Past Year Paper, Physics (Set - 3), Delhi, 2015, Class 12, Physics | Additional Study Material for NEET PDF Download

 Page 1


55/1/3/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No.  
 
 
 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :   
    (i) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ‡ÃÖ ¯ÖÏ¿®Ö ¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-Ûú, ÜÖÞ›ü-ÜÖ, ÜÖÞ›ü-ÝÖ, ÜÖÞ›ü-‘Ö †Öî¸ü ÜÖÞ›ü-’û …  
 (iii) ÜÖÞ›ü-Ûú ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 1 †ÓÛú ÛúÖ, ÜÖÞ›ü-ÜÖ ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 2 †ÓÛú Ûêú, ÜÖÞ›ü-ÝÖ ´Öë 12 ¯ÖÏ¿®Ö 
¯ÖÏŸµÖêÛú 3 †ÓÛú Ûêú, ÜÖÞ›ü-‘Ö ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö †Öî¸ü ÜÖÞ›ü-’û ´Öë 3 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 5 †ÓÛú 
Ûêú פü‹ ÝÖ‹ Æïü …  
 (iv) ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ×±ú¸ü ³Öß 2 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö, 3 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö †Öî¸ü 5 †ÓÛúÖë Ûêú 3 ¯ÖÏ¿®ÖÖë 
´Öë ³Öߟָüß ×¾ÖÛú»¯Ö פü‹ ÝÖ‹ Æïü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê ×¾ÖÛú»¯ÖÖë ´Öë ÃÖê ‹Ûú ÛúÖê Æü»Ö Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1 
55/1/3/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 16 Æïü … 
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê 
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 16 printed pages. 
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the 
question paper only and will not write any answer on the answer-book during this period. 
ÛúÖê›ü ®ÖÓ. 
Code No.  
     
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 3 
Page 2


55/1/3/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No.  
 
 
 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :   
    (i) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ‡ÃÖ ¯ÖÏ¿®Ö ¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-Ûú, ÜÖÞ›ü-ÜÖ, ÜÖÞ›ü-ÝÖ, ÜÖÞ›ü-‘Ö †Öî¸ü ÜÖÞ›ü-’û …  
 (iii) ÜÖÞ›ü-Ûú ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 1 †ÓÛú ÛúÖ, ÜÖÞ›ü-ÜÖ ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 2 †ÓÛú Ûêú, ÜÖÞ›ü-ÝÖ ´Öë 12 ¯ÖÏ¿®Ö 
¯ÖÏŸµÖêÛú 3 †ÓÛú Ûêú, ÜÖÞ›ü-‘Ö ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö †Öî¸ü ÜÖÞ›ü-’û ´Öë 3 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 5 †ÓÛú 
Ûêú פü‹ ÝÖ‹ Æïü …  
 (iv) ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ×±ú¸ü ³Öß 2 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö, 3 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö †Öî¸ü 5 †ÓÛúÖë Ûêú 3 ¯ÖÏ¿®ÖÖë 
´Öë ³Öߟָüß ×¾ÖÛú»¯Ö פü‹ ÝÖ‹ Æïü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê ×¾ÖÛú»¯ÖÖë ´Öë ÃÖê ‹Ûú ÛúÖê Æü»Ö Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1 
55/1/3/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 16 Æïü … 
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê 
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 16 printed pages. 
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the 
question paper only and will not write any answer on the answer-book during this period. 
ÛúÖê›ü ®ÖÓ. 
Code No.  
     
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 3 
55/1/3/D 2 
  
 (v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê, ¾ÖÆüÖÑ †Ö¯Ö ³ÖÖîןÖÛ †“Ö¸üÖë Ûêú ×®Ö´®Ö×»Ö×ÜÖŸÖ ´Ö滵ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  ®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg 
  ¯ÖÏÖê™üÖê®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg 
  ‹ê¾ÖÖêÝÖê›ÒüÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö  
  ²ÖÖò»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
 
 
General Instructions :   
 (i) There are 26 questions in all. All questions are compulsory.  
 (ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
 (iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
 (iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
 (v) You may use the following values of physical constants wherever necessary : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  mass of neutron = 1.675 × 10
–27
 kg 
  mass of proton = 1.673 × 10
–27
 kg 
  Avogadro’s number = 6.023 × 10
23
 per gram mole 
  Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
Page 3


55/1/3/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No.  
 
 
 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :   
    (i) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ‡ÃÖ ¯ÖÏ¿®Ö ¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-Ûú, ÜÖÞ›ü-ÜÖ, ÜÖÞ›ü-ÝÖ, ÜÖÞ›ü-‘Ö †Öî¸ü ÜÖÞ›ü-’û …  
 (iii) ÜÖÞ›ü-Ûú ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 1 †ÓÛú ÛúÖ, ÜÖÞ›ü-ÜÖ ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 2 †ÓÛú Ûêú, ÜÖÞ›ü-ÝÖ ´Öë 12 ¯ÖÏ¿®Ö 
¯ÖÏŸµÖêÛú 3 †ÓÛú Ûêú, ÜÖÞ›ü-‘Ö ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö †Öî¸ü ÜÖÞ›ü-’û ´Öë 3 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 5 †ÓÛú 
Ûêú פü‹ ÝÖ‹ Æïü …  
 (iv) ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ×±ú¸ü ³Öß 2 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö, 3 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö †Öî¸ü 5 †ÓÛúÖë Ûêú 3 ¯ÖÏ¿®ÖÖë 
´Öë ³Öߟָüß ×¾ÖÛú»¯Ö פü‹ ÝÖ‹ Æïü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê ×¾ÖÛú»¯ÖÖë ´Öë ÃÖê ‹Ûú ÛúÖê Æü»Ö Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1 
55/1/3/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 16 Æïü … 
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê 
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 16 printed pages. 
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the 
question paper only and will not write any answer on the answer-book during this period. 
ÛúÖê›ü ®ÖÓ. 
Code No.  
     
