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Page 1 PART-I (Single Correct MCQs) 1. The solubility of a solid in a liquid is significantly affected by temperature changes. Solute + Solvent Solution. The system being in a dynamic equilibrium must followLe-chatelier’s principle. Considering the Le-chatelier’s principle which of the following is correct? (a) ?? sol > 0; solubility ; temperature (b) ?? sol < 0; solubility ; temperature (c) ?? sol > 0; solubility ; temperature (d) ?? sol < 0; solubility ; temperature 2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and = 0.4) and B (p°= 120 mm Hg and = 0.6) is found to be 100 mm Hg. It shows that the solution exhibits (a) positive deviation from ideal behaviour Page 2 PART-I (Single Correct MCQs) 1. The solubility of a solid in a liquid is significantly affected by temperature changes. Solute + Solvent Solution. The system being in a dynamic equilibrium must followLe-chatelier’s principle. Considering the Le-chatelier’s principle which of the following is correct? (a) ?? sol > 0; solubility ; temperature (b) ?? sol < 0; solubility ; temperature (c) ?? sol > 0; solubility ; temperature (d) ?? sol < 0; solubility ; temperature 2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and = 0.4) and B (p°= 120 mm Hg and = 0.6) is found to be 100 mm Hg. It shows that the solution exhibits (a) positive deviation from ideal behaviour (b) negative deviation from ideal behaviour (c) ideal behaviour (d) positive deviation for lower conc. and negative for higher conc. 3. Henry’s law constant of oxygen is 1.4 × 10 –3 mol. lit –1 . atm –1 at 298 K. How much of oxygen is dissolved in 100 mL at 298 K when the partial pressure of oxygen is 0.5 atm? (a) 1.4 g (b) 3.2 g (c) 22.4 mg (d) 2.24 mg 4. A solution containing components A and B follows Raoult’s law when (a) A – B attraction force is greater than A – A and B – B (b) A – B attraction force is less than A – A and B – B (c) A – B attraction force remains same as A–A and B –B (d) Volume of solution is different from sum of volume of solute and solvent 5. Two 1-litre flask A and B are connected to each other by a valve which is closed. Flask A has benzene in equilibrium with its vapours at 30°C. The flask B, is evacuated, and the valve is opened. Which of the following is true. If temperature is kept constant.’ (a) Some of the benzene molecules would move to flask B from flask A. (b) Vapour pressure will be half the initial value. (c) The vapour pressure remains unchanged (d) Some more of the liquid benzene in flask A would evaporate. 6. For a solution of two liquids A and B it was proved that . The resulting solution will be (a) Non -ideal (b) ideal Page 3 PART-I (Single Correct MCQs) 1. The solubility of a solid in a liquid is significantly affected by temperature changes. Solute + Solvent Solution. The system being in a dynamic equilibrium must followLe-chatelier’s principle. Considering the Le-chatelier’s principle which of the following is correct? (a) ?? sol > 0; solubility ; temperature (b) ?? sol < 0; solubility ; temperature (c) ?? sol > 0; solubility ; temperature (d) ?? sol < 0; solubility ; temperature 2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and = 0.4) and B (p°= 120 mm Hg and = 0.6) is found to be 100 mm Hg. It shows that the solution exhibits (a) positive deviation from ideal behaviour (b) negative deviation from ideal behaviour (c) ideal behaviour (d) positive deviation for lower conc. and negative for higher conc. 3. Henry’s law constant of oxygen is 1.4 × 10 –3 mol. lit –1 . atm –1 at 298 K. How much of oxygen is dissolved in 100 mL at 298 K when the partial pressure of oxygen is 0.5 atm? (a) 1.4 g (b) 3.2 g (c) 22.4 mg (d) 2.24 mg 4. A solution containing components A and B follows Raoult’s law when (a) A – B attraction force is greater than A – A and B – B (b) A – B attraction force is less than A – A and B – B (c) A – B attraction force remains same as A–A and B –B (d) Volume of solution is different from sum of volume of solute and solvent 5. Two 1-litre flask A and B are connected to each other by a valve which is closed. Flask A has benzene in equilibrium with its vapours at 30°C. The flask B, is evacuated, and the valve is opened. Which of the following is true. If temperature is kept constant.’ (a) Some of the benzene molecules would move to flask B from flask A. (b) Vapour pressure will be half the initial value. (c) The vapour pressure remains unchanged (d) Some more of the liquid benzene in flask A would evaporate. 