Page 1
Two types of stability are studied:
1) Steady State Stability
2) Transient Stability
Steady State Stability
For Steady State Stability
dP
0
d
?
?
And for this condition to be true.
e max
PP ?
If power demand is greater than maximum demand than machine goes out of synchronous.
For a loss less machine,
max
S
EV
P
X
?
Transient Stability
Swing Equation
? ?
2
me 2
Md
PP
dt
?
??
M = inertia constant ( MJ-S / elect - rad)
P m= mechanical input (MW)
e
P = electrical output (MW)
? = rotor angle
Another Form
? ?
2
me 2
Hd
PP
f dt
?
??
?
H = inertia constant ( MJ / MVA)
m
P &
e
P both are in pu
Page 2
Two types of stability are studied:
1) Steady State Stability
2) Transient Stability
Steady State Stability
For Steady State Stability
dP
0
d
?
?
And for this condition to be true.
e max
PP ?
If power demand is greater than maximum demand than machine goes out of synchronous.
For a loss less machine,
max
S
EV
P
X
?
Transient Stability
Swing Equation
? ?
2
me 2
Md
PP
dt
?
??
M = inertia constant ( MJ-S / elect - rad)
P m= mechanical input (MW)
e
P = electrical output (MW)
? = rotor angle
Another Form
? ?
2
me 2
Hd
PP
f dt
?
??
?
H = inertia constant ( MJ / MVA)
m
P &
e
P both are in pu
GH
M
180f
? (MJ – S / elect - deg)
GH
M
f
?
?
(MJ – S / elect - rad)
G = machine rating (MVA)
? If two alternators are swinging coherently. Then they can be replaced by a single
alternator having
eq 1 2
M M M ??
But “ H “ cannot be added directly, they must first be on same base.
? If machines are not swinging coherently, then
12
eq
12
MM
M
MM
?
?
? Accelerating Power,
? ?
a m e
P P P ??
In steady state
me
PP ?
In transient,
me
PP ? so rotor accelerate or decelerate.
Equal area criterion
For system to possess transient stability
a
P d 0 ??
?
There are basically 3 stages in stability analysis
? Before Fault
We say maximum power transferrable is
max,1
P
&
e max,1
P P sin ??
? During fault
We say maximum power transferrable is
max,2
P
e max,2
P P sin ??
? After Fault
We say maximum power transferrable is
max,3
P
e max,3
P P sin ??
Page 3
Two types of stability are studied:
1) Steady State Stability
2) Transient Stability
Steady State Stability
For Steady State Stability
dP
0
d
?
?
And for this condition to be true.
e max
PP ?
If power demand is greater than maximum demand than machine goes out of synchronous.
For a loss less machine,
max
S
EV
P
X
?
Transient Stability
Swing Equation
? ?
2
me 2
Md
PP
dt
?
??
M = inertia constant ( MJ-S / elect - rad)
P m= mechanical input (MW)
e
P = electrical output (MW)
? = rotor angle
Another Form
? ?
2
me 2
Hd
PP
f dt
?
??
?
H = inertia constant ( MJ / MVA)
m
P &
e
P both are in pu
GH
M
180f
? (MJ – S / elect - deg)
GH
M
f
?
?
(MJ – S / elect - rad)
G = machine rating (MVA)
? If two alternators are swinging coherently. Then they can be replaced by a single
alternator having
eq 1 2
M M M ??
But “ H “ cannot be added directly, they must first be on same base.
? If machines are not swinging coherently, then
12
eq
12
MM
M
MM
?
?
? Accelerating Power,
? ?
a m e
P P P ??
In steady state
me
PP ?
In transient,
me
PP ? so rotor accelerate or decelerate.
Equal area criterion
For system to possess transient stability
a
P d 0 ??
?
There are basically 3 stages in stability analysis
? Before Fault
We say maximum power transferrable is
max,1
P
&
e max,1
P P sin ??
? During fault
We say maximum power transferrable is
max,2
P
e max,2
P P sin ??
? After Fault
We say maximum power transferrable is
max,3
P
e max,3
P P sin ??
