Coordination Compounds Practice Questions - DPP for JEE

 Page 1


1. (b) According to spectrochemical  series .
2. (b) CN
–
 is coordinated to cobalt as the ligand and coordinated
compounds have different properties than the individual species.
3. (d) [Ni X
4
]
2–
, the electronic configuration of Ni
2+
 is
It contains two unpaired electrons and the hybridisation is sp
3
(tetrahedral).
4. (b) The crystal field splitting in tetrahedral complexes is lower than
that in octahedral complexes, and 
5. (c) [Mn(CN)
6
]
3– 
and [Fe(CN)
6
]
3– 
are inner orbital complexes  and
paramagnetic while [Co(C
2
O
4
)
3
]
3–
 is   diamagnetic in nature.
6. (a) Ti(C
2
H
4
)
4
 is an organometallic compound due to Ti directly
attached to C- atom
7. (d) Tetraethyl lead Pb(C
2
H
5
)
4
 is not p bonded complex. It is s bonded
organometallic compound
8. (a)
Number of moles of the complex
=  = 0.01 moles
Number of moles of AgCl obtained
Page 2


1. (b) According to spectrochemical  series .
2. (b) CN
–
 is coordinated to cobalt as the ligand and coordinated
compounds have different properties than the individual species.
3. (d) [Ni X
4
]
2–
, the electronic configuration of Ni
2+
 is
It contains two unpaired electrons and the hybridisation is sp
3
(tetrahedral).
4. (b) The crystal field splitting in tetrahedral complexes is lower than
that in octahedral complexes, and 
5. (c) [Mn(CN)
6
]
3– 
and [Fe(CN)
6
]
3– 
are inner orbital complexes  and
paramagnetic while [Co(C
2
O
4
)
3
]
3–
 is   diamagnetic in nature.
6. (a) Ti(C
2
H
4
)
4
 is an organometallic compound due to Ti directly
attached to C- atom
7. (d) Tetraethyl lead Pb(C
2
H
5
)
4
 is not p bonded complex. It is s bonded
organometallic compound
8. (a)
Number of moles of the complex
=  = 0.01 moles
Number of moles of AgCl obtained
=  moles
? No. of moles of AgCl obtained
= 3 × No. of moles of complex
? n = 
9. (b) The  chemical formula of Pentaminenitrochromium (III) chloride
is
It can exist in following two structures
 and
Therefore the type of isomerism found in this compound is linkage
isomerism as nitro group
 
is linked through N as –NO
2
 or through
O as – ONO.
10. (c) Nickel ions are frequently detected by the formation of red
precipitate of the complex of nickel dimethylglyoxime, when
heated with dimethylglyoxime.
 
Page 3


1. (b) According to spectrochemical  series .
2. (b) CN
–
 is coordinated to cobalt as the ligand and coordinated
compounds have different properties than the individual species.
3. (d) [Ni X
4
]
2–
, the electronic configuration of Ni
2+
 is
It contains two unpaired electrons and the hybridisation is sp
3
(tetrahedral).
4. (b) The crystal field splitting in tetrahedral complexes is lower than
that in octahedral complexes, and 
5. (c) [Mn(CN)
6
]
3– 
and [Fe(CN)
6
]
3– 
are inner orbital complexes  and
paramagnetic while [Co(C
2
O
4
)
3
]
3–
 is   diamagnetic in nature.
6. (a) Ti(C
2
H
4
)
4
 is an organometallic compound due to Ti directly
attached to C- atom
7. (d) Tetraethyl lead Pb(C
2
H
5
)
4
 is not p bonded complex. It is s bonded
organometallic compound
8. (a)
Number of moles of the complex
=  = 0.01 moles
Number of moles of AgCl obtained
=  moles
? No. of moles of AgCl obtained
= 3 × No. of moles of complex
? n = 
9. (b) The  chemical formula of Pentaminenitrochromium (III) chloride
is
It can exist in following two structures
 and
Therefore the type of isomerism found in this compound is linkage
isomerism as nitro group
 
is linked through N as –NO
2
 or through
O as – ONO.
10. (c) Nickel ions are frequently detected by the formation of red
precipitate of the complex of nickel dimethylglyoxime, when
heated with dimethylglyoxime.
 
