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Class 10 Mathematics (Standard) Term II : CBSE (Official) Marking Scheme with Solution (2021-22) | Mathematics (Maths) Class 10 PDF Download

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 Page 1


Marking Scheme  
Class- X, Session- 2021-22 
TERM II 
Subject- Mathematics (Standard) 
  SECTION A  
Q.No
. 
HINTS/SOLUTION MARKS 
1 
a = 6, d = 3                   ;    a
25
  = 6 + 24(3) = 78     
a
15
  = 6 + 14(3) = 48    ;     a
25
 - a
15
 = 78 - 48 = 30 
 OR 
  7(?? + 6?? ) = 5(?? + 4?? )  
?2?? + 22?? = 0 ? ?? + 11?? = 0 ? ?? 12
= 0  
       1 
       1 
 
 
        1 
         
1 
2 
5mx² - 6mx + 9 = 0    
b² - 4ac = 0  ? (-6m)² - 4(5m)(9) = 0   
? 36m(m - 5) = 0   
? m = 0, 5  ; rejecting m=0, we get m = 5   
 
 
1 
 
 
 
 
1 
 
3 
 
let ??????? = ?? 
???????? =
????
????
=
1
2
? ?? = 30
0 
 
? ??????? = 2?? = 60
0
     
Also ??????? = ??????? = 60
0
 (? ???? = ???? ) 
?? ?????? is equilateral 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1/2 
 
1/2 
 
1/2 
 
1/2 
4 
CSA (cone) = ?????? = 12320 
22
7
× 56 × ?? = 12320 
?? = 70 ???? 
h = v70
2
- 56
2
 = 42 cm 
1/2 
 
 
 
1 
 
1/2 
 
O 
A 
B 
P 
r 
2r 
 
Page 2


Marking Scheme  
Class- X, Session- 2021-22 
TERM II 
Subject- Mathematics (Standard) 
  SECTION A  
Q.No
. 
HINTS/SOLUTION MARKS 
1 
a = 6, d = 3                   ;    a
25
  = 6 + 24(3) = 78     
a
15
  = 6 + 14(3) = 48    ;     a
25
 - a
15
 = 78 - 48 = 30 
 OR 
  7(?? + 6?? ) = 5(?? + 4?? )  
?2?? + 22?? = 0 ? ?? + 11?? = 0 ? ?? 12
= 0  
       1 
       1 
 
 
        1 
         
1 
2 
5mx² - 6mx + 9 = 0    
b² - 4ac = 0  ? (-6m)² - 4(5m)(9) = 0   
? 36m(m - 5) = 0   
? m = 0, 5  ; rejecting m=0, we get m = 5   
 
 
1 
 
 
 
 
1 
 
3 
 
let ??????? = ?? 
???????? =
????
????
=
1
2
? ?? = 30
0 
 
? ??????? = 2?? = 60
0
     
Also ??????? = ??????? = 60
0
 (? ???? = ???? ) 
?? ?????? is equilateral 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1/2 
 
1/2 
 
1/2 
 
1/2 
4 
CSA (cone) = ?????? = 12320 
22
7
× 56 × ?? = 12320 
?? = 70 ???? 
h = v70
2
- 56
2
 = 42 cm 
1/2 
 
 
 
1 
 
1/2 
 
O 
A 
B 
P 
r 
2r 
 
5 
Modal class is 40 - 60, ?? = 40, h = 20, ?? 1
=? , ?? 0
= 10, ?? 2
= 6 
45 = 40 + 20 × [
?? 1
- 10
2?? 1
- 10 - 6
] 
? 
1
4
=
?? 1
-10
2?? 1
-16
 
?2?? 1
- 16 = 4?? 1
- 40  ? ?? 1
= 12  
1/2 
 
1/2 
 
 
 
 
 
1 
6 
Let the present age of Ritu be ?? years 
(?? - 5)
2
= 5?? + 11 
?? 2
- 15?? + 14 = 0½ 
(?? - 14)(?? - 1) = 0  ? ?? = 1 ???? 14 
x = 14 years (rejecting ?? = 1 as in that case Ritu’s age 5 years ago will be –ve )  
OR 
9?? 2
- 6???? + (?? 2
- ?? 2
) = 0 
?? = 9, ?? = -6?? , ?? = ?? 2
- ?? 2
 