6. For a solution of two liquids A and B it was proved that . The resulting solution will be (a) Non -ideal (b) ideal (c) semi-ideal (d) None of these 7. All form ideal solution except (a) C 6 H 6 and C 6 H 5 CH 3 (b) C 2 H 6 and C 2 H 5 I (c) C 6 H 5 Cl and C 6 H 5 Br (d) C 2 H 5 I and C 2 H 5 OH. 8. A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution? (a) The solution is non-ideal, showing – ve deviation from Raoult’s Law. (b) The solution is non-ideal, showing + ve deviation from Raoult’s Law. (c) n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law. (d) The solution formed is an ideal solution. 9. During depression of freezing point in a solution the following are in equilibrium (a) liquid solvent, solid solvent (b) liquid solvent, solid solute (c) liquid solute, solid solute (d) liquid solute, solid solvent 10. Which of the following modes of expressing concentration is independent of temperature ? Page 4 PART-I (Single Correct MCQs) 1. The solubility of a solid in a liquid is significantly affected by temperature changes. Solute + Solvent Solution. The system being in a dynamic equilibrium must followLe-chatelier’s principle. Considering the Le-chatelier’s principle which of the following is correct? (a) ?? sol > 0; solubility ; temperature (b) ?? sol < 0; solubility ; temperature (c) ?? sol > 0; solubility ; temperature (d) ?? sol < 0; solubility ; temperature 2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and = 0.4) and B (p°= 120 mm Hg and = 0.6) is found to be 100 mm Hg. It shows that the solution exhibits (a) positive deviation from ideal behaviour (b) negative deviation from ideal behaviour (c) ideal behaviour (d) positive deviation for lower conc. and negative for higher conc. 3. Henry’s law constant of oxygen is 1.4 × 10 –3 mol. lit –1 . atm –1 at 298 K. How much of oxygen is dissolved in 100 mL at 298 K when the partial pressure of oxygen is 0.5 atm? (a) 1.4 g (b) 3.2 g (c) 22.4 mg (d) 2.24 mg 4. A solution containing components A and B follows Raoult’s law when (a) A – B attraction force is greater than A – A and B – B (b) A – B attraction force is less than A – A and B – B (c) A – B attraction force remains same as A–A and B –B (d) Volume of solution is different from sum of volume of solute and solvent 5. Two 1-litre flask A and B are connected to each other by a valve which is closed. Flask A has benzene in equilibrium with its vapours at 30°C. The flask B, is evacuated, and the valve is opened. Which of the following is true. If temperature is kept constant.’ (a) Some of the benzene molecules would move to flask B from flask A. (b) Vapour pressure will be half the initial value. (c) The vapour pressure remains unchanged (d) Some more of the liquid benzene in flask A would evaporate. 6. For a solution of two liquids A and B it was proved that . The resulting solution will be (a) Non -ideal (b) ideal (c) semi-ideal (d) None of these 7. All form ideal solution except (a) C 6 H 6 and C 6 H 5 CH 3 (b) C 2 H 6 and C 2 H 5 I (c) C 6 H 5 Cl and C 6 H 5 Br (d) C 2 H 5 I and C 2 H 5 OH. 8. A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution? (a) The solution is non-ideal, showing – ve deviation from Raoult’s Law. (b) The solution is non-ideal, showing + ve deviation from Raoult’s Law. (c) n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law. (d) The solution formed is an ideal solution. 9. During depression of freezing point in a solution the following are in equilibrium (a) liquid solvent, solid solvent (b) liquid solvent, solid solute (c) liquid solute, solid solute (d) liquid solute, solid solvent 10. Which of the following modes of expressing concentration is independent of temperature ? (a) Molarity (b) Molality (c) Formality (d) Normality 11. How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0M HNO 3 ? The concentrated acid is 70% HNO 3 (a) 90.0 g conc. HNO 3 (b) 70.0 g conc. HNO 3 (c) 54.0 g conc. HNO 3 (d) 45.0 g conc. HNO 3 12. Which among the following will show maximum osmotic pressure? (a) 1 M NaCl (b) 1 M MgCl 2 (c) 1 M (NH 4 ) 3 PO 4 (d) 1 M Na 2 SO 4 13. The boiling point of 0.2 mol kg –1 solution of X in water is greater than equimolal solution of Y in water. Which one of the following statements is true in this case ? (a) Molecular mass of X is greater than the molecular mass of Y. (b) Molecular mass of X is less than the molecular mass of Y. (c) Y is undergoing dissociation in water while X undergoes no change. (d) X is undergoing dissociation in water. 