JEE Exam > JEE Notes > Mathematics (Maths) for JEE Main & Advanced > Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024)
Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
JEE Mains Previous Year Questions
(2021-2024): Application of
Derivatives
2024
Q1 - 2024 (01 Feb Shift 1)
If 5f( x)+ 4f (
1
x
)= x
2
- 2, ?x ? 0 and y = 9x
2
f( x) , then y is strictly increasing in :
(1) ( 0,
1
v5
)? (
1
v5
, 8)
(2) ( -
1
v5
, 0)? (
1
v5
, 8)
(3) ( -
1
v5
, 0)? ( 0,
1
v5
)
(4) ( -8,
1
v5
)? ( 0,
1
v5
)
Q2 - 2024 (27 Jan Shift 2)
Let ?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0 for all x ? ( 0,3) . If g is decreasing in ( 0, ?? )
and increasing in ( ?? , 3) , then 8?? is
(1) 24
(2) 0
(3) 18
(4) 20
Q3 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )= 2?? + 3( ?? )
2
3
, ?? ? R, has
(1) exactly one point of local minima and no point of local maxima
(2) exactly one point of local maxima and no point of local minima
(3) exactly one point of local maxima and exactly one point of local minima
Page 2
JEE Mains Previous Year Questions
(2021-2024): Application of
Derivatives
2024
Q1 - 2024 (01 Feb Shift 1)
If 5f( x)+ 4f (
1
x
)= x
2
- 2, ?x ? 0 and y = 9x
2
f( x) , then y is strictly increasing in :
(1) ( 0,
1
v5
)? (
1
v5
, 8)
(2) ( -
1
v5
, 0)? (
1
v5
, 8)
(3) ( -
1
v5
, 0)? ( 0,
1
v5
)
(4) ( -8,
1
v5
)? ( 0,
1
v5
)
Q2 - 2024 (27 Jan Shift 2)
Let ?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0 for all x ? ( 0,3) . If g is decreasing in ( 0, ?? )
and increasing in ( ?? , 3) , then 8?? is
(1) 24
(2) 0
(3) 18
(4) 20
Q3 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )= 2?? + 3( ?? )
2
3
, ?? ? R, has
(1) exactly one point of local minima and no point of local maxima
(2) exactly one point of local maxima and no point of local minima
(3) exactly one point of local maxima and exactly one point of local minima
(4) exactly two points of local maxima and exactly one point of local minima
Q4 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )=
?? ?? 2
-6?? -16
, ?? ? R - {-2,8}
(1) decreases in ( -2,8) and increases in
( -8, -2)? ( 8, 8)
(2) decreases in ( -8, -2)? ( -2,8)? ( 8, 8)
(3) decreases in ( -8, -2) and increases in ( 8, 8)
(4) increases in ( -8, -2)? ( -2,8)? ( 8, 8)
Q5 - 2024 (30 Jan Shift 1)
Let g: R ? R be a non constant twice differentiable such that g
'
(
1
2
)= g
'
(
3
2
) . If a real
valued function f is defined as ?? ( ?? )=
1
2
[?? ( ?? )+ ?? ( 2 - ?? ) ], then
(1) ?? ''
( ?? )= 0 for atleast two ?? in ( 0,2)
