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 Page 1


 
 
 
PHYSICS 
 
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s 
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant. 
Calculate the magnitude of the force experienced by the electron at that instant. 
 
(1) 4× 10
-20
N 
(2) 8?? × 10
-20
N 
(3) 4?? × 10
-20
N 
(4) 8× 10
-20
N 
Correct Answer: (4) 
Q.1. Solution: 
M.F due to long current carrying wire at 20 cm , 
?? =
?? 0
?? 2????
 
?? =
2× 10
-7
× 5
20× 10
-2
 
?? = 0.5 × 10
-5
 T 
Now, 
Force experienced by electron = ?? V?? 
?? ?? = ?????? 
Page 2


 
 
 
PHYSICS 
 
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s 
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant. 
Calculate the magnitude of the force experienced by the electron at that instant. 
 
(1) 4× 10
-20
N 
(2) 8?? × 10
-20
N 
(3) 4?? × 10
-20
N 
(4) 8× 10
-20
N 
Correct Answer: (4) 
Q.1. Solution: 
M.F due to long current carrying wire at 20 cm , 
?? =
?? 0
?? 2????
 
?? =
2× 10
-7
× 5
20× 10
-2
 
?? = 0.5 × 10
-5
 T 
Now, 
Force experienced by electron = ?? V?? 
?? ?? = ?????? 
 
 
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
 
= 8 × 10
-20
 N 
 
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is: 
(1) n 
(2) 2?? 
(3) 3n 
(4) 4n 
Correct Answer: (2) 
Q.2. Solution: 
Given, 
frequency of SIHM = ?? 
as we know, 
? In one time period ???? become maximum & minimum two time  
So, 
It means frequency of ????  is 2?? . 
 
3. A radioactive nucleus 
?? A
X undergoes spontaneous decay in the sequence 
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where 
 Z  is the atomic number of element X. The possible decay particles in the sequence are: 
(1) ?? ,?? -
,?? +
 
(2) ?? ,?? +
,?? -
 
(3) ?? +
,?? ,?? -
 
(4) ?? -
,?? ,?? +
 
Correct Answer: (3) 
Q.3. Solution: 
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay 
mass number remains unchange and atomic number increases by 1. 
Due to  ?? +
 decay mass number remains unchange but atomic number decreares by 1.  
Page 3


 
 
 
PHYSICS 
 
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s 
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant. 
Calculate the magnitude of the force experienced by the electron at that instant. 
 
(1) 4× 10
-20
N 
(2) 8?? × 10
-20
N 
(3) 4?? × 10
-20
N 
(4) 8× 10
-20
N 
Correct Answer: (4) 
Q.1. Solution: 
M.F due to long current carrying wire at 20 cm , 
?? =
?? 0
?? 2????
 
?? =
2× 10
-7
× 5
20× 10
-2
 
?? = 0.5 × 10
-5
 T 
Now, 
Force experienced by electron = ?? V?? 
?? ?? = ?????? 
 
 
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
 
= 8 × 10
-20
 N 
 
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is: 
(1) n 
(2) 2?? 
(3) 3n 
(4) 4n 
Correct Answer: (2) 
Q.2. Solution: 
Given, 
frequency of SIHM = ?? 
as we know, 
? In one time period ???? become maximum & minimum two time  
So, 
It means frequency of ????  is 2?? . 
 
3. A radioactive nucleus 
?? A
X undergoes spontaneous decay in the sequence 
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where 
 Z  is the atomic number of element X. The possible decay particles in the sequence are: 
(1) ?? ,?? -
,?? +
 
(2) ?? ,?? +
,?? -
 
(3) ?? +
,?? ,?? -
 
(4) ?? -
,?? ,?? +
 
Correct Answer: (3) 
Q.3. Solution: 
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay 
mass number remains unchange and atomic number increases by 1. 
Due to  ?? +
 decay mass number remains unchange but atomic number decreares by 1.  
 
 
So, option (3) is correct option. 
 
