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Page 1
(For Class X Students)
MAT (Paper-1)
Time: 50 Min. Max. Marks: 50
1. The product of two fractions is
14
15
and their quotient is
35
24
. The greater fraction is:
(1)
4
5
(2)
7
6
(3)
7
4
(4)
7
3
1. 2
Sol. Let fractions =
a c
,
b d
?
ac 14 ad 35
,
bd 15 bc 24
? ?
Now,
7 7
3 12
ac ad 14 35 49
bd bc 15 24 36
? ? ? ?
? ? ? ?
? ?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
?
a 7
b 6
? ?
c 4
d 5
?
?Greater fraction =
7
6
2. The cost of an article are Rs. 75. The cost was first increased by 20% and later on it was
reduced by 20%. The present cost of the article is:
(1) Rs. 60 (2) Rs. 72
(3) Rs. 90 (4) Rs. 75
2. 2
Sol. Initial cost = 75
After 20% increment = 90
After 20% decrement = 72
3. Which one is in the ascending order in the following:
(1)
7 5 4 9
, , ,
6 4 3 7
(2)
7 5 9 4
, , ,
6 4 7 3
(3)
4 9 5 7
, , ,
3 7 4 6
(4)
9 4 7 5
, , ,
7 3 6 4
3. 2
Sol. Given fractions =
7 5 4 9
, , ,
6 4 3 7
(0 0)
=
7 84 5 84 4 84 9 84
, , ,
6 84 4 84 3 84 7 84
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? 7 14 5 21 4 28 9, 12
, , ,
84 84 84 84
?
98 105 112 108
, , ,
84 84 84 84
?
?
7 5 9 4
6 4 7 3
? ? ?
Page 2
(For Class X Students)
MAT (Paper-1)
Time: 50 Min. Max. Marks: 50
1. The product of two fractions is
14
15
and their quotient is
35
24
. The greater fraction is:
(1)
4
5
(2)
7
6
(3)
7
4
(4)
7
3
1. 2
Sol. Let fractions =
a c
,
b d
?
ac 14 ad 35
,
bd 15 bc 24
? ?
Now,
7 7
3 12
ac ad 14 35 49
bd bc 15 24 36
? ? ? ?
? ? ? ?
? ?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
?
a 7
b 6
? ?
c 4
d 5
?
?Greater fraction =
7
6
2. The cost of an article are Rs. 75. The cost was first increased by 20% and later on it was
reduced by 20%. The present cost of the article is:
(1) Rs. 60 (2) Rs. 72
(3) Rs. 90 (4) Rs. 75
2. 2
Sol. Initial cost = 75
After 20% increment = 90
After 20% decrement = 72
3. Which one is in the ascending order in the following:
(1)
7 5 4 9
, , ,
6 4 3 7
(2)
7 5 9 4
, , ,
6 4 7 3
(3)
4 9 5 7
, , ,
3 7 4 6
(4)
9 4 7 5
, , ,
7 3 6 4
3. 2
Sol. Given fractions =
7 5 4 9
, , ,
6 4 3 7
(0 0)
=
7 84 5 84 4 84 9 84
, , ,
6 84 4 84 3 84 7 84
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? 7 14 5 21 4 28 9, 12
, , ,
84 84 84 84
?
98 105 112 108
, , ,
84 84 84 84
?
?
7 5 9 4
6 4 7 3
? ? ?
4. If 10 men or 20 boys can make 260 mats in 20 days, then how, many mats will be made by 8
men and 4 boys in 20 days?
(1) 260 (2) 240
(3) 520 (4) 280
4. 1
Sol. Given 10 men makes 260 mats in 20 days
? 8 men will make 208 mats in 20 days
Similarly boys will make 52 mats in 20 days
? 8 men and 4 boys will make 260 mats in 20 days
5. A man completes 30 km of a journey at the speed of 6 km/hr and remaining 40 km of the
journey in 5 hrs. His average speed for the whole journey is :
(1) 14 km/hr (2) 7 km/hr
(3) 7.5 km/hr (4) 8 km/hr
5. 2
Sol. Average speed =
Totaldis tance
Totaltime taken
=
30 40 70
7km / hr
30
10
5
6
?
? ?
?
