Explore Exams
Login Signup
Sign in Open App
Commerce Exam  >  Commerce Notes  >  Mathematics (Maths) Class 11  >  RD Sharma Class 11 Solutions Chapter - Combinations

RD Sharma Class 11 Solutions Chapter - Combinations

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


17. Combinations
Exercise 17.1
1 A. Question
Evaluate the following:
14
C
3
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 364.
1 B. Question
Evaluate the following:
12
C
10
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 66.
1 C. Question
Evaluate the following:
35
C
35
Answer
Page 2


17. Combinations
Exercise 17.1
1 A. Question
Evaluate the following:
14
C
3
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 364.
1 B. Question
Evaluate the following:
12
C
10
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 66.
1 C. Question
Evaluate the following:
35
C
35
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
We know that 0! = 1
? 
? 
? The value of  is 1.
1 D. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is n + 1.
1 E. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
Page 3


17. Combinations
Exercise 17.1
1 A. Question
Evaluate the following:
14
C
3
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 364.
1 B. Question
Evaluate the following:
12
C
10
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 66.
1 C. Question
Evaluate the following:
35
C
35
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
We know that 0! = 1
? 
? 
? The value of  is 1.
1 D. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is n + 1.
1 E. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
We know that 0! = 1
? 
? 
? 
? The value of  is 31.
2. Question
If 
n
C
12
 = 
n
C
5
, find the value of n.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 12?5
So, the condition(ii) must be satisfied,
? n = 12 + 5
? n = 17.
? The value of n is 17.
3. Question
If 
n
C
4
 = 
n
C
6
, find 
12
C
n
.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 4?6
So, the condition(ii) must be satisfied,
? n = 4 + 6
? n = 10.
We need to find the value of 
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Page 4


17. Combinations
Exercise 17.1
1 A. Question
Evaluate the following:
14
C
3
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 364.
1 B. Question
Evaluate the following:
12
C
10
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 66.
1 C. Question
Evaluate the following:
35
C
35
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
We know that 0! = 1
? 
? 
? The value of  is 1.
1 D. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is n + 1.
1 E. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
We know that 0! = 1
? 
? 
? 
? The value of  is 31.
2. Question
If 
n
C
12
 = 
n
C
5
, find the value of n.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 12?5
So, the condition(ii) must be satisfied,
? n = 12 + 5
? n = 17.
? The value of n is 17.
3. Question
If 
n
C
4
 = 
n
C
6
, find 
12
C
n
.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 4?6
So, the condition(ii) must be satisfied,
? n = 4 + 6
? n = 10.
We need to find the value of 
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
From (1)
? 
? 
? 
? 
? The value of  is 66.
4. Question
If 
n
C
10
 = 
n
C
12
, find 
23
C
n
.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 10?12
So, the condition(ii) must be satisfied,
? n = 10 + 12
? n = 22.
We need to find the value of 
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
From (1)
? 
? 
? 
? 
? The value of  is 23.
5. Question
If 
24
C
x
 = 
24
C
2x + 3
, find x.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
Let us use condition (i),
Page 5