?? = ?? 2
- 4???? = (-6?? )
2
- 4(9)(?? 2
- ?? 2
) = 36?? 2
 
?? =
-?? ± v?? 2?? =
6?? ± 6?? 18
=
?? + ?? 3
???? 
?? - ?? 3
 
 
 
1 
 
 
1/2 
 
1/2 
 
 
 
 
 
1/2 
 
1/2 
 
1 
 
SECTION B 
 
7 
Distance (in m) 0 - 1 1 – 2 2 - 3 3 - 4 4 - 5 
Number of 
Students 
40 80 62 38 30 
???? 40 120 182 220 250 
?? 2
=
250
2
= 125 ? ???????????? ?????????? ???? 2 - 3, ?? = 2, h = 1, ???? = 120, ?? = 62 
???????????? = ?? +
?? 2
- ????
?? × ?? 
 = 2 +
5
62
 
=
129
62
= 2
5
62
?? ???? 2.08?? 
50% of students jumped below2
5
62
 m and 50% above it.   
 
 
 
 
 
 
 
       1 
 
 
1/2 
 
 
 
 
 
1 
 
1/2 
8 
Draw a circle of radius 4cm 
Draw OA and construct ??????? = 120
0
 
Draw ??????? = ??????? = 90
0
 
PA and PB are required tangents 
1 
 
1 
 
 
1 
9 
Runs Scored 0 - 40 40 - 80 80 - 120 120 - 160 160 - 200 TOTAL 
Number of 
Batsmen (?? ?? ) 
12 20 35 30 23 120 
 
 
 
 
 
Page 3


Marking Scheme  
Class- X, Session- 2021-22 
TERM II 
Subject- Mathematics (Standard) 
  SECTION A  
Q.No
. 
HINTS/SOLUTION MARKS 
1 
a = 6, d = 3                   ;    a
25
  = 6 + 24(3) = 78     
a
15
  = 6 + 14(3) = 48    ;     a
25
 - a
15
 = 78 - 48 = 30 
 OR 
  7(?? + 6?? ) = 5(?? + 4?? )  
?2?? + 22?? = 0 ? ?? + 11?? = 0 ? ?? 12
= 0  
       1 
       1 
 
 
        1 
         
1 
2 
5mx² - 6mx + 9 = 0    
b² - 4ac = 0  ? (-6m)² - 4(5m)(9) = 0   
? 36m(m - 5) = 0   
? m = 0, 5  ; rejecting m=0, we get m = 5   
 
 
1 
 
 
 
 
1 
 
3 
 
let ??????? = ?? 
???????? =
????
????
=
1
2
? ?? = 30
0 
 
? ??????? = 2?? = 60
0
     
Also ??????? = ??????? = 60
0
 (? ???? = ???? ) 
?? ?????? is equilateral 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1/2 
 
1/2 
 
1/2 
 
1/2 
4 
CSA (cone) = ?????? = 12320 
22
7
× 56 × ?? = 12320 
?? = 70 ???? 
h = v70
2
- 56
2
 = 42 cm 
1/2 
 
 
 
1 
 
1/2 
 
O 
A 
B 
P 
r 
2r 
 
5 
Modal class is 40 - 60, ?? = 40, h = 20, ?? 1
=? , ?? 0
= 10, ?? 2
= 6 
45 = 40 + 20 × [
?? 1
- 10
2?? 1
- 10 - 6
] 
? 
1
4
=
?? 1
-10
2?? 1
-16
 
?2?? 1
- 16 = 4?? 1
- 40  ? ?? 1
= 12  
1/2 
 
1/2 
 
 
 
 
 
1 
6 
Let the present age of Ritu be ?? years 
(?? - 5)
2
= 5?? + 11 
?? 2
- 15?? + 14 = 0½ 
(?? - 14)(?? - 1) = 0  ? ?? = 1 ???? 14 
x = 14 years (rejecting ?? = 1 as in that case Ritu’s age 5 years ago will be –ve )  
OR 
9?? 2
- 6???? + (?? 2
- ?? 2
) = 0 
?? = 9, ?? = -6?? , ?? = ?? 2
- ?? 2
 
?? = ?? 2
- 4???? = (-6?? )
2
- 4(9)(?? 2
- ?? 2
) = 36?? 2
 
?? =
-?? ± v?? 2?? =
6?? ± 6?? 18
=
?? + ?? 3
???? 
?? - ?? 3
 
 
 
1 
 
 
1/2 
 
1/2 
 
 
 
 
 
1/2 
 
1/2 
 
1 
 
SECTION B 
 
7 
Distance (in m) 0 - 1 1 – 2 2 - 3 3 - 4 4 - 5 
Number of 
Students 
40 80 62 38 30 
???? 40 120 182 220 250 
?? 2
=
250
2
= 125 ? ???????????? ?????????? ???? 2 - 3, ?? = 2, h = 1, ???? = 120, ?? = 62 
???????????? = ?? +
?? 2
- ????
?? × ?? 
 = 2 +
5
62
 
=
129
62
= 2
5
62
?? ???? 2.08?? 
50% of students jumped below2
5
62
 m and 50% above it.   
 
