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Page 1 FLUID MECHANISM Hydrostatics: 1. In a fluid that's not moving/ static fluid, the force per unit area at any spot stays the same no matter how you turn the surface. 2. This force always acts ? er to the chosen surface. Pressure = ?? ? ?? 3. The value of force acting on a unit area at any point is called pressure at that point. 4. Ideal fluids offer negligible resistance to tangential force. They cannot withstand tangential force. 5. Since ideal fluid cannot sustain shear stress therefore in a steady state liquid remains ? to the " g eff ". VARIATION OF PRESSURE WITH DEPTH (i) Let pressure at L is P 1 and pressure at M is P 2 Then, ?? 2 ?? =?? 1 ?? +?????? (?? 2 -?? 1 )??? 2 =?? 1 +???? (?? 2 -?? 1 ) Here pressure gradient ???? ???? =???? (ii) Pressure is the same at two points in the same horizontal level. Page 2 FLUID MECHANISM Hydrostatics: 1. In a fluid that's not moving/ static fluid, the force per unit area at any spot stays the same no matter how you turn the surface. 2. This force always acts ? er to the chosen surface. Pressure = ?? ? ?? 3. The value of force acting on a unit area at any point is called pressure at that point. 4. Ideal fluids offer negligible resistance to tangential force. They cannot withstand tangential force. 5. Since ideal fluid cannot sustain shear stress therefore in a steady state liquid remains ? to the " g eff ". VARIATION OF PRESSURE WITH DEPTH (i) Let pressure at L is P 1 and pressure at M is P 2 Then, ?? 2 ?? =?? 1 ?? +?????? (?? 2 -?? 1 )??? 2 =?? 1 +???? (?? 2 -?? 1 ) Here pressure gradient ???? ???? =???? (ii) Pressure is the same at two points in the same horizontal level. As body is in equilibrium, P 1 A=P 2 A?P 1 =P 2 {Note : Pressure ?? is independent of shape of container} P absolute Pressure =P 0 + ???? gh ? yauge pressure i.e. diff. from atmospheric pressure ? In terms of water coloumn =1 atm pressure Page 3 FLUID MECHANISM Hydrostatics: 1. In a fluid that's not moving/ static fluid, the force per unit area at any spot stays the same no matter how you turn the surface. 2. This force always acts ? er to the chosen surface. Pressure = ?? ? ?? 3. The value of force acting on a unit area at any point is called pressure at that point. 4. Ideal fluids offer negligible resistance to tangential force. They cannot withstand tangential force. 5. Since ideal fluid cannot sustain shear stress therefore in a steady state liquid remains ? to the " g eff ". VARIATION OF PRESSURE WITH DEPTH (i) Let pressure at L is P 1 and pressure at M is P 2 Then, ?? 2 ?? =?? 1 ?? +?????? (?? 2 -?? 1 )??? 2 =?? 1 +???? (?? 2 -?? 1 ) Here pressure gradient ???? ???? =???? (ii) Pressure is the same at two points in the same horizontal level. As body is in equilibrium, P 1 A=P 2 A?P 1 =P 2 {Note : Pressure ?? is independent of shape of container} P absolute Pressure =P 0 + ???? gh ? yauge pressure i.e. diff. from atmospheric pressure ? In terms of water coloumn =1 atm pressure (iii) M-1: In ground frame (?? 2 -?? 1 )?? =???????? ?? 2 =?? 1 +?????? M-2: ( g eff component) distance tan ?? = a g = h t P 0 +???? h=P 1 ?? 0 +?????? =?? Example. Page 4 FLUID MECHANISM Hydrostatics: 1. In a fluid that's not moving/ static fluid, the force per unit area at any spot stays the same no matter how you turn the surface. 