Critical clearing angle
It is the maximum value of ? beyond which if the fault is cleared system will be unstable. The
time instant corresponding to this angle is called as critical clearing time assuming fault occurs
at t = 0.
Case-1 : Fault occurs on TL near to bus
max,2
P0 ?
max,3 max,1
PP ?
Cr
clearing angle ??
By equal area criteria
? ?
2
0
m max,1
P P sin d 0
?
?
? ? ? ?
?
1 m
0
max,1
P
sin
P
?
??
??
??
??
??
For critical clearing
2 max
? ? ?
0 max
? ? ? ? ?
? ?
Cr 0
Cr
m
2H
t
fP
? ? ?
?
?
= Critical Clearing Time
Case-2 : Fault occurs on one of parallel lines close to bus
Before Fault
? ?
max,1
g 1 2
EV
P
X X X
?
?
During Fault
max,2
eq
EV
P0
X
??
After Fault
max,3
g1
EV
P
XX
?
?
Page 4
Two types of stability are studied:
1) Steady State Stability
2) Transient Stability
Steady State Stability
For Steady State Stability
dP
0
d
?
?
And for this condition to be true.
e max
PP ?
If power demand is greater than maximum demand than machine goes out of synchronous.
For a loss less machine,
max
S
EV
P
X
?
Transient Stability
Swing Equation
? ?
2
me 2
Md
PP
dt
?
??
M = inertia constant ( MJ-S / elect - rad)
P m= mechanical input (MW)
e
P = electrical output (MW)
? = rotor angle
Another Form
? ?
2
me 2
Hd
PP
f dt
?
??
?
H = inertia constant ( MJ / MVA)
m
P &
e
P both are in pu
GH
M
180f
? (MJ – S / elect - deg)
GH
M
f
?
?
(MJ – S / elect - rad)
G = machine rating (MVA)
? If two alternators are swinging coherently. Then they can be replaced by a single
alternator having
eq 1 2
M M M ??
But “ H “ cannot be added directly, they must first be on same base.
? If machines are not swinging coherently, then
12
eq
12
MM
M
MM
?
?
? Accelerating Power,
? ?
a m e
P P P ??
In steady state
me
PP ?
In transient,
me
PP ? so rotor accelerate or decelerate.
Equal area criterion
For system to possess transient stability
a
P d 0 ??
?
There are basically 3 stages in stability analysis
? Before Fault
We say maximum power transferrable is
max,1
P
&
e max,1
P P sin ??
? During fault
We say maximum power transferrable is
max,2
P
e max,2
P P sin ??
? After Fault
We say maximum power transferrable is
max,3
P
e max,3
P P sin ??
Critical clearing angle
It is the maximum value of ? beyond which if the fault is cleared system will be unstable. The
time instant corresponding to this angle is called as critical clearing time assuming fault occurs
at t = 0.
Case-1 : Fault occurs on TL near to bus
max,2
P0 ?
max,3 max,1
PP ?
Cr
clearing angle ??
By equal area criteria
? ?
2
0
m max,1
P P sin d 0
?
?
? ? ? ?
?
1 m
0
max,1
P
sin
P
?
??
??
??
??
??
For critical clearing
2 max
? ? ?
0 max
? ? ? ? ?
? ?
Cr 0
Cr
m
2H
t
fP
? ? ?
?
?
= Critical Clearing Time
Case-2 : Fault occurs on one of parallel lines close to bus
Before Fault
? ?
max,1
g 1 2
EV
P
X X X
?
?
During Fault
max,2
eq
EV
P0
X
??
After Fault
max,3
g1
EV
P
XX
?
?
1 m
0
max,1
P
sin
P
??
??
??
??
??
1 m
max
max,3
P
sin
P
?
??
??
??
??
? ? ? ?
For transient stability
2
0
a
P d 0
?
?
??
?
? ? ? ?
c 2
c 0
mm max,3
P 0 d P P sin d 0
? ?
??
? ? ? ? ? ? ?
??
For critical Clearing
2 max
? ? ?
? ?
Cr 0
Cr
m
2H
t
fP
? ? ?
?
?