6. Four bells ring at interval 6, 12, 18, 24 seconds. They starts ringing simultaneously at 8 o’c
clock. When will they ring again together:
(1) 1 minutes 12 seconds past 8 (2) 2 minutes 24 seconds past 8
(3) 5 minutes 17 seconds past 8 (4) 2 minutes 27 seconds past 8
6. 1
Sol. They will ring together again after L.C.M of (6, 12, 18, 24) seconds that means after 72
seconds (or) one minute 12 seconds.
7. A cricketer has a certain average of runs for his 64 innings. In his 65
th
inning, he is bowled
out for no score on his part. This brings down his average by 3 runs. His new average of
runs is:
(1) 195 (2) 130
(3) 192 (4) 128
7. 3
Sol. Assume, the average upto 64 innings = x
So the score for 64 innings = 64x
Now the average after 65 innings = x – 3
? Total score in 65 innings = 65 (x – 3)
From given data we have :
? ? 64x 65 x 3 ? ?
64x = 65x – 65 (3)
x = 195
8. If x 136 52 144 ? ? ? then value of x equals:
(1) 12 (2) 11
(3) 10 (4) 13
8. 1
Sol. x 136 52 144 ? ? ?
= 136 64 144 12 ? ? ?
Page 3
(For Class X Students)
MAT (Paper-1)
Time: 50 Min. Max. Marks: 50
1. The product of two fractions is
14
15
and their quotient is
35
24
. The greater fraction is:
(1)
4
5
(2)
7
6
(3)
7
4
(4)
7
3
1. 2
Sol. Let fractions =
a c
,
b d
?
ac 14 ad 35
,
bd 15 bc 24
? ?
Now,
7 7
3 12
ac ad 14 35 49
bd bc 15 24 36
? ? ? ?
? ? ? ?
? ?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
?
a 7
b 6
? ?
c 4
d 5
?
?Greater fraction =
7
6
2. The cost of an article are Rs. 75. The cost was first increased by 20% and later on it was
reduced by 20%. The present cost of the article is:
(1) Rs. 60 (2) Rs. 72
(3) Rs. 90 (4) Rs. 75
2. 2
Sol. Initial cost = 75
After 20% increment = 90
After 20% decrement = 72
3. Which one is in the ascending order in the following:
(1)
7 5 4 9
, , ,
6 4 3 7
(2)
7 5 9 4
, , ,
6 4 7 3
(3)
4 9 5 7
, , ,
3 7 4 6
(4)
9 4 7 5
, , ,
7 3 6 4
3. 2
Sol. Given fractions =
7 5 4 9
, , ,
6 4 3 7
(0 0)
=
7 84 5 84 4 84 9 84
, , ,
6 84 4 84 3 84 7 84
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? 7 14 5 21 4 28 9, 12
, , ,
84 84 84 84
?
98 105 112 108
, , ,
84 84 84 84
?
?
7 5 9 4
6 4 7 3
? ? ?
4. If 10 men or 20 boys can make 260 mats in 20 days, then how, many mats will be made by 8
men and 4 boys in 20 days?
(1) 260 (2) 240
(3) 520 (4) 280
4. 1
Sol. Given 10 men makes 260 mats in 20 days
? 8 men will make 208 mats in 20 days
Similarly boys will make 52 mats in 20 days
? 8 men and 4 boys will make 260 mats in 20 days
5. A man completes 30 km of a journey at the speed of 6 km/hr and remaining 40 km of the
journey in 5 hrs. His average speed for the whole journey is :
(1) 14 km/hr (2) 7 km/hr
(3) 7.5 km/hr (4) 8 km/hr
5. 2
Sol. Average speed =
Totaldis tance
Totaltime taken
=
30 40 70
7km / hr
30
10
5
6
?
? ?
?
6. Four bells ring at interval 6, 12, 18, 24 seconds. They starts ringing simultaneously at 8 o’c
clock. When will they ring again together:
(1) 1 minutes 12 seconds past 8 (2) 2 minutes 24 seconds past 8
(3) 5 minutes 17 seconds past 8 (4) 2 minutes 27 seconds past 8
6. 1
Sol. They will ring together again after L.C.M of (6, 12, 18, 24) seconds that means after 72
seconds (or) one minute 12 seconds.
