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Page 1 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. Page 2 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) Page 3 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) 2021 Numerical Type JEE Advanced 2021 Paper 1 Online Q1. The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using ???? ?? and ???? light is Ans: 13 Monobromination of 1-methyl cyclohex-1-ene in presence of UV-light gives following products ( 1 achiral and 6 optically active (*) compounds). So, total 13 products are formed ( 1 + 6 + 6 enantiomers) Radicals formed are Page 4 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) 2021 Numerical Type JEE Advanced 2021 Paper 1 Online Q1. The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using ???? ?? and ???? light is Ans: 13 Monobromination of 1-methyl cyclohex-1-ene in presence of UV-light gives following products ( 1 achiral and 6 optically active (*) compounds). So, total 13 products are formed ( 1 + 6 + 6 enantiomers) Radicals formed are JEE Advanced 2021 Paper 2 Online Q2. The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s- character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : Correct match of the ?? - ?? bonds (shown in bold) in Column ?? with their BDE in Column ?? is Column J Molecule Column K BDE (kcal mol -?? ) (P) ?? - ?? ?? (???? ?? ) ?? (i) 132 (Q) ?? - ???? ?? ???? (ii) 110 (R) ?? - ???? = ???? ?? (iii) 95 (S) ?? - ?? = ???? (iv) 88 Page 5 JEE Advanced Previous Year Questions (2021-2023): General Organic Chemistry 2023 Single Correct Type JEE Advanced 2023 Paper 1 Online Q1. Match the reactions in List-I with the features of their products in List-II and choose the correct option. ?? . ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? B. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? C. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? D. ?? ? ?? ; ?? ? ?? ; ?? ? ?? ; ?? ? ?? Ans: (B) 2021 Numerical Type JEE Advanced 2021 Paper 1 Online Q1. The maximum number of possible isomers (including stereoisomers) which may be formed on mono-bromination of 1-methylcyclohex-1-ene using ???? ?? and ???? light is Ans: 13 Monobromination of 1-methyl cyclohex-1-ene in presence of UV-light gives following products ( 1 achiral and 6 optically active (*) compounds). So, total 13 products are formed ( 1 + 6 + 6 enantiomers) Radicals formed are JEE Advanced 2021 Paper 2 Online Q2. The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s- character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : Correct match of the ?? - ?? bonds (shown in bold) in Column ?? with their BDE in Column ?? is Column J Molecule Column K BDE (kcal mol -?? ) (P) ?? - ?? ?? (???? ?? ) ?? (i) 132 (Q) ?? - ???? ?? ???? (ii) 110 (R) ?? - ???? = ???? ?? (iii) 95 (S) ?? - ?? = ???? (iv) 88 A. P - iii, Q - iv, R - ii, S - i B. P - i, Q - ii, R - iii, S - iv C. P - iii, Q - ii, R - i, S - iv D. P - ii, Q - i, R - iv, S – ii Ans: (A) A more stable radical means lesser the bond dissociation energy. Radicals formed are Radical formed from Q(PhCH 2 - H) is most stable due to resonance. Stability of free radical decreases with increase in % s-character. P radical ? sp 3 ? % s-character 25% R radical ? sp 2 ? % s-character 33% S radical ? sp ? % s-character 50% Thus, order of stability of free radical is Q > P > R > S Order of bond dissociation energy is ?? > ?? > ?? > ?? JEE Advanced 2021 Paper 2 Online Q3.The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s- character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : ???? - ???? (?? ) ? ???? (?? ) · + ???? (?? ) · ?? ?? ° = ???????????? ?????? -??Read More
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FAQs on JEE Advanced Previous Year Questions (2021 - 2024): General Organic Chemistry - Chemistry for JEE Main & Advanced
| 1. What are the key concepts of General Organic Chemistry important for JEE Advanced? |  |
Ans.The key concepts of General Organic Chemistry important for JEE Advanced include understanding the structure, bonding, and reactivity of organic molecules, functional groups, isomerism, stereochemistry, and reaction mechanisms. Mastery of these concepts is crucial for solving problems related to organic reactions and synthesis.
| 2. How do I prepare effectively for General Organic Chemistry for JEE Advanced exams? | |
Ans.Effective preparation for General Organic Chemistry involves a thorough understanding of the basics, regular practice of problems, and familiarity with previous years' question papers. Utilize textbooks, online resources, and practice tests to strengthen your grasp of concepts and improve your problem-solving skills.
| 3. What types of questions can I expect from General Organic Chemistry in JEE Advanced? | |
Ans.In JEE Advanced, questions from General Organic Chemistry can include mechanisms of reactions, identification of compounds based on reactions, synthesis problems, and application of concepts like acidity, basicity, and stability of intermediates. Questions may be theoretical or problem-solving in nature.
| 4. Are there any common mistakes students make in General Organic Chemistry for JEE Advanced? | |
Ans.Common mistakes include neglecting the importance of mechanisms, misunderstanding stereochemistry, and not practicing enough numerical problems. Additionally, many students may overlook the significance of functional groups and their reactivity patterns, leading to errors in application.
| 5. How can I improve my reaction mechanism skills in General Organic Chemistry for JEE Advanced? | |
Ans.Improving reaction mechanism skills involves studying the fundamental principles of each type of reaction, practicing drawing mechanisms step-by-step, and understanding the role of intermediates. Regularly solving previous years' questions and engaging in group studies can also enhance your understanding and retention.
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