(2) ?? ''
( ?? )= 0 for exactly one ?? in ( 0,1)
(3) ?? ''
( ?? )= 0 for no ?? in ( 0,1)
(4) f
'
(
3
2
)+ f
'
(
1
2
)= 1
Q6 - 2024 (30 Jan Shift 2)
Let ?? ( ?? )= ( ?? + 3)
2
( ?? - 2)
3
, ?? ? [-4,4]. If ?? and ?? are the maximum and minimum
values of ?? , respectively in [-4,4], then the value of ?? - ?? is :
(1) 600
(2) 392
(3) 608
(4) 108
Answer Key
Q1 (2)
Q2 (3)
Page 3
JEE Mains Previous Year Questions
(2021-2024): Application of
Derivatives
2024
Q1 - 2024 (01 Feb Shift 1)
If 5f( x)+ 4f (
1
x
)= x
2
- 2, ?x ? 0 and y = 9x
2
f( x) , then y is strictly increasing in :
(1) ( 0,
1
v5
)? (
1
v5
, 8)
(2) ( -
1
v5
, 0)? (
1
v5
, 8)
(3) ( -
1
v5
, 0)? ( 0,
1
v5
)
(4) ( -8,
1
v5
)? ( 0,
1
v5
)
Q2 - 2024 (27 Jan Shift 2)
Let ?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0 for all x ? ( 0,3) . If g is decreasing in ( 0, ?? )
and increasing in ( ?? , 3) , then 8?? is
(1) 24
(2) 0
(3) 18
(4) 20
Q3 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )= 2?? + 3( ?? )
2
3
, ?? ? R, has
(1) exactly one point of local minima and no point of local maxima
(2) exactly one point of local maxima and no point of local minima
(3) exactly one point of local maxima and exactly one point of local minima
(4) exactly two points of local maxima and exactly one point of local minima
Q4 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )=
?? ?? 2
-6?? -16
, ?? ? R - {-2,8}
(1) decreases in ( -2,8) and increases in
( -8, -2)? ( 8, 8)
(2) decreases in ( -8, -2)? ( -2,8)? ( 8, 8)
(3) decreases in ( -8, -2) and increases in ( 8, 8)
(4) increases in ( -8, -2)? ( -2,8)? ( 8, 8)
Q5 - 2024 (30 Jan Shift 1)
Let g: R ? R be a non constant twice differentiable such that g
'
(
1
2
)= g
'
(
3
2
) . If a real
valued function f is defined as ?? ( ?? )=
1
2
[?? ( ?? )+ ?? ( 2 - ?? ) ], then
(1) ?? ''
( ?? )= 0 for atleast two ?? in ( 0,2)
(2) ?? ''
( ?? )= 0 for exactly one ?? in ( 0,1)
(3) ?? ''
( ?? )= 0 for no ?? in ( 0,1)
(4) f
'
(
3
2
)+ f
'
(
1
2
)= 1
Q6 - 2024 (30 Jan Shift 2)
Let ?? ( ?? )= ( ?? + 3)
2
( ?? - 2)
3
, ?? ? [-4,4]. If ?? and ?? are the maximum and minimum
values of ?? , respectively in [-4,4], then the value of ?? - ?? is :
(1) 600
(2) 392
(3) 608
(4) 108
Answer Key
Q1 (2)
Q2 (3)
Q3 (3)
Q4 (2)
Q5 (1)
Q6 (3)
Solutions
Q1
5f( x)+ 4f (
1
?? )= x
2
- 2, ??? ? 0
Substitute ?? ?
1
??
5?? (
1
?? )+ 4?? ( ?? )=
1
?? 2
- 2
On solving (1) and (2)
?? ( ?? )=
5?? 4
- 2?? 2
- 4
9?? 2
?? = 9?? 2
?? ( ?? )
?? = 5?? 4
- 2?? 2
- 4.
????
????
= 20?? 3
- 4??
