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The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 KJ mol⁻¹ respectively .The enthalpy of formation of carbon monoxide per mol is
  • a)
    -110.5 KJ
  • b)
    -676.5 KJ
  • c)
    +676.5 KJ
  • d)
    110.5 KJ
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The enthalpies of combustion of carbon and carbon monoxide are -393.5 ...
-1 respectively. These values represent the amount of energy released when one mole of each substance is completely burned in oxygen to form carbon dioxide gas (CO2).

The enthalpy of combustion of carbon (-393.5 KJ mol-1) is more negative than that of carbon monoxide (-283 KJ mol-1) because carbon dioxide is a more stable compound than carbon monoxide. This means that more energy is released when carbon is burned to form carbon dioxide than when carbon monoxide is burned to form carbon dioxide.

The enthalpy of combustion is an important thermodynamic property that is used to calculate the amount of heat released or absorbed during a chemical reaction. It is also used to determine the energy content of fuels and other combustible materials.

Overall, the enthalpy of combustion of carbon and carbon monoxide highlights the difference in their stability and energy content, and provides insight into their reactivity and usefulness in various applications.
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The enthalpies of combustion of carbon and carbon monoxide are -393.5 ...
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The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 KJ mol⁻¹ respectively .The enthalpy of formation of carbon monoxide per mol isa)-110.5 KJb)-676.5 KJc)+676.5 KJd)110.5 KJCorrect answer is option 'A'. Can you explain this answer?
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The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 KJ mol⁻¹ respectively .The enthalpy of formation of carbon monoxide per mol isa)-110.5 KJb)-676.5 KJc)+676.5 KJd)110.5 KJCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 KJ mol⁻¹ respectively .The enthalpy of formation of carbon monoxide per mol isa)-110.5 KJb)-676.5 KJc)+676.5 KJd)110.5 KJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283 KJ mol⁻¹ respectively .The enthalpy of formation of carbon monoxide per mol isa)-110.5 KJb)-676.5 KJc)+676.5 KJd)110.5 KJCorrect answer is option 'A'. Can you explain this answer?.
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