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 3 
55/1/3/D 2 
  
 (v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê, ¾ÖÆüÖÑ †Ö¯Ö ³ÖÖîןÖÛ †“Ö¸üÖë Ûêú ×®Ö´®Ö×»Ö×ÜÖŸÖ ´Ö滵ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  ®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg 
  ¯ÖÏÖê™üÖê®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg 
  ‹ê¾ÖÖêÝÖê›ÒüÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö  
  ²ÖÖò»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
 
 
General Instructions :   
 (i) There are 26 questions in all. All questions are compulsory.  
 (ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
 (iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
 (iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
 (v) You may use the following values of physical constants wherever necessary : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  mass of neutron = 1.675 × 10
–27
 kg 
  mass of proton = 1.673 × 10
–27
 kg 
  Avogadro’s number = 6.023 × 10
23
 per gram mole 
  Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
55/1/3/D 3 [P.T.O. 
ÜÖÞ›ü – Ûú  
Section – A 
 
1. ×ÛúÃÖß ˆ¢Ö»Ö »ÖëÃÖ Ûêú ¯Ö¤üÖ£ÖÔ ÛúÖ †¯Ö¾ÖŸÖÔ®ÖÖÓÛú 1.5 Æîü … ‡ÃÖê 1.65 †¯Ö¾ÖŸÖÔ®ÖÖÓÛú Ûêú ×ÛúÃÖß ´ÖÖ¬µÖ´Ö ´Öë ›ãü²ÖÖ®Öê ¯Ö¸ü »ÖëÃÖ 
Ûúß ¯ÖÏÛéú×ŸÖ ÛîúÃÖß ÆüÖêÝÖß ? 1 
 A concave lens of refractive index 1.5 is immersed in a medium of refractive index 1.65. 
What is the nature of the lens ? 
 
2. ¯ÖÖ¿¾ÖÔ ²Öï›ü ÛîúÃÖê ˆŸ¯Ö®®Ö ÆüÖêŸÖê Æïü ? 1 
 How are side bands produced ? 
 
3. µÖÆüÖÑ ‹Ûú ¯Ö¤üÖ£ÖÔ, GaAs Ûêú ×»ÖµÖê, ¾ÖÖê»™üŸÖÖ Ûêú ÃÖÖ£Ö ¬ÖÖ¸üÖ Ûêú ¯Ö׸ü¾ÖŸÖÔ®Ö ÛúÖê ¤ü¿ÖÖÔ®Öê Ûêú ×»ÖµÖê ‹Ûú ÝÖÏÖ±ú (†Ö»ÖêÜÖ) 
פüµÖÖ ÝÖµÖÖ Æîü, ˆÃÖ õÖê¡Ö Ûúß ¯ÖÆü“ÖÖ®Ö ÛúßוֵÖê •ÖÆüÖÑ,  
 (i) ŠúÞÖÖŸ´ÖÛú ¯ÖÏןָüÖê¬Ö Æîü …  
 (ii) †Öê´Ö Ûêú ×®ÖµÖ´Ö ÛúÖ ¯ÖÖ»Ö®Ö ÆüÖêŸÖÖ Æîü …  1 
 
 Graph showing the variation of current versus voltage for a material GaAs is shown in 
the figure. Identify the region of  
 (i) negative resistance 
 (ii) where Ohm’s law is obeyed. 
 
 
4. ÃÖÓ¬ÖÖ׸ü¡Ö - ¯ÖÏן֑ÖÖŸÖ Ûúß ¯Ö׸ü³ÖÖÂÖÖ ×»Ö×ÜÖµÖê … ‡ÃÖÛúÖ ‹ÃÖ.†Ö‡Ô. (S.I.) ´ÖÖ¡ÖÛú ŒµÖÖ Æîü ? 1 
 Define capacitor reactance. Write its S.I. units. 
 
5. 1 cm ³Öã•ÖÖ Ûêú ‘Ö®Ö (ŒµÖæ²Ö) ´Öë ¯Ö׸ü²Ö¨ü (²Ö®¤ü) ×ÛúÃÖß ×«ü¬ÖÐã¾Ö Ûêú ÛúÖ¸üÞÖ ˆÃÖÃÖê ‘Ö®Ö ÃÖê ÝÖã•Ö¸ü®Öê ¾ÖÖ»Öê ×¾ÖªãŸÖ °»ÖŒÃÖ 
ÛúÖ ´ÖÖ®Ö ŒµÖÖ ÆüÖêÝÖÖ ?   1 
 What is the electric flux through a cube of side 1 cm which encloses an electric dipole ? 
Page 4


55/1/3/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No.  
 