7. A cricketer has a certain average of runs for his 64 innings. In his 65
th
inning, he is bowled
out for no score on his part. This brings down his average by 3 runs. His new average of
runs is:
(1) 195 (2) 130
(3) 192 (4) 128
7. 3
Sol. Assume, the average upto 64 innings = x
So the score for 64 innings = 64x
Now the average after 65 innings = x – 3
? Total score in 65 innings = 65 (x – 3)
From given data we have :
? ? 64x 65 x 3 ? ?
64x = 65x – 65 (3)
x = 195
8. If x 136 52 144 ? ? ? then value of x equals:
(1) 12 (2) 11
(3) 10 (4) 13
8. 1
Sol. x 136 52 144 ? ? ?
= 136 64 144 12 ? ? ?
9. A fruit seller buys bananas at 2 for a rupee and sells them at 5 for three rupees. His profit
per cent is:
(1) 25 (2) 10
(3) 15 (4) 20
9. 4
Sol. C.P of 10 bananas = Rs. 5
S.P of 10 bananas = Rs. 6
? Profit % =
6 5
x100 20%
5
?
?
For Questions 10 to 12. refer to following pie chart.
The following pie diagram shows the expenditure incurred on the preparation of a book by publisher
under various head:
A. Paper 20%
B. Printing 25%
C. binding Designing 30%
D. Royalty 15% or
E. Miscellaneous 10%
10. What is the angle of Pie diagram showing the expenditure incurred on paying royalty?
(1) 54
o
(2) 45
o
(3) 48
o
(4) 60
o
10. 1
Sol. Given expenditure on royalty = 15%
? The angle incurred = ? ?
3
18 0
2
15
360 54
100
?
11. Which two expenditure together will form an angle of 108
o
at the centre of pie – diagram?
(1) B and E (2) A and E
(3) A and D (4) D and E
11. 2
Sol. Angle formed by A = 72
o
Angle formed by B = 90
o
Angle formed by C = 108
o
Angle formed by D = 54
o
Angle formed by E = 36
o
Here clearly A and E together will form 108
o
12. If the difference between the expenditure be represented by 18
o
in the pie diagram. These
expenditures are:
(1) B and E (2) A and C
(3) B and D (4) B and C
12. 4
Sol. Clearly from the options B and C will have the difference of 18
o
Page 4
(For Class X Students)
MAT (Paper-1)
Time: 50 Min. Max. Marks: 50
1. The product of two fractions is
14
15
and their quotient is
35
24
. The greater fraction is:
(1)
4
5
(2)
7
6
(3)
7
4
(4)
7
3
1. 2
Sol. Let fractions =
a c
,
b d
?
ac 14 ad 35
,
bd 15 bc 24
? ?
Now,
7 7
3 12
ac ad 14 35 49
bd bc 15 24 36
? ? ? ?
? ? ? ?
? ?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
?
a 7
b 6
? ?
c 4
d 5
?
?Greater fraction =
7
6
2. The cost of an article are Rs. 75. The cost was first increased by 20% and later on it was
reduced by 20%. The present cost of the article is:
(1) Rs. 60 (2) Rs. 72
(3) Rs. 90 (4) Rs. 75
2. 2
Sol. Initial cost = 75
After 20% increment = 90
After 20% decrement = 72
3. Which one is in the ascending order in the following:
(1)
7 5 4 9
, , ,
6 4 3 7
(2)
7 5 9 4
, , ,
6 4 7 3
(3)
4 9 5 7
, , ,
3 7 4 6
(4)
9 4 7 5
, , ,
7 3 6 4
3. 2
Sol. Given fractions =
7 5 4 9
, , ,
6 4 3 7
(0 0)
=
7 84 5 84 4 84 9 84
, , ,
6 84 4 84 3 84 7 84
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? 7 14 5 21 4 28 9, 12
, , ,
84 84 84 84
?
98 105 112 108
, , ,
84 84 84 84
?
?
7 5 9 4
6 4 7 3
? ? ?
4. If 10 men or 20 boys can make 260 mats in 20 days, then how, many mats will be made by 8
men and 4 boys in 20 days?
