Open App

Electrical Engineering (EE) Exam > Electrical Engineering (EE) Notes > Short Notes for Electrical Engineering > Short Notes: Inverters

Short Notes: Inverters | Short Notes for Electrical Engineering - Electrical Engineering (EE) PDF Download

Download, print and study this document offline

Please wait while the PDF view is loading

 Page 1


 
 
 
 
 
Inverters circuits will convert DC power to AC power at required voltage & required frequency. 
Classification 
1) Voltage source Inverter 
? Input source is a voltage source. 
? Switching device is bidirectional & unipolar. 
? Load voltage depends on source voltage & load current depends on load parameters. 
 
2) Current source Inverters 
? Input source is a current source. 
? Switching device is bidirectional & bipolar 
? Load voltage depends on source current & load voltage on load parameters. 
Single phase half bridge VSI 
When 
1
S is ON, 
OO
V 0, I 0 ?? 
When 
2
S is ON, 
OO
V 0, I 0 ?? 
When 
1
D is ON, ??
OO
V 0, I 0 
When 
2
D is ON, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V
2
 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
2V
V sin n t
n
 
? rms value of fundamental components is given by 
   
??
? ? ?
??
??
??
dc
or1 dc
2V 12
VV
2
 
? rms value of output voltage ?
dc
or
V
V
2
 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
Page 2


 
 
 
 
 
Inverters circuits will convert DC power to AC power at required voltage & required frequency. 
Classification 
1) Voltage source Inverter 
? Input source is a voltage source. 
? Switching device is bidirectional & unipolar. 
? Load voltage depends on source voltage & load current depends on load parameters. 
 
2) Current source Inverters 
? Input source is a current source. 
? Switching device is bidirectional & bipolar 
? Load voltage depends on source current & load voltage on load parameters. 
Single phase half bridge VSI 
When 
1
S is ON, 
OO
V 0, I 0 ?? 
When 
2
S is ON, 
OO
V 0, I 0 ?? 
When 
1
D is ON, ??
OO
V 0, I 0 
When 
2
D is ON, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V
2
 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
2V
V sin n t
n
 
? rms value of fundamental components is given by 
   
??
? ? ?
??
??
??
dc
or1 dc
2V 12
VV
2
 
? rms value of output voltage ?
dc
or
V
V
2
 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
 
 
 
 
 
? If load power factor is lagging, then it requires forced commutation. 
? If load power factor is leading, then natural commutation occurs. 
 
 
Single phase Full Bridge VSI 
When
1
S ,
2
S conduct  
OO
V 0, I 0 ?? 
When
1
D ,
2
D conduct, ??
OO
V 0, I 0 
When
3
S ,
4
S conduct, ??
OO
V 0, I 0 
When
34
D ,D conduct, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
4V
V sin n t
n
 
? rms value of fundamental components is given by 
   ?
?
or1 dc
2
VV 
? rms value of output voltage ?
or dc
VV 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
Three phase full bridge VSI 
 
 
 
 
 
Page 3


 
 
 
 
 
Inverters circuits will convert DC power to AC power at required voltage & required frequency. 
Classification 
1) Voltage source Inverter 
? Input source is a voltage source. 
? Switching device is bidirectional & unipolar. 
? Load voltage depends on source voltage & load current depends on load parameters. 
 
2) Current source Inverters 
? Input source is a current source. 
? Switching device is bidirectional & bipolar 
? Load voltage depends on source current & load voltage on load parameters. 
Single phase half bridge VSI 
When 
1
S is ON, 
OO
V 0, I 0 ?? 
When 
2
S is ON, 
OO
V 0, I 0 ?? 
When 
1
D is ON, ??
OO
V 0, I 0 
When 
2
D is ON, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V
2
 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
2V
V sin n t
n
 
? rms value of fundamental components is given by 
   
??
? ? ?
??
??
??
dc
or1 dc
2V 12
VV
2
 
? rms value of output voltage ?
dc
or
V
V
2
 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
 
 
 
 
 
? If load power factor is lagging, then it requires forced commutation. 
? If load power factor is leading, then natural commutation occurs. 
 