 
 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :   
    (i) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ‡ÃÖ ¯ÖÏ¿®Ö ¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-Ûú, ÜÖÞ›ü-ÜÖ, ÜÖÞ›ü-ÝÖ, ÜÖÞ›ü-‘Ö †Öî¸ü ÜÖÞ›ü-’û …  
 (iii) ÜÖÞ›ü-Ûú ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 1 †ÓÛú ÛúÖ, ÜÖÞ›ü-ÜÖ ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 2 †ÓÛú Ûêú, ÜÖÞ›ü-ÝÖ ´Öë 12 ¯ÖÏ¿®Ö 
¯ÖÏŸµÖêÛú 3 †ÓÛú Ûêú, ÜÖÞ›ü-‘Ö ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö †Öî¸ü ÜÖÞ›ü-’û ´Öë 3 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 5 †ÓÛú 
Ûêú פü‹ ÝÖ‹ Æïü …  
 (iv) ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ×±ú¸ü ³Öß 2 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö, 3 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö †Öî¸ü 5 †ÓÛúÖë Ûêú 3 ¯ÖÏ¿®ÖÖë 
´Öë ³Öߟָüß ×¾ÖÛú»¯Ö פü‹ ÝÖ‹ Æïü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê ×¾ÖÛú»¯ÖÖë ´Öë ÃÖê ‹Ûú ÛúÖê Æü»Ö Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1 
55/1/3/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 16 Æïü … 
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê 
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 16 printed pages. 
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the 
question paper only and will not write any answer on the answer-book during this period. 
ÛúÖê›ü ®ÖÓ. 
Code No.  
     
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 3 
55/1/3/D 2 
  
 (v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê, ¾ÖÆüÖÑ †Ö¯Ö ³ÖÖîןÖÛ †“Ö¸üÖë Ûêú ×®Ö´®Ö×»Ö×ÜÖŸÖ ´Ö滵ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  ®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg 
  ¯ÖÏÖê™üÖê®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg 
  ‹ê¾ÖÖêÝÖê›ÒüÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö  
  ²ÖÖò»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
 
 
General Instructions :   
 (i) There are 26 questions in all. All questions are compulsory.  
 (ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
 (iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
 (iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
 (v) You may use the following values of physical constants wherever necessary : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  mass of neutron = 1.675 × 10
–27
 kg 
  mass of proton = 1.673 × 10
–27
 kg 
  Avogadro’s number = 6.023 × 10
23
 per gram mole 
  Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
55/1/3/D 3 [P.T.O. 
ÜÖÞ›ü – Ûú  
Section – A 
 
1. ×ÛúÃÖß ˆ¢Ö»Ö »ÖëÃÖ Ûêú ¯Ö¤üÖ£ÖÔ ÛúÖ †¯Ö¾ÖŸÖÔ®ÖÖÓÛú 1.5 Æîü … ‡ÃÖê 1.65 †¯Ö¾ÖŸÖÔ®ÖÖÓÛú Ûêú ×ÛúÃÖß ´ÖÖ¬µÖ´Ö ´Öë ›ãü²ÖÖ®Öê ¯Ö¸ü »ÖëÃÖ 
Ûúß ¯ÖÏÛéú×ŸÖ ÛîúÃÖß ÆüÖêÝÖß ? 1 
 A concave lens of refractive index 1.5 is immersed in a medium of refractive index 1.65. 
What is the nature of the lens ? 
 
2. ¯ÖÖ¿¾ÖÔ ²Öï›ü ÛîúÃÖê ˆŸ¯Ö®®Ö ÆüÖêŸÖê Æïü ? 1 
 How are side bands produced ? 
 
3. µÖÆüÖÑ ‹Ûú ¯Ö¤üÖ£ÖÔ, GaAs Ûêú ×»ÖµÖê, ¾ÖÖê»™üŸÖÖ Ûêú ÃÖÖ£Ö ¬ÖÖ¸üÖ Ûêú ¯Ö׸ü¾ÖŸÖÔ®Ö ÛúÖê ¤ü¿ÖÖÔ®Öê Ûêú ×»ÖµÖê ‹Ûú ÝÖÏÖ±ú (†Ö»ÖêÜÖ) 
פüµÖÖ ÝÖµÖÖ Æîü, ˆÃÖ õÖê¡Ö Ûúß ¯ÖÆü“ÖÖ®Ö ÛúßוֵÖê •ÖÆüÖÑ,  
 (i) ŠúÞÖÖŸ´ÖÛú ¯ÖÏןָüÖê¬Ö Æîü …  
 (ii) †Öê´Ö Ûêú ×®ÖµÖ´Ö ÛúÖ ¯ÖÖ»Ö®Ö ÆüÖêŸÖÖ Æîü …  1 
 
 Graph showing the variation of current versus voltage for a material GaAs is shown in 
the figure. Identify the region of  
 (i) negative resistance 
 (ii) where Ohm’s law is obeyed. 
 
 
4. ÃÖÓ¬ÖÖ׸ü¡Ö - ¯ÖÏן֑ÖÖŸÖ Ûúß ¯Ö׸ü³ÖÖÂÖÖ ×»Ö×ÜÖµÖê … ‡ÃÖÛúÖ ‹ÃÖ.†Ö‡Ô. (S.I.) ´ÖÖ¡ÖÛú ŒµÖÖ Æîü ? 1 
 Define capacitor reactance. Write its S.I. units. 
 
