 
(c) Rs 380 
(d) Rs 360 
Solution: 
 
The option (d) is correct answer. 
So B’s share = 1200 × 3/ (2 + 3 + 5) 
On further calculation 
B’s share = 1200 × 3/10 = Rs 360 
 
7. If a bus travels 126 km in 3 hours and a train travels 315 km in 5 hours, then the ratio of their speeds is 
(a) 2 : 5 
(b) 2 : 3 
(c) 5 : 2 
(d) 25 : 6 
Solution: 
 
The option (b) is correct answer. 
We know that speed = distance/time 
So the speed of bus = 126/3 = 42 km/h 
Speed of train = 315/5 = 63 km/h 
So the ratio of their speeds = 42: 63 = 2: 3 
 
8. The ratio of male and female employees in a multinational company is 5 : 3. If there are 115 male 
employees in the company, then the number of female employees is 
(a) 96 
(b) 52 
(c) 69 
(d) 66 
Solution: 
 
The option (c) is correct answer. 
 
 
 
 
 
 
Consider x as the number of female employees 
So we get 
5/3 = 115/x 
By cross multiplication 
5x = 115 × 3 = 345 
By division 
x = 345/5 = 69 
 
9. Length and width of a field are in the ratio 5 : 3. If the width of the field is 42 m, then its length is 
(a) 50 m 
(b) 70 m 
(c) 80 m 
(d) 100 m 
Solution: 
 
The option (b) is correct answer. 
It is given that length and width of a field = 5: 3 
Consider x m as the length 
Width of the filed = 42 m 
So the length can be written as 
5/3 = x/42 
By cross multiplication 
3x = 42 × 5 = 210 
By division 
x = 210/3 = 70 
 
10. If 57 : x = 51 : 85, then the value of x is 
(a) 95 
(b) 76 
(c) 114 
(d) None of these 
Solution: 
 
The option (a) is correct answer. 
It can be written as 
57/x = 51/85 
By cross multiplication 
57 × 85/51 = x 
So we get 
x = 95 
 
11. The ratio of boys and girls in a school is 12 : 5. If there are 840 girls in the school, then the number of 
boys is 
(a) 1190 
(b) 2380 
(c) 2856 
(d) 2142 
Solution: 
 
The options are not correct. 
 
 
 
 
 
 
Consider x as the number of boys 
Ratio of boys and girls = 12: 5 
It can be written as 
12/5 = x/840 
By cross multiplication 
x = 12/5 × 840 = 2016 
 
12. If 4, a, a, 36 are in proportion, then a = 
(a) 24 
(b) 12 
(c) 3 
(d) 24 
Solution: 
 
The option (b) is correct answer. 
It is given that 4, a, a, 36 are in proportion 
We can write it as 4 : a :: a : 36 
So we get 
4/a = a/36 
By cross multiplication 
4 × 36 = a × a 
We get 
a
2
 = 144  
So a = 12 
 
13. If 5 : 4 : : 30 : x, then the value of x is 
(a) 24 
(b) 12 
(c) 3/2 
(d) 6 
Solution: 
 
The option (a) is correct answer. 
It can be written as 
5/4 = 30/x 
By cross multiplication 
x = 30 × 4/5 = 24 
 
14. If a, b, c, d are in proportion, then 
(a) ab = cd 
(b) ac = bd 
(c) ad = bc 
(d) None of these 
Solution: 
 
The option (c) is correct answer. 
It is given that a, b, c, d are in proportion 
We can write it as a : b :: c : d 
So we get  
a/b = c/d 
 
 
 
 
 
 
By cross multiplication 
ad = bc 
 
15. If a, b, c, are in proportion, then 
(a) a
2
 = bc 
(b) b
2 
= ac 
(c) c
2
 = ab 
(d) None of these 
Solution: 
 
The option (b) is correct answer. 
It is given that a, b, c are in proportion 
We can write it as 
a : b :: b : c 
So we get 
a/b = b/c 
By cross multiplication 
b
2
 = ac 
 