 
Single phase Full Bridge VSI 
When
1
S ,
2
S conduct  
OO
V 0, I 0 ?? 
When
1
D ,
2
D conduct, ??
OO
V 0, I 0 
When
3
S ,
4
S conduct, ??
OO
V 0, I 0 
When
34
D ,D conduct, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
4V
V sin n t
n
 
? rms value of fundamental components is given by 
   ?
?
or1 dc
2
VV 
? rms value of output voltage ?
or dc
VV 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
Three phase full bridge VSI 
 
 
 
 
 
 
 
 
 
 
180
0
conduction mode 
In this mode, each switch will conduct for a period of 
0
180 and phase displacement between 
any two poles is 
0
120 
? Phase voltage 
? ?
?
ph dc
rms
2
VV
3
 
? ?
?
??
??
?
?
dc
RN
n 6k 1
2V
V sin n t
n
 
? ?
R1
V = rms value of fundamental component of 
RN
V 
?
?
dc
R1
2V
V 
Distortion factor, ??
?
R1
ph,rms
V 3
DF
V
 
? ? ? ?
2
1
THD 1 100 31%
DF
 
 
? Line voltage 
? ?
?
?
L L dc
rms
2
VV
3
 
? ? ? ? ? ?
?
??
??
? ? ?
?
?
dc
RY
n 6k 1
4V
n
V sin sin n t
36
n
 
? ?
RY
1
V = rms value of fundamental component of 
RY
V =
? ?
?
?
RY
1
6
V 
Distortion factor = 
3
?
 
In each phase, each switch conducts for 
0
180 out of 
0
360 
 ??
o, rms
r.rms
I
I
2
dc dc
2V V
3R 3R 2
??
?
, Where R = load resistance 
Page 4


 
 
 
 
 
Inverters circuits will convert DC power to AC power at required voltage & required frequency. 
Classification 
1) Voltage source Inverter 
? Input source is a voltage source. 
? Switching device is bidirectional & unipolar. 
? Load voltage depends on source voltage & load current depends on load parameters. 
 
2) Current source Inverters 
? Input source is a current source. 
? Switching device is bidirectional & bipolar 
? Load voltage depends on source current & load voltage on load parameters. 
Single phase half bridge VSI 
When 
1
S is ON, 
OO
V 0, I 0 ?? 
When 
2
S is ON, 
OO
V 0, I 0 ?? 
When 
1
D is ON, ??
OO
V 0, I 0 
When 
2
D is ON, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V
2
 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
2V
V sin n t
n
 
? rms value of fundamental components is given by 
   
??
? ? ?
??
??
??
dc
or1 dc
2V 12
VV
2
 
? rms value of output voltage ?
dc
or
V
V
2
 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
 
 
 
 
 
? If load power factor is lagging, then it requires forced commutation. 
? If load power factor is leading, then natural commutation occurs. 
 
 
Single phase Full Bridge VSI 
When
1
S ,
2
S conduct  
OO
V 0, I 0 ?? 
When
1
D ,
2
D conduct, ??
OO
V 0, I 0 
When
3
S ,
4
S conduct, ??
OO
V 0, I 0 
When
34
D ,D conduct, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
4V
V sin n t
n
 
? rms value of fundamental components is given by 
   ?
?
or1 dc
2
VV 
? rms value of output voltage ?
or dc
VV 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
Three phase full bridge VSI 
 
 
 
 
 
 
 
 
 
 
180
0
conduction mode 
In this mode, each switch will conduct for a period of 
0
180 and phase displacement between 
any two poles is 
0
120 
? Phase voltage 
? ?
?
ph dc
rms
2
VV
3
 
? ?
?
??
??
?
?
dc
RN
n 6k 1
2V
V sin n t
n
 
? ?
R1
V = rms value of fundamental component of 
RN
V 
?
?
dc
R1
2V
V 
Distortion factor, ??
?
R1
ph,rms
V 3
DF
V
 
? ? ? ?
2
1
THD 1 100 31%
DF
 
 
? Line voltage 
? ?
?
?
L L dc
rms
2
VV
3
 
? ? ? ? ? ?
?
??
??
? ? ?
?
?
dc
RY
n 6k 1
4V
n
V sin sin n t
36
n
 
? ?
RY
1
V = rms value of fundamental component of 
RY
V =
? ?
?
?
RY
1
6
V 
Distortion factor = 
3
?
 
In each phase, each switch conducts for 
0
180 out of 
0
360 
 ??
o, rms
r.rms
I
I
2
dc dc
2V V
3R 3R 2
??
?
, Where R = load resistance 
 
 
 
 
 
Voltage Total RMS Fundamental RMS 
Phase 
dc
2
V
3
 
dc
2
V
?
 
Line 
dc
2
V
3
 dc
6
V
?
 
 
? This conversion from total rms to fundamental rms can be performed by multiplication of
?
?
3
DF . 
? This conversion from phase to line voltage can be performed by multiplication of 3 . 
120
0
conduction mode 
For each thyristor, conduction angle is 
0
120 & last 
0
60 for commutation. 
? Phase Voltage 
? ?
?
dc
ph
rms
V
V
6
 
? ? ? ?
?
??
??
? ? ?
?
?
dc
RN
n 6k 1
2V
V sin n sin n t n
36
n
 
?
?
R1 dc
6
VV 
Distortion factor, ?
?
3
DF 
THD = 31% 
 
? Line Voltage 
? ?
?
dc
L
RMS
V
V
2
 
? ?
? ? ? ?
?
??
?
? ? ?
?
?
dc
RY
n 6k 1
3V
V sin n t
3
n
 
? ?
?
?
RY dc
1
3
VV
2
 
Page 5


 
 
 
 
 
Inverters circuits will convert DC power to AC power at required voltage & required frequency. 
Classification 
1) Voltage source Inverter 
? Input source is a voltage source. 
? Switching device is bidirectional & unipolar. 
? Load voltage depends on source voltage & load current depends on load parameters. 
 