14. Which of the following 0.10 m aqueous solutions will have the lowest freezing point ? (a) Al 2 (SO 4 ) 3 (b) C 6 H 12 O 6 Page 5 PART-I (Single Correct MCQs) 1. The solubility of a solid in a liquid is significantly affected by temperature changes. Solute + Solvent Solution. The system being in a dynamic equilibrium must followLe-chatelier’s principle. Considering the Le-chatelier’s principle which of the following is correct? (a) ?? sol > 0; solubility ; temperature (b) ?? sol < 0; solubility ; temperature (c) ?? sol > 0; solubility ; temperature (d) ?? sol < 0; solubility ; temperature 2. The vapour pressure of a solution of the liquids A (p° = 80 mm Hg and = 0.4) and B (p°= 120 mm Hg and = 0.6) is found to be 100 mm Hg. It shows that the solution exhibits (a) positive deviation from ideal behaviour (b) negative deviation from ideal behaviour (c) ideal behaviour (d) positive deviation for lower conc. and negative for higher conc. 3. Henry’s law constant of oxygen is 1.4 × 10 –3 mol. lit –1 . atm –1 at 298 K. How much of oxygen is dissolved in 100 mL at 298 K when the partial pressure of oxygen is 0.5 atm? (a) 1.4 g (b) 3.2 g (c) 22.4 mg (d) 2.24 mg 4. A solution containing components A and B follows Raoult’s law when (a) A – B attraction force is greater than A – A and B – B (b) A – B attraction force is less than A – A and B – B (c) A – B attraction force remains same as A–A and B –B (d) Volume of solution is different from sum of volume of solute and solvent 5. Two 1-litre flask A and B are connected to each other by a valve which is closed. Flask A has benzene in equilibrium with its vapours at 30°C. The flask B, is evacuated, and the valve is opened. Which of the following is true. If temperature is kept constant.’ (a) Some of the benzene molecules would move to flask B from flask A. (b) Vapour pressure will be half the initial value. (c) The vapour pressure remains unchanged (d) Some more of the liquid benzene in flask A would evaporate. 6. For a solution of two liquids A and B it was proved that . The resulting solution will be (a) Non -ideal (b) ideal (c) semi-ideal (d) None of these 7. All form ideal solution except (a) C 6 H 6 and C 6 H 5 CH 3 (b) C 2 H 6 and C 2 H 5 I (c) C 6 H 5 Cl and C 6 H 5 Br (d) C 2 H 5 I and C 2 H 5 OH. 8. A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution? (a) The solution is non-ideal, showing – ve deviation from Raoult’s Law. (b) The solution is non-ideal, showing + ve deviation from Raoult’s Law. (c) n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law. (d) The solution formed is an ideal solution. 9. During depression of freezing point in a solution the following are in equilibrium (a) liquid solvent, solid solvent (b) liquid solvent, solid solute (c) liquid solute, solid solute (d) liquid solute, solid solvent 10. Which of the following modes of expressing concentration is independent of temperature ? (a) Molarity (b) Molality (c) Formality (d) Normality 11. How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0M HNO 3 ? The concentrated acid is 70% HNO 3 (a) 90.0 g conc. HNO 3 (b) 70.0 g conc. HNO 3 (c) 54.0 g conc. HNO 3 (d) 45.0 g conc. HNO 3 12. Which among the following will show maximum osmotic pressure? (a) 1 M NaCl (b) 1 M MgCl 2 (c) 1 M (NH 4 ) 3 PO 4 (d) 1 M Na 2 SO 4 13. The boiling point of 0.2 mol kg –1 solution of X in water is greater than equimolal solution of Y in water. Which one of the following statements is true in this case ? (a) Molecular mass of X is greater than the molecular mass of Y. (b) Molecular mass of X is less than the molecular mass of Y. (c) Y is undergoing dissociation in water while X undergoes no change. (d) X is undergoing dissociation in water. 14. Which of the following 0.10 m aqueous solutions will have the lowest freezing point ? (a) Al 2 (SO 4 ) 3 (b) C 6 H 12 O 6 (c) KCl (d) C 12 H 22 O 11 15. If sodium sulphate is considered to be completely dissociated into cations and anions in aqueous solution, the change in freezing point of water (?T f ), when 0.01 mol of sodium sulphate is dissolved in 1 kg of water, is (K f = 1.86 K kg mol –1 ) (a) 0.372 K (b) 0.0558 K (c) 0.0744 K (d) 0.0186 K 16. Which one of the following salts will have the same value of van’t Hoff factor (i) as that of K 4 [Fe(CN) 6 ]. (a) Al 2 (SO 4 ) 3 (b) NaCl (c) Al(NO 3 ) 3 (d) Na 2 SO 4 . 17. Mole fraction of the solute in a 1.00 molal aqueous solution is : (a) 0.1770 (b) 0.0177 (c) 0.0344 (d) 1.7700 18. 25.3 g of sodium carbonate, is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, and carbonate ions,Read More
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