 
 
 
 
 
 
       1 
 
 
1/2 
 
 
 
 
 
1 
 
1/2 
8 
Draw a circle of radius 4cm 
Draw OA and construct ??????? = 120
0
 
Draw ??????? = ??????? = 90
0
 
PA and PB are required tangents 
1 
 
1 
 
 
1 
9 
Runs Scored 0 - 40 40 - 80 80 - 120 120 - 160 160 - 200 TOTAL 
Number of 
Batsmen (?? ?? ) 
12 20 35 30 23 120 
 
 
 
 
 
?? ?? 20 60 100 140 180  
?? ?? ?? ?? 240 1200 3500 4200 4140 13280 
???????? ( ?? ¯) =
? ?? ?? ?? ?? ? ?? ?? =
13280
120
= 110.67 ???????? 
      
 
   1
?? ?? 
 
    1
?? ?? 
 
 
 
 
 
 
10 
 
???? ??????? , ?????? 60
0
=
?? 20
? ?? = 20v3m 
???? ??????? , ?????? 30
0
=
?? 20
? ?? =
20
v3
?? 
?? - ?? = 20v3 -
20
v3
=
40
v3
=
40v3
3
= 23.06?? 
OR 
 
Let PR be the building and AB be the boy 
???? ??????? , ?????? 60
0
=
????
50
? ???? = 50v3?? 
Height of the building = ???? = (50v3 + 1.7)?? = 88.2?? 
 
 
 
 
 
 
 
 
 
 
1 
 
 
 
1/2 
 
 
1/2 
 
 
1 
 
 
 
 
 
 
 
 
 
 
 
 
1 
 
 
 
 
 
1 
 
 
1 
 
SECTION C 
 
11 
Volume of shell = Volume of cylinder 
?  
4?? 3
[ 5³  - 3³] = ?? (7)
2
h  
? h =
8
3
= 2
2
3
???? 
 
 
1
?? ?? 
 
1 
60° 
1.7 m 
50m 
 
60° 30° 
20m 
x 
y 
P 
Q 
R 
S 
P 
Q 
R 
A 
B 
Page 4


Marking Scheme  
Class- X, Session- 2021-22 
TERM II 
Subject- Mathematics (Standard) 
  SECTION A  
Q.No
. 
HINTS/SOLUTION MARKS 
1 
a = 6, d = 3                   ;    a
25
  = 6 + 24(3) = 78     
a
15
  = 6 + 14(3) = 48    ;     a
25
 - a
15
 = 78 - 48 = 30 
 OR 
  7(?? + 6?? ) = 5(?? + 4?? )  
?2?? + 22?? = 0 ? ?? + 11?? = 0 ? ?? 12
= 0  
       1 
       1 
 
 
        1 
         
1 
2 
5mx² - 6mx + 9 = 0    
b² - 4ac = 0  ? (-6m)² - 4(5m)(9) = 0   
? 36m(m - 5) = 0   
? m = 0, 5  ; rejecting m=0, we get m = 5   
 
 
1 
 
 
 
 
1 
 
3 
 
let ??????? = ?? 
???????? =
????
????
=
1
2
? ?? = 30
0 
 
? ??????? = 2?? = 60
0
     
Also ??????? = ??????? = 60
0
 (? ???? = ???? ) 
?? ?????? is equilateral 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1/2 
 
1/2 
 
1/2 
 
1/2 
4 
CSA (cone) = ?????? = 12320 
22
7
× 56 × ?? = 12320 
?? = 70 ???? 
h = v70
2
- 56
2
 = 42 cm 
1/2 
 
 
 
1 
 
1/2 
 
O 
A 
B 
P 
r 
2r 
 
5 
Modal class is 40 - 60, ?? = 40, h = 20, ?? 1
=? , ?? 0
= 10, ?? 2
= 6 
45 = 40 + 20 × [
?? 1
- 10
2?? 1
- 10 - 6
] 
? 
1
4
=
?? 1
-10
2?? 1
-16
 
