Mindmap: Permutations & Combinations

# Mindmap: Permutations & Combinations | Mathematics (Maths) for JEE Main & Advanced PDF Download

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## Mathematics (Maths) for JEE Main & Advanced

209 videos|443 docs|143 tests

## FAQs on Mindmap: Permutations & Combinations - Mathematics (Maths) for JEE Main & Advanced

 1. What is the difference between permutations and combinations in JEE?
Ans. Permutations and combinations are fundamental concepts in combinatorial mathematics. In JEE, permutations refer to the arrangement of objects in a particular order, while combinations refer to the selection of objects without considering their order. Permutations are denoted by nPr, where n is the total number of objects and r is the number of objects taken at a time. Combinations are denoted by nCr, where n is the total number of objects and r is the number of objects selected.
 2. How do I calculate the number of permutations in JEE?
Ans. To calculate the number of permutations in JEE, you can use the formula nPr = n! / (n-r)!, where n is the total number of objects and r is the number of objects taken at a time. Here, "!" denotes the factorial function which means multiplying a number by all the positive integers less than it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
 3. What is the formula for combinations in JEE?
Ans. The formula for combinations in JEE is given by nCr = n! / (r! * (n-r)!), where n is the total number of objects and r is the number of objects selected. This formula takes into account the fact that combinations do not consider the order of the selected objects.
 4. Can you give an example of a permutation problem in JEE?
Ans. Sure! Let's consider a problem where we need to arrange 3 different books (A, B, C) on a shelf. The number of ways to arrange these books is given by 3P3 = 3! = 3 x 2 x 1 = 6. Therefore, there are 6 different permutations possible for arranging these books on the shelf.
 5. How do I solve combination problems in JEE involving multiple selections?
Ans. When solving combination problems in JEE involving multiple selections, you can use the formula nC(r1, r2, ...) = n! / (r1! * r2! * ...), where n is the total number of objects and r1, r2, ... represent the number of objects selected from each group. For example, if you have to select 2 objects from a group of 4 red balls and 3 objects from a group of 5 blue balls, the number of combinations would be 4C2 * 5C3.

## Mathematics (Maths) for JEE Main & Advanced

209 videos|443 docs|143 tests

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