JEE Exam > JEE Notes > Mathematics (Maths) for JEE Main & Advanced > Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024)
Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1 JEE Mains Previous Year Questions (2021-2024): Trigonometric Ratios, Functions & Equations 2024 Q1 - 2024 (01 Feb Shift 1) If t a n ? A = 1 v ?? ( ?? 2 + ?? + 1 ) , t a n ? ?? = v ?? v ?? 2 + ?? + 1 and t a n ? ?? = ( ?? - 3 + ?? - 2 + ?? - 1 ) 1 2 , 0 < ?? , ?? , ?? < ?? 2 , then A + B is equal to : (1) C (2) ?? - ?? (3) 2 ?? - ?? (4) ?? 2 - ?? Q2 - 2024 (30 Jan Shift 2) For ?? , ?? ? ( 0 , ?? 2 ), let 3 s i n ? ( ?? + ?? ) = 2 s i n ? ( ?? - ?? ) and a real number k be such that t a n ? ?? = kt a n ? ?? . Then the value of ?? is equal to : (1) - 2 3 (2) -5 (3) 2 3 (4) 5 Q3 - 2024 (01 Feb Shift 2) The number of solutions of the equation 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] is : (1) 1 (2) 3 (3) 2 Page 2 JEE Mains Previous Year Questions (2021-2024): Trigonometric Ratios, Functions & Equations 2024 Q1 - 2024 (01 Feb Shift 1) If t a n ? A = 1 v ?? ( ?? 2 + ?? + 1 ) , t a n ? ?? = v ?? v ?? 2 + ?? + 1 and t a n ? ?? = ( ?? - 3 + ?? - 2 + ?? - 1 ) 1 2 , 0 < ?? , ?? , ?? < ?? 2 , then A + B is equal to : (1) C (2) ?? - ?? (3) 2 ?? - ?? (4) ?? 2 - ?? Q2 - 2024 (30 Jan Shift 2) For ?? , ?? ? ( 0 , ?? 2 ), let 3 s i n ? ( ?? + ?? ) = 2 s i n ? ( ?? - ?? ) and a real number k be such that t a n ? ?? = kt a n ? ?? . Then the value of ?? is equal to : (1) - 2 3 (2) -5 (3) 2 3 (4) 5 Q3 - 2024 (01 Feb Shift 2) The number of solutions of the equation 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] is : (1) 1 (2) 3 (3) 2 (4) 0 Q4 - 2024 (27 Jan Shift 1) Let the set of all ?? ? ?? such that the equation c o s ? 2 ?? + ?? sin ? ?? = 2 ?? - 7 has a solution be [ ?? , ?? ] and ?? = t a n ? 9 ° - t a n ? 27 ° - 1 c o t ? 63 ° + t a n ? 81 ° , then pqr is equal to Q5 - 2024 (27 Jan Shift 2) If 2 t a n 2 ? ?? - 5 s e c ? ?? = 1 has exactly 7 solutions in the interval [ 0 , ???? 2 ], for the least value of ?? ? ?? then ? k = 1 n ? k 2 k is equal to : (1) 1 2 15 ( 2 14 - 14 ) (2) 1 2 14 ( 2 15 - 15 ) (3) 1 - 15 2 13 (4) 1 2 13 ( 2 14 - 15 ) Q6 - 2024 (29 Jan Shift 1) If ?? , - ?? 2 < ?? < ?? 2 is the solution of 4 c o s ? ?? + 5 s i n ? ?? = 1, then the value of t a n ? ?? is (1) 10 - v 10 6 (2) 10 - v 10 12 (3) v 10 - 10 12 (4) v 10 - 10 6 Q7- 2024 (29 Jan Shift 2) The sum of the solutions ?? ? R of the equation 3 c o s ? 