5. 1 cm ³Öã•ÖÖ Ûêú ‘Ö®Ö (ŒµÖæ²Ö) ´Öë ¯Ö׸ü²Ö¨ü (²Ö®¤ü) ×ÛúÃÖß ×«ü¬ÖÐã¾Ö Ûêú ÛúÖ¸üÞÖ ˆÃÖÃÖê ‘Ö®Ö ÃÖê ÝÖã•Ö¸ü®Öê ¾ÖÖ»Öê ×¾ÖªãŸÖ °»ÖŒÃÖ 
ÛúÖ ´ÖÖ®Ö ŒµÖÖ ÆüÖêÝÖÖ ?   1 
 What is the electric flux through a cube of side 1 cm which encloses an electric dipole ? 
55/1/3/D 4 
  
ÜÖÞ›ü – ÜÖ  
Section – B 
 
6. ®Öî•Ö ŸÖ£ÖÖ †¯Ö×´Ö×ÁÖŸÖ †¬ÖÔ“ÖÖ»ÖÛúÖë ´Öë †®ŸÖ¸ü (³Öê¤ü) ÛúßוֵÖê …  2 
 Distinguish between ‘intrinsic’ and ‘extrinsic’ semiconductors. 
 
7. ¤ü¯ÖÔÞÖ ÃÖæ¡Ö Ûêú ˆ¯ÖµÖÖêÝÖ «üÖ¸üÖ ¤ü¿ÖÖÔ‡µÖê ×Ûú, ×ÛúÃÖß †¾ÖŸÖ»Ö ¤ü¯ÖÔÞÖ Ûêú ÃÖÖ´Ö®Öê ˆÃÖÛúß f (±úÖêÛúÃÖ ¤æü¸üß) ŸÖ£ÖÖ 2f (¾ÖÛÎúŸÖÖ 
ס֕µÖÖ) Ûêú ²Öß“Ö ×Ã£ÖŸÖ ×ÛúÃÖß ¾ÖßÖã ÛúÖ ¯ÖÏןÖײִ²Ö, 2f Ûêú ¯Ö¸êü (2f ÃÖê †Öî¸ü †ÖÝÖê) ²Ö®ÖŸÖÖ Æîü …  2 
 Use the mirror equation to show that an object placed between f and 2f of a concave 
mirror produces a real image beyond 2f. 
†£Ö¾ÖÖ/OR 
 ¤üÖê ÛÎúÖ×ÃÖŸÖ ¯ÖÖê»Öê¸üÖò‡›üÖë Ûêú ²Öß“Ö ´Öë ×ÛúÃÖß †®µÖ ¯ÖÖê»ÖÖò¸üÖ‡›ü Ûúß ¿Öß™ü (“ÖÖ¤ü¸ü) ÛúÖê ‘Öã´ÖÖ®Öê ÃÖê ¯ÖÖ¸üÝÖ×´ÖŸÖ ¯ÖÏÛúÖ¿Ö Ûúß 
ŸÖß¾ÖΟÖÖ Ûêú ×»ÖµÖê ¾µÖÓ•ÖÛú ¯ÖÏÖ¯ŸÖ ÛúßוֵÖê …  
 ‡ÃÖ ¿Öß™ü (“ÖÖ¤ü¸ü) Ûúß ×ÛúÃÖ ×ãÖ×ŸÖ ´Öë ¯ÖÖ¸üÝÖ×´ÖŸÖ ¯ÖÏÛúÖ¿Ö Ûúß ŸÖß¾ÖΟÖÖ †×¬ÖÛúŸÖ´Ö ÆüÖêÝÖß ? 
 Find an expression for intensity of transmitted light when a polaroid sheet is rotated 
between two crossed polaroids. In which position of the polaroid sheet will the 
transmitted intensity be maximum ? 
 
8. ×Ûú¸üÜÖÖê¯Ö Ûêú ×®ÖµÖ´ÖÖë Ûêú ˆ¯ÖµÖÖêÝÖ ÃÖê ×ÛúÃÖß ¾Æüß™üÙüÖê®Ö ײÖ륅 (ÃÖêŸÖã) ´Öë ÃÖÓŸÖã»Ö®Ö ×ãÖ×ŸÖ Ûêú ×»ÖµÖê ¯ÖÏןֲ֮¬Ö (¿ÖŸÖí) –ÖÖŸÖ 
ÛúßוֵÖê …    2 
 Use Kirchhoff’s rules to obtain conditions for the balance condition in a Wheatstone 
bridge. 
 
9. ‹Ûú ¯ÖÏÖê™üÖò®Ö ŸÖ£ÖÖ ‹Ûú ‹»±ÌúÖ (a) ÛúÞÖ ÃÖê ÃÖÓ²Ö¨ü ›üß-²ÖÎÖòÝ»Öß ŸÖ¸ÓüÝÖ¤îü¬µÖÖí ÛúÖ ´ÖÖ®Ö ÃÖ´ÖÖ®Ö Æîü, ŸÖÖê –ÖÖŸÖ ÛúßוֵÖê –  
 (i)  ˆ®ÖÛêú Ÿ¾Ö¸üÛú ×¾Ö³Ö¾ÖÖë ÛúÖ †®Öã¯ÖÖŸÖ  
 (ii)  ˆ®ÖÛúß “ÖÖ»ÖÖë ÛúÖ †®Öã¯ÖÖŸÖ  2 
 A proton and an a-particle have the same de-Broglie wavelength. Determine the ratio 
of (i) their accelerating potentials (ii) their speeds. 
 
