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The strength of 60 students has been divided into two sections A and B with 35 students and 25 students respectively. if you and your sister are among these 60 students then find the probability of both of you being in same section?
Most Upvoted Answer
The strength of 60 students has been divided into two sections A and B...
TOTAL STUDENTS
60
A. B
35. 25
P = 35C2+ 25C2 / 60C2
=( 35×34/2 + 25×24/2 ) /60×59/2
• .• Nc2 = n(n-1)/2 ]
= 895/1770
= 179/354 ans.
Community Answer
The strength of 60 students has been divided into two sections A and B...

Probability of Being in the Same Section

Given Information:
- Total students = 60
- Section A has 35 students
- Section B has 25 students

Calculating the Probability:
- Total number of ways to select 2 students out of 60 = 60C2 = 1770

Case 1: Both in Section A
- Number of ways to select 2 students from 35 in Section A = 35C2 = 595

Case 2: Both in Section B
- Number of ways to select 2 students from 25 in Section B = 25C2 = 300

Total favorable outcomes:
- Total ways for both in the same section = 595 (both in A) + 300 (both in B) = 895

Probability of both being in the same section:
- Probability = Favorable outcomes / Total outcomes = 895 / 1770 ≈ 0.5056

Therefore, the probability of you and your sister being in the same section is approximately 0.5056 or 50.56%.
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The strength of 60 students has been divided into two sections A and B with 35 students and 25 students respectively. if you and your sister are among these 60 students then find the probability of both of you being in same section?
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