16. If the cost of 5 bars of a soap is Rs. 30, then the cost of one dozen bars is 
(a) Rs 60 
(b) Rs 120 
(c) Rs 72 
(d) Rs 140 
Solution: 
 
The option (c) is correct answer. 
Consider Rs x as the cost of one dozen bars 
It can be written as 
30/5 = x/12 
So we get 
x = 30/5 × 12 = Rs 72 
 
17. 12 men can finish a piece of work in 25 days. The number of days in which the same piece of work can 
be done by 20 men, is 
(a) 10 days 
(b) 12 days 
(c) 15 days 
(d) 14 days 
Solution: 
 
The option (c) is correct answer. 
Consider x days required by 20 men to do the same work 
20/12 = 25/x 
So we get 
x = 12 × 25/20 = 15 days 
 
18. If the cost of 25 packets of 12 pencils each is Rs 750, then the cost of 30 packets of 8 pencils each is 
(a) Rs 600 
(b) Rs 720
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FAQs on Objective Type Questions: Ratio, Proportion and Unitary Method - Mathematics (Maths) Class 6

1. What is a ratio and how is it calculated?
A ratio is a comparison of two quantities. It is calculated by dividing one quantity by another quantity. For example, if there are 4 red balls and 6 blue balls, the ratio of red balls to blue balls is 4:6 or simplified as 2:3.
2. How is proportion related to ratio?
Proportion is a statement that two ratios are equal. It is used to compare two ratios and determine if they are equivalent. For example, if the ratio of red balls to blue balls is 2:3 and the ratio of green balls to yellow balls is 6:9, we can set up the proportion 2:3 = 6:9 and solve for the missing values.
3. What is the unitary method and how is it used?
The unitary method is a technique used to solve problems involving ratios and proportions. It involves finding the value of one unit and then using that value to find the value of another unit. For example, if the cost of 5 pens is $10, we can find the cost of 1 pen by dividing $10 by 5, which gives us $2. We can then use this value to find the cost of any number of pens.
4. How do you solve problems involving direct proportion?
To solve problems involving direct proportion, you need to set up a proportion and solve for the missing value. For example, if the distance travelled is directly proportional to the time taken, and it takes 4 hours to travel 240 miles, we can set up the proportion 4:240 = x:6 (where x is the unknown distance). Cross-multiplying and solving for x gives us x = 36, so the distance travelled in 6 hours is 36 miles.
5. How can I use the unitary method to convert between units of measurement?
To convert between units of measurement using the unitary method, you need to establish a ratio between the two units. For example, if 1 meter is equal to 100 centimeters, and you want to convert 5 meters to centimeters, you can set up the proportion 1:100 = 5:x (where x is the unknown value in centimeters). Cross-multiplying and solving for x gives us x = 500, so 5 meters is equal to 500 centimeters.
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The importance of Objective Type Questions: Ratio, Proportion and Unitary Method cannot be overstated, especially for Class 6 aspirants. This document holds the key to success in the Class 6 exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

Objective Type Questions: Ratio, Proportion and Unitary Method Notes

Objective Type Questions: Ratio, Proportion and Unitary Method Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to Objective Type Questions: Ratio, Proportion and Unitary Method. It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, Objective Type Questions: Ratio, Proportion and Unitary Method Notes on EduRev are your ultimate resource for success.

Objective Type Questions: Ratio, Proportion and Unitary Method Class 6

The "Objective Type Questions: Ratio, Proportion and Unitary Method Class 6 Questions" guide is a valuable resource for all aspiring students preparing for the Class 6 exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

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Students of Class 6 can study Objective Type Questions: Ratio, Proportion and Unitary Method alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the Objective Type Questions: Ratio, Proportion and Unitary Method, students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of Objective Type Questions: Ratio, Proportion and Unitary Method is prepared as per the latest Class 6 syllabus.
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