2 ?? + c o s 3 ? 2 ?? c o s 6 ? ?? - s i n 6 ? ?? = ?? 3 - ?? 2 + 6 is (1) 0 (2) 1 Page 3 JEE Mains Previous Year Questions (2021-2024): Trigonometric Ratios, Functions & Equations 2024 Q1 - 2024 (01 Feb Shift 1) If t a n ? A = 1 v ?? ( ?? 2 + ?? + 1 ) , t a n ? ?? = v ?? v ?? 2 + ?? + 1 and t a n ? ?? = ( ?? - 3 + ?? - 2 + ?? - 1 ) 1 2 , 0 < ?? , ?? , ?? < ?? 2 , then A + B is equal to : (1) C (2) ?? - ?? (3) 2 ?? - ?? (4) ?? 2 - ?? Q2 - 2024 (30 Jan Shift 2) For ?? , ?? ? ( 0 , ?? 2 ), let 3 s i n ? ( ?? + ?? ) = 2 s i n ? ( ?? - ?? ) and a real number k be such that t a n ? ?? = kt a n ? ?? . Then the value of ?? is equal to : (1) - 2 3 (2) -5 (3) 2 3 (4) 5 Q3 - 2024 (01 Feb Shift 2) The number of solutions of the equation 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] is : (1) 1 (2) 3 (3) 2 (4) 0 Q4 - 2024 (27 Jan Shift 1) Let the set of all ?? ? ?? such that the equation c o s ? 2 ?? + ?? sin ? ?? = 2 ?? - 7 has a solution be [ ?? , ?? ] and ?? = t a n ? 9 ° - t a n ? 27 ° - 1 c o t ? 63 ° + t a n ? 81 ° , then pqr is equal to Q5 - 2024 (27 Jan Shift 2) If 2 t a n 2 ? ?? - 5 s e c ? ?? = 1 has exactly 7 solutions in the interval [ 0 , ???? 2 ], for the least value of ?? ? ?? then ? k = 1 n ? k 2 k is equal to : (1) 1 2 15 ( 2 14 - 14 ) (2) 1 2 14 ( 2 15 - 15 ) (3) 1 - 15 2 13 (4) 1 2 13 ( 2 14 - 15 ) Q6 - 2024 (29 Jan Shift 1) If ?? , - ?? 2 < ?? < ?? 2 is the solution of 4 c o s ? ?? + 5 s i n ? ?? = 1, then the value of t a n ? ?? is (1) 10 - v 10 6 (2) 10 - v 10 12 (3) v 10 - 10 12 (4) v 10 - 10 6 Q7- 2024 (29 Jan Shift 2) The sum of the solutions ?? ? R of the equation 3 c o s ? 2 ?? + c o s 3 ? 2 ?? c o s 6 ? ?? - s i n 6 ? ?? = ?? 3 - ?? 2 + 6 is (1) 0 (2) 1 (3) -1 (4) 3 Q8 - 2024 (30 Jan Shift 1) If 2 sin 3 ? ?? + sin ? 2 ?? c o s ? ?? + 4 s i n ? ?? - 4 = 0 has exactly 3 solutions in the interval [ 0 , n ?? 2 ] , n ? N, then the roots of the equation ?? 2 + ???? + ( ?? - 3 ) = 0 belong to : (1) ( 0 , 8 ) (2) ( - 8 , 0 ) (3) ( - v 17 2 , v 17 2 ) (4) Z Answer Key Q1 (1) Q2 (2) Q3 (4) Q4 (48) Q5 (4) Q6 (3) Q7 (3) Q8 (2) Solutions Q1 Finding t a n ? ( ?? + ?? ) we get Page 4 JEE Mains Previous Year Questions (2021-2024): Trigonometric Ratios, Functions & Equations 2024 Q1 - 2024 (01 Feb Shift 1) If t a n ? A = 1 v ?? ( ?? 2 + ?? + 1 ) , t a n ? ?? = v ?? v ?? 2 + ?? + 1 and t a n ? ?? = ( ?? - 3 + ?? - 2 + ?? - 1 ) 1 2 , 0 < ?? , ?? , ?? < ?? 