2) Current source Inverters 
? Input source is a current source. 
? Switching device is bidirectional & bipolar 
? Load voltage depends on source current & load voltage on load parameters. 
Single phase half bridge VSI 
When 
1
S is ON, 
OO
V 0, I 0 ?? 
When 
2
S is ON, 
OO
V 0, I 0 ?? 
When 
1
D is ON, ??
OO
V 0, I 0 
When 
2
D is ON, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V
2
 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
2V
V sin n t
n
 
? rms value of fundamental components is given by 
   
??
? ? ?
??
??
??
dc
or1 dc
2V 12
VV
2
 
? rms value of output voltage ?
dc
or
V
V
2
 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
 
 
 
 
 
? If load power factor is lagging, then it requires forced commutation. 
? If load power factor is leading, then natural commutation occurs. 
 
 
Single phase Full Bridge VSI 
When
1
S ,
2
S conduct  
OO
V 0, I 0 ?? 
When
1
D ,
2
D conduct, ??
OO
V 0, I 0 
When
3
S ,
4
S conduct, ??
OO
V 0, I 0 
When
34
D ,D conduct, 
OO
V 0, I 0 ?? 
? The output voltage is a square wave of amplitude 
dc
V 
? The fourier series of output voltage is given by  
   
? ?
?
?
??
?
? O
dc
n 1,3,5
4V
V sin n t
n
 
? rms value of fundamental components is given by 
   ?
?
or1 dc
2
VV 
? rms value of output voltage ?
or dc
VV 
? Distortion Factor(DF) = ?
?
or1
or
V 22
V
 
? % Total Harmonic Distortion ??
2
1
THD 1
DF
= 48.43% 
 
Three phase full bridge VSI 
 
 
 
 
 
 
 
 
 
 
180
0
conduction mode 
In this mode, each switch will conduct for a period of 
0
180 and phase displacement between 
any two poles is 
0
120 
? Phase voltage 
? ?
?
ph dc
rms
2
VV
3
 
? ?
?
??
??
?
?
dc
RN
n 6k 1
2V
V sin n t
n
 
? ?
R1
V = rms value of fundamental component of 
RN
V 
?
?
dc
R1
2V
V 
Distortion factor, ??
?
R1
ph,rms
V 3
DF
V
 
? ? ? ?
2
1
THD 1 100 31%
DF
 
 
? Line voltage 
? ?
?
?
L L dc
rms
2
VV
3
 
? ? ? ? ? ?
?
??
??
? ? ?
?
?
dc
RY
n 6k 1
4V
n
V sin sin n t
36
n
 
? ?
RY
1
V = rms value of fundamental component of 
RY
V =
? ?
?
?
RY
1
6
V 
Distortion factor = 
3
?
 
In each phase, each switch conducts for 
0
180 out of 
0
360 
 ??
o, rms
r.rms
I
I
2
dc dc
2V V
3R 3R 2
??
?
, Where R = load resistance 
 
 
 
 
 
Voltage Total RMS Fundamental RMS 
Phase 
dc
2
V
3
 
dc
2
V
?
 
Line 
dc
2
V
3
 dc
6
V
?
 
 
? This conversion from total rms to fundamental rms can be performed by multiplication of
?
?
3
DF . 
? This conversion from phase to line voltage can be performed by multiplication of 3 . 
120
0
conduction mode 
For each thyristor, conduction angle is 
0
120 & last 
0
60 for commutation. 
? Phase Voltage 
? ?
?
dc
ph
rms
V
V
6
 
? ? ? ?
?
??
??
? ? ?
?
?
dc
RN
n 6k 1
2V
V sin n sin n t n
36
n
 
?
?
R1 dc
6
VV 
Distortion factor, ?
?
3
DF 
THD = 31% 
 
? Line Voltage 
? ?
?
dc
L
RMS
V
V
2
 
? ?
? ? ? ?
?
??
?
? ? ?
?
?
dc
RY
n 6k 1
3V
V sin n t
3
n
 
? ?
?
?
RY dc
1
3
VV
2
 
 
 
 
  
 
Distortion factor, = 
3
; THD 31% ?
?
 