11. (d) Isomers of given  complexes are as follows
Thus [Co(en)
2
Cl
2
]
+
 has large number of isomers.
12. (d) Due to some backbonding by sidewise overlapping between d-
orbitals of metal and p-orbital of carbon, the F–C bond has both s
and p characters.
13. (a) [PdCl
4
]
2–
 is dsp
2
 hybridized and square planar in shape.
14. (b)
For a given metal ion, weak field ligands create a complex with smaller
?, which will absorbs light of longer ? and thus lower frequency.
Conservely, stronger field ligands create a larger ?, absorb light of
shorter ? and thus higher v i.e. higher energy.
So order of ligand strength is
L
1
 < L
3
 < L
2
 < L
4
15. (d)
16. (c) In both states (paramagnetic  and diamagnetic) of the given
complex, Ni exists as Ni
2+
 whose electronic configuration is [Ar]
3d
8
4s
0
.
Page 4


1. (b) According to spectrochemical  series .
2. (b) CN
–
 is coordinated to cobalt as the ligand and coordinated
compounds have different properties than the individual species.
3. (d) [Ni X
4
]
2–
, the electronic configuration of Ni
2+
 is
It contains two unpaired electrons and the hybridisation is sp
3
(tetrahedral).
4. (b) The crystal field splitting in tetrahedral complexes is lower than
that in octahedral complexes, and 
5. (c) [Mn(CN)
6
]
3– 
and [Fe(CN)
6
]
3– 
are inner orbital complexes  and
paramagnetic while [Co(C
2
O
4
)
3
]
3–
 is   diamagnetic in nature.
6. (a) Ti(C
2
H
4
)
4
 is an organometallic compound due to Ti directly
attached to C- atom
7. (d) Tetraethyl lead Pb(C
2
H
5
)
4
 is not p bonded complex. It is s bonded
organometallic compound
8. (a)
Number of moles of the complex
=  = 0.01 moles
Number of moles of AgCl obtained
=  moles
? No. of moles of AgCl obtained
= 3 × No. of moles of complex
? n = 
9. (b) The  chemical formula of Pentaminenitrochromium (III) chloride
is
It can exist in following two structures
 and
Therefore the type of isomerism found in this compound is linkage
isomerism as nitro group
 
is linked through N as –NO
2
 or through
O as – ONO.
10. (c) Nickel ions are frequently detected by the formation of red
precipitate of the complex of nickel dimethylglyoxime, when
heated with dimethylglyoxime.
 
11. (d) Isomers of given  complexes are as follows
Thus [Co(en)
2
Cl
2
]
+
 has large number of isomers.
12. (d) Due to some backbonding by sidewise overlapping between d-
orbitals of metal and p-orbital of carbon, the F–C bond has both s
and p characters.
13. (a) [PdCl
4
]
2–
 is dsp
2
 hybridized and square planar in shape.
14. (b)
For a given metal ion, weak field ligands create a complex with smaller
?, which will absorbs light of longer ? and thus lower frequency.
Conservely, stronger field ligands create a larger ?, absorb light of
shorter ? and thus higher v i.e. higher energy.
So order of ligand strength is
L
1
 < L
3
 < L
2
 < L
4
15. (d)
16. (c) In both states (paramagnetic  and diamagnetic) of the given
complex, Ni exists as Ni
2+
 whose electronic configuration is [Ar]
3d
8
4s
0
.
Ni
2+
 : 
In the above paramagnetic state the geometry of the complex is sp
3
giving tetrahedral geometry.
The diamagnetic state is achieved by pairing of electrons in 3d orbital.
Thus the geometry of the complex will be dsp
2
 giving square planar
geometry.
17. (b)
 (ppt)
18. (b) The correct IUPAC Name of [Mn(CN)
5
]
2–
.
Pentacyanomangnate (III).
19. (c) EAN of a central metal ion = (atomic no. of central atom) –
oxidation state + no. of ligands × 2 = 26 – 3 + (6× 2) = 23 + 12 =
35
20. (c) In [Co(CO)
5
NH
3
]
2+
 CO is bonded to cobalt through s and p
bonding.
21. (15) [Co(NH
3
)
5
CO
3
]ClO
4. 
Six monodentate ligands are attached to Co
hence C. N. of  Co = 6;
O. N. = x + 5 × (0) + 1 × (–2) + 1× (–1) = 0 ? x = + 3 ; electronic
configuration of Co
3+
[Ar] 3d
6
4s
0
 hence number of d electrons is 6. 
All d electrons are paired due to strong ligand hence unpaired
electron is zero.
The sum of C.N, O. N. No of  d electron and number of uppaired d
electron = 6 + 3 + 6 + 0 = 15
Page 5


