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sunita is twice as old as Ashima. if 6 years is subtracted from ashima's age and 4 years added to Sunita's age then Sunita will be 4 times ashima's age. how old were the two years ago
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sunita is twice as old as Ashima. if 6 years is subtracted from ashima...
Let the age of sunita be 2x and age of ashima be x therefore according to the question equation will be 4(x-6)=2x+4 4x-24=2x+4 4x-2x=4+24 2x=28 x=28/2 x=14 so ages will be of sunita and ashima be 28 years and 14 years respectively
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sunita is twice as old as Ashima. if 6 years is subtracted from ashima's age and 4 years added to Sunita's age then Sunita will be 4 times ashima's age. how old were the two years ago
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