(1) 260 (2) 240
(3) 520 (4) 280
4. 1
Sol. Given 10 men makes 260 mats in 20 days
? 8 men will make 208 mats in 20 days
Similarly boys will make 52 mats in 20 days
? 8 men and 4 boys will make 260 mats in 20 days
5. A man completes 30 km of a journey at the speed of 6 km/hr and remaining 40 km of the
journey in 5 hrs. His average speed for the whole journey is :
(1) 14 km/hr (2) 7 km/hr
(3) 7.5 km/hr (4) 8 km/hr
5. 2
Sol. Average speed =
Totaldis tance
Totaltime taken
=
30 40 70
7km / hr
30
10
5
6
?
? ?
?
6. Four bells ring at interval 6, 12, 18, 24 seconds. They starts ringing simultaneously at 8 o’c
clock. When will they ring again together:
(1) 1 minutes 12 seconds past 8 (2) 2 minutes 24 seconds past 8
(3) 5 minutes 17 seconds past 8 (4) 2 minutes 27 seconds past 8
6. 1
Sol. They will ring together again after L.C.M of (6, 12, 18, 24) seconds that means after 72
seconds (or) one minute 12 seconds.
7. A cricketer has a certain average of runs for his 64 innings. In his 65
th
inning, he is bowled
out for no score on his part. This brings down his average by 3 runs. His new average of
runs is:
(1) 195 (2) 130
(3) 192 (4) 128
7. 3
Sol. Assume, the average upto 64 innings = x
So the score for 64 innings = 64x
Now the average after 65 innings = x – 3
? Total score in 65 innings = 65 (x – 3)
From given data we have :
? ? 64x 65 x 3 ? ?
64x = 65x – 65 (3)
x = 195
8. If x 136 52 144 ? ? ? then value of x equals:
(1) 12 (2) 11
(3) 10 (4) 13
8. 1
Sol. x 136 52 144 ? ? ?
= 136 64 144 12 ? ? ?
9. A fruit seller buys bananas at 2 for a rupee and sells them at 5 for three rupees. His profit
per cent is:
(1) 25 (2) 10
(3) 15 (4) 20
9. 4
Sol. C.P of 10 bananas = Rs. 5
S.P of 10 bananas = Rs. 6
? Profit % =
6 5
x100 20%
5
?
?
For Questions 10 to 12. refer to following pie chart.
The following pie diagram shows the expenditure incurred on the preparation of a book by publisher
under various head:
A. Paper 20%
B. Printing 25%
C. binding Designing 30%
D. Royalty 15% or
E. Miscellaneous 10%
10. What is the angle of Pie diagram showing the expenditure incurred on paying royalty?
(1) 54
o
(2) 45
o
(3) 48
o
(4) 60
o
10. 1
Sol. Given expenditure on royalty = 15%
? The angle incurred = ? ?
3
18 0
2
15
360 54
100
?
11. Which two expenditure together will form an angle of 108
o
at the centre of pie – diagram?
(1) B and E (2) A and E
(3) A and D (4) D and E
11. 2
Sol. Angle formed by A = 72
o
Angle formed by B = 90
o
Angle formed by C = 108
o
Angle formed by D = 54
o
Angle formed by E = 36
o
Here clearly A and E together will form 108
o
12. If the difference between the expenditure be represented by 18
o
in the pie diagram. These
expenditures are:
(1) B and E (2) A and C
(3) B and D (4) B and C
12. 4
Sol. Clearly from the options B and C will have the difference of 18
o
13. A number whose double is 48 greater than its half: is-
(1) 30 (2) 32
(3) 31 (4) 29
13. 2
Sol. Let number = x
Given
x
2x 48
2
? ?
4x = 96 + x
3x + 96 ? x = 32
14. Value of
1
1
1
1
1
1
6
?
?
?
is
(1)
16
11
(2) 1
(3)
11
16
(4) 10
14. 1
Sol.
1
1
1
1
1
1
6
?
?
?
=
1 1
1 1
1 6
1 1
5
5
6
? ? ?
? ?
=
1
1
11
5
?
=
5 16
1
11 11
? ?
