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PPT: Bending Stresses in Beams

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4.1 SIMPLE BENDING OR PURE 
BENDING 
? When some external force acts on a beam, the 
shear force and bending moments are set up at 
all the sections of the beam
? Due to shear force and bending moment, the 
beam undergoes deformation. The material of the 
beam offers resistance to deformation
? Stresses introduced by bending moment are 
known as bending stresses
? Bending stresses are indirect normal stresses
Page 2


4.1 SIMPLE BENDING OR PURE 
BENDING 
? When some external force acts on a beam, the 
shear force and bending moments are set up at 
all the sections of the beam
? Due to shear force and bending moment, the 
beam undergoes deformation. The material of the 
beam offers resistance to deformation
? Stresses introduced by bending moment are 
known as bending stresses
? Bending stresses are indirect normal stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? When a length of a beam is subjected to zero 
shear force and constant bending moment, then 
that length of beam is subjected to pure bending 
or simple pending.
? The stress set up in that length of the beam due 
to pure bending is called simple bending stresses
Page 3


4.1 SIMPLE BENDING OR PURE 
BENDING 
? When some external force acts on a beam, the 
shear force and bending moments are set up at 
all the sections of the beam
? Due to shear force and bending moment, the 
beam undergoes deformation. The material of the 
beam offers resistance to deformation
? Stresses introduced by bending moment are 
known as bending stresses
? Bending stresses are indirect normal stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? When a length of a beam is subjected to zero 
shear force and constant bending moment, then 
that length of beam is subjected to pure bending 
or simple pending.
? The stress set up in that length of the beam due 
to pure bending is called simple bending stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? Consider a simply supported beam with over 
hanging portions of equal lengths. Suppose the 
beam is subjected to equal loads of intensity W at 
either ends of the over hanging portion
? In the portion of beam of length l, the beam is 
subjected to constant bending moment of 
intensity w x a and shear force in this portion is 
zero
? Hence the portion AB is said to be subjected to 
pure bending or simple bending
Page 4


4.1 SIMPLE BENDING OR PURE 
BENDING 
? When some external force acts on a beam, the 
shear force and bending moments are set up at 
all the sections of the beam
? Due to shear force and bending moment, the 
beam undergoes deformation. The material of the 
beam offers resistance to deformation
? Stresses introduced by bending moment are 
known as bending stresses
? Bending stresses are indirect normal stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? When a length of a beam is subjected to zero 
shear force and constant bending moment, then 
that length of beam is subjected to pure bending 
or simple pending.
? The stress set up in that length of the beam due 
to pure bending is called simple bending stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? Consider a simply supported beam with over 
hanging portions of equal lengths. Suppose the 
beam is subjected to equal loads of intensity W at 
either ends of the over hanging portion
? In the portion of beam of length l, the beam is 
subjected to constant bending moment of 
intensity w x a and shear force in this portion is 
zero
? Hence the portion AB is said to be subjected to 
pure bending or simple bending
4.2 ASSUMPTIONS FOR THE 
THEORY OF PURE BENDING
? The material of the beam is isotropic and 
homogeneous. Ie of same density and elastic 
properties throughout
? The beam is initially straight and unstressed and 
all the longitudinal filaments bend into a circular 
arc with a common  centre of curvature 
? The elastic limit is nowhere exceeded during the 
bending
? Young's modulus for the material is the same in 
tension and compression
Page 5


4.1 SIMPLE BENDING OR PURE 
BENDING 
? When some external force acts on a beam, the 
shear force and bending moments are set up at 
all the sections of the beam
? Due to shear force and bending moment, the 
beam undergoes deformation. The material of the 
beam offers resistance to deformation
? Stresses introduced by bending moment are 
known as bending stresses
? Bending stresses are indirect normal stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? When a length of a beam is subjected to zero 
shear force and constant bending moment, then 
that length of beam is subjected to pure bending 
or simple pending.
? The stress set up in that length of the beam due 
to pure bending is called simple bending stresses
4.1 SIMPLE BENDING OR PURE 
BENDING 
? Consider a simply supported beam with over 
hanging portions of equal lengths. Suppose the 
beam is subjected to equal loads of intensity W at 
either ends of the over hanging portion
? In the portion of beam of length l, the beam is 
subjected to constant bending moment of 
intensity w x a and shear force in this portion is 
zero
? Hence the portion AB is said to be subjected to 
pure bending or simple bending
4.2 ASSUMPTIONS FOR THE 
THEORY OF PURE BENDING
? The material of the beam is isotropic and 
homogeneous. Ie of same density and elastic 
properties throughout
? The beam is initially straight and unstressed and 
all the longitudinal filaments bend into a circular 
arc with a common  centre of curvature 
? The elastic limit is nowhere exceeded during the 
bending
? Young's modulus for the material is the same in 
tension and compression
4.2 ASSUMPTIONS FOR THE 
THEORY OF PURE BENDING
? The transverse sections which were plane before 
bending remain plane after bending also
? Radius of curvature is large compared to the 
dimensions of the cross section of the beam
? There is no resultant force perpendicular to any 
cross section
? All the layers of the beam are free to elongate 
and contract, independently of the layer, above or 
below it.
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FAQs on PPT: Bending Stresses in Beams

1. What's the difference between bending stress and shear stress in beams?
Ans. Bending stress develops perpendicular to a beam's cross-section due to external loads causing curvature, while shear stress acts parallel to the cross-section resisting internal sliding. In beam bending, maximum bending stress occurs at the extreme fibres (top and bottom), whereas shear stress is maximum at the neutral axis. Both are critical for beam design and safety calculations.
2. How do I calculate bending stress using the bending stress formula?
Ans. Bending stress is calculated using σ = M/I × y, where M is bending moment, I is second moment of area, and y is the distance from the neutral axis. The neutral axis runs through the geometric centre of the cross-section. For a rectangular beam, I = bd³/12. This formula helps determine maximum stress at outermost fibres, essential for checking beam safety against material yield strength.
3. Why does the neutral axis matter when finding bending stresses in beams?
Ans. The neutral axis is the line where bending stress equals zero-fibres above experience tension while below experience compression. Its location determines how stress distributes across the cross-section; shifting it changes stress magnitude throughout the beam. For symmetrical sections, it's at the geometric centre; for asymmetrical beams, calculations differ. Understanding neutral axis position is fundamental to predicting beam failure and designing safe structures.
4. What happens to bending stress at the extreme fibres of a beam?
Ans. Extreme fibres-the topmost and bottommost layers-experience maximum bending stress, either maximum tension or maximum compression. Stress magnitude increases linearly from the neutral axis to these extreme points. Material failure typically initiates here first. The relationship between extreme fibre stress and maximum bending moment makes this critical for determining safe load-carrying capacity and material selection in beam design problems.
5. How do I find the second moment of area for different beam cross-sections?
Ans. The second moment of area (I) varies by shape: for rectangular sections, I = bd³/12; for circular sections, I = πd⁴/64; for I-beams, sum individual rectangular components. The second moment measures resistance to bending-larger values mean less deflection under load. Calculating I accurately is essential because bending stress inversely depends on it. EduRev's detailed notes and flashcards provide formulas for all standard cross-sections used in mechanical engineering exams.
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