1. (b) According to spectrochemical  series .
2. (b) CN
–
 is coordinated to cobalt as the ligand and coordinated
compounds have different properties than the individual species.
3. (d) [Ni X
4
]
2–
, the electronic configuration of Ni
2+
 is
It contains two unpaired electrons and the hybridisation is sp
3
(tetrahedral).
4. (b) The crystal field splitting in tetrahedral complexes is lower than
that in octahedral complexes, and 
5. (c) [Mn(CN)
6
]
3– 
and [Fe(CN)
6
]
3– 
are inner orbital complexes  and
paramagnetic while [Co(C
2
O
4
)
3
]
3–
 is   diamagnetic in nature.
6. (a) Ti(C
2
H
4
)
4
 is an organometallic compound due to Ti directly
attached to C- atom
7. (d) Tetraethyl lead Pb(C
2
H
5
)
4
 is not p bonded complex. It is s bonded
organometallic compound
8. (a)
Number of moles of the complex
=  = 0.01 moles
Number of moles of AgCl obtained
=  moles
? No. of moles of AgCl obtained
= 3 × No. of moles of complex
? n = 
9. (b) The  chemical formula of Pentaminenitrochromium (III) chloride
is
It can exist in following two structures
 and
Therefore the type of isomerism found in this compound is linkage
isomerism as nitro group
 
is linked through N as –NO
2
 or through
O as – ONO.
10. (c) Nickel ions are frequently detected by the formation of red
precipitate of the complex of nickel dimethylglyoxime, when
heated with dimethylglyoxime.
 
11. (d) Isomers of given  complexes are as follows
Thus [Co(en)
2
Cl
2
]
+
 has large number of isomers.
12. (d) Due to some backbonding by sidewise overlapping between d-
orbitals of metal and p-orbital of carbon, the F–C bond has both s
and p characters.
13. (a) [PdCl
4
]
2–
 is dsp
2
 hybridized and square planar in shape.
14. (b)
For a given metal ion, weak field ligands create a complex with smaller
?, which will absorbs light of longer ? and thus lower frequency.
Conservely, stronger field ligands create a larger ?, absorb light of
shorter ? and thus higher v i.e. higher energy.
So order of ligand strength is
L
1
 < L
3
 < L
2
 < L
4
15. (d)
16. (c) In both states (paramagnetic  and diamagnetic) of the given
complex, Ni exists as Ni
2+
 whose electronic configuration is [Ar]
3d
8
4s
0
.
Ni
2+
 : 
In the above paramagnetic state the geometry of the complex is sp
3
giving tetrahedral geometry.
The diamagnetic state is achieved by pairing of electrons in 3d orbital.
Thus the geometry of the complex will be dsp
2
 giving square planar
geometry.
17. (b)
 (ppt)
18. (b) The correct IUPAC Name of [Mn(CN)
5
]
2–
.
Pentacyanomangnate (III).
19. (c) EAN of a central metal ion = (atomic no. of central atom) –
oxidation state + no. of ligands × 2 = 26 – 3 + (6× 2) = 23 + 12 =
35
20. (c) In [Co(CO)
5
NH
3
]
2+
 CO is bonded to cobalt through s and p
bonding.
21. (15) [Co(NH
3
)
5
CO
3
]ClO
4. 
Six monodentate ligands are attached to Co
hence C. N. of  Co = 6;
O. N. = x + 5 × (0) + 1 × (–2) + 1× (–1) = 0 ? x = + 3 ; electronic
configuration of Co
3+
[Ar] 3d
6
4s
0
 hence number of d electrons is 6. 
All d electrons are paired due to strong ligand hence unpaired
electron is zero.
The sum of C.N, O. N. No of  d electron and number of uppaired d
electron = 6 + 3 + 6 + 0 = 15
22. (1.0)EDTA has hexadentate four donor O atoms and 2 donor N atoms
and for the formation of octahedral complex one molecule is
required.
23. (3) [MA
6
] No. of geometrical isomers
[MA
5
B] No. of geometrical isomers
Thus, 3 complexes will show geometrical isomerism.
24. (7.93) Gd (64) = [Xe] 4f 
7
 5d
1 
6s
2
Gd
3+
 = [Xe] 4f 
7
 5d
0 
6s
0
i.e. no. of unpaired electrons = 7
 
 = 7.93 BM
25. (3)
The number of geometrical isomers is 3.