for strictly increasing
dy
dx
> 0
4x( 5x
2
- 1)> 0
x ? ( -
1
v5
, 0)? (
1
v5
, 8)
Q2
?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0??? ? ( 0,3)? f
'
( x) is increasing function
Page 4
JEE Mains Previous Year Questions
(2021-2024): Application of
Derivatives
2024
Q1 - 2024 (01 Feb Shift 1)
If 5f( x)+ 4f (
1
x
)= x
2
- 2, ?x ? 0 and y = 9x
2
f( x) , then y is strictly increasing in :
(1) ( 0,
1
v5
)? (
1
v5
, 8)
(2) ( -
1
v5
, 0)? (
1
v5
, 8)
(3) ( -
1
v5
, 0)? ( 0,
1
v5
)
(4) ( -8,
1
v5
)? ( 0,
1
v5
)
Q2 - 2024 (27 Jan Shift 2)
Let ?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0 for all x ? ( 0,3) . If g is decreasing in ( 0, ?? )
and increasing in ( ?? , 3) , then 8?? is
(1) 24
(2) 0
(3) 18
(4) 20
Q3 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )= 2?? + 3( ?? )
2
3
, ?? ? R, has
(1) exactly one point of local minima and no point of local maxima
(2) exactly one point of local maxima and no point of local minima
(3) exactly one point of local maxima and exactly one point of local minima
(4) exactly two points of local maxima and exactly one point of local minima
Q4 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )=
?? ?? 2
-6?? -16
, ?? ? R - {-2,8}
(1) decreases in ( -2,8) and increases in
( -8, -2)? ( 8, 8)
(2) decreases in ( -8, -2)? ( -2,8)? ( 8, 8)
(3) decreases in ( -8, -2) and increases in ( 8, 8)
(4) increases in ( -8, -2)? ( -2,8)? ( 8, 8)
Q5 - 2024 (30 Jan Shift 1)
Let g: R ? R be a non constant twice differentiable such that g
'
(
1
2
)= g
'
(
3
2
) . If a real
valued function f is defined as ?? ( ?? )=
1
2
[?? ( ?? )+ ?? ( 2 - ?? ) ], then
(1) ?? ''
( ?? )= 0 for atleast two ?? in ( 0,2)
(2) ?? ''
( ?? )= 0 for exactly one ?? in ( 0,1)
(3) ?? ''
( ?? )= 0 for no ?? in ( 0,1)
(4) f
'
(
3
2
)+ f
'
(
1
2
)= 1
Q6 - 2024 (30 Jan Shift 2)
Let ?? ( ?? )= ( ?? + 3)
2
( ?? - 2)
3
, ?? ? [-4,4]. If ?? and ?? are the maximum and minimum
values of ?? , respectively in [-4,4], then the value of ?? - ?? is :
(1) 600
(2) 392
(3) 608
(4) 108
Answer Key
Q1 (2)
Q2 (3)
Q3 (3)
Q4 (2)
Q5 (1)
Q6 (3)
Solutions
Q1
5f( x)+ 4f (
1
?? )= x
2
- 2, ??? ? 0
Substitute ?? ?
1
??
5?? (
1
?? )+ 4?? ( ?? )=
1
?? 2
- 2
On solving (1) and (2)
?? ( ?? )=
5?? 4
- 2?? 2
- 4
9?? 2
?? = 9?? 2
?? ( ?? )
?? = 5?? 4
- 2?? 2
- 4.
????
????
= 20?? 3
- 4??
for strictly increasing
dy
dx
> 0
4x( 5x
2
- 1)> 0
x ? ( -
1
v5
, 0)? (
1
v5
, 8)
Q2
?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0??? ? ( 0,3)? f
'
( x) is increasing function
?? '
( ?? )= 3 ×
1
3
· ?? '
(
?? 3
)- ?? '
( 3 - ?? )
= ?? '
(
?? 3
)- ?? '
( 3 - ?? )
If g is decreasing in ( 0, ?? )
g
'
( x)< 0
f
'
(
x
3
)+ f
'
( 3 - x)< 0
f
'
(
x
3
)< f
'
( 3 - x)
?
x
3
< 3 - x
? x <
9
4
Therefore ?? =
9
4
Then 8?? = 8 ×
9
4
= 18
Q3
?? ( ?? )= 2?? + 3( ?? )
2
3
?? '
( ?? )= 2 + 2?? -1
3
= 2 (1 +
1
?? 1
3
)
= 2 (
?? 1
3
+ 1
?? 1
3
)
So, maxima ( M) at x = -1&minima ( m) at x = 0
Q4
?? ( ?? )=
?? ?? 2
- 6?? - 16
Now,
Page 5
JEE Mains Previous Year Questions
(2021-2024): Application of
Derivatives
2024
Q1 - 2024 (01 Feb Shift 1)
If 5f( x)+ 4f (
1
x
)= x
2
- 2, ?x ? 0 and y = 9x
2
f( x) , then y is strictly increasing in :
(1) ( 0,
1
v5
)? (
1
v5
, 8)
(2) ( -
1
v5
, 0)? (
1
v5
, 8)
(3) ( -
1
v5
, 0)? ( 0,
1
v5
)
(4) ( -8,
1
v5
)? ( 0,
1
v5
)
Q2 - 2024 (27 Jan Shift 2)
Let ?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0 for all x ? ( 0,3) . If g is decreasing in ( 0, ?? )
and increasing in ( ?? , 3) , then 8?? is
(1) 24
(2) 0
(3) 18
(4) 20
Q3 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )= 2?? + 3( ?? )
2
3
, ?? ? R, has
(1) exactly one point of local minima and no point of local maxima
(2) exactly one point of local maxima and no point of local minima
(3) exactly one point of local maxima and exactly one point of local minima
(4) exactly two points of local maxima and exactly one point of local minima
Q4 - 2024 (29 Jan Shift 2)
The function ?? ( ?? )=
?? ?? 2
-6?? -16
, ?? ? R - {-2,8}
(1) decreases in ( -2,8) and increases in
( -8, -2)? ( 8, 8)
(2) decreases in ( -8, -2)? ( -2,8)? ( 8, 8)
(3) decreases in ( -8, -2) and increases in ( 8, 8)
(4) increases in ( -8, -2)? ( -2,8)? ( 8, 8)
Q5 - 2024 (30 Jan Shift 1)
Let g: R ? R be a non constant twice differentiable such that g
'
(
1
2
)= g
'
(
3
2
) . If a real
valued function f is defined as ?? ( ?? )=
1
2
[?? ( ?? )+ ?? ( 2 - ?? ) ], then
(1) ?? ''
( ?? )= 0 for atleast two ?? in ( 0,2)
(2) ?? ''
( ?? )= 0 for exactly one ?? in ( 0,1)
(3) ?? ''
( ?? )= 0 for no ?? in ( 0,1)
(4) f
'
(
3
2
)+ f
'
(
1
2
)= 1
Q6 - 2024 (30 Jan Shift 2)
Let ?? ( ?? )= ( ?? + 3)
2
( ?? - 2)
3
, ?? ? [-4,4]. If ?? and ?? are the maximum and minimum
values of ?? , respectively in [-4,4], then the value of ?? - ?? is :
(1) 600
(2) 392
(3) 608
(4) 108
Answer Key
Q1 (2)
Q2 (3)
Q3 (3)
Q4 (2)
Q5 (1)
Q6 (3)
Solutions
Q1
5f( x)+ 4f (
1
?? )= x
2
- 2, ??? ? 0
Substitute ?? ?
1
??
5?? (
1
?? )+ 4?? ( ?? )=
1
?? 2
- 2
On solving (1) and (2)
?? ( ?? )=
5?? 4
- 2?? 2
- 4
9?? 2
?? = 9?? 2
?? ( ?? )
?? = 5?? 4
- 2?? 2
- 4.
????
????
= 20?? 3
- 4??
for strictly increasing
dy
dx
> 0
4x( 5x
2
- 1)> 0
x ? ( -
1
v5
, 0)? (
1
v5
, 8)
Q2
?? ( ?? )= 3?? (
?? 3
)+ ?? ( 3 - ?? ) and ?? ''
( ?? )> 0??? ? ( 0,3)? f
'
( x) is increasing function
?? '
( ?? )= 3 ×
1
3
· ?? '
(
?? 3
)- ?? '
( 3 - ?? )
= ?? '
(
?? 3
)- ?? '
( 3 - ?? )
If g is decreasing in ( 0, ?? )
g
'
( x)< 0
f
'
(
x
3
)+ f
'
( 3 - x)< 0
f
'
(
x
3
)< f
'
( 3 - x)
?