2 , then A + B is equal to : (1) C (2) ?? - ?? (3) 2 ?? - ?? (4) ?? 2 - ?? Q2 - 2024 (30 Jan Shift 2) For ?? , ?? ? ( 0 , ?? 2 ), let 3 s i n ? ( ?? + ?? ) = 2 s i n ? ( ?? - ?? ) and a real number k be such that t a n ? ?? = kt a n ? ?? . Then the value of ?? is equal to : (1) - 2 3 (2) -5 (3) 2 3 (4) 5 Q3 - 2024 (01 Feb Shift 2) The number of solutions of the equation 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] is : (1) 1 (2) 3 (3) 2 (4) 0 Q4 - 2024 (27 Jan Shift 1) Let the set of all ?? ? ?? such that the equation c o s ? 2 ?? + ?? sin ? ?? = 2 ?? - 7 has a solution be [ ?? , ?? ] and ?? = t a n ? 9 ° - t a n ? 27 ° - 1 c o t ? 63 ° + t a n ? 81 ° , then pqr is equal to Q5 - 2024 (27 Jan Shift 2) If 2 t a n 2 ? ?? - 5 s e c ? ?? = 1 has exactly 7 solutions in the interval [ 0 , ???? 2 ], for the least value of ?? ? ?? then ? k = 1 n ? k 2 k is equal to : (1) 1 2 15 ( 2 14 - 14 ) (2) 1 2 14 ( 2 15 - 15 ) (3) 1 - 15 2 13 (4) 1 2 13 ( 2 14 - 15 ) Q6 - 2024 (29 Jan Shift 1) If ?? , - ?? 2 < ?? < ?? 2 is the solution of 4 c o s ? ?? + 5 s i n ? ?? = 1, then the value of t a n ? ?? is (1) 10 - v 10 6 (2) 10 - v 10 12 (3) v 10 - 10 12 (4) v 10 - 10 6 Q7- 2024 (29 Jan Shift 2) The sum of the solutions ?? ? R of the equation 3 c o s ? 2 ?? + c o s 3 ? 2 ?? c o s 6 ? ?? - s i n 6 ? ?? = ?? 3 - ?? 2 + 6 is (1) 0 (2) 1 (3) -1 (4) 3 Q8 - 2024 (30 Jan Shift 1) If 2 sin 3 ? ?? + sin ? 2 ?? c o s ? ?? + 4 s i n ? ?? - 4 = 0 has exactly 3 solutions in the interval [ 0 , n ?? 2 ] , n ? N, then the roots of the equation ?? 2 + ???? + ( ?? - 3 ) = 0 belong to : (1) ( 0 , 8 ) (2) ( - 8 , 0 ) (3) ( - v 17 2 , v 17 2 ) (4) Z Answer Key Q1 (1) Q2 (2) Q3 (4) Q4 (48) Q5 (4) Q6 (3) Q7 (3) Q8 (2) Solutions Q1 Finding t a n ? ( ?? + ?? ) we get ? ? t a n ? ( A + B ) = t a n ? ?? + t a n ? ?? 1 - t a n ? ?? t a n ? ?? = 1 v ?? ( ?? 2 + ?? + 1 ) + v ?? v ?? 2 + ?? + 1 1 - 1 ?? 2 + ?? + 1 ? ? t a n ? ( A + B ) = ( 1 + ?? ) ( v ?? 2 + ?? + 1 ) ( ?? 2 + ?? ) ( v ?? ) ( 1 + ?? ) ( v ?? 2 + ?? + 1 ) ( ?? 2 + ?? ) ( v ?? ) t a n ? ( ?? + ?? ) = v ?? 2 + ?? + 1 ?? v ?? = t a n ? ?? ?? + ?? = ?? Q2 3 s i n ? ?? c o s ? ?? + 3 s i n ? ?? c o s ? ?? = 2 s i n ? ?? c o s ? ?? - 2 s i n ? ?? c o s ? ?? 5 s i n ? ?? c o s ? ?? = - sin ? ?? c o s ? ?? t a n ? ?? = - 1 5 t a n ? ?? t a n ? ?? = - 5 t a n ? ?? Q3 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] 4 - 4 c o s 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 4 c o s 3 ? ?? + 4 c o s 2 ? ?? + 4 c o s ? ?? - 13 = 0 4 c o s 3 ? ?? + 4 c o s 2 ? ?? + 4 c o s ? ?? = 13 L.H.S. = 12 c a n ' t be equal to 13 . Q4 c o s ? 