15. How many numbers between 11 and 90 are divisible by 7?
(1) 10 (2) 11
(3) 12 (4) 7
15. 2
Sol. Divisible by ‘7’ means the number = 7k (for k = 1, 2, 3 …)
Now between 11 and 90 means
K = 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
Total values = 11
16. Given that 2x – y + z = 240. If z = 2y, y = 2x, then x = ?
(1) 0 (2) 50
(3) 70 (4) 60
16. 4
Sol. z = 27
y = 2x
? z = 2 (2x) = 4x
2x – y + z = 240
2x – 2x + 4x = 240
4x = 240
X = 60.
Page 5
(For Class X Students)
MAT (Paper-1)
Time: 50 Min. Max. Marks: 50
1. The product of two fractions is
14
15
and their quotient is
35
24
. The greater fraction is:
(1)
4
5
(2)
7
6
(3)
7
4
(4)
7
3
1. 2
Sol. Let fractions =
a c
,
b d
?
ac 14 ad 35
,
bd 15 bc 24
? ?
Now,
7 7
3 12
ac ad 14 35 49
bd bc 15 24 36
? ? ? ?
? ? ? ?
? ?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
?
a 7
b 6
? ?
c 4
d 5
?
?Greater fraction =
7
6
2. The cost of an article are Rs. 75. The cost was first increased by 20% and later on it was
reduced by 20%. The present cost of the article is:
(1) Rs. 60 (2) Rs. 72
(3) Rs. 90 (4) Rs. 75
2. 2
Sol. Initial cost = 75
After 20% increment = 90
After 20% decrement = 72
3. Which one is in the ascending order in the following:
(1)
7 5 4 9
, , ,
6 4 3 7
(2)
7 5 9 4
, , ,
6 4 7 3
(3)
4 9 5 7
, , ,
3 7 4 6
(4)
9 4 7 5
, , ,
7 3 6 4
3. 2
Sol. Given fractions =
7 5 4 9
, , ,
6 4 3 7
(0 0)
=
7 84 5 84 4 84 9 84
, , ,
6 84 4 84 3 84 7 84
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? ? ?
? ? ? ? ? ? ? ? 7 14 5 21 4 28 9, 12
, , ,
84 84 84 84
?
98 105 112 108
, , ,
84 84 84 84
?
?
7 5 9 4
6 4 7 3
? ? ?
4. If 10 men or 20 boys can make 260 mats in 20 days, then how, many mats will be made by 8
men and 4 boys in 20 days?
(1) 260 (2) 240
(3) 520 (4) 280
4. 1
Sol. Given 10 men makes 260 mats in 20 days
? 8 men will make 208 mats in 20 days
Similarly boys will make 52 mats in 20 days
? 8 men and 4 boys will make 260 mats in 20 days
5. A man completes 30 km of a journey at the speed of 6 km/hr and remaining 40 km of the
journey in 5 hrs. His average speed for the whole journey is :
(1) 14 km/hr (2) 7 km/hr
(3) 7.5 km/hr (4) 8 km/hr
5. 2
Sol. Average speed =
Totaldis tance
Totaltime taken
=
30 40 70
7km / hr
30
10
5
6
?
? ?
?
6. Four bells ring at interval 6, 12, 18, 24 seconds. They starts ringing simultaneously at 8 o’c
clock. When will they ring again together:
(1) 1 minutes 12 seconds past 8 (2) 2 minutes 24 seconds past 8
(3) 5 minutes 17 seconds past 8 (4) 2 minutes 27 seconds past 8
6. 1
Sol. They will ring together again after L.C.M of (6, 12, 18, 24) seconds that means after 72
seconds (or) one minute 12 seconds.
7. A cricketer has a certain average of runs for his 64 innings. In his 65
th
inning, he is bowled
out for no score on his part. This brings down his average by 3 runs. His new average of
runs is:
(1) 195 (2) 130
(3) 192 (4) 128
7. 3
Sol. Assume, the average upto 64 innings = x
So the score for 64 innings = 64x
Now the average after 65 innings = x – 3
? Total score in 65 innings = 65 (x – 3)
From given data we have :
? ? 64x 65 x 3 ? ?
64x = 65x – 65 (3)
x = 195
8. If x 136 52 144 ? ? ? then value of x equals:
(1) 12 (2) 11
(3) 10 (4) 13
8. 1
Sol. x 136 52 144 ? ? ?