?2?? 1
- 16 = 4?? 1
- 40  ? ?? 1
= 12  
1/2 
 
1/2 
 
 
 
 
 
1 
6 
Let the present age of Ritu be ?? years 
(?? - 5)
2
= 5?? + 11 
?? 2
- 15?? + 14 = 0½ 
(?? - 14)(?? - 1) = 0  ? ?? = 1 ???? 14 
x = 14 years (rejecting ?? = 1 as in that case Ritu’s age 5 years ago will be –ve )  
OR 
9?? 2
- 6???? + (?? 2
- ?? 2
) = 0 
?? = 9, ?? = -6?? , ?? = ?? 2
- ?? 2
 
?? = ?? 2
- 4???? = (-6?? )
2
- 4(9)(?? 2
- ?? 2
) = 36?? 2
 
?? =
-?? ± v?? 2?? =
6?? ± 6?? 18
=
?? + ?? 3
???? 
?? - ?? 3
 
 
 
1 
 
 
1/2 
 
1/2 
 
 
 
 
 
1/2 
 
1/2 
 
1 
 
SECTION B 
 
7 
Distance (in m) 0 - 1 1 – 2 2 - 3 3 - 4 4 - 5 
Number of 
Students 
40 80 62 38 30 
???? 40 120 182 220 250 
?? 2
=
250
2
= 125 ? ???????????? ?????????? ???? 2 - 3, ?? = 2, h = 1, ???? = 120, ?? = 62 
???????????? = ?? +
?? 2
- ????
?? × ?? 
 = 2 +
5
62
 
=
129
62
= 2
5
62
?? ???? 2.08?? 
50% of students jumped below2
5
62
 m and 50% above it.   
 
 
 
 
 
 
 
       1 
 
 
1/2 
 
 
 
 
 
1 
 
1/2 
8 
Draw a circle of radius 4cm 
Draw OA and construct ??????? = 120
0
 
Draw ??????? = ??????? = 90
0
 
PA and PB are required tangents 
1 
 
1 
 
 
1 
9 
Runs Scored 0 - 40 40 - 80 80 - 120 120 - 160 160 - 200 TOTAL 
Number of 
Batsmen (?? ?? ) 
12 20 35 30 23 120 
 
 
 
 
 
?? ?? 20 60 100 140 180  
?? ?? ?? ?? 240 1200 3500 4200 4140 13280 
???????? ( ?? ¯) =
? ?? ?? ?? ?? ? ?? ?? =
13280
120
= 110.67 ???????? 
      
 
   1
?? ?? 
 
    1
?? ?? 
 
 
 
 
 
 
10 
 
???? ??????? , ?????? 60
0
=
?? 20
? ?? = 20v3m 
???? ??????? , ?????? 30
0
=
?? 20
? ?? =
20
v3
?? 
?? - ?? = 20v3 -
20
v3
=
40
v3
=
40v3
3
= 23.06?? 
OR 
 
Let PR be the building and AB be the boy 
???? ??????? , ?????? 60
0
=
????
50
? ???? = 50v3?? 
Height of the building = ???? = (50v3 + 1.7)?? = 88.2?? 
 
 
 
 
 
 
 
 
 
 
1 
 
 
 
1/2 
 
 
1/2 
 
 
1 
 
 
 
 
 
 
 
 
 
 
 
 
1 
 
 
 
 
 
1 
 
 
1 
 
SECTION C 
 
11 
Volume of shell = Volume of cylinder 
?  
4?? 3
[ 5³  - 3³] = ?? (7)
2
h  
? h =
8
3
= 2
2
3
???? 
 
 
1
?? ?? 
 
1 
60° 
1.7 m 
50m 
 
60° 30° 
20m 
x 
y 
P 
Q 
R 
S 
P 
Q 
R 
A 
B 
TSA of cylinder is 
= 2???? (?? + h) = 2 ×
22
7
× 7 × (7 +
8
3
) = 44 ×
29
3
= 
1276
3
????
2
  ????  425.33????
2 
 
 
 
1
?? ?? 
 