Case-3 : Fault occurs in middle of one of parallel lines
The equivalent reactance during the fault is highest and thus
max,2
P is lowest
max,1 max,3 max,2
P P P ??
2
0
a
P d 0
?
?
??
?
? ? ? ?
c 2
c
0
mm
max,2 max,3
P P sin d P sin P d
?
?
??
? ? ? ? ? ? ?
??
For critical clearing,
2 max
? ? ?
1 m
max,3
P
sin
P
?
??
??
??
??
? ? ?
Page 5
Two types of stability are studied:
1) Steady State Stability
2) Transient Stability
Steady State Stability
For Steady State Stability
dP
0
d
?
?
And for this condition to be true.
e max
PP ?
If power demand is greater than maximum demand than machine goes out of synchronous.
For a loss less machine,
max
S
EV
P
X
?
Transient Stability
Swing Equation
? ?
2
me 2
Md
PP
dt
?
??
M = inertia constant ( MJ-S / elect - rad)
P m= mechanical input (MW)
e
P = electrical output (MW)
? = rotor angle
Another Form
? ?
2
me 2
Hd
PP
f dt
?
??
?
H = inertia constant ( MJ / MVA)
m
P &
e
P both are in pu
GH
M
180f
? (MJ – S / elect - deg)
GH
M
f
?
?
(MJ – S / elect - rad)
G = machine rating (MVA)
? If two alternators are swinging coherently. Then they can be replaced by a single
alternator having
eq 1 2
M M M ??
But “ H “ cannot be added directly, they must first be on same base.
? If machines are not swinging coherently, then
12
eq
12
MM
M
MM
?
?
? Accelerating Power,
? ?
a m e
P P P ??
In steady state
me
PP ?
In transient,
me
PP ? so rotor accelerate or decelerate.
Equal area criterion
For system to possess transient stability
a
P d 0 ??
?
There are basically 3 stages in stability analysis
? Before Fault
We say maximum power transferrable is
max,1
P
&
e max,1
P P sin ??
? During fault
We say maximum power transferrable is
max,2
P
e max,2
P P sin ??
? After Fault
We say maximum power transferrable is
max,3
P
e max,3
P P sin ??
Critical clearing angle
It is the maximum value of ? beyond which if the fault is cleared system will be unstable. The
time instant corresponding to this angle is called as critical clearing time assuming fault occurs
at t = 0.
Case-1 : Fault occurs on TL near to bus
max,2
P0 ?
max,3 max,1
PP ?
Cr
clearing angle ??
By equal area criteria
? ?
2
0
m max,1
P P sin d 0
?
?
? ? ? ?
?
1 m
0
max,1
P
sin
P
?
??
??
??
??
??
For critical clearing
2 max
? ? ?
0 max
? ? ? ? ?
? ?
Cr 0
Cr
m
2H
t
fP
? ? ?
?
?
= Critical Clearing Time
Case-2 : Fault occurs on one of parallel lines close to bus
Before Fault
? ?
max,1
g 1 2
EV
P
X X X
?
?
During Fault
max,2
eq
EV
P0
X
??
After Fault
max,3
g1
EV
P
XX
?
?
1 m
0
max,1
P
sin
P
??
??
??
??
??
1 m
max
max,3
P
sin
P
?
??
??
??
??
? ? ? ?
For transient stability
2
0
a
P d 0
?
?
??
?
? ? ? ?
c 2
c 0
mm max,3
P 0 d P P sin d 0
? ?
??
? ? ? ? ? ? ?
??
For critical Clearing
2 max
? ? ?
? ?
Cr 0
Cr
m
2H
t
fP
? ? ?
?
?
Case-3 : Fault occurs in middle of one of parallel lines
The equivalent reactance during the fault is highest and thus
max,2
P is lowest
max,1 max,3 max,2
P P P ??
2
0
a
P d 0
?
?
??
?
? ? ? ?
c 2
c
0
mm
max,2 max,3
P P sin d P sin P d
?
?
??
? ? ? ? ? ? ?
??
For critical clearing,
2 max
? ? ?
1 m
max,3
P
sin
P
?
??
??
??
??
? ? ?
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