In each, phase each switch conducts for 
0
120 out of 
0
360 
 
o, rms
T, rms
I
I
3
?
dc
V
2R
? 
 R = load resistance 
Voltage  Total RMS Fundamental RMS 
Phase 
dc
V
6
 
dc
6
V
?
 
Line 
dc
V
2
 
dc
3
V
2 ?
 
 
? The conversion factor remain same as in 
0
180 conduction mode. 
? In both 
00
120 & 180 conduction mode both phase & line voltages are free from even & triplen 
harmonics. 
 
Voltage control using PWM techniques 
1) Single PWM techniques 
 
In this case, width of positive & negative cycle is not ? but rather equal to 2d. 
? ?
? ? ? ?
?
?
?
??
?
? O
S
n 1,3,5
4V
V sin n sin nd sin n t
2
n
 
To eliminate n
th
 harmonics 
 Sin (nd) = 0 
 d
n
?
? 
Pulse width, 
2 4 6
2d , , ,...................
n n n
? ? ?
? 
 but 2d ?? 
To eliminate 3
rd
 harmonics 
 
2
3d ; d ; 2d
33
??
? ? ? ? 
So pulse width of 
0
120 is required.

	Short Notes for Electrical Engineering 69 docs

Short Notes for Electrical Engineering

69 docs

Join Course for Free

Top Courses for Electrical Engineering (EE)

View all

Related Exams

Electrical Engineering (EE)

About this Document

	4.65/5 Rating
	Nov 06, 2024 Last updated

Document Description: Short Notes: Inverters for Electrical Engineering (EE) 2024 is part of Short Notes for Electrical Engineering preparation. The notes and questions for Short Notes: Inverters have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Short Notes: Inverters covers topics like and Short Notes: Inverters Example, for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Short Notes: Inverters.

Introduction of Short Notes: Inverters in English is available as part of our Short Notes for Electrical Engineering for Electrical Engineering (EE) & Short Notes: Inverters in Hindi for Short Notes for Electrical Engineering course. Download more important topics related with notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Electrical Engineering (EE): Short Notes: Inverters | Short Notes for Electrical Engineering - Electrical Engineering (EE)

Description

Full syllabus notes, lecture & questions for Short Notes: Inverters | Short Notes for Electrical Engineering - Electrical Engineering (EE) - Electrical Engineering (EE) | Plus excerises question with solution to help you revise complete syllabus for Short Notes for Electrical Engineering | Best notes, free PDF download

Information about Short Notes: Inverters

In this doc you can find the meaning of Short Notes: Inverters defined & explained in the simplest way possible. Besides explaining types of Short Notes: Inverters theory, EduRev gives you an ample number of questions to practice Short Notes: Inverters tests, examples and also practice Electrical Engineering (EE) tests

	Short Notes for Electrical Engineering 69 docs

Short Notes for Electrical Engineering

69 docs

Join Course for Free

Download as PDF

Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses

Signup for Free!

Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.

Start learning for Free

10M+ students study on EduRev

Summary

Sample Paper

Short Notes: Inverters | Short Notes for Electrical Engineering - Electrical Engineering (EE)

ppt

Free

Previous Year Questions with Solutions

Extra Questions

video lectures

mock tests for examination

Exam

Viva Questions

study material

past year papers

shortcuts and tricks

Semester Notes

Short Notes: Inverters | Short Notes for Electrical Engineering - Electrical Engineering (EE)

MCQs

Important questions

practice quizzes

Short Notes: Inverters | Short Notes for Electrical Engineering - Electrical Engineering (EE)

Objective type Questions

pdf

;

Additional Information about Short Notes: Inverters for Electrical Engineering (EE) Preparation

Short Notes: Inverters Free PDF Download

The Short Notes: Inverters is an invaluable resource that delves deep into the core of the Electrical Engineering (EE) exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the Short Notes: Inverters now and kickstart your journey towards success in the Electrical Engineering (EE) exam.

Importance of Short Notes: Inverters

The importance of Short Notes: Inverters cannot be overstated, especially for Electrical Engineering (EE) aspirants. This document holds the key to success in the Electrical Engineering (EE) exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

Short Notes: Inverters

Short Notes: Inverters Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to Short Notes: Inverters. It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, Short Notes: Inverters Notes on EduRev are your ultimate resource for success.

Short Notes: Inverters Electrical Engineering (EE) Questions

The "Short Notes: Inverters Electrical Engineering (EE) Questions" guide is a valuable resource for all aspiring students preparing for the Electrical Engineering (EE) exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study Short Notes: Inverters on the App

Students of Electrical Engineering (EE) can study Short Notes: Inverters alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the Short Notes: Inverters, students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of Short Notes: Inverters is prepared as per the latest Electrical Engineering (EE) syllabus.

Education Revolution