17. Combinations
Exercise 17.1
1 A. Question
Evaluate the following:
14
C
3
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 364.
1 B. Question
Evaluate the following:
12
C
10
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is 66.
1 C. Question
Evaluate the following:
35
C
35
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
We know that 0! = 1
? 
? 
? The value of  is 1.
1 D. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
? 
? The value of  is n + 1.
1 E. Question
Evaluate the following:
Answer
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
Given that we need to find the value of 
From (1)
? 
? 
? 
We know that 0! = 1
? 
? 
? 
? The value of  is 31.
2. Question
If 
n
C
12
 = 
n
C
5
, find the value of n.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 12?5
So, the condition(ii) must be satisfied,
? n = 12 + 5
? n = 17.
? The value of n is 17.
3. Question
If 
n
C
4
 = 
n
C
6
, find 
12
C
n
.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 4?6
So, the condition(ii) must be satisfied,
? n = 4 + 6
? n = 10.
We need to find the value of 
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
From (1)
? 
? 
? 
? 
? The value of  is 66.
4. Question
If 
n
C
10
 = 
n
C
12
, find 
23
C
n
.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? 10?12
So, the condition(ii) must be satisfied,
? n = 10 + 12
? n = 22.
We need to find the value of 
We know that  ..... (1)
And also n! = n(n – 1)(n – 2)…………2.1
From (1)
? 
? 
? 
? 
? The value of  is 23.
5. Question
If 
24
C
x
 = 
24
C
2x + 3
, find x.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
Let us use condition (i),
? x = 2x + 3
? x = – 3
We know that for a combination 
n
C
r
,r=0 and r should be an integer which is not satisfies here,
So, the condition (ii) must be satisfied,
? 24 = x + 2x + 3
? 3x = 21
? 
? x = 7.
? The value of x is 7.
6. Question
If 
18
C
x
 = 
18
C
x + 2
, find x.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
From the problem  we can say that,
? x?x + 2
So, the condition(ii) must be satisfied,
? 18 = x + x + 2
? 2x = 16
? 
? x = 8.
? The value of x is 8.
7. Question
If 
15
C
3r
 = 
15
C
r + 3
, find r.
Answer
We know that if , then one of the following conditions need to be satisfied:
i. p = q
ii. n = p + q
Let us use condition (i),
? 3r = r + 3
? 2r = 3
? 
? 
?
Read More
Join Course for Free
About this Document
4.80/5 Rating
Apr 29, 2026 Last updated
Related Exams
Document Description: RD Sharma Class 11 Solutions Chapter - Combinations for Commerce 2026 is part of Mathematics (Maths) Class 11 preparation. The notes and questions for RD Sharma Class 11 Solutions Chapter - Combinations have been prepared according to the Commerce exam syllabus. Information about RD Sharma Class 11 Solutions Chapter - Combinations covers topics like and RD Sharma Class 11 Solutions Chapter - Combinations Example, for Commerce 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Class 11 Solutions Chapter - Combinations.
Introduction of RD Sharma Class 11 Solutions Chapter - Combinations in English is available as part of our Mathematics (Maths) Class 11 for Commerce & RD Sharma Class 11 Solutions Chapter - Combinations in Hindi for Mathematics (Maths) Class 11 course. Download more important topics related with notes, lectures and mock test series for Commerce Exam by signing up for free. Commerce: RD Sharma Class 11 Solutions Chapter - Combinations
Description
RD Sharma Class 11 Solutions Chapter of Maths Class 11 on EduRev - covers important questions, MCQs with answers. Helps you prepare for exam.
Information about RD Sharma Class 11 Solutions Chapter - Combinations
In this doc you can find the meaning of RD Sharma Class 11 Solutions Chapter - Combinations defined & explained in the simplest way possible. Besides explaining types of RD Sharma Class 11 Solutions Chapter - Combinations theory, EduRev gives you an ample number of questions to practice RD Sharma Class 11 Solutions Chapter - Combinations tests, examples and also practice Commerce tests
Explore Courses for Commerce exam
Related Searches
RD Sharma Class 11 Solutions Chapter - Combinations, mock tests for examination, ppt, RD Sharma Class 11 Solutions Chapter - Combinations, Exam, Extra Questions, Free, Viva Questions, Previous Year Questions with Solutions, Summary, Sample Paper, practice quizzes, Semester Notes, study material, MCQs, Objective type Questions, Important questions, video lectures, RD Sharma Class 11 Solutions Chapter - Combinations, pdf , shortcuts and tricks, past year papers;
Additional Information about RD Sharma Class 11 Solutions Chapter - Combinations for Commerce Preparation

RD Sharma Class 11 Solutions Chapter - Combinations Free PDF Download

The RD Sharma Class 11 Solutions Chapter - Combinations is an invaluable resource that delves deep into the core of the Commerce exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the RD Sharma Class 11 Solutions Chapter - Combinations now and kickstart your journey towards success in the Commerce exam.

Importance of RD Sharma Class 11 Solutions Chapter - Combinations

The importance of RD Sharma Class 11 Solutions Chapter - Combinations cannot be overstated, especially for Commerce aspirants. This document holds the key to success in the Commerce exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

RD Sharma Class 11 Solutions Chapter - Combinations Notes

RD Sharma Class 11 Solutions Chapter - Combinations Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to RD Sharma Class 11 Solutions Chapter - Combinations. It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, RD Sharma Class 11 Solutions Chapter - Combinations Notes on EduRev are your ultimate resource for success.

RD Sharma Class 11 Solutions Chapter - Combinations Commerce Questions

The "RD Sharma Class 11 Solutions Chapter - Combinations Commerce Questions" guide is a valuable resource for all aspiring students preparing for the Commerce exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study RD Sharma Class 11 Solutions Chapter - Combinations on the App

Students of Commerce can study RD Sharma Class 11 Solutions Chapter - Combinations alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the RD Sharma Class 11 Solutions Chapter - Combinations, students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of RD Sharma Class 11 Solutions Chapter - Combinations is prepared as per the latest Commerce syllabus.
Signup to see your scores go up
within 7 days!
Takes less than 10 seconds to signup