 
 
 
12 
 
??????? + ??????? + ??????? + ??????? = 360
?? 
? 90
0
+ 90
0
+ ??????? + ??????? = 360
?? (? ?????????????? ? ???????????? ) 
? ??????? + ??????? = 180
0
 
OR 
 
Let ??????? = ?? 
?????? is an isosceles triangle. 
??????? = ??????? =
1
2
(180
?? - ?? ) = 90° -
?? 2
 
??????? = 90
?? 
??????? = ??????? - ??????? = 90
?? - (90
?? -
?? 2
) =
?? 2
 
??????? =
1
2
??????? 
2??????? = ??????? 
 
 
1 
 
 
 
 
1
?? ?? 
 
1
?? ?? 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
?? ?? 
 
 
1
?? ?? 
 
 
 
 
         1 
13 
Case Study-1 
i) 
 
 
 
   In ??????? , tan 30
?? =
240
?? ? ?? = 240v3 ?? 
 
 
 
 
 
 
 
 
 
1 
 
 
 
 
 
 
 
 
1 
 
 
 
240m 
?? 
30
° 
T 
R 
P 
30° 
Page 5


Marking Scheme  
Class- X, Session- 2021-22 
TERM II 
Subject- Mathematics (Standard) 
  SECTION A  
Q.No
. 
HINTS/SOLUTION MARKS 
1 
a = 6, d = 3                   ;    a
25
  = 6 + 24(3) = 78     
a
15
  = 6 + 14(3) = 48    ;     a
25
 - a
15
 = 78 - 48 = 30 
 OR 
  7(?? + 6?? ) = 5(?? + 4?? )  
?2?? + 22?? = 0 ? ?? + 11?? = 0 ? ?? 12
= 0  
       1 
       1 
 
 
        1 
         
1 
2 
5mx² - 6mx + 9 = 0    
b² - 4ac = 0  ? (-6m)² - 4(5m)(9) = 0   
? 36m(m - 5) = 0   
? m = 0, 5  ; rejecting m=0, we get m = 5   
 
 
1 
 
 
 
 
1 
 
3 
 
let ??????? = ?? 
???????? =
????
????
=
1
2
? ?? = 30
0 
 
? ??????? = 2?? = 60
0
     
Also ??????? = ??????? = 60
0
 (? ???? = ???? ) 
?? ?????? is equilateral 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1/2 
 
1/2 
 
1/2 
 
1/2 
4 
CSA (cone) = ?????? = 12320 
22
7
× 56 × ?? = 12320 
?? = 70 ???? 
h = v70
2
- 56
2
 = 42 cm 
1/2 
 
 
 
1 
 
1/2 
 
O 
A 
B 
P 
r 
2r 
 
5 
Modal class is 40 - 60, ?? = 40, h = 20, ?? 1
=? , ?? 0
= 10, ?? 2
= 6 
45 = 40 + 20 × [
?? 1
- 10
2?? 1
- 10 - 6
] 
? 
1
4
=
?? 1
-10
2?? 1
-16
 
?2?? 1
- 16 = 4?? 1
- 40  ? ?? 1
= 12  
1/2 
 
1/2 
 
 
 
 
 
1 
6 
Let the present age of Ritu be ?? years 
(?? - 5)
2
= 5?? + 11 
?? 2
- 15?? + 14 = 0½ 
(?? - 14)(?? - 1) = 0  ? ?? = 1 ???? 14 
x = 14 years (rejecting ?? = 1 as in that case Ritu’s age 5 years ago will be –ve )  
OR 
9?? 2
- 6???? + (?? 2
- ?? 2
) = 0 
?? = 9, ?? = -6?? , ?? = ?? 2
- ?? 2
 
?? = ?? 2
- 4???? = (-6?? )
2
- 4(9)(?? 2
- ?? 2
) = 36?? 2
 
?? =
-?? ± v?? 2?? =
6?? ± 6?? 18
=
?? + ?? 3
???? 
?? - ?? 3
 
 
 
1 
 
 
1/2 
 
1/2 
 
 
 
 
 
1/2 
 
1/2 
 
1 
 
SECTION B 
 
7 
Distance (in m) 0 - 1 1 – 2 2 - 3 3 - 4 4 - 5 
Number of 
Students 
40 80 62 38 30 
???? 40 120 182 220 250 
?? 2
=
250
2
= 125 ? ???????????? ?????????? ???? 2 - 3, ?? = 2, h = 1, ???? = 120, ?? = 62 
???????????? = ?? +
?? 2
- ????
?? × ?? 
 = 2 +
5
62
 
=
129
62
= 2
5
62
?? ???? 2.08?? 
50% of students jumped below2
5
62
 m and 50% above it.   
 
