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UnitsandMeasurements
CheatSheet
Fundamental and Derived Quantities
Type Description Examples
Fundamental Basic quantities independent of others. Length (m), Mass (kg), Time
(s)
Derived Quantities derived from fundamental
quantities using mathematical relations.
Velocity (m/s), Force
(kg·m/s
2
), Energy (J)
SI Units
Quantity Unit Symbol
Length Meter m
Mass Kilogram kg
Time Second s
Electric Current Ampere A
Temperature Kelvin K
Amount of Substance Mole mol
Luminous Intensity Candela cd
Dimensional Analysis
• De?nition: Technique to check equation consistency using dimensions of physical quantities.
• Key Formula: [M
a
L
b
T
c
], where M = mass, L = length, T = time.
• Applications:
– Verify formula correctness.
– Derive relations between physical quantities.
– Convert units across systems (e.g., SI to CGS).
Signi?cant Figures
• Rules:
– Non-zero digits are always signi?cant.
– Zeros between non-zero digits are signi?cant.
– Leading zeros are not signi?cant.
– Trailing zeros in a decimal are signi?cant.
• Operations:
1
Page 2


UnitsandMeasurements
CheatSheet
Fundamental and Derived Quantities
Type Description Examples
Fundamental Basic quantities independent of others. Length (m), Mass (kg), Time
(s)
Derived Quantities derived from fundamental
quantities using mathematical relations.
Velocity (m/s), Force
(kg·m/s
2
), Energy (J)
SI Units
Quantity Unit Symbol
Length Meter m
Mass Kilogram kg
Time Second s
Electric Current Ampere A
Temperature Kelvin K
Amount of Substance Mole mol
Luminous Intensity Candela cd
Dimensional Analysis
• De?nition: Technique to check equation consistency using dimensions of physical quantities.
• Key Formula: [M
a
L
b
T
c
], where M = mass, L = length, T = time.
• Applications:
– Verify formula correctness.
– Derive relations between physical quantities.
– Convert units across systems (e.g., SI to CGS).
Signi?cant Figures
• Rules:
– Non-zero digits are always signi?cant.
– Zeros between non-zero digits are signi?cant.
– Leading zeros are not signi?cant.
– Trailing zeros in a decimal are signi?cant.
• Operations:
1
– Addition/Subtraction: Result has same decimal places as the number with the least decimal
places.
– Multiplication/Division: Result has same signi?cant ?gures as the number with the least sig-
ni?cant ?gures.
Errors in Measurement
Type Description Formula
Absolute Error Di?erence between measured and true
value.
? a =|a
m
-a
t
|
Relative Error Ratio of absolute error to true value. da = ? a/a
t
Percentage Error Relative error expressed as a percentage. % Error = (? a/a
t
)×100
Combination of Er-
rors
For a function Z =A
m
B
n
/C
p
: ? Z/Z = m(? A/A) +
n(? B/B)+p(? C/C)
Measurement Techniques
Instrument Purpose Precision (Least Count)
Vernier Caliper Measures length, diameter,
thickness.
LC=1MSD-1VSD(typically0.01
cm)
Screw Gauge Measures small dimensions
(e.g., wire).
LC = Pitch / No. of divisions (e.g.,
0.001 cm)
Stopwatch Measures time intervals. Typically 0.01 s
Conversion of Units
• Length: 1 m = 100 cm = 10
9
nm; 1 km = 0.621 miles.
• Mass: 1 kg = 1000 g; 1 tonne = 1000 kg.
• Time: 1 hr = 3600 s; 1 year ˜ 3.156×10
7
s.
• Energy: 1 J = 10
7
erg; 1 eV = 1.602×10
-19
J.
• Pressure: 1 Pa = 1 N/m
2
; 1 atm = 101325 Pa.
Key Formulas and Concepts
• Density: ? =m/V (kg/m
3
)
• Speed: v =d/t (m/s)
• Acceleration: a = ? v/? t (m/s
2
)
• Order of Magnitude: Approximate value to the nearest power of 10.