2 ?? + ?? · sin ? ?? = 2 ?? - 7 ?? ( sin ? ?? - 2 ) = 2 ( sin ? ?? - 2 ) ( sin ? ?? + 2 ) sin ? ?? = 2 , ? ?? = 2 ( sin ? ?? + 2 ) ? ?? ? [ 2 , 6 ] ?? = 2 ? ?? = 6 Page 5 JEE Mains Previous Year Questions (2021-2024): Trigonometric Ratios, Functions & Equations 2024 Q1 - 2024 (01 Feb Shift 1) If t a n ? A = 1 v ?? ( ?? 2 + ?? + 1 ) , t a n ? ?? = v ?? v ?? 2 + ?? + 1 and t a n ? ?? = ( ?? - 3 + ?? - 2 + ?? - 1 ) 1 2 , 0 < ?? , ?? , ?? < ?? 2 , then A + B is equal to : (1) C (2) ?? - ?? (3) 2 ?? - ?? (4) ?? 2 - ?? Q2 - 2024 (30 Jan Shift 2) For ?? , ?? ? ( 0 , ?? 2 ), let 3 s i n ? ( ?? + ?? ) = 2 s i n ? ( ?? - ?? ) and a real number k be such that t a n ? ?? = kt a n ? ?? . Then the value of ?? is equal to : (1) - 2 3 (2) -5 (3) 2 3 (4) 5 Q3 - 2024 (01 Feb Shift 2) The number of solutions of the equation 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] is : (1) 1 (2) 3 (3) 2 (4) 0 Q4 - 2024 (27 Jan Shift 1) Let the set of all ?? ? ?? such that the equation c o s ? 2 ?? + ?? sin ? ?? = 2 ?? - 7 has a solution be [ ?? , ?? ] and ?? = t a n ? 9 ° - t a n ? 27 ° - 1 c o t ? 63 ° + t a n ? 81 ° , then pqr is equal to Q5 - 2024 (27 Jan Shift 2) If 2 t a n 2 ? ?? - 5 s e c ? ?? = 1 has exactly 7 solutions in the interval [ 0 , ???? 2 ], for the least value of ?? ? ?? then ? k = 1 n ? k 2 k is equal to : (1) 1 2 15 ( 2 14 - 14 ) (2) 1 2 14 ( 2 15 - 15 ) (3) 1 - 15 2 13 (4) 1 2 13 ( 2 14 - 15 ) Q6 - 2024 (29 Jan Shift 1) If ?? , - ?? 2 < ?? < ?? 2 is the solution of 4 c o s ? ?? + 5 s i n ? ?? = 1, then the value of t a n ? ?? is (1) 10 - v 10 6 (2) 10 - v 10 12 (3) v 10 - 10 12 (4) v 10 - 10 6 Q7- 2024 (29 Jan Shift 2) The sum of the solutions ?? ? R of the equation 3 c o s ? 2 ?? + c o s 3 ? 2 ?? c o s 6 ? ?? - s i n 6 ? ?? = ?? 3 - ?? 2 + 6 is (1) 0 (2) 1 (3) -1 (4) 3 Q8 - 2024 (30 Jan Shift 1) If 2 sin 3 ? ?? + sin ? 2 ?? c o s ? ?? + 4 s i n ? ?? - 4 = 0 has exactly 3 solutions in the interval [ 0 , n ?? 2 ] , n ? N, then the roots of the equation ?? 2 + ???? + ( ?? - 3 ) = 0 belong to : (1) ( 0 , 8 ) (2) ( - 8 , 0 ) (3) ( - v 17 2 , v 17 2 ) (4) Z Answer Key Q1 (1) Q2 (2) Q3 (4) Q4 (48) Q5 (4) Q6 (3) Q7 (3) Q8 (2) Solutions Q1 Finding t a n ? ( ?? + ?? ) we get ? ? t a n ? ( A + B ) = t a n ? ?? + t a n ? ?? 