 
 
 
 
 
 
       1 
 
 
1/2 
 
 
 
 
 
1 
 
1/2 
8 
Draw a circle of radius 4cm 
Draw OA and construct ??????? = 120
0
 
Draw ??????? = ??????? = 90
0
 
PA and PB are required tangents 
1 
 
1 
 
 
1 
9 
Runs Scored 0 - 40 40 - 80 80 - 120 120 - 160 160 - 200 TOTAL 
Number of 
Batsmen (?? ?? ) 
12 20 35 30 23 120 
 
 
 
 
 
?? ?? 20 60 100 140 180  
?? ?? ?? ?? 240 1200 3500 4200 4140 13280 
???????? ( ?? ¯) =
? ?? ?? ?? ?? ? ?? ?? =
13280
120
= 110.67 ???????? 
      
 
   1
?? ?? 
 
    1
?? ?? 
 
 
 
 
 
 
10 
 
???? ??????? , ?????? 60
0
=
?? 20
? ?? = 20v3m 
???? ??????? , ?????? 30
0
=
?? 20
? ?? =
20
v3
?? 
?? - ?? = 20v3 -
20
v3
=
40
v3
=
40v3
3
= 23.06?? 
OR 
 
Let PR be the building and AB be the boy 
???? ??????? , ?????? 60
0
=
????
50
? ???? = 50v3?? 
Height of the building = ???? = (50v3 + 1.7)?? = 88.2?? 
 
 
 
 
 
 
 
 
 
 
1 
 
 
 
1/2 
 
 
1/2 
 
 
1 
 
 
 
 
 
 
 
 
 
 
 
 
1 
 
 
 
 
 
1 
 
 
1 
 
SECTION C 
 
11 
Volume of shell = Volume of cylinder 
?  
4?? 3
[ 5³  - 3³] = ?? (7)
2
h  
? h =
8
3
= 2
2
3
???? 
 
 
1
?? ?? 
 
1 
60° 
1.7 m 
50m 
 
60° 30° 
20m 
x 
y 
P 
Q 
R 
S 
P 
Q 
R 
A 
B 
TSA of cylinder is 
= 2???? (?? + h) = 2 ×
22
7
× 7 × (7 +
8
3
) = 44 ×
29
3
= 
1276
3
????
2
  ????  425.33????
2 
 
 
 
1
?? ?? 
 
 
 
 
12 
 
??????? + ??????? + ??????? + ??????? = 360
?? 
? 90
0
+ 90
0
+ ??????? + ??????? = 360
?? (? ?????????????? ? ???????????? ) 
? ??????? + ??????? = 180
0
 
OR 
 
Let ??????? = ?? 
?????? is an isosceles triangle. 
??????? = ??????? =
1
2
(180
?? - ?? ) = 90° -
?? 2
 
??????? = 90
?? 
??????? = ??????? - ??????? = 90
?? - (90
?? -
?? 2
) =
?? 2
 
??????? =
1
2
??????? 
2??????? = ??????? 
 
 
1 
 
 
 
 
1
?? ?? 
 
1
?? ?? 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
?? ?? 
 
 
1
?? ?? 
 
 
 
 
         1 
13 
Case Study-1 
i) 
 
 
 
   In ??????? , tan 30
?? =
240
?? ? ?? = 240v3 ?? 
 
 
 
 
 
 
 
 
 
1 
 
 
 
 
 
 
 
 
1 
 
 
 
240m 
?? 
30
° 
T 
R 
P 
30° 
 
 ii)  Distance of boat from tower= 240v3 - 240(
v3 - 1) = 240?? 
      Let the angle of depression = ?? 
      ???????? =
240
240
= 1  ? ?? = 45
?? 
       
 
 
 
1 
 
 
        1 
 
 
14 
i) 3000, 3005, 3010, ...,3900. 
                ?? ?? = ?? + (?? - 1)?? 
                   3900 = 3000 + (n - 1)5  
                ? 900 = 5?? - 5 ? 5?? = 905 ? ?? = 181 
     Minimum number of days of practice = ?? - 1 = 180 ???????? 
  
       ii)            ?? ?? = 
?? 2
(?? + ?? ) 
                            =  
181
2
× (3000 + 3900) = 624450 pushups 
 
1 
 
 
 
       1 
 
        
       1 
        
1 
 
 
 
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