10. ¤ü¿ÖÖÔ‡µÖê ×Ûú ÆüÖ‡›ÒüÖê•Ö®Ö ¯Ö¸ü´ÖÖÞÖã Ûúß ÛúõÖÖë Ûúß ×¡Ö•µÖÖ ´Öë n
2
 Ûêú †®ÖãÃÖÖ¸ü ¯Ö׸ü¾ÖŸÖÔ®Ö ÆüÖêŸÖÖ Æïü … •ÖÆüÖÑ, n ¯Ö¸ü´ÖÖÞÖã Ûúß 
Œ¾ÖÖÓ™ü´Ö ÃÖÓܵÖÖ Æîü …  2  
 Show that the radius of the orbit in hydrogen atom varies as n
2
, where n is the 
principal quantum number of the atom. 
Page 5


55/1/3/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No.  
 
 
 
³ÖÖîןÖÛú ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
PHYSICS (Theory)  
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ  : 3 ‘ÖÓ™êü ] [ †×¬ÖÛúŸÖ´Ö †ÓÛú  : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö    : : : :   
    (i) ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë Ûãú»Ö 26 ¯ÖÏ¿®Ö Æïü … ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ‡ÃÖ ¯ÖÏ¿®Ö ¯Ö¡Ö Ûêú 5 ³ÖÖÝÖ Æïü : ÜÖÞ›ü-Ûú, ÜÖÞ›ü-ÜÖ, ÜÖÞ›ü-ÝÖ, ÜÖÞ›ü-‘Ö †Öî¸ü ÜÖÞ›ü-’û …  
 (iii) ÜÖÞ›ü-Ûú ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 1 †ÓÛú ÛúÖ, ÜÖÞ›ü-ÜÖ ´Öë 5 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 2 †ÓÛú Ûêú, ÜÖÞ›ü-ÝÖ ´Öë 12 ¯ÖÏ¿®Ö 
¯ÖÏŸµÖêÛú 3 †ÓÛú Ûêú, ÜÖÞ›ü-‘Ö ´Öë 4 †ÓÛú ÛúÖ ‹Ûú ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö †Öî¸ü ÜÖÞ›ü-’û ´Öë 3 ¯ÖÏ¿®Ö ¯ÖÏŸµÖêÛú 5 †ÓÛú 
Ûêú פü‹ ÝÖ‹ Æïü …  
 (iv) ÃÖ´ÖÝÖÏ ¯Ö¸ü ÛúÖê‡Ô ×¾ÖÛú»¯Ö ®ÖÆüà Æîü … ×±ú¸ü ³Öß 2 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö, 3 †ÓÛú Ûêú 1 ¯ÖÏ¿®Ö †Öî¸ü 5 †ÓÛúÖë Ûêú 3 ¯ÖÏ¿®ÖÖë 
´Öë ³Öߟָüß ×¾ÖÛú»¯Ö פü‹ ÝÖ‹ Æïü … ‹êÃÖê ¯ÖÏ¿®ÖÖë ´Öë †Ö¯ÖÛúÖê ×¾ÖÛú»¯ÖÖë ´Öë ÃÖê ‹Ûú ÛúÖê Æü»Ö Ûú¸ü®ÖÖ Æîü …  
 Series : SSO/1 
55/1/3/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 16 Æïü … 
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê 
ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 16 printed pages. 
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will read the 
question paper only and will not write any answer on the answer-book during this period. 
ÛúÖê›ü ®ÖÓ. 
Code No.  
     
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 3 
55/1/3/D 2 
  
 (v) •ÖÆüÖÑ †Ö¾Ö¿µÖÛú ÆüÖê, ¾ÖÆüÖÑ †Ö¯Ö ³ÖÖîןÖÛ †“Ö¸üÖë Ûêú ×®Ö´®Ö×»Ö×ÜÖŸÖ ´Ö滵ÖÖë ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  ®µÖæ™ÒüÖò®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.675 × 10
–27
 kg 
  ¯ÖÏÖê™üÖê®Ö ÛúÖ ¦ü¾µÖ´ÖÖ®Ö = 1.673 × 10
–27
 kg 
  ‹ê¾ÖÖêÝÖê›ÒüÖê ÃÖÓܵÖÖ = 6.023 × 10
23
 ¯ÖÏ×ŸÖ ÝÖÏÖ´Ö ´ÖÖê»Ö  
  ²ÖÖò»™Ëü•ÖÌ´ÖÖ®Ö ×®ÖµÖŸÖÖÓÛú = 1.38 × 10
–23
 JK
–1
 
 
General Instructions :   
 (i) There are 26 questions in all. All questions are compulsory.  
 (ii) This question paper has five sections : Section A, Section B, Section C, Section D 
and Section E. 
 (iii) Section A contains five questions of one mark each, Section B contains five 
questions of two marks each, Section C contains twelve questions of three marks 
each, Section D contains one value based question of four marks and Section E 
contains three questions of five marks each. 
 (iv) There is no overall choice. However, an internal choice has been provided in one 
question of two marks, one question of three marks and all the three questions of 
five marks weightage. You have to attempt only one of the choices in such 
questions. 
 (v) You may use the following values of physical constants wherever necessary : 
  c = 3 × 10
8
 m/s 
  h = 6.63 × 10
–34
 Js 
  e = 1.6 × 10
–19
 C 
  µ
0
 = 4p × 10
–7
 T m A
–1 
  
e
0
 = 8.854 × 10
–12
 C
2
 N
–1
 m
–2 
 
  
1
4pe
0
 = 9 × 10
9
 N m
2
 C
–2 
  m
e
 = 9.1 × 10
–31
 kg 
  mass of neutron = 1.675 × 10
–27
 kg 
  mass of proton = 1.673 × 10
–27
 kg 
  Avogadro’s number = 6.023 × 10
23
 per gram mole 
  Boltzmann constant = 1.38 × 10
–23
 JK
–1
 
55/1/3/D 3 [P.T.O. 
ÜÖÞ›ü – Ûú  
Section – A 
 
1. ×ÛúÃÖß ˆ¢Ö»Ö »ÖëÃÖ Ûêú ¯Ö¤üÖ£ÖÔ ÛúÖ †¯Ö¾ÖŸÖÔ®ÖÖÓÛú 1.5 Æîü … ‡ÃÖê 1.65 †¯Ö¾ÖŸÖÔ®ÖÖÓÛú Ûêú ×ÛúÃÖß ´ÖÖ¬µÖ´Ö ´Öë ›ãü²ÖÖ®Öê ¯Ö¸ü »ÖëÃÖ 
Ûúß ¯ÖÏÛéú×ŸÖ ÛîúÃÖß ÆüÖêÝÖß ? 1 
 A concave lens of refractive index 1.5 is immersed in a medium of refractive index 1.65. 
What is the nature of the lens ? 
 
2. ¯ÖÖ¿¾ÖÔ ²Öï›ü ÛîúÃÖê ˆŸ¯Ö®®Ö ÆüÖêŸÖê Æïü ? 1 
 How are side bands produced ? 
 
3. µÖÆüÖÑ ‹Ûú ¯Ö¤üÖ£ÖÔ, GaAs Ûêú ×»ÖµÖê, ¾ÖÖê»™üŸÖÖ Ûêú ÃÖÖ£Ö ¬ÖÖ¸üÖ Ûêú ¯Ö׸ü¾ÖŸÖÔ®Ö ÛúÖê ¤ü¿ÖÖÔ®Öê Ûêú ×»ÖµÖê ‹Ûú ÝÖÏÖ±ú (†Ö»ÖêÜÖ) 
פüµÖÖ ÝÖµÖÖ Æîü, ˆÃÖ õÖê¡Ö Ûúß ¯ÖÆü“ÖÖ®Ö ÛúßוֵÖê •ÖÆüÖÑ,  
 (i) ŠúÞÖÖŸ´ÖÛú ¯ÖÏןָüÖê¬Ö Æîü …  
 (ii) †Öê´Ö Ûêú ×®ÖµÖ´Ö ÛúÖ ¯ÖÖ»Ö®Ö ÆüÖêŸÖÖ Æîü …  1 
 
 Graph showing the variation of current versus voltage for a material GaAs is shown in 
the figure. Identify the region of  
 (i) negative resistance 
 (ii) where Ohm’s law is obeyed. 
 
 
4. ÃÖÓ¬ÖÖ׸ü¡Ö - ¯ÖÏן֑ÖÖŸÖ Ûúß ¯Ö׸ü³ÖÖÂÖÖ ×»Ö×ÜÖµÖê … ‡ÃÖÛúÖ ‹ÃÖ.†Ö‡Ô. (S.I.) ´ÖÖ¡ÖÛú ŒµÖÖ Æîü ? 1 
 Define capacitor reactance. Write its S.I. units. 
 
5. 1 cm ³Öã•ÖÖ Ûêú ‘Ö®Ö (ŒµÖæ²Ö) ´Öë ¯Ö׸ü²Ö¨ü (²Ö®¤ü) ×ÛúÃÖß ×«ü¬ÖÐã¾Ö Ûêú ÛúÖ¸üÞÖ ˆÃÖÃÖê ‘Ö®Ö ÃÖê ÝÖã•Ö¸ü®Öê ¾ÖÖ»Öê ×¾ÖªãŸÖ °»ÖŒÃÖ 
ÛúÖ ´ÖÖ®Ö ŒµÖÖ ÆüÖêÝÖÖ ?   1 
 What is the electric flux through a cube of side 1 cm which encloses an electric dipole ? 
55/1/3/D 4 
  
ÜÖÞ›ü – ÜÖ  
Section – B 
 
6. ®Öî•Ö ŸÖ£ÖÖ †¯Ö×´Ö×ÁÖŸÖ †¬ÖÔ“ÖÖ»ÖÛúÖë ´Öë †®ŸÖ¸ü (³Öê¤ü) ÛúßוֵÖê …  2 
 Distinguish between ‘intrinsic’ and ‘extrinsic’ semiconductors. 
 