• Parallax Error: Error due to improper alignment of observers eye with the measurement scale.
Solved Examples
1. Dimensional Analysis: Derive the dimensional formula for viscosity (?) in the formula F =
?A(v/l), where F is force, A is area, v is velocity, and l is length.
• Solution:
– Dimensions of F = [MLT
-2
], A = [L
2
], v = [LT
-1
], l = [L].
2
Page 3


UnitsandMeasurements
CheatSheet
Fundamental and Derived Quantities
Type Description Examples
Fundamental Basic quantities independent of others. Length (m), Mass (kg), Time
(s)
Derived Quantities derived from fundamental
quantities using mathematical relations.
Velocity (m/s), Force
(kg·m/s
2
), Energy (J)
SI Units
Quantity Unit Symbol
Length Meter m
Mass Kilogram kg
Time Second s
Electric Current Ampere A
Temperature Kelvin K
Amount of Substance Mole mol
Luminous Intensity Candela cd
Dimensional Analysis
• De?nition: Technique to check equation consistency using dimensions of physical quantities.
• Key Formula: [M
a
L
b
T
c
], where M = mass, L = length, T = time.
• Applications:
– Verify formula correctness.
– Derive relations between physical quantities.
– Convert units across systems (e.g., SI to CGS).
Signi?cant Figures
• Rules:
– Non-zero digits are always signi?cant.
– Zeros between non-zero digits are signi?cant.
– Leading zeros are not signi?cant.
– Trailing zeros in a decimal are signi?cant.
• Operations:
1
– Addition/Subtraction: Result has same decimal places as the number with the least decimal
places.
– Multiplication/Division: Result has same signi?cant ?gures as the number with the least sig-
ni?cant ?gures.
Errors in Measurement
Type Description Formula
Absolute Error Di?erence between measured and true
value.
? a =|a
m
-a
t
|
Relative Error Ratio of absolute error to true value. da = ? a/a
t
Percentage Error Relative error expressed as a percentage. % Error = (? a/a
t
)×100
Combination of Er-
rors
For a function Z =A
m
B
n
/C
p
: ? Z/Z = m(? A/A) +
n(? B/B)+p(? C/C)
Measurement Techniques
Instrument Purpose Precision (Least Count)
Vernier Caliper Measures length, diameter,
thickness.
LC=1MSD-1VSD(typically0.01
cm)
Screw Gauge Measures small dimensions
(e.g., wire).
LC = Pitch / No. of divisions (e.g.,
0.001 cm)
Stopwatch Measures time intervals. Typically 0.01 s
Conversion of Units
• Length: 1 m = 100 cm = 10
9
nm; 1 km = 0.621 miles.
• Mass: 1 kg = 1000 g; 1 tonne = 1000 kg.
• Time: 1 hr = 3600 s; 1 year ˜ 3.156×10
7
s.
• Energy: 1 J = 10
7
erg; 1 eV = 1.602×10
-19
J.
• Pressure: 1 Pa = 1 N/m
2
; 1 atm = 101325 Pa.
Key Formulas and Concepts
• Density: ? =m/V (kg/m
3
)
• Speed: v =d/t (m/s)
• Acceleration: a = ? v/? t (m/s
2
)
• Order of Magnitude: Approximate value to the nearest power of 10.
• Parallax Error: Error due to improper alignment of observers eye with the measurement scale.
Solved Examples
1. Dimensional Analysis: Derive the dimensional formula for viscosity (?) in the formula F =
?A(v/l), where F is force, A is area, v is velocity, and l is length.
• Solution:
– Dimensions of F = [MLT
-2
], A = [L
2
], v = [LT
-1
], l = [L].
2
– F =?A(v/l)? [MLT
-2
] =?[L
2
]([LT
-1
]/[L]) =?[L
2
][T
-1
].
– ? = [MLT
-2
]/[L
2
T
-1
] = [ML
-1
T
-1
].
– Answer: [ML
-1
T
-1
].
2. ErrorPropagation: Theradiusofasphereismeasuredas 7.00±0.02cm. Calculatethepercentage
error in its volume.
• Solution:
– Volume of sphere, V = (4/3)pr
3
, so ? V/V = 3(? r/r).
– Given r = 7.00 cm, ? r = 0.02 cm.
– Relative error = ? r/r = 0.02/7.00 = 0.002857.
– Percentage error in volume = 3×0.002857×100 = 0.857%.
– Answer: 0.86% (to 2 signi?cant ?gures).
3. Signi?cant Figures: Calculate the area of a rectangle with length 12.4 cm and breadth 3.567 cm,
expressing the result with appropriate signi?cant ?gures.
• Solution:
– Area = length × breadth = 12.4×3.567 = 44.2308 cm
2
.
– Lengthhas3signi?cant?gures, breadthhas4; resultshouldhave3signi?cant?gures(least
of the two).
– Round 44.2308 to 44.2 cm
2
.
– Answer: 44.2 cm
2
.
4. Vernier Caliper: A vernier caliper has a main scale division (MSD) of 1 mm and 10 vernier
divisions coincide with 9 main scale divisions. Find its least count and measure a length of 5.3 cm
with an error.
• Solution:
– Least count (LC) = 1 MSD - 1 VSD, where 10 VSD = 9 MSD ? 1 VSD = 0.9 mm.
– LC = 1 mm - 0.9 mm = 0.1 mm = 0.01 cm.
– Measured length = 5.3 cm ± 0.01 cm (error is ± LC).
– Answer: Least count = 0.01 cm, length = 5.3±0.01 cm.
5. Unit Conversion: A cars speed is 72 km/h. Convert this to cm/s and determine the order of
magnitude.
• Solution:
– 72 km/h = 72×1000 m / 3600 s = 72×1000/3600 = 20 m/s.
– 20 m/s = 20×100 cm/s = 2000 cm/s.
– Order of magnitude: 2000 = 2×10
3
? order of magnitude is 10
3
.
– Answer: 2000 cm/s, order of magnitude = 10
3
.
3
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FAQs on Cheat Sheet: Units & Measurements - Physics Class 11 - NEET

1. What are the fundamental units of measurement in the International System of Units (SI) ?
Ans.The International System of Units (SI) is based on seven fundamental units: meter (length), kilogram (mass), second (time), ampere (electric current), kelvin (temperature), mole (amount of substance), and candela (luminous intensity). These units provide a standard for scientific measurements.
2. How do you convert between different units of measurement ?
Ans.Converting between different units involves multiplying or dividing by conversion factors that relate the units to one another. For example, to convert meters to kilometers, you divide by 1,000 (since 1 kilometer = 1,000 meters). It is essential to know the relationship between the units you are converting.
3. Why is dimensional analysis important in physics and engineering ?
Ans.Dimensional analysis is crucial because it helps to check the consistency of equations and calculations. By ensuring that both sides of an equation have the same dimensions, one can validate whether the equation makes physical sense. It also aids in converting units and predicting the relationship between different physical quantities.
4. What is the significance of significant figures in measurements ?
Ans.Significant figures are important because they convey the precision of a measurement. The number of significant figures indicates how reliable the measurement is, guiding how results should be reported and calculated. For example, when multiplying or dividing measurements, the result should be reported with the same number of significant figures as the measurement with the fewest significant figures.
5. How do you calculate the area and volume in different units ?
Ans.To calculate area, you typically multiply length by width (for example, square meters for area). To convert area from square meters to square centimeters, you multiply by 10,000 (since 1 square meter = 10,000 square centimeters). For volume, you multiply length, width, and height (cubic meters for volume). Converting volume follows a similar approach, requiring the appropriate conversion factor for cubic measurements.
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