1 - t a n ? ?? t a n ? ?? = 1 v ?? ( ?? 2 + ?? + 1 ) + v ?? v ?? 2 + ?? + 1 1 - 1 ?? 2 + ?? + 1 ? ? t a n ? ( A + B ) = ( 1 + ?? ) ( v ?? 2 + ?? + 1 ) ( ?? 2 + ?? ) ( v ?? ) ( 1 + ?? ) ( v ?? 2 + ?? + 1 ) ( ?? 2 + ?? ) ( v ?? ) t a n ? ( ?? + ?? ) = v ?? 2 + ?? + 1 ?? v ?? = t a n ? ?? ?? + ?? = ?? Q2 3 s i n ? ?? c o s ? ?? + 3 s i n ? ?? c o s ? ?? = 2 s i n ? ?? c o s ? ?? - 2 s i n ? ?? c o s ? ?? 5 s i n ? ?? c o s ? ?? = - sin ? ?? c o s ? ?? t a n ? ?? = - 1 5 t a n ? ?? t a n ? ?? = - 5 t a n ? ?? Q3 4 sin 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 ; ?? ? [ - 2 ?? , 2 ?? ] 4 - 4 c o s 2 ? ?? - 4 c o s 3 ? ?? + 9 - 4 c o s ? ?? = 0 4 c o s 3 ? ?? + 4 c o s 2 ? ?? + 4 c o s ? ?? - 13 = 0 4 c o s 3 ? ?? + 4 c o s 2 ? ?? + 4 c o s ? ?? = 13 L.H.S. = 12 c a n ' t be equal to 13 . Q4 c o s ? 2 ?? + ?? · sin ? ?? = 2 ?? - 7 ?? ( sin ? ?? - 2 ) = 2 ( sin ? ?? - 2 ) ( sin ? ?? + 2 ) sin ? ?? = 2 , ? ?? = 2 ( sin ? ?? + 2 ) ? ?? ? [ 2 , 6 ] ?? = 2 ? ?? = 6 ?? = t a n ? 9 ° + c o t ? 9 ° - t a n ? 27 - c o t ? 27 ?? = 1 sin ? 9 · c o s ? 9 - 1 sin ? 27 · c o s ? 27 = 2 [ 4 v 5 - 1 - 4 v 5 + 1 ] ?? = 4 p.q. . ?? = 2 × 6 × 4 = 48 Q5 2 t a n 2 ? ?? - 5 s e c ? ?? - 1 = 0 ? ? 2 s e c 2 ? ?? - 5 s e c ? ?? - 3 = 0 ? ? ( 2 s e c ? ?? + 1 ) ( s e c ? ?? - 3 ) = 0 ? ? s e c ? ?? = - 1 2 , 3 ? ? c o s ? ?? = - 2 , 1 3 ? ? c o s ? ?? = 1 3 For 7 solutions n = 13 So, ? k = 1 13 ? k 2 k = S (say) S = 1 2 + 2 2 2 + 3 2 3 + ? + 13 2 13 1 2 ?? = 1 2 2 + 1 2 3 + ? . + 12 2 13 + 13 2 14 ? ?? 2 = 1 2 · 1 - 1 2 13 1 - 1 2 - 13 2 14 ? ?? = 2 · ( 2 13 - 1 2 13 ) - 13 2 13 Q6 4 + 5 t a n ? ?? = s e c ? ?? Squaring : 24 t a n 2 ? ?? + 4 0 t a n ? ?? + 15 = 0 t a n ? ?? = - 10 ± v 10 12 and t a n ? ?? = - ( 10 + v 10 12 ) is Rejected.Read More
|
209 videos|443 docs|143 tests
|
FAQs on Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) - Mathematics (Maths) for JEE Main & Advanced
| 1. How do you find the trigonometric ratios of an angle in a right triangle? |  |
Ans. To find the trigonometric ratios of an angle in a right triangle, you can use the ratios of the sides of the triangle. The sine ratio is the ratio of the length of the side opposite the angle to the hypotenuse, the cosine ratio is the ratio of the length of the side adjacent to the angle to the hypotenuse, and the tangent ratio is the ratio of the length of the side opposite the angle to the side adjacent to the angle.