7. ¤ü¯ÖÔÞÖ ÃÖæ¡Ö Ûêú ˆ¯ÖµÖÖêÝÖ «üÖ¸üÖ ¤ü¿ÖÖÔ‡µÖê ×Ûú, ×ÛúÃÖß †¾ÖŸÖ»Ö ¤ü¯ÖÔÞÖ Ûêú ÃÖÖ´Ö®Öê ˆÃÖÛúß f (±úÖêÛúÃÖ ¤æü¸üß) ŸÖ£ÖÖ 2f (¾ÖÛÎúŸÖÖ 
ס֕µÖÖ) Ûêú ²Öß“Ö ×Ã£ÖŸÖ ×ÛúÃÖß ¾ÖßÖã ÛúÖ ¯ÖÏןÖײִ²Ö, 2f Ûêú ¯Ö¸êü (2f ÃÖê †Öî¸ü †ÖÝÖê) ²Ö®ÖŸÖÖ Æîü …  2 
 Use the mirror equation to show that an object placed between f and 2f of a concave 
mirror produces a real image beyond 2f. 
†£Ö¾ÖÖ/OR 
 ¤üÖê ÛÎúÖ×ÃÖŸÖ ¯ÖÖê»Öê¸üÖò‡›üÖë Ûêú ²Öß“Ö ´Öë ×ÛúÃÖß †®µÖ ¯ÖÖê»ÖÖò¸üÖ‡›ü Ûúß ¿Öß™ü (“ÖÖ¤ü¸ü) ÛúÖê ‘Öã´ÖÖ®Öê ÃÖê ¯ÖÖ¸üÝÖ×´ÖŸÖ ¯ÖÏÛúÖ¿Ö Ûúß 
ŸÖß¾ÖΟÖÖ Ûêú ×»ÖµÖê ¾µÖÓ•ÖÛú ¯ÖÏÖ¯ŸÖ ÛúßוֵÖê …  
 ‡ÃÖ ¿Öß™ü (“ÖÖ¤ü¸ü) Ûúß ×ÛúÃÖ ×ãÖ×ŸÖ ´Öë ¯ÖÖ¸üÝÖ×´ÖŸÖ ¯ÖÏÛúÖ¿Ö Ûúß ŸÖß¾ÖΟÖÖ †×¬ÖÛúŸÖ´Ö ÆüÖêÝÖß ? 
 Find an expression for intensity of transmitted light when a polaroid sheet is rotated 
between two crossed polaroids. In which position of the polaroid sheet will the 
transmitted intensity be maximum ? 
 
8. ×Ûú¸üÜÖÖê¯Ö Ûêú ×®ÖµÖ´ÖÖë Ûêú ˆ¯ÖµÖÖêÝÖ ÃÖê ×ÛúÃÖß ¾Æüß™üÙüÖê®Ö ײÖ륅 (ÃÖêŸÖã) ´Öë ÃÖÓŸÖã»Ö®Ö ×ãÖ×ŸÖ Ûêú ×»ÖµÖê ¯ÖÏןֲ֮¬Ö (¿ÖŸÖí) –ÖÖŸÖ 
ÛúßוֵÖê …    2 
 Use Kirchhoff’s rules to obtain conditions for the balance condition in a Wheatstone 
bridge. 
 
9. ‹Ûú ¯ÖÏÖê™üÖò®Ö ŸÖ£ÖÖ ‹Ûú ‹»±ÌúÖ (a) ÛúÞÖ ÃÖê ÃÖÓ²Ö¨ü ›üß-²ÖÎÖòÝ»Öß ŸÖ¸ÓüÝÖ¤îü¬µÖÖí ÛúÖ ´ÖÖ®Ö ÃÖ´ÖÖ®Ö Æîü, ŸÖÖê –ÖÖŸÖ ÛúßוֵÖê –  
 (i)  ˆ®ÖÛêú Ÿ¾Ö¸üÛú ×¾Ö³Ö¾ÖÖë ÛúÖ †®Öã¯ÖÖŸÖ  
 (ii)  ˆ®ÖÛúß “ÖÖ»ÖÖë ÛúÖ †®Öã¯ÖÖŸÖ  2 
 A proton and an a-particle have the same de-Broglie wavelength. Determine the ratio 
of (i) their accelerating potentials (ii) their speeds. 
 
10. ¤ü¿ÖÖÔ‡µÖê ×Ûú ÆüÖ‡›ÒüÖê•Ö®Ö ¯Ö¸ü´ÖÖÞÖã Ûúß ÛúõÖÖë Ûúß ×¡Ö•µÖÖ ´Öë n
2
 Ûêú †®ÖãÃÖÖ¸ü ¯Ö׸ü¾ÖŸÖÔ®Ö ÆüÖêŸÖÖ Æïü … •ÖÆüÖÑ, n ¯Ö¸ü´ÖÖÞÖã Ûúß 
Œ¾ÖÖÓ™ü´Ö ÃÖÓܵÖÖ Æîü …  2  
 Show that the radius of the orbit in hydrogen atom varies as n
2
, where n is the 
principal quantum number of the atom. 
55/1/3/D 5 [P.T.O. 
ÜÖÞ›ü – ÝÖ 
Section – C 
 