= 136 64 144 12 ? ? ?
9. A fruit seller buys bananas at 2 for a rupee and sells them at 5 for three rupees. His profit
per cent is:
(1) 25 (2) 10
(3) 15 (4) 20
9. 4
Sol. C.P of 10 bananas = Rs. 5
S.P of 10 bananas = Rs. 6
? Profit % =
6 5
x100 20%
5
?
?
For Questions 10 to 12. refer to following pie chart.
The following pie diagram shows the expenditure incurred on the preparation of a book by publisher
under various head:
A. Paper 20%
B. Printing 25%
C. binding Designing 30%
D. Royalty 15% or
E. Miscellaneous 10%
10. What is the angle of Pie diagram showing the expenditure incurred on paying royalty?
(1) 54
o
(2) 45
o
(3) 48
o
(4) 60
o
10. 1
Sol. Given expenditure on royalty = 15%
? The angle incurred = ? ?
3
18 0
2
15
360 54
100
?
11. Which two expenditure together will form an angle of 108
o
at the centre of pie – diagram?
(1) B and E (2) A and E
(3) A and D (4) D and E
11. 2
Sol. Angle formed by A = 72
o
Angle formed by B = 90
o
Angle formed by C = 108
o
Angle formed by D = 54
o
Angle formed by E = 36
o
Here clearly A and E together will form 108
o
12. If the difference between the expenditure be represented by 18
o
in the pie diagram. These
expenditures are:
(1) B and E (2) A and C
(3) B and D (4) B and C
12. 4
Sol. Clearly from the options B and C will have the difference of 18
o
13. A number whose double is 48 greater than its half: is-
(1) 30 (2) 32
(3) 31 (4) 29
13. 2
Sol. Let number = x
Given
x
2x 48
2
? ?
4x = 96 + x
3x + 96 ? x = 32
14. Value of
1
1
1
1
1
1
6
?
?
?
is
(1)
16
11
(2) 1
(3)
11
16
(4) 10
14. 1
Sol.
1
1
1
1
1
1
6
?
?
?
=
1 1
1 1
1 6
1 1
5
5
6
? ? ?
? ?
=
1
1
11
5
?
=
5 16
1
11 11
? ?
15. How many numbers between 11 and 90 are divisible by 7?
(1) 10 (2) 11
(3) 12 (4) 7
15. 2
Sol. Divisible by ‘7’ means the number = 7k (for k = 1, 2, 3 …)
Now between 11 and 90 means
K = 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
Total values = 11
16. Given that 2x – y + z = 240. If z = 2y, y = 2x, then x = ?
(1) 0 (2) 50
(3) 70 (4) 60
16. 4
Sol. z = 27
y = 2x
? z = 2 (2x) = 4x
2x – y + z = 240
2x – 2x + 4x = 240
4x = 240
X = 60.
17. Ratio of milk is to water in certain solution of 75 litres is 2 :1. How much water is to be mixed
in solution so that ratio becomes 1:2 :
(1) 75 litres (2) 60 litres
(3) 65 litres (4) 80 litres
17. 1
Sol. Amount of water in first solution =
1
x75 25
3
? ?
Amount milk in first solution =
2
x75 50
3
? ?
Let the amount of water to be mixed be x ?
? ?
2
25 x 75 x
3
? ? ?
1
x 50 25
3
? ?
X = 75 ?
18. Simple interest on a sum of money is
1
25
of the principal and the number of years is equal to
the rate percent per annum is:
(1) 2 ½ % (2) 2%
(3) 3 ½ % (4) 1 ½ %
18. 2
Sol.
PTR
SI
100
?
PTR P
100 25
?
P.R.R P
100 25
?
R
2
= 4
R = 2% p.a.
19. The average of the first 100 natural number is
(1) 51 (2) 100
(3) 50.5 (4) 101
19. 3
Sol. Average of first 100 natural numbers =
100x101
50.5
2x100
?
20. The unit’s digit in the expansion (2317)
759
is:
(1) 7 (2) 9
(3) 3 (4) 1
20. 3
Sol. 759 = 4 (189) + 3
? Units digit of (2317)
759
= Unit’s digit of (7)
759
= Unit’s digit of (7)
3
= 3
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