| 2. What are the properties of trigonometric functions? | |
Ans. Trigonometric functions have various properties, including periodicity, symmetry, and the relationships between different functions like sine, cosine, and tangent. They also have specific ranges and domains, such as sine and cosine functions having a range of [-1,1] and tangent having a domain excluding odd multiples of pi/2.
| 3. How do you solve trigonometric equations? | |
Ans. To solve trigonometric equations, you can use algebraic techniques along with trigonometric identities and properties. You may need to simplify the equation, use trigonometric identities to rewrite it in a more manageable form, and then solve for the variable by isolating it on one side of the equation.
| 4. What are the common trigonometric identities used in trigonometry? | |
Ans. Some common trigonometric identities used in trigonometry include Pythagorean identities (sin^2θ + cos^2θ = 1), reciprocal identities (cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ), and double angle identities (sin2θ = 2sinθcosθ).
| 5. How are trigonometric functions used in real-life applications? | |
Ans. Trigonometric functions are used in various real-life applications such as engineering, physics, and astronomy. They help in calculating distances, angles, and heights in structures, analyzing wave patterns, and predicting celestial events.
Related Exams
About this Document
|
4.68/5 Rating |
|
Nov 21, 2024 Last updated |
Document Description: Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) for JEE 2024 is part of Mathematics (Maths) for JEE Main & Advanced preparation.
The notes and questions for Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) have been prepared according to the JEE exam syllabus. Information about Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) covers topics
like and Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024).
Introduction of Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) in English is available as part of our Mathematics (Maths) for JEE Main & Advanced
for JEE & Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) in Hindi for Mathematics (Maths) for JEE Main & Advanced course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
Description
Full syllabus notes, lecture & questions for Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced - JEE | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) for JEE Main & Advanced | Best notes, free PDF download
Information about Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024)
In this doc you can find the meaning of Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) defined & explained in the simplest way possible. Besides explaining types of
Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) theory, EduRev gives you an ample number of questions to practice Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) tests, examples and also practice JEE
tests
|
209 videos|443 docs|143 tests
|
Download as PDF
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Previous Year Questions with Solutions
,ppt
,Exam
,Trigonometric Ratios
,Semester Notes
,Summary
,Sample Paper
,Extra Questions
,Free
,practice quizzes
,study material
,Trigonometric Ratios
,Functions & Equations: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
,Important questions
,Objective type Questions
,Viva Questions
,MCQs
,Functions & Equations: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
,Trigonometric Ratios
,video lectures
,past year papers
,Functions & Equations: JEE Mains Previous Year Questions (2021-2024) | Mathematics (Maths) for JEE Main & Advanced
,mock tests for examination
,shortcuts and tricks
;
Additional Information about Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) for JEE Preparation
Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) Free PDF Download
The Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) now and kickstart your journey towards success in the JEE exam.
Importance of Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024)
The importance of Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) Notes
Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024).
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) Notes on EduRev are your ultimate resource for success.
Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) JEE
The "Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) on the App
Students of JEE can study Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024),
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Trigonometric Ratios, Functions & Equations: JEE Mains Previous Year Questions (2021-2024) is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup