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Page 1 8085 Programs Gursharan Singh Maninder Kaur Page 1 of 2 Program 1: 1’s complement of an 8-bit number. Flowchart: Program: Address Mnemonics Operand Opcode Remarks 2000 LDA 3000H 3A Load H-L pair with data from 3000H. 2001 00 Lower-order of 3000H. 2002 30 Higher-order of 3000H. 2003 CMA 2F Complement accumulator. 2004 STA 3001H 32 Store the result at memory location 3001H. 2005 01 Lower-order of 3001H. 2006 30 Higher-order of 3001H. 2007 HLT 76 Halt. Explanation: ? This program finds the 1’s complement of an 8-bit number stored in memory location 3000H. ? Let us assume that the operand stored at memory location 3000H is 85H. ? The operand is moved to accumulator from memory location 3000H. ? Then, its complement is found by using CMA instruction. ? The result is stored at memory location 3001H. Start Load accumulator with operand from memory. Complement accumulator. Store the result from accumulator to memory. Stop Page 2 8085 Programs Gursharan Singh Maninder Kaur Page 1 of 2 Program 1: 1’s complement of an 8-bit number. Flowchart: Program: Address Mnemonics Operand Opcode Remarks 2000 LDA 3000H 3A Load H-L pair with data from 3000H. 2001 00 Lower-order of 3000H. 2002 30 Higher-order of 3000H. 2003 CMA 2F Complement accumulator. 2004 STA 3001H 32 Store the result at memory location 3001H. 2005 01 Lower-order of 3001H. 2006 30 Higher-order of 3001H. 2007 HLT 76 Halt. Explanation: ? This program finds the 1’s complement of an 8-bit number stored in memory location 3000H. ? Let us assume that the operand stored at memory location 3000H is 85H. ? The operand is moved to accumulator from memory location 3000H. ? Then, its complement is found by using CMA instruction. ? The result is stored at memory location 3001H. Start Load accumulator with operand from memory. Complement accumulator. Store the result from accumulator to memory. Stop 8085 Programs Gursharan Singh Maninder Kaur Page 2 of 2 Output: Before Execution: 3000H: 85H After Execution: 3001H: 7AHRead More
FAQs on Program - 1s Complement of 8-bit Number - 8085 - Computer Science Engineering (CSE)
| 1. What is 1s complement of an 8-bit number? |  |
Ans. The 1s complement of an 8-bit number is obtained by changing all 1s to 0s and 0s to 1s in the binary representation of the number.
| 2. How to find the 1s complement of an 8-bit number using 8085 assembly code? | |
Ans. To find the 1s complement of an 8-bit number using 8085 assembly code, we can use the instruction "CMA" which stands for "Complement Accumulator". This instruction complements all the bits in the accumulator.
| 3. What is the significance of 1s complement in computer arithmetic? | |
Ans. The 1s complement is used in computer arithmetic to represent negative numbers. The sign bit is the leftmost bit in the binary representation of a number. If the sign bit is 1, then the number is negative. To get the 1s complement of a negative number, we flip all the bits in the binary representation except the sign bit.
| 4. What is the difference between 1s complement and 2s complement? | |
Ans. The 1s complement and 2s complement are both used to represent negative numbers in computer arithmetic. The difference between them is that in 1s complement, the negative number is represented by flipping all the bits in the binary representation except the sign bit, whereas in 2s complement, the negative number is represented by taking the 1s complement and adding 1 to the result.
| 5. What are some applications of 1s complement in computer networking? | |
Ans. The 1s complement is used in computer networking for error detection and correction. In the Internet Protocol (IP) header, there is a field called "Checksum" which is used to ensure the integrity of the data being transmitted. The 1s complement is used to calculate the checksum value of the data. If there is an error in the data during transmission, the receiver can detect it by recalculating the checksum value using the 1s complement and comparing it with the received checksum value.
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