4. The escape velocity from the Earth's surface is ?? . The escape velocity from the surface of another planet having a 
radius, four times that of Earth and same mass density is : 
(1) ?? 
(2) 2?? 
(3) 3?? 
(4) 4?? 
Correct Answer: (4) 
Q.4. Solution: 
As we know escape velocity is given by, 
?? ?? = v2???? =
v
2???? 4
3
?? ?? 3
4
3
?? ?? 2
=
v
2???? ?? 4
3
?? ?? 2
 
?? ?? ?
v
?? 2
? ?? 
Escape velocity from Earth’s surface = ?? 
Escape velocity from surface of another planet =? 
?? ???????????? = 4?? ???????? h
 
?? ???????????? = ?? ???????? h
 
So we can write , 
(?? ?? )
earth 
(?? ?? ) planet 
=
 ?? ???????? h
 
?? ???????????? =
?? 4?? =
1
4
 
It means, 
(?? ?? )
earth 
= (?? ?? )
Planet
 
 
(?? ?? )
Planet
 
= 4?? 
 
Page 4


 
 
 
PHYSICS 
 
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s 
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant. 
Calculate the magnitude of the force experienced by the electron at that instant. 
 
(1) 4× 10
-20
N 
(2) 8?? × 10
-20
N 
(3) 4?? × 10
-20
N 
(4) 8× 10
-20
N 
Correct Answer: (4) 
Q.1. Solution: 
M.F due to long current carrying wire at 20 cm , 
?? =
?? 0
?? 2????
 
?? =
2× 10
-7
× 5
20× 10
-2
 
?? = 0.5 × 10
-5
 T 
Now, 
Force experienced by electron = ?? V?? 
?? ?? = ?????? 
 
 
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
 
= 8 × 10
-20
 N 
 
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is: 
(1) n 
(2) 2?? 
(3) 3n 
(4) 4n 
Correct Answer: (2) 
Q.2. Solution: 
Given, 
frequency of SIHM = ?? 
as we know, 
? In one time period ???? become maximum & minimum two time  
So, 
It means frequency of ????  is 2?? . 
 
3. A radioactive nucleus 
?? A
X undergoes spontaneous decay in the sequence 
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where 
 Z  is the atomic number of element X. The possible decay particles in the sequence are: 
(1) ?? ,?? -
,?? +
 
(2) ?? ,?? +
,?? -
 
(3) ?? +
,?? ,?? -
 
(4) ?? -
,?? ,?? +
 
Correct Answer: (3) 
Q.3. Solution: 
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay 
mass number remains unchange and atomic number increases by 1. 
Due to  ?? +
 decay mass number remains unchange but atomic number decreares by 1.  
 
 
So, option (3) is correct option. 
 
4. The escape velocity from the Earth's surface is ?? . The escape velocity from the surface of another planet having a 
radius, four times that of Earth and same mass density is : 
(1) ?? 
(2) 2?? 
(3) 3?? 
(4) 4?? 
Correct Answer: (4) 
Q.4. Solution: 
As we know escape velocity is given by, 
?? ?? = v2???? =
v
2???? 4
3
?? ?? 3
4
3
?? ?? 2
=
v
2???? ?? 4
3
?? ?? 2
 
?? ?? ?
v
?? 2
? ?? 
Escape velocity from Earth’s surface = ?? 
Escape velocity from surface of another planet =? 
?? ???????????? = 4?? ???????? h
 
?? ???????????? = ?? ???????? h
 
So we can write , 
(?? ?? )
earth 
(?? ?? ) planet 
=
 ?? ???????? h
 
?? ???????????? =
?? 4?? =
1
4
 
It means, 
(?? ?? )
earth 
= (?? ?? )
Planet
 
 
(?? ?? )
Planet
 
= 4?? 
 