11. ÝÖÖê®ÖÖê´Öß™ü¸ü Ûúß ÛúÖµÖÔ¯ÖÏÞÖÖ»Öß Ûêú ×ÃÖ¨üÖ®ŸÖ ÛúÖ ¾ÖÞÖÔ®Ö ÛúßוֵÖê …  
 ‹Ûú ÝÖÖê®ÖÖê´Öß™ü¸ü ÛúÖ ¯ÖÏןָüÖê¬Ö G Æîü … ‡ÃÖÛêú ÁÖêÞÖßÛÎú´Ö ´Öë ‹Ûú ¯ÖÏןָüÖê¬Ö R
1
 •ÖÖê›ÌüÛú¸ü ‡ÃÖê V ¾ÖÖê»™ü ¯Ö¸üÖÃÖü Ûêú 
¾ÖÖê»™ü´Öß™ü¸ü ´Öë ºþ¯ÖÖ®ŸÖ׸üŸÖ ×ÛúµÖÖ •ÖÖŸÖÖ Æîü … µÖפü ÝÖÖê®ÖÖê´Öß™ü¸ü Ûêú ÃÖÖ£Ö ÁÖêÞÖßÛÎú´Ö ´Öë R
2
 ¯ÖÏןָüÖê¬Ö •ÖÖê›ÌüÖ •ÖÖµÖ ŸÖÖê 
¾ÖÖê»™ü´Öß™ü¸ü V/2 ¾ÖÖê»™ü ŸÖÛú ´ÖÖ¯Ö ÃÖÛúŸÖÖ Æîü … R
1
 ŸÖ£ÖÖ R
2
 Ûêú ¯Ö¤üÖë ´Öë ¾ÖÆü ¯ÖÏןָüÖê¬Ö –ÖÖŸÖ ÛúßוֵÖê, •ÖÖê ‡ÃÖ 
ÝÖÖê®ÖÖê´Öß™ü¸ü ÛúÖê 2 V ¯Ö¸üÖÃÖ Ûêú ¾ÖÖê»™ü´Öß™ü¸ü ´Öë ºþ¯ÖÖ®ŸÖ׸üŸÖ Ûú¸ü ÃÖÛêú …  R
1
 ŸÖ£ÖÖ R
2
 Ûêú ¯Ö¤üÖë ´Öë ÝÖÖê®ÖÖê´Öß™ü¸ü Ûêú 
¯ÖÏןָüÖê¬Ö ‘G’ ÛúÖ ´ÖÖ®Ö ³Öß –ÖÖŸÖ ÛúßוֵÖê …  3 
 State the principle of working of a galvanometer. 
 A galvanometer of resistance G is converted into a voltmeter to measure upto V volts 
by connecting a resistance R
1
 in series with the coil. If a resistance R
2
 is connected in 
series with it, then it can measure upto V/2 volts. Find the resistance, in terms of               
R
1
 and R
2
, required to be connected to convert it into a voltmeter that can read upto            
2 V. Also find the resistance G of the galvanometer in terms of R
1
 and R
2
. 
 
12. ±úÖê™üÖê›üÖµÖÖê›üÖë Ûúß ÃÖÓ¸ü“Ö®ÖÖ ×Ûú®Ö ¯ÖÏןֱú»ÖÖë ÛúÖê ¬µÖÖ®Ö ´Öë ¸üÜÖÛú¸ü Ûúß •ÖÖŸÖß Æîü ? ‹Ûú ˆ¯ÖµÖãŒŸÖ †Ö¸êüÜÖ Ûúß ÃÖÆüÖµÖŸÖÖ ÃÖê 
‡ÃÖÛúß ÛúÖµÖÔ×¾Ö×¬Ö ÛúÖ ¾ÖÞÖÔ®Ö ÛúßוֵÖê …  
 µÖª×¯Ö ¯Ö¿“Öפü׿ÖÛú ²ÖÖµÖÃÖ Ûúß ¬ÖÖ¸üÖ Ûúß ŸÖã»Ö®ÖÖ ´Öë †ÝÖÏפü׿ÖÛú ²ÖÖµÖÃÖ Ûúß ¬ÖÖ¸üÖ †×¬ÖÛú ÆüÖêŸÖß Æîü, ×±ú¸ü ³Öß 
±úÖê™üÖê›üÖµÖÖê›ü ÛúÖê ¯Ö¿“Öפü׿ÖÛú ²ÖÖµÖÃÖ ´Öë ¯ÖÏ“ÖÖ×»ÖŸÖ Ûú¸ü®Öê ÛúÖ ÛúÖ¸üÞÖ ŒµÖÖ Æîü ? 3 
 With what considerations in view, a photodiode is fabricated ? State its working with 
the help of a suitable diagram.  
 Eventhough the current in the forward bias is known to be more than in the reverse 
bias, yet the photodiode works in reverse bias. What is the reason ? 
 
13. ˆ³ÖµÖ×®Öšü ˆŸÃÖ•ÖÔÛú (CE) ×¾Ö®µÖÖÃÖ ´Öë ™ÒüÖÓוÖÙü¸ü ¯ÖϾ֬ÖÔÛú ÛúÖ ‹Ûú ¯Ö׸ü¯Ö£Ö †Ö¸êüÜÖ ²Ö®ÖÖ‡µÖê …  
 (i) ×®Ö¾Öê¿Öß ¯ÖÏןָüÖê¬Ö ŸÖ£ÖÖ (ii) ¬ÖÖ¸üÖ ¯ÖϾ֬ÖÔÛú ÝÖãÞÖÖÓÛú ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ ÛúßוֵÖê … ¯ÖϺþ¯Öß ×®Ö¾Öê¿Ö ŸÖ£ÖÖ ×®ÖÝÖÔŸÖ 
†×³Ö»ÖÖõÖ×ÞÖÛúÖë Ûêú ˆ¯ÖµÖÖêÝÖ «üÖ¸üÖ ‡®ÖÛúÖ ´ÖÖ®Ö ÛîúÃÖê ×®Ö¬ÖÖÔ׸üŸÖ ×ÛúµÖÖ •ÖÖŸÖÖ Æîü ?  3 
 Draw a circuit diagram of a transistor amplifier in CE configuration. 
 Define the terms :  (i) Input resistance and (ii) Current amplification factor. How are 
these determined using typical input and output characteristics ?