2. This force always acts ? er to the chosen surface. Pressure = ?? ? ?? 3. The value of force acting on a unit area at any point is called pressure at that point. 4. Ideal fluids offer negligible resistance to tangential force. They cannot withstand tangential force. 5. Since ideal fluid cannot sustain shear stress therefore in a steady state liquid remains ? to the " g eff ". VARIATION OF PRESSURE WITH DEPTH (i) Let pressure at L is P 1 and pressure at M is P 2 Then, ?? 2 ?? =?? 1 ?? +?????? (?? 2 -?? 1 )??? 2 =?? 1 +???? (?? 2 -?? 1 ) Here pressure gradient ???? ???? =???? (ii) Pressure is the same at two points in the same horizontal level. As body is in equilibrium, P 1 A=P 2 A?P 1 =P 2 {Note : Pressure ?? is independent of shape of container} P absolute Pressure =P 0 + ???? gh ? yauge pressure i.e. diff. from atmospheric pressure ? In terms of water coloumn =1 atm pressure (iii) M-1: In ground frame (?? 2 -?? 1 )?? =???????? ?? 2 =?? 1 +?????? M-2: ( g eff component) distance tan ?? = a g = h t P 0 +???? h=P 1 ?? 0 +?????? =?? Example. ? In terms of ?? 1 ,?? ,?? ,?? ,h ?? 1 +???? h=?? 2 ?? 1 +?????? cos ?? +?????? sin ?? =?? 5 ??? 1 +?????? =?? 4 ??? 1 +???? h+?????? =?? 3 Solution: ? ?? 1 +?? ( 2?? 3 )h=?? 2 ?? 2 -?? 1 = 2 3 ???? h Example. Find tan ?? Solution: ? g:???? ] ] ?? ?tan ?? = a g ?? =tan -1 ( a g ) Page 5 FLUID MECHANISM Hydrostatics: 1. In a fluid that's not moving/ static fluid, the force per unit area at any spot stays the same no matter how you turn the surface. 2. This force always acts ? er to the chosen surface. Pressure = ?? ? ?? 3. The value of force acting on a unit area at any point is called pressure at that point. 4. Ideal fluids offer negligible resistance to tangential force. They cannot withstand tangential force. 5. Since ideal fluid cannot sustain shear stress therefore in a steady state liquid remains ? to the " g eff ". VARIATION OF PRESSURE WITH DEPTH (i) Let pressure at L is P 1 and pressure at M is P 2 Then, ?? 2 ?? =?? 1 ?? +?????? (?? 2 -?? 1 )??? 2 =?? 1 +???? (?? 2 -?? 1 ) Here pressure gradient ???? ???? =???? (ii) Pressure is the same at two points in the same horizontal level. As body is in equilibrium, P 1 A=P 2 A?P 1 =P 2 {Note : Pressure ?? is independent of shape of container} P absolute Pressure =P 0 + ???? gh ? yauge pressure i.e. diff. from atmospheric pressure ? In terms of water coloumn =1 atm pressure (iii) M-1: In ground frame (?? 2 -?? 1 )?? =???????? ?? 2 =?? 1 +?????? M-2: ( g eff component) distance tan ?? = a g = h t P 0 +???? h=P 1 ?? 0 +?????? =?? Example. ? In terms of ?? 1 ,?? ,?? ,?? ,h ?? 1 +???? h=?? 2 ?? 1 +?????? cos ?? +?????? sin ?? =?? 5 ??? 1 +?????? =?? 4 ??? 1 +???? h+?????? =?? 3 Solution: ? ?? 1 +?? ( 2?? 3 )h=?? 2 ?? 2 -?? 1 = 2 3 ???? h Example. Find tan ?? Solution: ? g:???? ] ] ?? ?tan ?? = a g ?? =tan -1 ( a g ) a is slowly ? from 0 to ?? 3 mi volume of liquid remaining inside beaker? Solution: tan ?? = a g = 1 3 ? volume out =( Area )×t=( 1 2 × t 3 ×t)×t? t 3 6 ? Volume remaining =t 3 - t 3 6 = 5t 3 6 from 0 to 3 g 2 ? when acc. is 'g' But when acc. is 3?? 2Read More
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