 
 
5. The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours 
would be : 
(1) 1/2 
(2) 
1
2v2
 
(3) 
2
3
 
(4) 
2
3v2
 
Correct Answer: (2) 
Q.5. Solution: 
Given, 
?? 1
2
= 100 hours 
?? = 150 hours 
? no. of nuclide remain after ?? half life, ?? =
?? 0
2
?? 
? 100 hours = 1 half life 
 150 hours =
1
100
× 150 
=
3
2
 half life 
So, Fraction Remain after 
3
2
 half life 
?? ?? 0
= (
1
2
)
3/2
=
1
2v2
  
 
6. A convex lens 'A' of focal length 20cm and a concave lens ' ?? ' of focal length 5cm are kept along the same axis with a 
distance 'd' between them. If a parallel beam of light falling on 'A' leaves 'B' as a parallel beam, then the distance 'd' in cm 
will be : 
(1) 25 
(2) 15 
(3) 50 
(4) 30 
Page 5


 
 
 
PHYSICS 
 
1. An infinitely long straight conductor carries a current of 5?? as shown. An electron is moving with a speed of 10
5
m/s 
parallel to the conductor. The perpendicular distance between the electron and the conductor is 20cm at an instant. 
Calculate the magnitude of the force experienced by the electron at that instant. 
 
(1) 4× 10
-20
N 
(2) 8?? × 10
-20
N 
(3) 4?? × 10
-20
N 
(4) 8× 10
-20
N 
Correct Answer: (4) 
Q.1. Solution: 
M.F due to long current carrying wire at 20 cm , 
?? =
?? 0
?? 2????
 
?? =
2× 10
-7
× 5
20× 10
-2
 
?? = 0.5 × 10
-5
 T 
Now, 
Force experienced by electron = ?? V?? 
?? ?? = ?????? 
 
 
?? ?? = 1.6× 10
-19
× 10
5
× 0.5 × 10
-5
 
= 8 × 10
-20
 N 
 
2. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is: 
(1) n 
(2) 2?? 
(3) 3n 
(4) 4n 
Correct Answer: (2) 
Q.2. Solution: 
Given, 
frequency of SIHM = ?? 
as we know, 
? In one time period ???? become maximum & minimum two time  
So, 
It means frequency of ????  is 2?? . 
 
3. A radioactive nucleus 
?? A
X undergoes spontaneous decay in the sequence 
Z
A
X ?
Z-1
B ?
Z-3
C ?
Z-2
D where 
 Z  is the atomic number of element X. The possible decay particles in the sequence are: 
(1) ?? ,?? -
,?? +
 
(2) ?? ,?? +
,?? -
 
(3) ?? +
,?? ,?? -
 
(4) ?? -
,?? ,?? +
 
Correct Answer: (3) 
Q.3. Solution: 
As we know due to ?? -decay atomic number decreases by 2 and mass number decreases by 4. Due to ?? -
decay 
mass number remains unchange and atomic number increases by 1. 
Due to  ?? +
 decay mass number remains unchange but atomic number decreares by 1.  
 
 
So, option (3) is correct option. 
 
4. The escape velocity from the Earth's surface is ?? . The escape velocity from the surface of another planet having a 
radius, four times that of Earth and same mass density is : 
(1) ?? 
(2) 2?? 
(3) 3?? 
(4) 4?? 
Correct Answer: (4) 
Q.4. Solution: 
As we know escape velocity is given by, 
?? ?? = v2???? =
v
2???? 4
3
?? ?? 3
4
3
?? ?? 2
=
v
2???? ?? 4
3
?? ?? 2
 
?? ?? ?
v
?? 2
? ?? 
Escape velocity from Earth’s surface = ?? 
Escape velocity from surface of another planet =? 
?? ???????????? = 4?? ???????? h
 
?? ???????????? = ?? ???????? h
 
So we can write , 
(?? ?? )
earth 
(?? ?? ) planet 
=
 ?? ???????? h
 
?? ???????????? =
?? 4?? =
1
4
 
It means, 
(?? ?? )
earth 
= (?? ?? )
Planet
 
 
(?? ?? )
Planet
 
= 4?? 
 
 
 
5. The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours 
would be : 
(1) 1/2 
(2) 
1
2v2
 
(3) 
2
3
 
(4) 
2
3v2
 
Correct Answer: (2) 
Q.5. Solution: 
Given, 
?? 1
2
= 100 hours 
?? = 150 hours 
? no. of nuclide remain after ?? half life, ?? =
?? 0
2
?? 
? 100 hours = 1 half life 
 150 hours =
1
100
× 150 
=
3
2
 half life 
So, Fraction Remain after 
3
2
 half life 
?? ?? 0
= (
1
2
)
3/2
=
1
2v2
  
 
6. A convex lens 'A' of focal length 20cm and a concave lens ' ?? ' of focal length 5cm are kept along the same axis with a 
distance 'd' between them. If a parallel beam of light falling on 'A' leaves 'B' as a parallel beam, then the distance 'd' in cm 
will be : 
(1) 25 
(2) 15 
(3) 50 
(4) 30 
 
 
Correct Answer: (1) 
Q.6. Solution: 
 
Total distance = ?? 1
+ ?? 2
 
= 25 ????  
 
7. A capacitor of capacitance '?? ', is connected across an ac source of voltage ?? , given by V = V
0
sin ?? t The displacement 
current between the plates of the capacitor, would then be given by: 
(1) I
d
= V
0
?? Ccos?? t 
(2) I
d
=
V
0
?? C
cos ?? t 
(3) ?? ?? =
?? 0
????
sin ???? 
 (4) I
d
= V
0
?? Csin ?? t 
Correct Answer: (1) 
Q.7. Solution: 
?  ?? = ????  
And ?? = ?? 0
sin???? 
?? ?? =?  
As we know, 
?  ?? ?? = ?? 0
?? Ø
????
  
= ?? 0
??????
????
    (?  ?? =
?? ?? ) 
=
?? 0
?? ????
?? ????
  
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FAQs on NEET 2021 Past Year Paper with Detailed Solutions - NEET Mock Test Series 2025

1. What is NEET 2021?
NEET 2021 refers to the National Eligibility cum Entrance Test, which is a common entrance examination conducted in India for students who wish to pursue undergraduate medical and dental courses. It is conducted by the National Testing Agency (NTA) and serves as a qualifying exam for admission to medical and dental colleges across the country.
2. Can I get the NEET 2021 past year paper with detailed solutions?
Yes, you can find NEET 2021 past year papers with detailed solutions online. Many educational websites, coaching institutes, and online platforms offer these resources for free or for a nominal fee. These past year papers can be a valuable tool for exam preparation as they provide an insight into the exam pattern, types of questions asked, and help you understand the areas where you need to focus more.
3. How can solving past year papers benefit me in NEET 2021 exam preparation?
Solving past year papers of NEET 2021 can be highly beneficial for your exam preparation. It helps you familiarize yourself with the exam pattern, time management, and the types of questions asked in the actual exam. By solving these papers, you can also identify your strengths and weaknesses, work on improving your problem-solving skills, and gain confidence for the final exam.
4. Are the detailed solutions provided for NEET 2021 past year papers reliable?
The reliability of the detailed solutions for NEET 2021 past year papers depends on the source you choose. It is recommended to refer to solutions provided by reputable coaching institutes, experts, or official websites. These solutions are generally accurate and reliable. However, it is always a good practice to cross-check the solutions with other reference materials or consult with subject experts if you have any doubts or discrepancies.
5. How can I find frequently asked questions (FAQs) related to NEET 2021?
To find frequently asked questions (FAQs) related to NEET 2021, you can search on educational forums, official websites, or online communities dedicated to NEET preparation. You can also refer to popular study materials, coaching institute websites, or educational blogs that often publish FAQs based on student queries and concerns. Additionally, online platforms and social media groups focused on NEET preparation can also provide valuable FAQs and answers from experts and peers.
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