x
3
< 3 - x
? x <
9
4
Therefore ?? =
9
4
Then 8?? = 8 ×
9
4
= 18
Q3
?? ( ?? )= 2?? + 3( ?? )
2
3
?? '
( ?? )= 2 + 2?? -1
3
= 2 (1 +
1
?? 1
3
)
= 2 (
?? 1
3
+ 1
?? 1
3
)
So, maxima ( M) at x = -1&minima ( m) at x = 0
Q4
?? ( ?? )=
?? ?? 2
- 6?? - 16
Now,
f
'
( x)=
-( x
2
+ 16)
( x
2
- 6x - 16)
2
f
'
( x)< 0
Thus ?? ( ?? ) is decreasing in
( -8, -2)? ( -2,8)? ( 8, 8)
Q5
?? '
( ?? )=
?? '
( ?? )- ?? '
( 2 - ?? )
2
, ?? '
(
3
2
)=
?? '
(
3
2
)- ?? '
(
1
2
)
2
= 0
Also f
'
(
1
2
)=
g
'
(
1
2
) -g
'
(
3
2
)
2
= 0, f
'
(
1
2
)= 0
? f
'
(
3
2
)= f
'
(
1
2
)= 0
? roots in (
1
2
, 1) and ( 1,
3
2
)
? f
''
( x) is zero at least twice in (
1
2
,
3
2
)
Q6
f
'
( x)= ( x + 3)
2
· 3( x - 2)
2
+ ( x - 2)
3
2( x + 3)
= 5( x + 3) ( x - 2)
2
( x + 1)
f
'
( x)= 0, x = -3, -1,2
?? ( -4)= -216
?? ( -3)= 0, ?? ( 4)= 49 × 8 = 392
?? = 392, ?? = -216
?? - ?? = 392 + 216 = 608
Read More
|
209 videos|443 docs|143 tests
|
FAQs on Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) - Mathematics (Maths) for JEE Main & Advanced
| 1. What are some common applications of derivatives in real life? |  |
Ans. Some common applications of derivatives in real life include determining maximum and minimum values, analyzing rates of change, optimizing functions, and modeling physical systems such as motion and growth.
| 2. How are derivatives used in economics and finance? | |
Ans. In economics and finance, derivatives are used to analyze and predict changes in variables like stock prices, interest rates, and currency exchange rates. They help in risk management, portfolio optimization, and pricing financial instruments.
| 3. Can derivatives be used to solve optimization problems? | |
Ans. Yes, derivatives can be used to solve optimization problems by finding the critical points of a function and determining whether they correspond to a maximum, minimum, or saddle point. This is useful in maximizing profits, minimizing costs, and optimizing processes.
| 4. What is the relationship between derivatives and tangents in calculus? | |
Ans. Derivatives represent the slope of a function at a given point, which is equivalent to the slope of the tangent line to the function at that point. This relationship allows us to approximate the behavior of a function near a specific point.
| 5. How do derivatives help in analyzing motion and velocity? | |
Ans. Derivatives help in analyzing motion and velocity by providing information about the rate at which an object's position changes with respect to time. The derivative of the position function gives the velocity function, which describes the object's speed and direction at any given moment.
Related Exams
About this Document
|
4.77/5 Rating |
|
Nov 22, 2024 Last updated |
Document Description: Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) for JEE 2024 is part of Mathematics (Maths) for JEE Main & Advanced preparation.
The notes and questions for Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) have been prepared according to the JEE exam syllabus. Information about Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) covers topics
like and Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024).
Introduction of Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) in English is available as part of our Mathematics (Maths) for JEE Main & Advanced
for JEE & Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) in Hindi for Mathematics (Maths) for JEE Main & Advanced course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
Description
Full syllabus notes, lecture & questions for Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced - JEE | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) for JEE Main & Advanced | Best notes, free PDF download
Information about Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024)
In this doc you can find the meaning of Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) defined & explained in the simplest way possible. Besides explaining types of
Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) theory, EduRev gives you an ample number of questions to practice Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) tests, examples and also practice JEE
tests
|
209 videos|443 docs|143 tests
|
Download as PDF
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
mock tests for examination
,Important questions
,past year papers
,study material
,Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
,Semester Notes
,MCQs
,Free
,Viva Questions
,ppt
,Sample Paper
,Summary
,practice quizzes
,Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
,Objective type Questions
,Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
,Previous Year Questions with Solutions
,video lectures
,shortcuts and tricks
,Exam
,Extra Questions
;
Additional Information about Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) for JEE Preparation
Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) Free PDF Download
The Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) now and kickstart your journey towards success in the JEE exam.
Importance of Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024)
The importance of Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) Notes
Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024).
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) Notes on EduRev are your ultimate resource for success.
Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) JEE
The "Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) on the App
Students of JEE can study Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024),
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Applications of Derivatives: JEE Mains Previous Year Questions (2021-2024) is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup